Invalid reference to variable PL/SQL



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1















I'm having trouble in getting started with PL/SQL
Here is my code:



SET SERVEROUTPUT ON;

DECLARE
v_cname customers.customer_name%type := '&customer_name';
v_cardno customers.card_number%type := '&card_number';
v_lastcid customers.customer_id%type;

BEGIN
SELECT customer_id INTO v_lastcid from customers
where customer_id = (select max(customer_id) from customers);
dbms_output.put_line(v_lastcid);

INSERT INTO customers(customer_id, customer_name, card_number)
VALUES(v_lastcid.NEXTVAL, v_cname, v_cardno);
COMMIT;
END;


This returns an error:



ORA-06550: line 12, column 20:
PLS-00487: Invalid reference to variable 'V_LASTCID'
ORA-06550: line 12, column 20:
PL/SQL: ORA-02289: sequence does not exist
ORA-06550: line 11, column 13:
PL/SQL: SQL Statement ignored
06550. 00000 - "line %s, column %s:n%s"
*Cause: Usually a PL/SQL compilation error.


Any help would me much appreciated!










share|improve this question

















  • 1





    Why do you think v_lastcid is a sequence? It is not. A good place to start is reading the Oracle docs.

    – OldProgrammer
    Nov 13 '18 at 21:19











  • @OldProgrammer - why do you think the OP thinks v_lastcid is a sequence? The OP may not even know what a sequence is, or what NEXTVAL means. He (she?) described the issue, much better than many (most?) posters on this site. An explanation of sequences, as in one of the Answers below, makes perfect sense for this poster.

    – mathguy
    Nov 13 '18 at 21:35


















1















I'm having trouble in getting started with PL/SQL
Here is my code:



SET SERVEROUTPUT ON;

DECLARE
v_cname customers.customer_name%type := '&customer_name';
v_cardno customers.card_number%type := '&card_number';
v_lastcid customers.customer_id%type;

BEGIN
SELECT customer_id INTO v_lastcid from customers
where customer_id = (select max(customer_id) from customers);
dbms_output.put_line(v_lastcid);

INSERT INTO customers(customer_id, customer_name, card_number)
VALUES(v_lastcid.NEXTVAL, v_cname, v_cardno);
COMMIT;
END;


This returns an error:



ORA-06550: line 12, column 20:
PLS-00487: Invalid reference to variable 'V_LASTCID'
ORA-06550: line 12, column 20:
PL/SQL: ORA-02289: sequence does not exist
ORA-06550: line 11, column 13:
PL/SQL: SQL Statement ignored
06550. 00000 - "line %s, column %s:n%s"
*Cause: Usually a PL/SQL compilation error.


Any help would me much appreciated!










share|improve this question

















  • 1





    Why do you think v_lastcid is a sequence? It is not. A good place to start is reading the Oracle docs.

    – OldProgrammer
    Nov 13 '18 at 21:19











  • @OldProgrammer - why do you think the OP thinks v_lastcid is a sequence? The OP may not even know what a sequence is, or what NEXTVAL means. He (she?) described the issue, much better than many (most?) posters on this site. An explanation of sequences, as in one of the Answers below, makes perfect sense for this poster.

    – mathguy
    Nov 13 '18 at 21:35














1












1








1








I'm having trouble in getting started with PL/SQL
Here is my code:



SET SERVEROUTPUT ON;

DECLARE
v_cname customers.customer_name%type := '&customer_name';
v_cardno customers.card_number%type := '&card_number';
v_lastcid customers.customer_id%type;

BEGIN
SELECT customer_id INTO v_lastcid from customers
where customer_id = (select max(customer_id) from customers);
dbms_output.put_line(v_lastcid);

INSERT INTO customers(customer_id, customer_name, card_number)
VALUES(v_lastcid.NEXTVAL, v_cname, v_cardno);
COMMIT;
END;


This returns an error:



ORA-06550: line 12, column 20:
PLS-00487: Invalid reference to variable 'V_LASTCID'
ORA-06550: line 12, column 20:
PL/SQL: ORA-02289: sequence does not exist
ORA-06550: line 11, column 13:
PL/SQL: SQL Statement ignored
06550. 00000 - "line %s, column %s:n%s"
*Cause: Usually a PL/SQL compilation error.


