charAt() not working second time in function for javascript

charAt() not working second time in function for javascript


function translateWord(n)
for (var i = 0; i < n.length; i++)
if( n.charAt(i).toLowerCase() == "a")
return n.charAt(i) = "alpha ";





im trying to translate the letter at "i" into alpha but whenever i add the charAt(i) statement it just stops working?



note: im trying to translate the letter at "i" into alpha, not check if it is alpha



for example if i was to write 'aa' i want it to come out as 'alpha alpha'





return n.charAt(i) = "alpha "; Invalid syntax - = is assignment.
– CertainPerformance
Aug 31 at 6:57


return n.charAt(i) = "alpha ";


=





return n.charAt(i) == "alpha "; SInlge = is assignment == equality check
– Manos Kounelakis
Aug 31 at 7:00





Also charAt returns a char not a string.Why would you compare a char with a string
– Manos Kounelakis
Aug 31 at 7:01





What do you want to do? Assignment statement with return clause is an invalid clause...
– codeLover
Aug 31 at 7:02





Syntax error aside, the return statement would also break out of the loop. So n.charAt(i) would only get called once. There's a lot of errors in just 3 lines of code.
– Claus Jørgensen
Aug 31 at 7:13


n.charAt(i)




3 Answers
3



How by doing something like this:




var mystring = "amazon";
mystring = mystring.split('a').join('alpha');
console.log(mystring);





it worked, thank you ^-^
– xaegi
Aug 31 at 7:46





@xaegi Happy to help. Best of luck!
– Karan Dhir
Aug 31 at 7:58



Simple use String.replace()


String.replace()




function translateWord(n)
return n.replace('a','alpha');


console.log(translateWord('man'));



Method 1)




function translateWord(str, word, newWord)

var len = 0, newStr = '';

while (len < str.length)
newStr += ( str.charAt(len).toLowerCase() === word ) ? newWord : str[len];
len++;


return newStr;



console.log(translateWord('Amazon','a','alpha'));



Method 2)




function translateWord(str)
return str.replace(/a/gi,'alpha');


console.log(translateWord('Amazon'));



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