How to integrate a function with a multidimensional constant matrix in Matlab?
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0
down vote
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I have a function,
F = exp(-B(i,j).*cos(x))
wherein B(i,j) is a constant matrix of dimension i-j
Now, I want to numerically integrate the above function w.r.t 'x' in an interval (0, pi/2) in Matlab.
Thanks in advance!!!
function Z = Z_normalization(E0,f)
%Evaluating the Normalization partition function for the calculation
% Detailed explanation goes here
% E0 = electric field amplitude;
% f = frequency
% B(i,j) = product of electric dipole moment and field
%f = 10:100:1000000;
%E0 = [650, 750, 850, 950, 1000];
for j = 1:length(E0)
for i = 1:length(f)
%B(i,j) = E0(i).*f(j);
B = Scalar_electric_potential(E0,f);
F = @(x) exp(-B(j,i).*cos(x)).*cos(2.*x);
Z(j,i) = integral(F, 0, pi/2)
end
end
end
Here, B(i,j) is a function of f, E0 So the integration is perfectly fine when I dont have exp(F). When the exp(F) is appended the result of integration is same for all values.
matlab numerical-integration
asked Nov 5 at 5:00
Hisay
62
add a comment |
up vote
0
down vote
favorite
I have a function,
F = exp(-B(i,j).*cos(x))
wherein B(i,j) is a constant matrix of dimension i-j
Now, I want to numerically integrate the above function w.r.t 'x' in an interval (0, pi/2) in Matlab.
Thanks in advance!!!
function Z = Z_normalization(E0,f)
%Evaluating the Normalization partition function for the calculation
% Detailed explanation goes here
% E0 = electric field amplitude;
% f = frequency
% B(i,j) = product of electric dipole moment and field
%f = 10:100:1000000;
%E0 = [650, 750, 850, 950, 1000];
for j = 1:length(E0)
for i = 1:length(f)
%B(i,j) = E0(i).*f(j);
B = Scalar_electric_potential(E0,f);
F = @(x) exp(-B(j,i).*cos(x)).*cos(2.*x);
Z(j,i) = integral(F, 0, pi/2)
end
end
end
Here, B(i,j) is a function of f, E0 So the integration is perfectly fine when I dont have exp(F). When the exp(F) is appended the result of integration is same for all values.
matlab numerical-integration
asked Nov 5 at 5:00
Hisay
62
2
Where is the difficulty? How have you tried integrating this function? What problem did you run into?
– Cris Luengo
Nov 5 at 5:07
You need to work on the mathematical problem first - what method of numerical integration do you want to use?
– Mikhail Genkin
Nov 5 at 11:31
@ Cris Luengo Thank you for the reply. I first evaluate the product B(i,j) a 3 x 3 matrix with cos (x) and then calculate the exponential. Thereafter evaluate integrate using Int(F, 0, pi.2). The problem is that the integration values are same for all functions. SO I doubt my way of integration may not be correct.
– Hisay
Nov 9 at 2:22
@Mekhaiil Genkin. I do understand your point, I simplify the expression as mentioned above and then intgrate it using a function called int(F, 0, pi/2) in Matlab. But the results are having same value whenever integrates.
– Hisay
Nov 9 at 2:24
Any suggestions to this problem welcome!!!
– Hisay
Nov 13 at 9:33
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have a function,
F = exp(-B(i,j).*cos(x))
wherein B(i,j) is a constant matrix of dimension i-j
Now, I want to numerically integrate the above function w.r.t 'x' in an interval (0, pi/2) in Matlab.
Thanks in advance!!!
function Z = Z_normalization(E0,f)
%Evaluating the Normalization partition function for the calculation
% Detailed explanation goes here
% E0 = electric field amplitude;
% f = frequency
% B(i,j) = product of electric dipole moment and field
%f = 10:100:1000000;
%E0 = [650, 750, 850, 950, 1000];
for j = 1:length(E0)
for i = 1:length(f)
%B(i,j) = E0(i).*f(j);
B = Scalar_electric_potential(E0,f);
F = @(x) exp(-B(j,i).*cos(x)).*cos(2.*x);
Z(j,i) = integral(F, 0, pi/2)
end
end
end
Here, B(i,j) is a function of f, E0 So the integration is perfectly fine when I dont have exp(F). When the exp(F) is appended the result of integration is same for all values.
matlab numerical-integration
asked Nov 5 at 5:00
Hisay
62
I have a function,
F = exp(-B(i,j).*cos(x))
wherein B(i,j) is a constant matrix of dimension i-j
Now, I want to numerically integrate the above function w.r.t 'x' in an interval (0, pi/2) in Matlab.