Any help would me much appreciated!










share|improve this question














I'm having trouble in getting started with PL/SQL
Here is my code:



SET SERVEROUTPUT ON;

DECLARE
v_cname customers.customer_name%type := '&customer_name';
v_cardno customers.card_number%type := '&card_number';
v_lastcid customers.customer_id%type;

BEGIN
SELECT customer_id INTO v_lastcid from customers
where customer_id = (select max(customer_id) from customers);
dbms_output.put_line(v_lastcid);

INSERT INTO customers(customer_id, customer_name, card_number)
VALUES(v_lastcid.NEXTVAL, v_cname, v_cardno);
COMMIT;
END;


This returns an error:



ORA-06550: line 12, column 20:
PLS-00487: Invalid reference to variable 'V_LASTCID'
ORA-06550: line 12, column 20:
PL/SQL: ORA-02289: sequence does not exist
ORA-06550: line 11, column 13:
PL/SQL: SQL Statement ignored
06550. 00000 - "line %s, column %s:n%s"
*Cause: Usually a PL/SQL compilation error.


Any help would me much appreciated!







oracle plsql






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asked Nov 13 '18 at 21:15









J Nereka HJ Nereka H

82




82







  • 1





    Why do you think v_lastcid is a sequence? It is not. A good place to start is reading the Oracle docs.

    – OldProgrammer
    Nov 13 '18 at 21:19











  • @OldProgrammer - why do you think the OP thinks v_lastcid is a sequence? The OP may not even know what a sequence is, or what NEXTVAL means. He (she?) described the issue, much better than many (most?) posters on this site. An explanation of sequences, as in one of the Answers below, makes perfect sense for this poster.

    – mathguy
    Nov 13 '18 at 21:35













  • 1





    Why do you think v_lastcid is a sequence? It is not. A good place to start is reading the Oracle docs.

    – OldProgrammer
    Nov 13 '18 at 21:19











  • @OldProgrammer - why do you think the OP thinks v_lastcid is a sequence? The OP may not even know what a sequence is, or what NEXTVAL means. He (she?) described the issue, much better than many (most?) posters on this site. An explanation of sequences, as in one of the Answers below, makes perfect sense for this poster.

    – mathguy
    Nov 13 '18 at 21:35








1




1





Why do you think v_lastcid is a sequence? It is not. A good place to start is reading the Oracle docs.

– OldProgrammer
Nov 13 '18 at 21:19





Why do you think v_lastcid is a sequence? It is not. A good place to start is reading the Oracle docs.

– OldProgrammer
Nov 13 '18 at 21:19













@OldProgrammer - why do you think the OP thinks v_lastcid is a sequence? The OP may not even know what a sequence is, or what NEXTVAL means. He (she?) described the issue, much better than many (most?) posters on this site. An explanation of sequences, as in one of the Answers below, makes perfect sense for this poster.

– mathguy
Nov 13 '18 at 21:35






@OldProgrammer - why do you think the OP thinks v_lastcid is a sequence? The OP may not even know what a sequence is, or what NEXTVAL means. He (she?) described the issue, much better than many (most?) posters on this site. An explanation of sequences, as in one of the Answers below, makes perfect sense for this poster.

– mathguy
Nov 13 '18 at 21:35













2 Answers
2






active

oldest

votes


















1














You probably meant to say MAX + 1 (see lines 7 and 12), i.e.



SQL> create table customers
2 (customer_id number,
3 customer_name varchar2(20),
4 card_number varchar2(20));

Table created.

SQL> DECLARE
2 v_cname customers.customer_name%type := '&customer_name';
3 v_cardno customers.card_number%type := '&card_number';
4 v_lastcid customers.customer_id%type;
5
6 BEGIN
7 SELECT nvl(max(customer_id), 0) INTO v_lastcid from customers
8 where customer_id = (select max(customer_id) from customers);
9 dbms_output.put_line(v_lastcid);
10
11 INSERT INTO customers(customer_id, customer_name, card_number)
12 VALUES(v_lastcid + 1, v_cname, v_cardno);
13 COMMIT;
14 END;
15 /
Enter value for customer_name: Little
Enter value for card_number: Foot
0

PL/SQL procedure successfully completed.

