Regex Python 3.x

My string is:

s = '"location":"state":"WA","active":true'


I want to get a regex expression so I can capture the following:

group 1: location":
group 2: state":
group 3: active":


Since these 3 words all end with ":

I have tried the following regex, but it is not working:

"[(a-zA-Z)*]+":


I need to capture via 3 groups.

2 Answers
2

This works fine.

>>> re.findall("([a-zA-Z]+)":", s)
['location', 'state', 'active']


Or you can use two steps to complete it.
First, use re.findall with [a-zA-Z]+": to find 3 groups.

re.findall

[a-zA-Z]+":

>>> re.findall("[a-zA-Z]+":", s)
['location":', 'state":', 'active":']


Second, replace ": with empty: r.replace("":", "")

":

r.replace("":", "")

>>> res = re.findall("[a-zA-Z]+":", s)
>>> res
['location":', 'state":', 'active":']
>>> for r in res:
... r.replace("":", "")
...
'location'
'state'
'active'


I was able to capture it with a simple (r'w+":')

(r'w+":')

>>> import re
>>> s = '"location":"state":"WA","active": True'
>>> a = re.compile(r'w+":')
>>> location, state, active = a.findall(s)
>>> location, state, active
('location":', 'state":', 'active":')


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