How to get MAX value for a given week having data per day
Not sure if the title is readable enough, will try to explain it better here
I have data in the following schema:
ID | Date | Unit1 | Hours | TENURE_Hours
"Alex" | '2018-11-04' | 21 | 12 | 134
"Adam" | '2018-11-04' | 21 | 26 | 156
"John" | '2018-11-04' | 21 | 32 | 122
"Alex" | '2018-11-06' | 21 | 67 | 146
"Adam" | '2018-11-06' | 21 | 74 | 182
"John" | '2018-11-06' | 21 | 45 | 154
"Alex" | '2018-11-11' | 21 | 22 | 213
"Adam" | '2018-11-11' | 21 | 22 | 256
"John" | '2018-11-11' | 21 | 22 | 199
And what I would like to achieve is to have the split per week number with the highest number in the week
I tried to use MAX(), but it returns the highest value within the whole range, if I try to pull data for previous 10 months ,it will return the highest value for this period of time, not specific week.
In the above example I would like to have:
Week | ID | TENURE_Hours
45 | "Alex" | 146
45 | "Adam" | 182
45 | "John" | 154
46 | "Alex" | 213
46 | "Adam" | 256
46 | "John" | 199
What do you think? Is there a way to do this?
I'm using Microsoft SQL Server, but I think this problem can be solved in every SQL engine
Thanks in advance
sql
sql-server edited Nov 13 '18 at 17:27
Sami
9,29331244
asked Nov 13 '18 at 17:22
akaribiakaribi
172
add a comment |
Not sure if the title is readable enough, will try to explain it better here
I have data in the following schema:
ID | Date | Unit1 | Hours | TENURE_Hours
"Alex" | '2018-11-04' | 21 | 12 | 134
"Adam" | '2018-11-04' | 21 | 26 | 156
"John" | '2018-11-04' | 21 | 32 | 122
"Alex" | '2018-11-06' | 21 | 67 | 146
"Adam" | '2018-11-06' | 21 | 74 | 182
"John" | '2018-11-06' | 21 | 45 | 154
"Alex" | '2018-11-11' | 21 | 22 | 213
"Adam" | '2018-11-11' | 21 | 22 | 256
"John" | '2018-11-11' | 21 | 22 | 199
And what I would like to achieve is to have the split per week number with the highest number in the week
I tried to use MAX(), but it returns the highest value within the whole range, if I try to pull data for previous 10 months ,it will return the highest value for this period of time, not specific week.
In the above example I would like to have:
Week | ID | TENURE_Hours
45 | "Alex" | 146
45 | "Adam" | 182
45 | "John" | 154
46 | "Alex" | 213
46 | "Adam" | 256
46 | "John" | 199
What do you think? Is there a way to do this?
I'm using Microsoft SQL Server, but I think this problem can be solved in every SQL engine
Thanks in advance
sql
sql-server edited Nov 13 '18 at 17:27
Sami
9,29331244
asked Nov 13 '18 at 17:22
akaribiakaribi
172
1
First figure out which RDBMS you're using.
– Strawberry
Nov 13 '18 at 17:26
1
The problem can be solved in every SQL engine, but functions, especially date functions are very different for different dbms. It's useless if someone is posting MySQL or Oracle code if you're using SQL Server, so tag your question properly.
– Eric
Nov 13 '18 at 17:37
add a comment |
Not sure if the title is readable enough, will try to explain it better here
I have data in the following schema:
ID | Date | Unit1 | Hours | TENURE_Hours
"Alex" | '2018-11-04' | 21 | 12 | 134
"Adam" | '2018-11-04' | 21 | 26 | 156
"John" | '2018-11-04' | 21 | 32 | 122
"Alex" | '2018-11-06' | 21 | 67 | 146
"Adam" | '2018-11-06' | 21 | 74 | 182
"John" | '2018-11-06' | 21 | 45 | 154
"Alex" | '2018-11-11' | 21 | 22 | 213
"Adam" | '2018-11-11' | 21 | 22 | 256
"John" | '2018-11-11' | 21 | 22 | 199
And what I would like to achieve is to have the split per week number with the highest number in the week
I tried to use MAX(), but it returns the highest value within the whole range, if I try to pull data for previous 10 months ,it will return the highest value for this period of time, not specific week.
In the above example I would like to have:
Week | ID | TENURE_Hours
45 | "Alex" | 146
45 | "Adam" | 182
45 | "John" | 154
46 | "Alex" | 213
46 | "Adam" | 256
46 | "John" | 199
What do you think? Is there a way to do this?
I'm using Microsoft SQL Server, but I think this problem can be solved in every SQL engine
Thanks in advance
sql
sql-server edited Nov 13 '18 at 17:27
Sami
9,29331244
asked Nov 13 '18 at 17:22
akaribiakaribi
172
Not sure if the title is readable enough, will try to explain it better here
I have data in the following schema:
ID | Date | Unit1 | Hours | TENURE_Hours
"Alex" | '2018-11-04' | 21 | 12 | 134
"Adam" | '2018-11-04' | 21 | 26 | 156
"John" | '2018-11-04' | 21 | 32 | 122
"Alex" | '2018-11-06' | 21 | 67 | 146
"Adam" | '2018-11-06' | 21 | 74 | 182
"John" | '2018-11-06' | 21 | 45 | 154
"Alex" | '2018-11-11' | 21 | 22 | 213
"Adam" | '2018-11-11' | 21 | 22 | 256
"John" | '2018-11-11' | 21 | 22 | 199
And what I would like to achieve is to have the split per week number with the highest number in the week
I tried to use MAX(), but it returns the highest value within the whole range, if I try to pull data for previous 10 months ,it will return the highest value for this period of time, not specific week.
