MS Access SQL - How to pull last 13 months data from the first of the first month?

I tried the below code to pull last 13 months of data. But it is not pulling from the 1st of the month. How can I modify it to pull data from the first day of the month?
For e.g. If I am running it today (11/13/18), I want data from 11/1/17 to today.

 SELECT * FROM MyTable T 
 WHERE T.[Date Joined] >= DATEADD("m", -13, DATE());

edited Nov 13 '18 at 17:23

Gordon Linoff

792k36316419

asked Nov 13 '18 at 17:23

SKay

add a comment |

 SELECT * FROM MyTable T 
 WHERE T.[Date Joined] >= DATEADD("m", -13, DATE());

edited Nov 13 '18 at 17:23

Gordon Linoff

792k36316419

asked Nov 13 '18 at 17:23

SKay

add a comment |

 SELECT * FROM MyTable T 
 WHERE T.[Date Joined] >= DATEADD("m", -13, DATE());

edited Nov 13 '18 at 17:23

Gordon Linoff

792k36316419

asked Nov 13 '18 at 17:23

SKay

 SELECT * FROM MyTable T 
 WHERE T.[Date Joined] >= DATEADD("m", -13, DATE());

sql ms-access ms-access-2016

edited Nov 13 '18 at 17:23

Gordon Linoff

792k36316419

asked Nov 13 '18 at 17:23

SKay

edited Nov 13 '18 at 17:23

Gordon Linoff

792k36316419

asked Nov 13 '18 at 17:23

SKay

edited Nov 13 '18 at 17:23

Gordon Linoff

792k36316419

edited Nov 13 '18 at 17:23

Gordon Linoff

792k36316419

edited Nov 13 '18 at 17:23

Gordon Linoff

792k36316419

asked Nov 13 '18 at 17:23

SKay

asked Nov 13 '18 at 17:23

SKay

asked Nov 13 '18 at 17:23

SKay

add a comment |

2 Answers
2

active

oldest

votes

You need to change the day to 1 as

SELECT * 
FROM MyTable T 
WHERE T.[Date Joined] >= DATEADD("d", -(DAY(Date())-1),DATEADD("m", -13, DATE());

Or by using DATESERIAL() function which return a DATE from parts as

SELECT * 
FROM MyTable T 
WHERE T.[Date Joined] >= DATEADD("m", -13, DATESERIAL(YEAR(Date()), MONTH(DATE()), 1))

It will get the YEAR part from the date which is 2018 in your case, then get the MONTH part which is 11 and 1 which is the day and concatenate them to return a DATE as 2018-11-1

edited Nov 13 '18 at 17:49

answered Nov 13 '18 at 17:35

Sami

9,29331244

Great job, now you made an exact copy...

– forpas
Nov 13 '18 at 17:51

Oh yeah that's what you think

– Sami
Nov 13 '18 at 17:52

Of course it is

– forpas
Nov 13 '18 at 17:53

Thank you @Sami. I used Dateseriel function.

– SKay
Nov 13 '18 at 22:30

add a comment |

This:

SELECT * FROM MyTable T 
 WHERE T.[Date Joined] >= DATEADD("m", -13, Dateserial(year(date()), month(date()),1));

uses

Dateserial(year(date()), month(date()),1)

which gives you the 1st of the current month

so you subtract from this the 13 months.

answered Nov 13 '18 at 17:40

forpas

19.1k3828

Thank you @forpas, it worked!

– SKay
Nov 13 '18 at 22:28

add a comment |

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2 Answers
2

active

oldest

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2 Answers
2

active

oldest

votes

You need to change the day to 1 as

SELECT * 
FROM MyTable T 
WHERE T.[Date Joined] >= DATEADD("d", -(DAY(Date())-1),DATEADD("m", -13, DATE());

Or by using DATESERIAL() function which return a DATE from parts as

SELECT * 
FROM MyTable T 
WHERE T.[Date Joined] >= DATEADD("m", -13, DATESERIAL(YEAR(Date()), MONTH(DATE()), 1))

It will get the YEAR part from the date which is 2018 in your case, then get the MONTH part which is 11 and 1 which is the day and concatenate them to return a DATE as 2018-11-1

edited Nov 13 '18 at 17:49

answered Nov 13 '18 at 17:35

Sami

9,29331244

Great job, now you made an exact copy...

– forpas
Nov 13 '18 at 17:51

Oh yeah that's what you think

– Sami
Nov 13 '18 at 17:52

Of course it is

– forpas
Nov 13 '18 at 17:53

Thank you @Sami. I used Dateseriel function.

– SKay
Nov 13 '18 at 22:30

add a comment |

You need to change the day to 1 as

SELECT * 
FROM MyTable T 
WHERE T.[Date Joined] >= DATEADD("d", -(DAY(Date())-1),DATEADD("m", -13, DATE());

Or by using DATESERIAL() function which return a DATE from parts as

SELECT * 
FROM MyTable T 
WHERE T.[Date Joined] >= DATEADD("m", -13, DATESERIAL(YEAR(Date()), MONTH(DATE()), 1))

It will get the YEAR part from the date which is 2018 in your case, then get the MONTH part which is 11 and 1 which is the day and concatenate them to return a DATE as 2018-11-1

edited Nov 13 '18 at 17:49

answered Nov 13 '18 at 17:35

Sami

9,29331244

Great job, now you made an exact copy...

