Python, regex to filter elements endswith a style in a list

With regex, I want to find out which of the elements in a list, endswith the style (yyyy-mm-dd), for example (2016-05-04) etc.

The pattern r'(2016-dd-dd)' looks alright even tough naive. What's the right way to combine it with Endswith?

Thank you.

import re

a_list = ["Peter arrived on (2016-05-04)", "Building 4 floor (2020)", "Fox movie (2016-04-04)", "David 2016-08-", "Mary comes late(true)"]

style = r'(2016-dd-dd)'

for a in a_list:
if a.endswith(style):
print a


style = r'(d4-d2-d2)'

3 Answers
3

You cannot combine regex with string operations. Just use re.search to find match and use the anchor $ in your pattern to check if the match happens at the end

re.search

$

>>> import re
>>> style = re.compile(r'(2016-dd-dd)$')
>>> for a in a_list:
... if style.search(a):
... print (a)
...
Peter arrived on (2016-05-04)
Fox movie (2016-04-04)


Use r'(d4-d2-d2)$'

r'(d4-d2-d2)$'

Ex:

import re

a_list = ["Peter arrived on (2016-05-04)", "Building 4 floor (2020)", "Fox movie (2016-04-04)", "David 2016-08-", "Mary comes late(true)"]

style = r'(d4-d2-d2)$'

for a in a_list:
if re.search(style, a):
print a


Output:

Peter arrived on (2016-05-04)
Fox movie (2016-04-04)


It would be

.*(2016-d2-d2)$


The $ symbol says its at the end

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