In the above example I would like to have:
Week | ID | TENURE_Hours
45 | "Alex" | 146
45 | "Adam" | 182
45 | "John" | 154
46 | "Alex" | 213
46 | "Adam" | 256
46 | "John" | 199
What do you think? Is there a way to do this?
I'm using Microsoft SQL Server, but I think this problem can be solved in every SQL engine
Thanks in advance
sql
sql-server sql
sql-server edited Nov 13 '18 at 17:27
Sami
9,29331244
asked Nov 13 '18 at 17:22
akaribiakaribi
172
edited Nov 13 '18 at 17:27
Sami
9,29331244
asked Nov 13 '18 at 17:22
akaribiakaribi
172
edited Nov 13 '18 at 17:27
Sami
9,29331244
edited Nov 13 '18 at 17:27
Sami
9,29331244
edited Nov 13 '18 at 17:27
Sami
9,29331244
9,29331244
asked Nov 13 '18 at 17:22
akaribiakaribi
172
asked Nov 13 '18 at 17:22
akaribiakaribi
172
asked Nov 13 '18 at 17:22
akaribiakaribi
172
172
1
First figure out which RDBMS you're using.
– Strawberry
Nov 13 '18 at 17:26
1
The problem can be solved in every SQL engine, but functions, especially date functions are very different for different dbms. It's useless if someone is posting MySQL or Oracle code if you're using SQL Server, so tag your question properly.
– Eric
Nov 13 '18 at 17:37
add a comment |
1
First figure out which RDBMS you're using.
– Strawberry
Nov 13 '18 at 17:26
1
The problem can be solved in every SQL engine, but functions, especially date functions are very different for different dbms. It's useless if someone is posting MySQL or Oracle code if you're using SQL Server, so tag your question properly.
– Eric
Nov 13 '18 at 17:37
1
1
First figure out which RDBMS you're using.
– Strawberry
Nov 13 '18 at 17:26
First figure out which RDBMS you're using.
– Strawberry
Nov 13 '18 at 17:26
1
1
The problem can be solved in every SQL engine, but functions, especially date functions are very different for different dbms. It's useless if someone is posting MySQL or Oracle code if you're using SQL Server, so tag your question properly.
– Eric
Nov 13 '18 at 17:37
The problem can be solved in every SQL engine, but functions, especially date functions are very different for different dbms. It's useless if someone is posting MySQL or Oracle code if you're using SQL Server, so tag your question properly.
– Eric
Nov 13 '18 at 17:37
add a comment |
1 Answer
1
active
oldest
votes
Is this what you want?
select year(date) as yyyy, datepart(week, date) as wk, id, max(tenure_hours)
from t
group by year(date), datepart(week, date), id
order by yyyy, wk, id;
answered Nov 13 '18 at 17:25
Gordon LinoffGordon Linoff
792k36316419
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1 Answer
1
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oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Is this what you want?
select year(date) as yyyy, datepart(week, date) as wk, id, max(tenure_hours)
from t
group by year(date), datepart(week, date), id
order by yyyy, wk, id;
answered Nov 13 '18 at 17:25
Gordon LinoffGordon Linoff
792k36316419
add a comment |
Is this what you want?
select year(date) as yyyy, datepart(week, date) as wk, id, max(tenure_hours)
from t
group by year(date), datepart(week, date), id
order by yyyy, wk, id;
answered Nov 13 '18 at 17:25
Gordon LinoffGordon Linoff
792k36316419
add a comment |
Is this what you want?
select year(date) as yyyy, datepart(week, date) as wk, id, max(tenure_hours)
from t
group by year(date), datepart(week, date), id
order by yyyy, wk, id;
answered Nov 13 '18 at 17:25
Gordon LinoffGordon Linoff
792k36316419
Is this what you want?
select year(date) as yyyy, datepart(week, date) as wk, id, max(tenure_hours)
from t
group by year(date), datepart(week, date), id
order by yyyy, wk, id;
answered Nov 13 '18 at 17:25
Gordon LinoffGordon Linoff
792k36316419
answered Nov 13 '18 at 17:25
Gordon LinoffGordon Linoff
792k36316419
answered Nov 13 '18 at 17:25
Gordon LinoffGordon Linoff
792k36316419
answered Nov 13 '18 at 17:25
Gordon LinoffGordon Linoff
792k36316419
792k36316419
add a comment |
add a comment |
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1
First figure out which RDBMS you're using.
– Strawberry
Nov 13 '18 at 17:26
1
The problem can be solved in every SQL engine, but functions, especially date functions are very different for different dbms. It's useless if someone is posting MySQL or Oracle code if you're using SQL Server, so tag your question properly.
– Eric
Nov 13 '18 at 17:37