How to send a SOAP API call in java and return it in json










0















I'm trying to send an api call and then read the returned json and print a value in the json information that is returned. The curl looks like this:



curl "https://(address goes here)?where=eq(open,true)&fields=name,totals" 
-H 'Api-Key: (api key here)'


This is what I have so far:



import java.io.*;
import java.net.*;
import org.json.JSONObject;
import java.util.LinkedHashMap;
import java.util.Map;

public class Caller

public void APICall(String str) throws Exception

String url = "(address)" + str +
"(address continued)";

URL obj = new URL(url);
HttpURLConnection conn = (HttpURLConnection) obj.openConnection();

conn.setRequestProperty("Api-Key",
"(API Key)";
conn.setDoOutput(true);
conn.setDoInput(true);

conn.setRequestMethod("PUT");
JSONObject data = new JSONObject();

OutputStreamWriter out = new
OutputStreamWriter(conn.getOutputStream());
out.write(data);

BufferedReader in = new BufferedReader(
new InputStreamReader(conn.getInputStream()));

String inputLine;

StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null)
response.append(inputLine);

in.close();
out.close();








And then I call it from another class like this:



 try 
call.APICall(codeArray.get(x));
catch (Exception e)
e.printStackTrace();



str is the inputed API code for this address, and codeArray.get(x) is stored API codes. I'm not sure how to add the parameters in the curl code or return it in json format. I have hidden the address and API Key.










share|improve this question


























    0















    I'm trying to send an api call and then read the returned json and print a value in the json information that is returned. The curl looks like this:



    curl "https://(address goes here)?where=eq(open,true)&fields=name,totals" 
    -H 'Api-Key: (api key here)'


    This is what I have so far:



    import java.io.*;
    import java.net.*;
    import org.json.JSONObject;
    import java.util.LinkedHashMap;
    import java.util.Map;

    public class Caller

    public void APICall(String str) throws Exception

    String url = "(address)" + str +
    "(address continued)";

    URL obj = new URL(url);
    HttpURLConnection conn = (HttpURLConnection) obj.openConnection();

    conn.setRequestProperty("Api-Key",
    "(API Key)";
    conn.setDoOutput(true);
    conn.setDoInput(true);

    conn.setRequestMethod("PUT");
    JSONObject data = new JSONObject();

    OutputStreamWriter out = new
    OutputStreamWriter(conn.getOutputStream());
    out.write(data);

    BufferedReader in = new BufferedReader(
    new InputStreamReader(conn.getInputStream()));

    String inputLine;

    StringBuffer response = new StringBuffer();
    while ((inputLine = in.readLine()) != null)
    response.append(inputLine);

    in.close();
    out.close();








    And then I call it from another class like this:



     try 
    call.APICall(codeArray.get(x));
    catch (Exception e)
    e.printStackTrace();



    str is the inputed API code for this address, and codeArray.get(x) is stored API codes. I'm not sure how to add the parameters in the curl code or return it in json format. I have hidden the address and API Key.










    share|improve this question
























      0












      0








      0








      I'm trying to send an api call and then read the returned json and print a value in the json information that is returned. The curl looks like this:



      curl "https://(address goes here)?where=eq(open,true)&fields=name,totals" 
      -H 'Api-Key: (api key here)'


      This is what I have so far:



      import java.io.*;
      import java.net.*;
      import org.json.JSONObject;
      import java.util.LinkedHashMap;
      import java.util.Map;

      public class Caller

      public void APICall(String str) throws Exception

      String url = "(address)" + str +
      "(address continued)";

      URL obj = new URL(url);
      HttpURLConnection conn = (HttpURLConnection) obj.openConnection();

      conn.setRequestProperty("Api-Key",
      "(API Key)";
      conn.setDoOutput(true);
      conn.setDoInput(true);

      conn.setRequestMethod("PUT");
      JSONObject data = new JSONObject();

      OutputStreamWriter out = new
      OutputStreamWriter(conn.getOutputStream());
      out.write(data);

      BufferedReader in = new BufferedReader(
      new InputStreamReader(conn.getInputStream()));

      String inputLine;

      StringBuffer response = new StringBuffer();
      while ((inputLine = in.readLine()) != null)
      response.append(inputLine);

      in.close();
      out.close();