– forpas
Nov 13 '18 at 17:51

Oh yeah that's what you think

– Sami
Nov 13 '18 at 17:52

Of course it is

– forpas
Nov 13 '18 at 17:53

Thank you @Sami. I used Dateseriel function.

– SKay
Nov 13 '18 at 22:30

add a comment |

You need to change the day to 1 as

SELECT * 
FROM MyTable T 
WHERE T.[Date Joined] >= DATEADD("d", -(DAY(Date())-1),DATEADD("m", -13, DATE());

Or by using DATESERIAL() function which return a DATE from parts as

SELECT * 
FROM MyTable T 
WHERE T.[Date Joined] >= DATEADD("m", -13, DATESERIAL(YEAR(Date()), MONTH(DATE()), 1))

It will get the YEAR part from the date which is 2018 in your case, then get the MONTH part which is 11 and 1 which is the day and concatenate them to return a DATE as 2018-11-1

edited Nov 13 '18 at 17:49

answered Nov 13 '18 at 17:35

Sami

9,29331244

You need to change the day to 1 as

SELECT * 
FROM MyTable T 
WHERE T.[Date Joined] >= DATEADD("d", -(DAY(Date())-1),DATEADD("m", -13, DATE());

Or by using DATESERIAL() function which return a DATE from parts as

SELECT * 
FROM MyTable T 
WHERE T.[Date Joined] >= DATEADD("m", -13, DATESERIAL(YEAR(Date()), MONTH(DATE()), 1))

It will get the YEAR part from the date which is 2018 in your case, then get the MONTH part which is 11 and 1 which is the day and concatenate them to return a DATE as 2018-11-1

edited Nov 13 '18 at 17:49

answered Nov 13 '18 at 17:35

Sami

9,29331244

edited Nov 13 '18 at 17:49

answered Nov 13 '18 at 17:35

Sami

9,29331244

answered Nov 13 '18 at 17:35

Sami

9,29331244

answered Nov 13 '18 at 17:35

Sami

9,29331244

Great job, now you made an exact copy...

– forpas
Nov 13 '18 at 17:51

Oh yeah that's what you think

– Sami
Nov 13 '18 at 17:52

Of course it is

– forpas
Nov 13 '18 at 17:53

Thank you @Sami. I used Dateseriel function.

– SKay
Nov 13 '18 at 22:30

add a comment |

Great job, now you made an exact copy...

– forpas
Nov 13 '18 at 17:51

Oh yeah that's what you think

– Sami
Nov 13 '18 at 17:52

Of course it is

– forpas
Nov 13 '18 at 17:53

Thank you @Sami. I used Dateseriel function.

– SKay
Nov 13 '18 at 22:30

Great job, now you made an exact copy...

– forpas
Nov 13 '18 at 17:51

Oh yeah that's what you think

– Sami
Nov 13 '18 at 17:52

Of course it is

– forpas
Nov 13 '18 at 17:53

Thank you @Sami. I used Dateseriel function.

– SKay
Nov 13 '18 at 22:30

add a comment |

This:

SELECT * FROM MyTable T 
 WHERE T.[Date Joined] >= DATEADD("m", -13, Dateserial(year(date()), month(date()),1));

uses

Dateserial(year(date()), month(date()),1)

which gives you the 1st of the current month

so you subtract from this the 13 months.

answered Nov 13 '18 at 17:40

forpas

19.1k3828

Thank you @forpas, it worked!

– SKay
Nov 13 '18 at 22:28

add a comment |

This:

SELECT * FROM MyTable T 
 WHERE T.[Date Joined] >= DATEADD("m", -13, Dateserial(year(date()), month(date()),1));

uses

Dateserial(year(date()), month(date()),1)

which gives you the 1st of the current month

so you subtract from this the 13 months.

answered Nov 13 '18 at 17:40

forpas

19.1k3828

Thank you @forpas, it worked!

– SKay
Nov 13 '18 at 22:28

add a comment |

This:

SELECT * FROM MyTable T 
 WHERE T.[Date Joined] >= DATEADD("m", -13, Dateserial(year(date()), month(date()),1));

uses

Dateserial(year(date()), month(date()),1)

which gives you the 1st of the current month

so you subtract from this the 13 months.

answered Nov 13 '18 at 17:40

forpas

19.1k3828

This:

SELECT * FROM MyTable T 
 WHERE T.[Date Joined] >= DATEADD("m", -13, Dateserial(year(date()), month(date()),1));

uses

Dateserial(year(date()), month(date()),1)

which gives you the 1st of the current month

so you subtract from this the 13 months.

answered Nov 13 '18 at 17:40

forpas

19.1k3828

answered Nov 13 '18 at 17:40

forpas

19.1k3828

answered Nov 13 '18 at 17:40

forpas

19.1k3828

answered Nov 13 '18 at 17:40

forpas

19.1k3828

Thank you @forpas, it worked!

– SKay
Nov 13 '18 at 22:28

add a comment |

Thank you @forpas, it worked!

– SKay
Nov 13 '18 at 22:28

Thank you @forpas, it worked!

– SKay
Nov 13 '18 at 22:28

add a comment |

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