How to convert a string to class type in Kotlin?
How to convert a string to class type in Kotlin?
I want to convert this string into AppDatabase type, I tried this Class.forName() but this is not working properly.
AppDatabase
Class.forName()
val str = "com.crypto.wallet.data.AppDatabase_Impl@14731a42"
my class path is "com.crypto.wallet.data.AppDatabase"
I am new to Kotlin environment, please guide me.
Foot Note:
I need to pass the values to Main.kt to activityTwo.kt so here i use ShardPref for handling the data. Above the values are not String type so i need to convert this to string values and pass to ActivityTwo.kt class. Important: ActivityTwo.kt file have a one method, it will support args types are ClassA,ClassB, and ClassC e.g for MyFunctionSample(ClassA,ClassB,ClassC) but i have a values in String Type so i need to convert the type to String to ClassA type. Here is i struck.
@Tim Same error nothing works, i got thus error " Caused by: java.lang.ClassNotFoundException: Invalid name: com.crypto.wallet.data.AppDatabase_Impl@1056420" i tried ths way " val kClass = Class.forName(appDatabase1) val object1 = kClass.newInstance() as AppDatabase"
– Karthikeyan
Sep 17 '18 at 6:34
You would need to use just the fully qualified class name, that is
com.crypto.wallet.data.AppDatabase_Impl.– Tim Biegeleisen
Sep 17 '18 at 6:39
com.crypto.wallet.data.AppDatabase_Impl
my fully qualtfied class path name is "com.crypto.wallet.data.AppDatabase" here where i can pass my string value for converting my string value to class type??
– Karthikeyan
Sep 17 '18 at 6:45
what are you trying to accomplish exactly?
– Roland
Sep 17 '18 at 10:49
2 Answers
2
You can use this:
val classType = Class.forName("packageName.class")
in your case
val classType = Class.forName("com.crypto.wallet.data.AppDatabase_Impl")
my class name is "com.crypto.wallet.data.AppDatabase'i tried this but not wkkroing i got error found Class<*> any but required Appdatabase
– Karthikeyan
Sep 17 '18 at 6:42
val str = "com.crypto.wallet.data.AppDatabase_Impl@14731a42"
For my common understanding to Java (yes, Java, not Kotlin), this implies:
com.crypto.wallet.data.AppDatabase
com.crypto.wallet.data.AppDatabase_Impl
implements
com.crypto.wallet.data.AppDatabase
com.crypto.wallet.data.AppDatabase_Impl
14731a42
@Override
toString()
toString()
"com.crypto.wallet.data.AppDatabase_Impl@14731a42"
This results to the val str mentioned in the original question.
val str
There maybe some important content inside this instance, however it is missing if you call toString() directly.
toString()
To achieve your target, you should better implement a serializer and deserializer for your "AppDatabase" data structure, an easy way is to use JSON.
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Possible duplicate of Is there a way to instantiate a class by name in Java?.
– Tim Biegeleisen
Sep 17 '18 at 6:26