Thanks in advance!!!
function Z = Z_normalization(E0,f)
%Evaluating the Normalization partition function for the calculation
% Detailed explanation goes here
% E0 = electric field amplitude;
% f = frequency
% B(i,j) = product of electric dipole moment and field
%f = 10:100:1000000;
%E0 = [650, 750, 850, 950, 1000];
for j = 1:length(E0)
for i = 1:length(f)
%B(i,j) = E0(i).*f(j);
B = Scalar_electric_potential(E0,f);
F = @(x) exp(-B(j,i).*cos(x)).*cos(2.*x);
Z(j,i) = integral(F, 0, pi/2)
end
end
end
Here, B(i,j) is a function of f, E0 So the integration is perfectly fine when I dont have exp(F). When the exp(F) is appended the result of integration is same for all values.
matlab numerical-integration
matlab numerical-integration
asked Nov 5 at 5:00
Hisay
62
asked Nov 5 at 5:00
Hisay
62
edited Nov 9 at 6:42
asked Nov 5 at 5:00
Hisay
62
asked Nov 5 at 5:00
Hisay
62
asked Nov 5 at 5:00
Hisay
62
62
2
Where is the difficulty? How have you tried integrating this function? What problem did you run into?
– Cris Luengo
Nov 5 at 5:07
You need to work on the mathematical problem first - what method of numerical integration do you want to use?
– Mikhail Genkin
Nov 5 at 11:31
@ Cris Luengo Thank you for the reply. I first evaluate the product B(i,j) a 3 x 3 matrix with cos (x) and then calculate the exponential. Thereafter evaluate integrate using Int(F, 0, pi.2). The problem is that the integration values are same for all functions. SO I doubt my way of integration may not be correct.
– Hisay
Nov 9 at 2:22
@Mekhaiil Genkin. I do understand your point, I simplify the expression as mentioned above and then intgrate it using a function called int(F, 0, pi/2) in Matlab. But the results are having same value whenever integrates.
– Hisay
Nov 9 at 2:24
Any suggestions to this problem welcome!!!
– Hisay
Nov 13 at 9:33
add a comment |
2
Where is the difficulty? How have you tried integrating this function? What problem did you run into?
– Cris Luengo
Nov 5 at 5:07
You need to work on the mathematical problem first - what method of numerical integration do you want to use?
– Mikhail Genkin
Nov 5 at 11:31
@ Cris Luengo Thank you for the reply. I first evaluate the product B(i,j) a 3 x 3 matrix with cos (x) and then calculate the exponential. Thereafter evaluate integrate using Int(F, 0, pi.2). The problem is that the integration values are same for all functions. SO I doubt my way of integration may not be correct.
– Hisay
Nov 9 at 2:22
@Mekhaiil Genkin. I do understand your point, I simplify the expression as mentioned above and then intgrate it using a function called int(F, 0, pi/2) in Matlab. But the results are having same value whenever integrates.
– Hisay
Nov 9 at 2:24
Any suggestions to this problem welcome!!!
– Hisay
Nov 13 at 9:33
2
2
Where is the difficulty? How have you tried integrating this function? What problem did you run into?
– Cris Luengo
Nov 5 at 5:07
Where is the difficulty? How have you tried integrating this function? What problem did you run into?
– Cris Luengo
Nov 5 at 5:07
You need to work on the mathematical problem first - what method of numerical integration do you want to use?
– Mikhail Genkin
Nov 5 at 11:31
You need to work on the mathematical problem first - what method of numerical integration do you want to use?
– Mikhail Genkin
Nov 5 at 11:31
@ Cris Luengo Thank you for the reply. I first evaluate the product B(i,j) a 3 x 3 matrix with cos (x) and then calculate the exponential. Thereafter evaluate integrate using Int(F, 0, pi.2). The problem is that the integration values are same for all functions. SO I doubt my way of integration may not be correct.
– Hisay
Nov 9 at 2:22
@ Cris Luengo Thank you for the reply. I first evaluate the product B(i,j) a 3 x 3 matrix with cos (x) and then calculate the exponential. Thereafter evaluate integrate using Int(F, 0, pi.2). The problem is that the integration values are same for all functions. SO I doubt my way of integration may not be correct.
– Hisay
Nov 9 at 2:22
@Mekhaiil Genkin. I do understand your point, I simplify the expression as mentioned above and then intgrate it using a function called int(F, 0, pi/2) in Matlab. But the results are having same value whenever integrates.
– Hisay
Nov 9 at 2:24
@Mekhaiil Genkin. I do understand your point, I simplify the expression as mentioned above and then intgrate it using a function called int(F, 0, pi/2) in Matlab. But the results are having same value whenever integrates.
– Hisay
Nov 9 at 2:24
Any suggestions to this problem welcome!!!
– Hisay
Nov 13 at 9:33
Any suggestions to this problem welcome!!!
– Hisay
Nov 13 at 9:33
add a comment |
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2
Where is the difficulty? How have you tried integrating this function? What problem did you run into?
– Cris Luengo
Nov 5 at 5:07
You need to work on the mathematical problem first - what method of numerical integration do you want to use?
– Mikhail Genkin
Nov 5 at 11:31
@ Cris Luengo Thank you for the reply. I first evaluate the product B(i,j) a 3 x 3 matrix with cos (x) and then calculate the exponential. Thereafter evaluate integrate using Int(F, 0, pi.2). The problem is that the integration values are same for all functions. SO I doubt my way of integration may not be correct.
– Hisay
Nov 9 at 2:22
@Mekhaiil Genkin. I do understand your point, I simplify the expression as mentioned above and then intgrate it using a function called int(F, 0, pi/2) in Matlab. But the results are having same value whenever integrates.
– Hisay
Nov 9 at 2:24
Any suggestions to this problem welcome!!!
– Hisay
Nov 13 at 9:33