SQL> select * from customers;

CUSTOMER_ID CUSTOMER_NAME CARD_NUMBER
----------- -------------------- --------------------
1 Little Foot

SQL>


Although it works, it is doomed to fail in a multi-user environment if two (or more) users fetch the same MAX value; insert would fail with a DUP-VAL-ON-INDEX error (if the ID is supposed to be unique).



Therefore, use a sequence (which is what NEXTVAL in your code suggests):



SQL> create sequence seq_cust;

Sequence created.

SQL> DECLARE
2 v_cname customers.customer_name%type := '&customer_name';
3 v_cardno customers.card_number%type := '&card_number';
4 v_lastcid customers.customer_id%type;
5 BEGIN
6 INSERT INTO customers(customer_id, customer_name, card_number)
7 VALUES(seq_cust.nextval, v_cname, v_cardno);
8 COMMIT;
9 END;
10 /
Enter value for customer_name: Big
Enter value for card_number: Foot

PL/SQL procedure successfully completed.





share|improve this answer






























    0














    nextval is used to get the next value from a sequence. It's usually used to create a pseudo primary key. You can think of it like a special function that can only be called on sequences.



    v_lastcid is a variable that has the same type as the customer_id column in the customers table. So if you had a table like this...



    CREATE TABLE CUSTOMERS ( CUSTOMER_ID INTEGER );


    ...then v_lastcid is an integer;



    If you're trying to make a dummy customer with the next highest number maybe you mean something like...



    INSERT INTO customers(customer_id, customer_name, card_number)
    VALUES(v_lastcid + 1, v_cname, v_cardno);


    Hope this helps.






    share|improve this answer























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      2 Answers
      2






      active

      oldest

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      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      You probably meant to say MAX + 1 (see lines 7 and 12), i.e.



      SQL> create table customers
      2 (customer_id number,
      3 customer_name varchar2(20),
      4 card_number varchar2(20));

      Table created.

      SQL> DECLARE
      2 v_cname customers.customer_name%type := '&customer_name';
      3 v_cardno customers.card_number%type := '&card_number';
      4 v_lastcid customers.customer_id%type;
      5
      6 BEGIN
      7 SELECT nvl(max(customer_id), 0) INTO v_lastcid from customers
      8 where customer_id = (select max(customer_id) from customers);
      9 dbms_output.put_line(v_lastcid);
      10
      11 INSERT INTO customers(customer_id, customer_name, card_number)
      12 VALUES(v_lastcid + 1, v_cname, v_cardno);
      13 COMMIT;
      14 END;
      15 /
      Enter value for customer_name: Little
      Enter value for card_number: Foot
      0

      PL/SQL procedure successfully completed.

      SQL> select * from customers;

      CUSTOMER_ID CUSTOMER_NAME CARD_NUMBER
      ----------- -------------------- --------------------
      1 Little Foot

      SQL>


      Although it works, it is doomed to fail in a multi-user environment if two (or more) users fetch the same MAX value; insert would fail with a DUP-VAL-ON-INDEX error (if the ID is supposed to be unique).



      Therefore, use a sequence (which is what NEXTVAL in your code suggests):



      SQL> create sequence seq_cust;

      Sequence created.

      SQL> DECLARE
      2 v_cname customers.customer_name%type := '&customer_name';
      3 v_cardno customers.card_number%type := '&card_number';
      4 v_lastcid customers.customer_id%type;
      5 BEGIN
      6 INSERT INTO customers(customer_id, customer_name, card_number)
      7 VALUES(seq_cust.nextval, v_cname, v_cardno);
      8 COMMIT;
      9 END;
      10 /
      Enter value for customer_name: Big
      Enter value for card_number: Foot

      PL/SQL procedure successfully completed.





      share|improve this answer



























        1














        You probably meant to say MAX + 1 (see lines 7 and 12), i.e.



        SQL> create table customers
        2 (customer_id number,
        3 customer_name varchar2(20),
        4 card_number varchar2(20));

        Table created.

