SQL Server DATEPART() Function

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SQL Server DATEPART() Function

❮ SQL Server Functions

Example

Return a specified part of a date:

SELECT DATEPART(year, '2017/08/25') AS DatePartInt;

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Definition and Usage

The DATEPART() function returns a specified part of a date.

This function returns the result as an integer value.

Syntax

DATEPART(interval, date)

Parameter Values

Parameter	Description
interval	Required. The part to return. Can be one of the following values: year, yyyy, yy = Year quarter, qq, q = Quarter month, mm, m = month dayofyear = Day of the year day, dy, y = Day week, ww, wk = Week weekday, dw, w = Weekday hour, hh = hour minute, mi, n = Minute second, ss, s = Second millisecond, ms = Millisecond
date	Required. The date to use

Technical Details

Works in:	SQL Server (starting with 2008), Azure SQL Database, Azure SQL Data Warehouse, Parallel Data Warehouse

More Examples

Example

Return a specified part of a date:

SELECT DATEPART(yy, '2017/08/25') AS DatePartInt;

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Example

Return a specified part of a date:

SELECT DATEPART(month, '2017/08/25') AS DatePartInt;

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Example

Return a specified part of a date:

SELECT DATEPART(hour, '2017/08/25 08:36') AS DatePartInt;

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Example

Return a specified part of a date:

SELECT DATEPART(minute, '2017/08/25 08:36') AS DatePartInt;

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❮ SQL Server Functions

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