Short name of the file path on Windows is not correctly returned










0















I want to get short file path from a given Windows path.
For this reason I use the following JAVA code (with JNA library):



 char result = new char[65535];
Kernel32.INSTANCE.GetShortPathName(file.toString(), result, result.length);
System.out.println(Native.toString(result));


The above code works fine. However, in some cases the returned value is empty string. For example, using the following existing path on Windows yeilds an empty value:



C:UserssomeuserDownloadsGfl4AHIHf6SVMPMT9hjitNZOSXVofG1A9VJrv66YerqDfW8TW73O3VUb1wYYnOOB2l9CvSmTjfPLUvIwwvkddiL3sj7XNB1gqGGrUnmotsG4V3WR50SV1JAkXe2M0MpR4VDoYAUt5WgLpdLqoIdRlH4bd7OcZ3j0GOs90FGuZpZpjhEZBobNz1CwK50jJWYCwAHNmaYOYrC3JnOl6xtX4phNJmGfl4AHIHf6SVMPMT9hjitNZOSXVofG1A9VJrv66YerqDfW8TW73O3VUb1wYYnOOB2l9CvSmTjfPLUvIwwvkddiL3sj7XNB1gqGGrUnmotsG4V3WR50SV1JAkXe2M0MpR4VDoYAUt5WgLpdLqoIdRlH4bd7OcZ3j0GOs90FGuZpZpjhEZBobNz1CwK50jJWYCwAHNmaYOYrC3JnOl6xtX4phNJmdsMlll



The returned value of Kernel32.INSTANCE.GetShortPathName is 0, which according to javadoc is




If the function fails for any other reason, the return value is zero. To get extended error information, call GetLastError.




Calling GetLastError returns 3.



Now, using the following command:



dir /x


I'm able to see that the file actually has an alredy generated short name (GFL4AH~1).



What I've missed?










share|improve this question




























    0















    I want to get short file path from a given Windows path.
    For this reason I use the following JAVA code (with JNA library):



     char result = new char[65535];
    Kernel32.INSTANCE.GetShortPathName(file.toString(), result, result.length);
    System.out.println(Native.toString(result));


    The above code works fine. However, in some cases the returned value is empty string. For example, using the following existing path on Windows yeilds an empty value:



    C:UserssomeuserDownloadsGfl4AHIHf6SVMPMT9hjitNZOSXVofG1A9VJrv66YerqDfW8TW73O3VUb1wYYnOOB2l9CvSmTjfPLUvIwwvkddiL3sj7XNB1gqGGrUnmotsG4V3WR50SV1JAkXe2M0MpR4VDoYAUt5WgLpdLqoIdRlH4bd7OcZ3j0GOs90FGuZpZpjhEZBobNz1CwK50jJWYCwAHNmaYOYrC3JnOl6xtX4phNJmGfl4AHIHf6SVMPMT9hjitNZOSXVofG1A9VJrv66YerqDfW8TW73O3VUb1wYYnOOB2l9CvSmTjfPLUvIwwvkddiL3sj7XNB1gqGGrUnmotsG4V3WR50SV1JAkXe2M0MpR4VDoYAUt5WgLpdLqoIdRlH4bd7OcZ3j0GOs90FGuZpZpjhEZBobNz1CwK50jJWYCwAHNmaYOYrC3JnOl6xtX4phNJmdsMlll



    The returned value of Kernel32.INSTANCE.GetShortPathName is 0, which according to javadoc is




    If the function fails for any other reason, the return value is zero. To get extended error information, call GetLastError.




    Calling GetLastError returns 3.



    Now, using the following command:



    dir /x


    I'm able to see that the file actually has an alredy generated short name (GFL4AH~1).



    What I've missed?










    share|improve this question


























      0












      0








      0








      I want to get short file path from a given Windows path.
      For this reason I use the following JAVA code (with JNA library):



       char result = new char[65535];
      Kernel32.INSTANCE.GetShortPathName(file.toString(), result, result.length);
      System.out.println(Native.toString(result));


      The above code works fine. However, in some cases the returned value is empty string. For example, using the following existing path on Windows yeilds an empty value:



      C:UserssomeuserDownloadsGfl4AHIHf6SVMPMT9hjitNZOSXVofG1A9VJrv66YerqDfW8TW73O3VUb1wYYnOOB2l9CvSmTjfPLUvIwwvkddiL3sj7XNB1gqGGrUnmotsG4V3WR50SV1JAkXe2M0MpR4VDoYAUt5WgLpdLqoIdRlH4bd7OcZ3j0GOs90FGuZpZpjhEZBobNz1CwK50jJWYCwAHNmaYOYrC3JnOl6xtX4phNJmGfl4AHIHf6SVMPMT9hjitNZOSXVofG1A9VJrv66YerqDfW8TW73O3VUb1wYYnOOB2l9CvSmTjfPLUvIwwvkddiL3sj7XNB1gqGGrUnmotsG4V3WR50SV1JAkXe2M0MpR4VDoYAUt5WgLpdLqoIdRlH4bd7OcZ3j0GOs90FGuZpZpjhEZBobNz1CwK50jJWYCwAHNmaYOYrC3JnOl6xtX4phNJmdsMlll



      The returned value of Kernel32.INSTANCE.GetShortPathName is 0, which according to javadoc is




      If the function fails for any other reason, the return value is zero. To get extended error information, call GetLastError.




      Calling GetLastError returns 3.



      Now, using the following command:



      dir /x


      I'm able to see that the file actually has an alredy generated short name (GFL4AH~1).



      What I've missed?










      share|improve this question
















      I want to get short file path from a given Windows path.
      For this reason I use the following JAVA code (with JNA library):



       char result = new char[65535];
      Kernel32.INSTANCE.GetShortPathName(file.toString(), result, result.length);
      System.out.println(Native.toString(result));


      The above code works fine. However, in some cases the returned value is empty string. For example, using the following existing path on Windows yeilds an empty value:



      C:UserssomeuserDownloadsGfl4AHIHf6SVMPMT9hjitNZOSXVofG1A9VJrv66YerqDfW8TW73O3VUb1wYYnOOB2l9CvSmTjfPLUvIwwvkddiL3sj7XNB1gqGGrUnmotsG4V3WR50SV1JAkXe2M0MpR4VDoYAUt5WgLpdLqoIdRlH4bd7OcZ3j0GOs90FGuZpZpjhEZBobNz1CwK50jJWYCwAHNmaYOYrC3JnOl6xtX4phNJmGfl4AHIHf6SVMPMT9hjitNZOSXVofG1A9VJrv66YerqDfW8TW73O3VUb1wYYnOOB2l9CvSmTjfPLUvIwwvkddiL3sj7XNB1gqGGrUnmotsG4V3WR50SV1JAkXe2M0MpR4VDoYAUt5WgLpdLqoIdRlH4bd7OcZ3j0GOs90FGuZpZpjhEZBobNz1CwK50jJWYCwAHNmaYOYrC3JnOl6xtX4phNJmdsMlll



      The returned value of Kernel32.INSTANCE.GetShortPathName is 0, which according to javadoc is




      If the function fails for any other reason, the return value is zero. To get extended error information, call GetLastError.




      Calling GetLastError returns 3.



      Now, using the following command:



      dir /x


      I'm able to see that the file actually has an alredy generated short name (GFL4AH~1).



      What I've missed?







      java windows filesystems jna






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      edited Nov 11 '18 at 16:46







      user4881671

















      asked Nov 11 '18 at 16:13









      user4881671user4881671

      407




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          I found the solution:



           int returnCode = Kernel32.INSTANCE.GetShortPathName("\\?\" + file.toString(), result, result.length);


          From MS docs:




          To specify an extended-length path, use the "?" prefix. For example, "?D:very long path".







          share|improve this answer






















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            1 Answer
            1






            active

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            active

            oldest

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            active

            oldest

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            0














            I found the solution:



             int returnCode = Kernel32.INSTANCE.GetShortPathName("\\?\" + file.toString(), result, result.length);


            From MS docs:




            To specify an extended-length path, use the "?" prefix. For example, "?D:very long path".







            share|improve this answer



























              0














              I found the solution:



               int returnCode = Kernel32.INSTANCE.GetShortPathName("\\?\" + file.toString(), result, result.length);


              From MS docs:




              To specify an extended-length path, use the "?" prefix. For example, "?D:very long path".







              share|improve this answer

























                0












                0








                0







                I found the solution:



                 int returnCode = Kernel32.INSTANCE.GetShortPathName("\\?\" + file.toString(), result, result.length);


                From MS docs:




                To specify an extended-length path, use the "?" prefix. For example, "?D:very long path".







                share|improve this answer













                I found the solution:



                 int returnCode = Kernel32.INSTANCE.GetShortPathName("\\?\" + file.toString(), result, result.length);


                From MS docs:




                To specify an extended-length path, use the "?" prefix. For example, "?D:very long path".








                share|improve this answer












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                share|improve this answer










                answered Nov 12 '18 at 8:14









                user4881671user4881671

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