How to send a SOAP API call in java and return it in json
I'm trying to send an api call and then read the returned json and print a value in the json information that is returned. The curl looks like this:
curl "https://(address goes here)?where=eq(open,true)&fields=name,totals"
-H 'Api-Key: (api key here)'
This is what I have so far:
import java.io.*;
import java.net.*;
import org.json.JSONObject;
import java.util.LinkedHashMap;
import java.util.Map;
public class Caller
public void APICall(String str) throws Exception
String url = "(address)" + str +
"(address continued)";
URL obj = new URL(url);
HttpURLConnection conn = (HttpURLConnection) obj.openConnection();
conn.setRequestProperty("Api-Key",
"(API Key)";
conn.setDoOutput(true);
conn.setDoInput(true);
conn.setRequestMethod("PUT");
JSONObject data = new JSONObject();
OutputStreamWriter out = new
OutputStreamWriter(conn.getOutputStream());
out.write(data);
BufferedReader in = new BufferedReader(
new InputStreamReader(conn.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null)
response.append(inputLine);
in.close();
out.close();
And then I call it from another class like this:
try
call.APICall(codeArray.get(x));
catch (Exception e)
e.printStackTrace();
str is the inputed API code for this address, and codeArray.get(x) is stored API codes. I'm not sure how to add the parameters in the curl code or return it in json format. I have hidden the address and API Key.
java json api post soap
add a comment |
I'm trying to send an api call and then read the returned json and print a value in the json information that is returned. The curl looks like this:
curl "https://(address goes here)?where=eq(open,true)&fields=name,totals"
-H 'Api-Key: (api key here)'
This is what I have so far:
import java.io.*;
import java.net.*;
import org.json.JSONObject;
import java.util.LinkedHashMap;
import java.util.Map;
public class Caller
public void APICall(String str) throws Exception
String url = "(address)" + str +
"(address continued)";
URL obj = new URL(url);
HttpURLConnection conn = (HttpURLConnection) obj.openConnection();
conn.setRequestProperty("Api-Key",
"(API Key)";
conn.setDoOutput(true);
conn.setDoInput(true);
conn.setRequestMethod("PUT");
JSONObject data = new JSONObject();
OutputStreamWriter out = new
OutputStreamWriter(conn.getOutputStream());
out.write(data);
BufferedReader in = new BufferedReader(
new InputStreamReader(conn.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null)
response.append(inputLine);
in.close();
out.close();
And then I call it from another class like this:
try
call.APICall(codeArray.get(x));
catch (Exception e)
e.printStackTrace();
str is the inputed API code for this address, and codeArray.get(x) is stored API codes. I'm not sure how to add the parameters in the curl code or return it in json format. I have hidden the address and API Key.
java json api post soap
add a comment |
I'm trying to send an api call and then read the returned json and print a value in the json information that is returned. The curl looks like this:
curl "https://(address goes here)?where=eq(open,true)&fields=name,totals"
-H 'Api-Key: (api key here)'
This is what I have so far:
import java.io.*;
import java.net.*;
import org.json.JSONObject;
import java.util.LinkedHashMap;
import java.util.Map;
public class Caller
public void APICall(String str) throws Exception
String url = "(address)" + str +
"(address continued)";
URL obj = new URL(url);
HttpURLConnection conn = (HttpURLConnection) obj.openConnection();
conn.setRequestProperty("Api-Key",
"(API Key)";
conn.setDoOutput(true);
conn.setDoInput(true);
conn.setRequestMethod("PUT");
JSONObject data = new JSONObject();
OutputStreamWriter out = new
OutputStreamWriter(conn.getOutputStream());
out.write(data);
BufferedReader in = new BufferedReader(
new InputStreamReader(conn.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null)
response.append(inputLine);
in.close();
out.close();
And then I call it from another class like this:
try
call.APICall(codeArray.get(x));
catch (Exception e)
e.printStackTrace();
str is the inputed API code for this address, and codeArray.get(x) is stored API codes. I'm not sure how to add the parameters in the curl code or return it in json format. I have hidden the address and API Key.