        SQL> DECLARE
        2 v_cname customers.customer_name%type := '&customer_name';
        3 v_cardno customers.card_number%type := '&card_number';
        4 v_lastcid customers.customer_id%type;
        5
        6 BEGIN
        7 SELECT nvl(max(customer_id), 0) INTO v_lastcid from customers
        8 where customer_id = (select max(customer_id) from customers);
        9 dbms_output.put_line(v_lastcid);
        10
        11 INSERT INTO customers(customer_id, customer_name, card_number)
        12 VALUES(v_lastcid + 1, v_cname, v_cardno);
        13 COMMIT;
        14 END;
        15 /
        Enter value for customer_name: Little
        Enter value for card_number: Foot
        0

        PL/SQL procedure successfully completed.

        SQL> select * from customers;

        CUSTOMER_ID CUSTOMER_NAME CARD_NUMBER
        ----------- -------------------- --------------------
        1 Little Foot

        SQL>


        Although it works, it is doomed to fail in a multi-user environment if two (or more) users fetch the same MAX value; insert would fail with a DUP-VAL-ON-INDEX error (if the ID is supposed to be unique).



        Therefore, use a sequence (which is what NEXTVAL in your code suggests):



        SQL> create sequence seq_cust;

        Sequence created.

        SQL> DECLARE
        2 v_cname customers.customer_name%type := '&customer_name';
        3 v_cardno customers.card_number%type := '&card_number';
        4 v_lastcid customers.customer_id%type;
        5 BEGIN
        6 INSERT INTO customers(customer_id, customer_name, card_number)
        7 VALUES(seq_cust.nextval, v_cname, v_cardno);
        8 COMMIT;
        9 END;
        10 /
        Enter value for customer_name: Big
        Enter value for card_number: Foot

        PL/SQL procedure successfully completed.





        share|improve this answer

























          1












          1








          1







          You probably meant to say MAX + 1 (see lines 7 and 12), i.e.



          SQL> create table customers
          2 (customer_id number,
          3 customer_name varchar2(20),
          4 card_number varchar2(20));

          Table created.

          SQL> DECLARE
          2 v_cname customers.customer_name%type := '&customer_name';
          3 v_cardno customers.card_number%type := '&card_number';
          4 v_lastcid customers.customer_id%type;
          5
          6 BEGIN
          7 SELECT nvl(max(customer_id), 0) INTO v_lastcid from customers
          8 where customer_id = (select max(customer_id) from customers);
          9 dbms_output.put_line(v_lastcid);
          10
          11 INSERT INTO customers(customer_id, customer_name, card_number)
          12 VALUES(v_lastcid + 1, v_cname, v_cardno);
          13 COMMIT;
          14 END;
          15 /
          Enter value for customer_name: Little
          Enter value for card_number: Foot
          0

          PL/SQL procedure successfully completed.

          SQL> select * from customers;

          CUSTOMER_ID CUSTOMER_NAME CARD_NUMBER
          ----------- -------------------- --------------------
          1 Little Foot

          SQL>


          Although it works, it is doomed to fail in a multi-user environment if two (or more) users fetch the same MAX value; insert would fail with a DUP-VAL-ON-INDEX error (if the ID is supposed to be unique).



          Therefore, use a sequence (which is what NEXTVAL in your code suggests):



          SQL> create sequence seq_cust;

          Sequence created.

          SQL> DECLARE
          2 v_cname customers.customer_name%type := '&customer_name';
          3 v_cardno customers.card_number%type := '&card_number';
          4 v_lastcid customers.customer_id%type;
          5 BEGIN
          6 INSERT INTO customers(customer_id, customer_name, card_number)
          7 VALUES(seq_cust.nextval, v_cname, v_cardno);
          8 COMMIT;
          9 END;
          10 /
          Enter value for customer_name: Big
          Enter value for card_number: Foot

          PL/SQL procedure successfully completed.





          share|improve this answer













          You probably meant to say MAX + 1 (see lines 7 and 12), i.e.



          SQL> create table customers
          2 (customer_id number,
          3 customer_name varchar2(20),
          4 card_number varchar2(20));

          Table created.

          SQL> DECLARE
          2 v_cname customers.customer_name%type := '&customer_name';
          3 v_cardno customers.card_number%type := '&card_number';
          4 v_lastcid customers.customer_id%type;
          5
          6 BEGIN
          7 SELECT nvl(max(customer_id), 0) INTO v_lastcid from customers
          8 where customer_id = (select max(customer_id) from customers);
          9 dbms_output.put_line(v_lastcid);
          10
          11 INSERT INTO customers(customer_id, customer_name, card_number)
          12 VALUES(v_lastcid + 1, v_cname, v_cardno);
          13 COMMIT;
          14 END;
          15 /
          Enter value for customer_name: Little
          Enter value for card_number: Foot
          0

          PL/SQL procedure successfully completed.

          SQL> select * from customers;

          CUSTOMER_ID CUSTOMER_NAME CARD_NUMBER
          ----------- -------------------- --------------------
          1 Little Foot

          SQL>


          Although it works, it is doomed to fail in a multi-user environment if two (or more) users fetch the same MAX value; insert would fail with a DUP-VAL-ON-INDEX error (if the ID is supposed to be unique).



          Therefore, use a sequence (which is what NEXTVAL in your code suggests):



          SQL> create sequence seq_cust;

          Sequence created.

          SQL> DECLARE
          2 v_cname customers.customer_name%type := '&customer_name';
          3 v_cardno customers.card_number%type := '&card_number';
          4 v_lastcid customers.customer_id%type;
          5 BEGIN
          6 INSERT INTO customers(customer_id, customer_name, card_number)
          7 VALUES(seq_cust.nextval, v_cname, v_cardno);
          8 COMMIT;
          9 END;
          10 /
          Enter value for customer_name: Big
          Enter value for card_number: Foot

          PL/SQL procedure successfully completed.






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 13 '18 at 21:32









          LittlefootLittlefoot

          25.5k71734




          25.5k71734























              0














              nextval is used to get the next value from a sequence. It's usually used to create a pseudo primary key. You can think of it like a special function that can only be called on sequences.



              v_lastcid is a variable that has the same type as the customer_id column in the customers table. So if you had a table like this...



              CREATE TABLE CUSTOMERS ( CUSTOMER_ID INTEGER );


              ...then v_lastcid is an integer;



              If you're trying to make a dummy customer with the next highest number maybe you mean something like...



              INSERT INTO customers(customer_id, customer_name, card_number)
              VALUES(v_lastcid + 1, v_cname, v_cardno);


              Hope this helps.






              share|improve this answer



























                0














                nextval is used to get the next value from a sequence. It's usually used to create a pseudo primary key. You can think of it like a special function that can only be called on sequences.



                v_lastcid is a variable that has the same type as the customer_id column in the customers table. So if you had a table like this...



                CREATE TABLE CUSTOMERS ( CUSTOMER_ID INTEGER );


                ...then v_lastcid is an integer;



                If you're trying to make a dummy customer with the next highest number maybe you mean something like...



                INSERT INTO customers(customer_id, customer_name, card_number)
                VALUES(v_lastcid + 1, v_cname, v_cardno);


                Hope this helps.






                share|improve this answer

























                  0












                  0








                  0







                  nextval is used to get the next value from a sequence. It's usually used to create a pseudo primary key. You can think of it like a special function that can only be called on sequences.



                  v_lastcid is a variable that has the same type as the customer_id column in the customers table. So if you had a table like this...



                  CREATE TABLE CUSTOMERS ( CUSTOMER_ID INTEGER );


                  ...then v_lastcid is an integer;



                  If you're trying to make a dummy customer with the next highest number maybe you mean something like...



                  INSERT INTO customers(customer_id, customer_name, card_number)
                  VALUES(v_lastcid + 1, v_cname, v_cardno);


                  Hope this helps.






                  share|improve this answer













                  nextval is used to get the next value from a sequence. It's usually used to create a pseudo primary key. You can think of it like a special function that can only be called on sequences.



                  v_lastcid is a variable that has the same type as the customer_id column in the customers table. So if you had a table like this...



                  CREATE TABLE CUSTOMERS ( CUSTOMER_ID INTEGER );


                  ...then v_lastcid is an integer;



                  If you're trying to make a dummy customer with the next highest number maybe you mean something like...



                  INSERT INTO customers(customer_id, customer_name, card_number)
                  VALUES(v_lastcid + 1, v_cname, v_cardno);


                  Hope this helps.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 13 '18 at 21:29









                  Jon TheriaultJon Theriault

                  11314




                  11314



























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