      And then I call it from another class like this:



       try 
      call.APICall(codeArray.get(x));
      catch (Exception e)
      e.printStackTrace();



      str is the inputed API code for this address, and codeArray.get(x) is stored API codes. I'm not sure how to add the parameters in the curl code or return it in json format. I have hidden the address and API Key.










      share|improve this question














      I'm trying to send an api call and then read the returned json and print a value in the json information that is returned. The curl looks like this:



      curl "https://(address goes here)?where=eq(open,true)&fields=name,totals" 
      -H 'Api-Key: (api key here)'


      This is what I have so far:



      import java.io.*;
      import java.net.*;
      import org.json.JSONObject;
      import java.util.LinkedHashMap;
      import java.util.Map;

      public class Caller

      public void APICall(String str) throws Exception

      String url = "(address)" + str +
      "(address continued)";

      URL obj = new URL(url);
      HttpURLConnection conn = (HttpURLConnection) obj.openConnection();

      conn.setRequestProperty("Api-Key",
      "(API Key)";
      conn.setDoOutput(true);
      conn.setDoInput(true);

      conn.setRequestMethod("PUT");
      JSONObject data = new JSONObject();

      OutputStreamWriter out = new
      OutputStreamWriter(conn.getOutputStream());
      out.write(data);

      BufferedReader in = new BufferedReader(
      new InputStreamReader(conn.getInputStream()));

      String inputLine;

      StringBuffer response = new StringBuffer();
      while ((inputLine = in.readLine()) != null)
      response.append(inputLine);

      in.close();
      out.close();








      And then I call it from another class like this:



       try 
      call.APICall(codeArray.get(x));
      catch (Exception e)
      e.printStackTrace();



      str is the inputed API code for this address, and codeArray.get(x) is stored API codes. I'm not sure how to add the parameters in the curl code or return it in json format. I have hidden the address and API Key.







      java json api post soap






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 11 '18 at 3:33









      Eman936Eman936

      185




      185






















          1 Answer
          1






          active

          oldest

          votes


















          0














          I think you need to explain more about the SOAP payload you send and the answer received, and how is the JSON you expect to return, but I'm going to guess what you are trying to ask and try to answer it.



          I can see in the code that you send a JSON to the API call, so I assume that a client will consume your endpoint with SOAP. The API you call should return a JSON right? Your endpoint will return a SOAP XML answer (or should it be raw JSON?), so you must do a conversion from JSON to XML (SOAP).



          If you want to return a JSON to client and send a SOAP XML payload then read the following paragraph.



          You may be wanting to instead return a XML, return a JSON, to do this, if you are using a framework either on the server side or client side, you must read the documentation. If it is possible to change the headers (server side) through the framework you should accept the XML format (Accept: application/soap+xml; charset=utf-8) and send to your client Content-type: application/json. In your client, when you send the request, you must have the headers of Content-type: application/soap+xml; charset=utf-8 and Accept: application/json.



          TL;DR; (For client sending XML and receiving JSON)



          Server:



          Accept: application/soap+xml; charset=utf-8
          Content-type: application/json


          Client:



          Accept: application/json
          Content-type: application/soap+xml; charset=utf-8


          Resources:



          Header Field Definitions



          SOAP Headers HTTP






          share|improve this answer






















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            1 Answer
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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            0














            I think you need to explain more about the SOAP payload you send and the answer received, and how is the JSON you expect to return, but I'm going to guess what you are trying to ask and try to answer it.



            I can see in the code that you send a JSON to the API call, so I assume that a client will consume your endpoint with SOAP. The API you call should return a JSON right? Your endpoint will return a SOAP XML answer (or should it be raw JSON?), so you must do a conversion from JSON to XML (SOAP).



            If you want to return a JSON to client and send a SOAP XML payload then read the following paragraph.



            You may be wanting to instead return a XML, return a JSON, to do this, if you are using a framework either on the server side or client side, you must read the documentation. If it is possible to change the headers (server side) through the framework you should accept the XML format (Accept: application/soap+xml; charset=utf-8) and send to your client Content-type: application/json. In your client, when you send the request, you must have the headers of Content-type: application/soap+xml; charset=utf-8 and Accept: application/json.



            TL;DR; (For client sending XML and receiving JSON)



            Server:



            Accept: application/soap+xml; charset=utf-8
            Content-type: application/json


            Client:



            Accept: application/json
            Content-type: application/soap+xml; charset=utf-8


            Resources:



            Header Field Definitions



            SOAP Headers HTTP






            share|improve this answer



























              0














              I think you need to explain more about the SOAP payload you send and the answer received, and how is the JSON you expect to return, but I'm going to guess what you are trying to ask and try to answer it.



              I can see in the code that you send a JSON to the API call, so I assume that a client will consume your endpoint with SOAP. The API you call should return a JSON right? Your endpoint will return a SOAP XML answer (or should it be raw JSON?), so you must do a conversion from JSON to XML (SOAP).



              If you want to return a JSON to client and send a SOAP XML payload then read the following paragraph.



              You may be wanting to instead return a XML, return a JSON, to do this, if you are using a framework either on the server side or client side, you must read the documentation. If it is possible to change the headers (server side) through the framework you should accept the XML format (Accept: application/soap+xml; charset=utf-8) and send to your client Content-type: application/json. In your client, when you send the request, you must have the headers of Content-type: application/soap+xml; charset=utf-8 and Accept: application/json.



              TL;DR; (For client sending XML and receiving JSON)



              Server:



              Accept: application/soap+xml; charset=utf-8
              Content-type: application/json


              Client:



              Accept: application/json
              Content-type: application/soap+xml; charset=utf-8


              Resources:



              Header Field Definitions



              SOAP Headers HTTP






              share|improve this answer

























                0












                0








                0







                I think you need to explain more about the SOAP payload you send and the answer received, and how is the JSON you expect to return, but I'm going to guess what you are trying to ask and try to answer it.



                I can see in the code that you send a JSON to the API call, so I assume that a client will consume your endpoint with SOAP. The API you call should return a JSON right? Your endpoint will return a SOAP XML answer (or should it be raw JSON?), so you must do a conversion from JSON to XML (SOAP).



                If you want to return a JSON to client and send a SOAP XML payload then read the following paragraph.



                You may be wanting to instead return a XML, return a JSON, to do this, if you are using a framework either on the server side or client side, you must read the documentation. If it is possible to change the headers (server side) through the framework you should accept the XML format (Accept: application/soap+xml; charset=utf-8) and send to your client Content-type: application/json. In your client, when you send the request, you must have the headers of Content-type: application/soap+xml; charset=utf-8 and Accept: application/json.



                TL;DR; (For client sending XML and receiving JSON)



                Server:



                Accept: application/soap+xml; charset=utf-8
                Content-type: application/json


                Client:



                Accept: application/json
                Content-type: application/soap+xml; charset=utf-8


                Resources:



                Header Field Definitions



                SOAP Headers HTTP






                share|improve this answer













                I think you need to explain more about the SOAP payload you send and the answer received, and how is the JSON you expect to return, but I'm going to guess what you are trying to ask and try to answer it.



                I can see in the code that you send a JSON to the API call, so I assume that a client will consume your endpoint with SOAP. The API you call should return a JSON right? Your endpoint will return a SOAP XML answer (or should it be raw JSON?), so you must do a conversion from JSON to XML (SOAP).



                If you want to return a JSON to client and send a SOAP XML payload then read the following paragraph.



                You may be wanting to instead return a XML, return a JSON, to do this, if you are using a framework either on the server side or client side, you must read the documentation. If it is possible to change the headers (server side) through the framework you should accept the XML format (Accept: application/soap+xml; charset=utf-8) and send to your client Content-type: application/json. In your client, when you send the request, you must have the headers of Content-type: application/soap+xml; charset=utf-8 and Accept: application/json.



                TL;DR; (For client sending XML and receiving JSON)



                Server:



                Accept: application/soap+xml; charset=utf-8
                Content-type: application/json


                Client:



                Accept: application/json
                Content-type: application/soap+xml; charset=utf-8


                Resources:



                Header Field Definitions



                SOAP Headers HTTP







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 11 '18 at 4:54









                guitartswordguitartsword

                54




                54



























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