java json api post soap
I'm trying to send an api call and then read the returned json and print a value in the json information that is returned. The curl looks like this:
curl "https://(address goes here)?where=eq(open,true)&fields=name,totals"
-H 'Api-Key: (api key here)'
This is what I have so far:
import java.io.*;
import java.net.*;
import org.json.JSONObject;
import java.util.LinkedHashMap;
import java.util.Map;
public class Caller
public void APICall(String str) throws Exception
String url = "(address)" + str +
"(address continued)";
URL obj = new URL(url);
HttpURLConnection conn = (HttpURLConnection) obj.openConnection();
conn.setRequestProperty("Api-Key",
"(API Key)";
conn.setDoOutput(true);
conn.setDoInput(true);
conn.setRequestMethod("PUT");
JSONObject data = new JSONObject();
OutputStreamWriter out = new
OutputStreamWriter(conn.getOutputStream());
out.write(data);
BufferedReader in = new BufferedReader(
new InputStreamReader(conn.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null)
response.append(inputLine);
in.close();
out.close();
And then I call it from another class like this:
try
call.APICall(codeArray.get(x));
catch (Exception e)
e.printStackTrace();
str is the inputed API code for this address, and codeArray.get(x) is stored API codes. I'm not sure how to add the parameters in the curl code or return it in json format. I have hidden the address and API Key.
java json api post soap
java json api post soap
asked Nov 11 '18 at 3:33
Eman936Eman936
185
185
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I think you need to explain more about the SOAP payload you send and the answer received, and how is the JSON you expect to return, but I'm going to guess what you are trying to ask and try to answer it.
I can see in the code that you send a JSON to the API call, so I assume that a client will consume your endpoint with SOAP. The API you call should return a JSON right? Your endpoint will return a SOAP XML answer (or should it be raw JSON?), so you must do a conversion from JSON to XML (SOAP).
If you want to return a JSON to client and send a SOAP XML payload then read the following paragraph.
You may be wanting to instead return a XML, return a JSON, to do this, if you are using a framework either on the server side or client side, you must read the documentation. If it is possible to change the headers (server side) through the framework you should accept the XML format (Accept: application/soap+xml; charset=utf-8
) and send to your client Content-type: application/json
. In your client, when you send the request, you must have the headers of Content-type: application/soap+xml; charset=utf-8
and Accept: application/json
.
TL;DR; (For client sending XML and receiving JSON)
Server:
Accept: application/soap+xml; charset=utf-8
Content-type: application/json
Client:
Accept: application/json
Content-type: application/soap+xml; charset=utf-8
Resources:
Header Field Definitions
SOAP Headers HTTP
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53245614%2fhow-to-send-a-soap-api-call-in-java-and-return-it-in-json%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I think you need to explain more about the SOAP payload you send and the answer received, and how is the JSON you expect to return, but I'm going to guess what you are trying to ask and try to answer it.
I can see in the code that you send a JSON to the API call, so I assume that a client will consume your endpoint with SOAP. The API you call should return a JSON right? Your endpoint will return a SOAP XML answer (or should it be raw JSON?), so you must do a conversion from JSON to XML (SOAP).
If you want to return a JSON to client and send a SOAP XML payload then read the following paragraph.
You may be wanting to instead return a XML, return a JSON, to do this, if you are using a framework either on the server side or client side, you must read the documentation. If it is possible to change the headers (server side) through the framework you should accept the XML format (Accept: application/soap+xml; charset=utf-8
) and send to your client Content-type: application/json
. In your client, when you send the request, you must have the headers of Content-type: application/soap+xml; charset=utf-8
and Accept: application/json
.
