Conditionally call ViewComponent inside Razor Page










1














I'm new to Razor Pages and View Components and I'm cleary failing to put my head around the concepts:



I have a Example page, this page is rendered inside a _Layout, like the following:



@page "value1?/value2?"
@model MyProject.Pages.ExampleModel
@
ViewData["Title"] = "Example";



Now I need to call a ViewComponent conditionally based on value1 and value2:



public class ExampleModel : PageModel

public async Task<IActionResult> OnGetAsync(string value1, string value2)

// this contains a lot of logic, db access etc, and passing objects to the component, but I'm abbreviating

if (value1 == null && value2 == null)

return this.ViewComponent(nameof(SomeComponent));

else

return this.ViewComponent(nameof(SomeOtherComponent));


// return Page();




This is the extension I'm using to call the components:



public static class PageModelExtensions

public static ViewComponentResult ViewComponent(this PageModel pageModel, string componentName, object arguments)

return new ViewComponentResult

ViewComponentName = componentName,
Arguments = arguments,
ViewData = pageModel.ViewData,
TempData = pageModel.TempData
;




This is working, but because I'm not calling return Page(), the component is being rendered without calling _Layout. How should I approach this?










share|improve this question




























    1














    I'm new to Razor Pages and View Components and I'm cleary failing to put my head around the concepts:



    I have a Example page, this page is rendered inside a _Layout, like the following:



    @page "value1?/value2?"
    @model MyProject.Pages.ExampleModel
    @
    ViewData["Title"] = "Example";



    Now I need to call a ViewComponent conditionally based on value1 and value2:



    public class ExampleModel : PageModel

    public async Task<IActionResult> OnGetAsync(string value1, string value2)

    // this contains a lot of logic, db access etc, and passing objects to the component, but I'm abbreviating

    if (value1 == null && value2 == null)

    return this.ViewComponent(nameof(SomeComponent));

    else

    return this.ViewComponent(nameof(SomeOtherComponent));


    // return Page();




    This is the extension I'm using to call the components:



    public static class PageModelExtensions

    public static ViewComponentResult ViewComponent(this PageModel pageModel, string componentName, object arguments)

    return new ViewComponentResult

    ViewComponentName = componentName,
    Arguments = arguments,
    ViewData = pageModel.ViewData,
    TempData = pageModel.TempData
    ;




    This is working, but because I'm not calling return Page(), the component is being rendered without calling _Layout. How should I approach this?










    share|improve this question


























      1












      1








      1


      0





      I'm new to Razor Pages and View Components and I'm cleary failing to put my head around the concepts:



      I have a Example page, this page is rendered inside a _Layout, like the following:



      @page "value1?/value2?"
      @model MyProject.Pages.ExampleModel
      @
      ViewData["Title"] = "Example";



      Now I need to call a ViewComponent conditionally based on value1 and value2:



      public class ExampleModel : PageModel

      public async Task<IActionResult> OnGetAsync(string value1, string value2)

      // this contains a lot of logic, db access etc, and passing objects to the component, but I'm abbreviating

      if (value1 == null && value2 == null)

      return this.ViewComponent(nameof(SomeComponent));

      else

      return this.ViewComponent(nameof(SomeOtherComponent));


      // return Page();




      This is the extension I'm using to call the components:



      public static class PageModelExtensions

      public static ViewComponentResult ViewComponent(this PageModel pageModel, string componentName, object arguments)

      return new ViewComponentResult

      ViewComponentName = componentName,
      Arguments = arguments,
      ViewData = pageModel.ViewData,
      TempData = pageModel.TempData
      ;




      This is working, but because I'm not calling return Page(), the component is being rendered without calling _Layout. How should I approach this?










      share|improve this question















      I'm new to Razor Pages and View Components and I'm cleary failing to put my head around the concepts:



      I have a Example page, this page is rendered inside a _Layout, like the following:



      @page "value1?/value2?"
      @model MyProject.Pages.ExampleModel
      @
      ViewData["Title"] = "Example";



      Now I need to call a ViewComponent conditionally based on value1 and value2:



      public class ExampleModel : PageModel

      public async Task<IActionResult> OnGetAsync(string value1, string value2)

