Evaluate another awk expression inside awk










1














In the dataset I am processing, the 5th ($5) column of each line contains a date in '%d/%m/%y' format. I want to compare this with a user provided one.



I know that in order to easily compare dates with relational binary operators they need to be in %y-%m-%d so I need to inline-convert the 5th columns value to that in order for the expression to evaluate to true:



Here's what I've come up with till now:



 awk -F "$columnsep" -v dateA="$bornsince" ' awk -F '/' 'print $3"-"$2"-"$1'") ) print' $file


As you can see, the ' awk -F '/' 'print $3"-"$2"-"$1'") ) print' is the expression I am trying to evaluate but I have trouble getting the system call to parse. I really just want to call awk -F '/' 'print $3"-"$2"-"$1'", piping $5 into it in order to convert the date properly.



  • Needs to work on macos and linux (ubuntu)

Minimal example dataset:



1099511629352 Nunez Jorge female 17/11/1986










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  • 2




    You could provide a minimal example of your dataset
    – miimote
    Nov 10 '18 at 16:44






  • 1




    awk version 20121220 on a macbook pro late 2017 up-to-date
    – Zarkopafilis
    Nov 10 '18 at 16:44















1














In the dataset I am processing, the 5th ($5) column of each line contains a date in '%d/%m/%y' format. I want to compare this with a user provided one.



I know that in order to easily compare dates with relational binary operators they need to be in %y-%m-%d so I need to inline-convert the 5th columns value to that in order for the expression to evaluate to true:



Here's what I've come up with till now:



 awk -F "$columnsep" -v dateA="$bornsince" ' awk -F '/' 'print $3"-"$2"-"$1'") ) print' $file


As you can see, the ' awk -F '/' 'print $3"-"$2"-"$1'") ) print' is the expression I am trying to evaluate but I have trouble getting the system call to parse. I really just want to call awk -F '/' 'print $3"-"$2"-"$1'", piping $5 into it in order to convert the date properly.



  • Needs to work on macos and linux (ubuntu)

Minimal example dataset:



1099511629352 Nunez Jorge female 17/11/1986










share|improve this question



















  • 2




    You could provide a minimal example of your dataset
    – miimote
    Nov 10 '18 at 16:44






  • 1




    awk version 20121220 on a macbook pro late 2017 up-to-date
    – Zarkopafilis
    Nov 10 '18 at 16:44













1












1








1







In the dataset I am processing, the 5th ($5) column of each line contains a date in '%d/%m/%y' format. I want to compare this with a user provided one.



I know that in order to easily compare dates with relational binary operators they need to be in %y-%m-%d so I need to inline-convert the 5th columns value to that in order for the expression to evaluate to true:



Here's what I've come up with till now:



 awk -F "$columnsep" -v dateA="$bornsince" ' awk -F '/' 'print $3"-"$2"-"$1'") ) print' $file


As you can see, the ' awk -F '/' 'print $3"-"$2"-"$1'") ) print' is the expression I am trying to evaluate but I have trouble getting the system call to parse. I really just want to call awk -F '/' 'print $3"-"$2"-"$1'", piping $5 into it in order to convert the date properly.



  • Needs to work on macos and linux (ubuntu)

Minimal example dataset:



1099511629352 Nunez Jorge female 17/11/1986










share|improve this question















In the dataset I am processing, the 5th ($5) column of each line contains a date in '%d/%m/%y' format. I want to compare this with a user provided one.



I know that in order to easily compare dates with relational binary operators they need to be in %y-%m-%d so I need to inline-convert the 5th columns value to that in order for the expression to evaluate to true:



Here's what I've come up with till now:



 awk -F "$columnsep" -v dateA="$bornsince" ' awk -F '/' 'print $3"-"$2"-"$1'") ) print' $file


As you can see, the ' awk -F '/' 'print $3"-"$2"-"$1'") ) print' is the expression I am trying to evaluate but I have trouble getting the system call to parse. I really just want to call awk -F '/' 'print $3"-"$2"-"$1'", piping $5 into it in order to convert the date properly.



  • Needs to work on macos and linux (ubuntu)

Minimal example dataset:



1099511629352 Nunez Jorge female 17/11/1986







bash awk






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 10 '18 at 16:45







Zarkopafilis

















asked Nov 10 '18 at 16:18









ZarkopafilisZarkopafilis

3471516




3471516







  • 2




    You could provide a minimal example of your dataset
    – miimote
    Nov 10 '18 at 16:44






  • 1




    awk version 20121220 on a macbook pro late 2017 up-to-date
    – Zarkopafilis
    Nov 10 '18 at 16:44












  • 2




    You could provide a minimal example of your dataset
    – miimote
    Nov 10 '18 at 16:44






  • 1




    awk version 20121220 on a macbook pro late 2017 up-to-date
    – Zarkopafilis
    Nov 10 '18 at 16:44







2




2




You could provide a minimal example of your dataset
– miimote
Nov 10 '18 at 16:44




You could provide a minimal example of your dataset
– miimote
Nov 10 '18 at 16:44




1




1




awk version 20121220 on a macbook pro late 2017 up-to-date
– Zarkopafilis
Nov 10 '18 at 16:44




awk version 20121220 on a macbook pro late 2017 up-to-date
– Zarkopafilis
Nov 10 '18 at 16:44












1 Answer
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1














Here is a gawk solution



awk -F "$columnsep" -v dateA="$bornsince" '
(FNR > 1 && dateA <= cnv_date($5))
function cnv_date(date, a)
split(date, a, "/")
return a[3] "-" a[2] "-" a[1]
' $file





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    1 Answer
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    active

    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

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    active

    oldest

    votes









    1














    Here is a gawk solution



    awk -F "$columnsep" -v dateA="$bornsince" '
    (FNR > 1 && dateA <= cnv_date($5))
    function cnv_date(date, a)
    split(date, a, "/")
    return a[3] "-" a[2] "-" a[1]
    ' $file





    share|improve this answer



























      1














      Here is a gawk solution



      awk -F "$columnsep" -v dateA="$bornsince" '
      (FNR > 1 && dateA <= cnv_date($5))
      function cnv_date(date, a)
      split(date, a, "/")
      return a[3] "-" a[2] "-" a[1]
      ' $file





      share|improve this answer

























        1












        1








        1






        Here is a gawk solution



        awk -F "$columnsep" -v dateA="$bornsince" '
        (FNR > 1 && dateA <= cnv_date($5))
        function cnv_date(date, a)
        split(date, a, "/")
        return a[3] "-" a[2] "-" a[1]
        ' $file





        share|improve this answer














        Here is a gawk solution



        awk -F "$columnsep" -v dateA="$bornsince" '
        (FNR > 1 && dateA <= cnv_date($5))
        function cnv_date(date, a)
        split(date, a, "/")
        return a[3] "-" a[2] "-" a[1]
        ' $file






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 10 '18 at 17:01

























        answered Nov 10 '18 at 16:51









        oguzismailoguzismail

        3,33031025




        3,33031025



























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