touchesBegan not called in NSScrollView subclass until the first mouse/trackpad click on the view
I subclass an NSScrollView to monitor 2-finger panning with touchesBegan/Moved/Ended. It works as long as I click on the view once after the app is launched. Then it will always work till the next time I start the app fresh.
I think I'm missing out something very obvious here. Perhaps a NSScrollView/NSView property that allows it to immediately accept touches. Can someone help?
By the way, the NSScrollView is one automatically created in Storyboard when I add a NSTableView.
macos gesture nsscrollview nsevent
asked Nov 12 '18 at 9:50
honchenghoncheng
1,8271113
add a comment |
I subclass an NSScrollView to monitor 2-finger panning with touchesBegan/Moved/Ended. It works as long as I click on the view once after the app is launched. Then it will always work till the next time I start the app fresh.
I think I'm missing out something very obvious here. Perhaps a NSScrollView/NSView property that allows it to immediately accept touches. Can someone help?
By the way, the NSScrollView is one automatically created in Storyboard when I add a NSTableView.
macos gesture nsscrollview nsevent
asked Nov 12 '18 at 9:50
honchenghoncheng
1,8271113
add a comment |
I subclass an NSScrollView to monitor 2-finger panning with touchesBegan/Moved/Ended. It works as long as I click on the view once after the app is launched. Then it will always work till the next time I start the app fresh.
I think I'm missing out something very obvious here. Perhaps a NSScrollView/NSView property that allows it to immediately accept touches. Can someone help?
By the way, the NSScrollView is one automatically created in Storyboard when I add a NSTableView.
macos gesture nsscrollview nsevent
asked Nov 12 '18 at 9:50
honchenghoncheng
1,8271113
I subclass an NSScrollView to monitor 2-finger panning with touchesBegan/Moved/Ended. It works as long as I click on the view once after the app is launched. Then it will always work till the next time I start the app fresh.
I think I'm missing out something very obvious here. Perhaps a NSScrollView/NSView property that allows it to immediately accept touches. Can someone help?
By the way, the NSScrollView is one automatically created in Storyboard when I add a NSTableView.
macos gesture nsscrollview nsevent
macos gesture nsscrollview nsevent
asked Nov 12 '18 at 9:50
honchenghoncheng
1,8271113
asked Nov 12 '18 at 9:50
honchenghoncheng
1,8271113
asked Nov 12 '18 at 9:50
honchenghoncheng
1,8271113
asked Nov 12 '18 at 9:50
honchenghoncheng
1,8271113
asked Nov 12 '18 at 9:50
honchenghoncheng
1,8271113
1,8271113
add a comment |
add a comment |
1 Answer
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Found the solution.
This is actually a menu bar app, so the view controller is inside a NSPopover. Showing the app in the popover does not make the app the activate app. I have to use the following line to make it active before it can respond to touches.
NSApplication.shared.activate(ignoringOtherApps: true)
answered Nov 13 '18 at 8:25
honchenghoncheng
1,8271113
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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active
oldest
votes
active
oldest
votes
Found the solution.
This is actually a menu bar app, so the view controller is inside a NSPopover. Showing the app in the popover does not make the app the activate app. I have to use the following line to make it active before it can respond to touches.
NSApplication.shared.activate(ignoringOtherApps: true)
answered Nov 13 '18 at 8:25
honchenghoncheng
1,8271113
add a comment |
Found the solution.
This is actually a menu bar app, so the view controller is inside a NSPopover. Showing the app in the popover does not make the app the activate app. I have to use the following line to make it active before it can respond to touches.
NSApplication.shared.activate(ignoringOtherApps: true)
answered Nov 13 '18 at 8:25
honchenghoncheng
1,8271113
add a comment |
Found the solution.
This is actually a menu bar app, so the view controller is inside a NSPopover. Showing the app in the popover does not make the app the activate app. I have to use the following line to make it active before it can respond to touches.
NSApplication.shared.activate(ignoringOtherApps: true)
answered Nov 13 '18 at 8:25
honchenghoncheng
1,8271113
Found the solution.
This is actually a menu bar app, so the view controller is inside a NSPopover. Showing the app in the popover does not make the app the activate app. I have to use the following line to make it active before it can respond to touches.
NSApplication.shared.activate(ignoringOtherApps: true)
answered Nov 13 '18 at 8:25
honchenghoncheng
1,8271113
answered Nov 13 '18 at 8:25
honchenghoncheng
1,8271113
answered Nov 13 '18 at 8:25
honchenghoncheng
1,8271113
answered Nov 13 '18 at 8:25
honchenghoncheng
1,8271113
1,8271113
add a comment |
add a comment |
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