      // this contains a lot of logic, db access etc, and passing objects to the component, but I'm abbreviating

      if (value1 == null && value2 == null)

      return this.ViewComponent(nameof(SomeComponent));

      else

      return this.ViewComponent(nameof(SomeOtherComponent));


      // return Page();




      This is the extension I'm using to call the components:



      public static class PageModelExtensions

      public static ViewComponentResult ViewComponent(this PageModel pageModel, string componentName, object arguments)

      return new ViewComponentResult

      ViewComponentName = componentName,
      Arguments = arguments,
      ViewData = pageModel.ViewData,
      TempData = pageModel.TempData
      ;




      This is working, but because I'm not calling return Page(), the component is being rendered without calling _Layout. How should I approach this?







      c# asp.net-core






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 10 '18 at 16:22









      Kirk Larkin

      20k33857




      20k33857










      asked Nov 10 '18 at 16:17









      lolollolol

      2,57622643




      2,57622643






















          1 Answer
          1






          active

          oldest

          votes


















          1














          If you want to render a View Component from within a Razor Page like this, one option is to specify the name of said View Component in your PageModel class and then use Component.InvokeAsync in the correpsonding .cshtml file. Here's what that might look like:



          Example.cshtml.cs



          public class ExampleModel : PageModel

          public string ViewComponentName get; set;

          public async Task<IActionResult> OnGetAsync(string value1, string value2)

          ...

          if (value1 == null && value2 == null)
          ViewComponentName = nameof(SomeComponent);
          else
          ViewComponentName = nameof(SomeOtherComponent);

          return Page();




          Example.cshtml



          @page "value1?/value2?"
          @model MyProject.Pages.ExampleModel

          ...

          @await Component.InvokeAsync(Model.ViewComponentName)


          In Example.cshtml.cs, ViewComponentName is a new property that (unsurprisingly) represents the name of the View Component that should be rendered as part of the page, which is realised in Example.cshtml using Component.InvokeAsync.






          share|improve this answer
















          • 1




            Oh, I see. I can see how to apply the same method using parameters Component.InvokeAsync(Model.ViewComponentName, Model.SomeParameter). Is this right? Thx.
            – lolol
            Nov 10 '18 at 16:36











          • Yes, that looks right.
            – Kirk Larkin
            Nov 10 '18 at 16:37










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          1 Answer
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          active

          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          If you want to render a View Component from within a Razor Page like this, one option is to specify the name of said View Component in your PageModel class and then use Component.InvokeAsync in the correpsonding .cshtml file. Here's what that might look like:



          Example.cshtml.cs



          public class ExampleModel : PageModel

          public string ViewComponentName get; set;

          public async Task<IActionResult> OnGetAsync(string value1, string value2)

          ...

          if (value1 == null && value2 == null)
          ViewComponentName = nameof(SomeComponent);
          else
          ViewComponentName = nameof(SomeOtherComponent);

          return Page();




          Example.cshtml



          @page "value1?/value2?"
          @model MyProject.Pages.ExampleModel

          ...

          @await Component.InvokeAsync(Model.ViewComponentName)


          In Example.cshtml.cs, ViewComponentName is a new property that (unsurprisingly) represents the name of the View Component that should be rendered as part of the page, which is realised in Example.cshtml using Component.InvokeAsync.






          share|improve this answer
















          • 1




            Oh, I see. I can see how to apply the same method using parameters Component.InvokeAsync(Model.ViewComponentName, Model.SomeParameter). Is this right? Thx.
            – lolol
            Nov 10 '18 at 16:36











          • Yes, that looks right.
            – Kirk Larkin
            Nov 10 '18 at 16:37















          1














          If you want to render a View Component from within a Razor Page like this, one option is to specify the name of said View Component in your PageModel class and then use Component.InvokeAsync in the correpsonding .cshtml file. Here's what that might look like:



          Example.cshtml.cs



          public class ExampleModel : PageModel

          public string ViewComponentName get; set;

          public async Task<IActionResult> OnGetAsync(string value1, string value2)

          ...

          if (value1 == null && value2 == null)
          ViewComponentName = nameof(SomeComponent);
          else
          ViewComponentName = nameof(SomeOtherComponent);

          return Page();




          Example.cshtml



          @page "value1?/value2?"
          @model MyProject.Pages.ExampleModel

          ...