TL;DR; (For client sending XML and receiving JSON)
Server:
Accept: application/soap+xml; charset=utf-8
Content-type: application/json
Client:
Accept: application/json
Content-type: application/soap+xml; charset=utf-8
Resources:
Header Field Definitions
SOAP Headers HTTP
add a comment |
I think you need to explain more about the SOAP payload you send and the answer received, and how is the JSON you expect to return, but I'm going to guess what you are trying to ask and try to answer it.
I can see in the code that you send a JSON to the API call, so I assume that a client will consume your endpoint with SOAP. The API you call should return a JSON right? Your endpoint will return a SOAP XML answer (or should it be raw JSON?), so you must do a conversion from JSON to XML (SOAP).
If you want to return a JSON to client and send a SOAP XML payload then read the following paragraph.
You may be wanting to instead return a XML, return a JSON, to do this, if you are using a framework either on the server side or client side, you must read the documentation. If it is possible to change the headers (server side) through the framework you should accept the XML format (Accept: application/soap+xml; charset=utf-8
) and send to your client Content-type: application/json
. In your client, when you send the request, you must have the headers of Content-type: application/soap+xml; charset=utf-8
and Accept: application/json
.
TL;DR; (For client sending XML and receiving JSON)
Server:
Accept: application/soap+xml; charset=utf-8
Content-type: application/json
Client:
Accept: application/json
Content-type: application/soap+xml; charset=utf-8
Resources:
Header Field Definitions
SOAP Headers HTTP
add a comment |
I think you need to explain more about the SOAP payload you send and the answer received, and how is the JSON you expect to return, but I'm going to guess what you are trying to ask and try to answer it.
I can see in the code that you send a JSON to the API call, so I assume that a client will consume your endpoint with SOAP. The API you call should return a JSON right? Your endpoint will return a SOAP XML answer (or should it be raw JSON?), so you must do a conversion from JSON to XML (SOAP).
If you want to return a JSON to client and send a SOAP XML payload then read the following paragraph.
You may be wanting to instead return a XML, return a JSON, to do this, if you are using a framework either on the server side or client side, you must read the documentation. If it is possible to change the headers (server side) through the framework you should accept the XML format (Accept: application/soap+xml; charset=utf-8
) and send to your client Content-type: application/json
. In your client, when you send the request, you must have the headers of Content-type: application/soap+xml; charset=utf-8
and Accept: application/json
.
TL;DR; (For client sending XML and receiving JSON)
Server:
Accept: application/soap+xml; charset=utf-8
Content-type: application/json
Client:
Accept: application/json
Content-type: application/soap+xml; charset=utf-8
Resources:
Header Field Definitions
SOAP Headers HTTP
I think you need to explain more about the SOAP payload you send and the answer received, and how is the JSON you expect to return, but I'm going to guess what you are trying to ask and try to answer it.
I can see in the code that you send a JSON to the API call, so I assume that a client will consume your endpoint with SOAP. The API you call should return a JSON right? Your endpoint will return a SOAP XML answer (or should it be raw JSON?), so you must do a conversion from JSON to XML (SOAP).
If you want to return a JSON to client and send a SOAP XML payload then read the following paragraph.
You may be wanting to instead return a XML, return a JSON, to do this, if you are using a framework either on the server side or client side, you must read the documentation. If it is possible to change the headers (server side) through the framework you should accept the XML format (Accept: application/soap+xml; charset=utf-8
) and send to your client Content-type: application/json
. In your client, when you send the request, you must have the headers of Content-type: application/soap+xml; charset=utf-8
and Accept: application/json
.
TL;DR; (For client sending XML and receiving JSON)
Server:
Accept: application/soap+xml; charset=utf-8
Content-type: application/json
Client:
Accept: application/json
Content-type: application/soap+xml; charset=utf-8
Resources:
Header Field Definitions
SOAP Headers HTTP
answered Nov 11 '18 at 4:54
guitartswordguitartsword
54
54
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53245614%2fhow-to-send-a-soap-api-call-in-java-and-return-it-in-json%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown