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Showing posts from January 12, 2019

SAS Championship

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Clash Royale CLAN TAG #URR8PPP SAS Championship Tournament information Location Cary, North Carolina, U.S. Established 2001 Course(s) Prestonwood Country Club Par 72 [1] Length 7,137 yards (6,526 m) [1] Tour(s) Champions Tour Format Stroke play Prize fund US$2,100,000 Month played October Tournament record score Aggregate 194 Bernhard Langer (2018) To par –22 Bernhard Langer (2018) Current champion Bernhard Langer Prestonwood CC Location in the United States The SAS Championship is a golf tournament on the Champions Tour. It is played annually in the autumn in Cary, North Carolina at the Prestonwood Country Club. SAS Institute is the main sponsor of the tournament. The purse for the 2014 tournament was US$2,100,000, with $315,000 going to the winner. The tournament was founded in 2001. Winners SAS Championship 2018 Bernhard Langer 2017 Colin Montgomerie 2016 Doug Garwood 2015 Tom Lehman 2014 Kirk Triplett 2013 Russ Cochran 2012 Bernhard Langer 2011 Kenny Perry 2010 Russ Co

Return strings in array that begin with the initial passed

Return strings in array that begin with the initial passed I have a .txt file which has data for states as given below: AL,Alab,4860 AK,Alas,7415 AZ,Ariz,6908 AR,Arka,2988 I have made a function which counts how many states there are that start with the initial passed as such: public int CInitial(char initial) int total = 0; for(int i = 0; i < states.length; i++) //states is an array which includes all states present in the .txt file String testString = states[i].getName(); // getName gets the name of the states present in the .txt file char stringToCharArray = testString.toCharArray(); for (char output : stringToCharArray) if(initial == output) total++; return total; This would return the number 4 if "A" is passed and 0 if any other initial is passed as there are 4 states that begin with the letter "A". Now how can I create a new function that passes a character and returns the name of all the states that begin with that character? For Instance th

Intra-City Hotel Selection [closed]

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1 Context: I am attempting to find an accommodation on the route between two near points, in a major city in the USA. They are separated by less than 5 miles. I arrive at a bus stop, and must find a place to stay for a day. I will arrive late at night, so I would like to find a hotel near my origin. I need to go to a different bus stop, a short distance away, that does not open until the next day. Simply waiting outside is not an option. Problem: I cannot find any such place within my budget, that is near my origin, or even near my destination. Is there a better way than what I have been doing to find accommodations? What I have done to research the problem: I have put my origin and destination into search engines, with a query to find hotels near the route. All the results are out of my price range. When I try to use an accommodation website, the results given are outside of the distance I am willing to go. This is not a shopping question because I am asking "I am a

Cannot use hasMany relationship on for loop in view (Laravel)

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0 I am trying to code an app which has several "Locations" which users can add as their favorites. I have a model for Locations, a model for Favorites and a database table where I log pairs of user_id and location_id to indicate a user's favorite locations. In my Location model I have defined the following hasMany relationship: public function favorites() return $this->hasMany(Favorite::class); I have also defined the inverse relationship on the Favorite model as follows: public function location() return $this->belongsTo(Location::class); Then in a view I'm trying to get a list of all locations and mark those which the user has marked as favorite. To do this I am looping through all locations, and trying to get a count on how many favorites the location has. It should be either 1 or 0, since the user_id/location_id combination row only exists if the user has the specific location as hi favorite. Here is the relevant part of the code (I am passin