          @await Component.InvokeAsync(Model.ViewComponentName)


          In Example.cshtml.cs, ViewComponentName is a new property that (unsurprisingly) represents the name of the View Component that should be rendered as part of the page, which is realised in Example.cshtml using Component.InvokeAsync.






          share|improve this answer
















          • 1




            Oh, I see. I can see how to apply the same method using parameters Component.InvokeAsync(Model.ViewComponentName, Model.SomeParameter). Is this right? Thx.
            – lolol
            Nov 10 '18 at 16:36











          • Yes, that looks right.
            – Kirk Larkin
            Nov 10 '18 at 16:37













          1












          1








          1






          If you want to render a View Component from within a Razor Page like this, one option is to specify the name of said View Component in your PageModel class and then use Component.InvokeAsync in the correpsonding .cshtml file. Here's what that might look like:



          Example.cshtml.cs



          public class ExampleModel : PageModel

          public string ViewComponentName get; set;

          public async Task<IActionResult> OnGetAsync(string value1, string value2)

          ...

          if (value1 == null && value2 == null)
          ViewComponentName = nameof(SomeComponent);
          else
          ViewComponentName = nameof(SomeOtherComponent);

          return Page();




          Example.cshtml



          @page "value1?/value2?"
          @model MyProject.Pages.ExampleModel

          ...

          @await Component.InvokeAsync(Model.ViewComponentName)


          In Example.cshtml.cs, ViewComponentName is a new property that (unsurprisingly) represents the name of the View Component that should be rendered as part of the page, which is realised in Example.cshtml using Component.InvokeAsync.






          share|improve this answer












          If you want to render a View Component from within a Razor Page like this, one option is to specify the name of said View Component in your PageModel class and then use Component.InvokeAsync in the correpsonding .cshtml file. Here's what that might look like:



          Example.cshtml.cs



          public class ExampleModel : PageModel

          public string ViewComponentName get; set;

          public async Task<IActionResult> OnGetAsync(string value1, string value2)

          ...

          if (value1 == null && value2 == null)
          ViewComponentName = nameof(SomeComponent);
          else
          ViewComponentName = nameof(SomeOtherComponent);

          return Page();




          Example.cshtml



          @page "value1?/value2?"
          @model MyProject.Pages.ExampleModel

          ...

          @await Component.InvokeAsync(Model.ViewComponentName)


          In Example.cshtml.cs, ViewComponentName is a new property that (unsurprisingly) represents the name of the View Component that should be rendered as part of the page, which is realised in Example.cshtml using Component.InvokeAsync.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 10 '18 at 16:32









          Kirk LarkinKirk Larkin

          20k33857




          20k33857







          • 1




            Oh, I see. I can see how to apply the same method using parameters Component.InvokeAsync(Model.ViewComponentName, Model.SomeParameter). Is this right? Thx.
            – lolol
            Nov 10 '18 at 16:36











          • Yes, that looks right.
            – Kirk Larkin
            Nov 10 '18 at 16:37












          • 1




            Oh, I see. I can see how to apply the same method using parameters Component.InvokeAsync(Model.ViewComponentName, Model.SomeParameter). Is this right? Thx.
            – lolol
            Nov 10 '18 at 16:36











          • Yes, that looks right.
            – Kirk Larkin
            Nov 10 '18 at 16:37







          1




          1




          Oh, I see. I can see how to apply the same method using parameters Component.InvokeAsync(Model.ViewComponentName, Model.SomeParameter). Is this right? Thx.
          – lolol
          Nov 10 '18 at 16:36





          Oh, I see. I can see how to apply the same method using parameters Component.InvokeAsync(Model.ViewComponentName, Model.SomeParameter). Is this right? Thx.
          – lolol
          Nov 10 '18 at 16:36













          Yes, that looks right.
          – Kirk Larkin
          Nov 10 '18 at 16:37




          Yes, that looks right.
          – Kirk Larkin
          Nov 10 '18 at 16:37

















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