charAt() not working second time in function for javascript
charAt() not working second time in function for javascript
function translateWord(n)
for (var i = 0; i < n.length; i++)
if( n.charAt(i).toLowerCase() == "a")
return n.charAt(i) = "alpha ";
im trying to translate the letter at "i" into alpha but whenever i add the charAt(i) statement it just stops working?
note: im trying to translate the letter at "i" into alpha, not check if it is alpha
for example if i was to write 'aa' i want it to come out as 'alpha alpha'
return n.charAt(i) = "alpha ";
=
return n.charAt(i) == "alpha "; SInlge = is assignment == equality check
– Manos Kounelakis
Aug 31 at 7:00
Also charAt returns a char not a string.Why would you compare a char with a string
– Manos Kounelakis
Aug 31 at 7:01
What do you want to do? Assignment statement with return clause is an invalid clause...
– codeLover
Aug 31 at 7:02
Syntax error aside, the return statement would also break out of the loop. So
n.charAt(i)
would only get called once. There's a lot of errors in just 3 lines of code.– Claus Jørgensen
Aug 31 at 7:13
n.charAt(i)
3 Answers
3
How by doing something like this:
var mystring = "amazon";
mystring = mystring.split('a').join('alpha');
console.log(mystring);
it worked, thank you ^-^
– xaegi
Aug 31 at 7:46
@xaegi Happy to help. Best of luck!
– Karan Dhir
Aug 31 at 7:58
Simple use String.replace()
String.replace()
function translateWord(n)
return n.replace('a','alpha');
console.log(translateWord('man'));
Method 1)
function translateWord(str, word, newWord)
var len = 0, newStr = '';
while (len < str.length)
newStr += ( str.charAt(len).toLowerCase() === word ) ? newWord : str[len];
len++;
return newStr;
console.log(translateWord('Amazon','a','alpha'));
Method 2)
function translateWord(str)
return str.replace(/a/gi,'alpha');
console.log(translateWord('Amazon'));
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return n.charAt(i) = "alpha ";
Invalid syntax -=
is assignment.– CertainPerformance
Aug 31 at 6:57