Append a tag before img tag
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I have the below code. I am trying to append a element before image tag. It works, but it always replace previous content with the last content. I tried to use $i to separate the content. But, I am not quite sure how to implement it. Any suggestion?
preg_match_all('#src="(?:.*/)?(.*?)"#', $content, $match);
foreach($match[0] as $k => $v)
$replace = '<a href="'.$v.'"><img src="'.$v.'" /></a>';
$content = preg_replace('#<s*img.*?src="(?:[^"]+/)?(.*?)".*?>#s', $replace, $content);
php preg-replace
asked Nov 9 at 4:01
Cristal
218110
add a comment |
up vote
1
down vote
favorite
I have the below code. I am trying to append a element before image tag. It works, but it always replace previous content with the last content. I tried to use $i to separate the content. But, I am not quite sure how to implement it. Any suggestion?
preg_match_all('#src="(?:.*/)?(.*?)"#', $content, $match);
foreach($match[0] as $k => $v)
$replace = '<a href="'.$v.'"><img src="'.$v.'" /></a>';
$content = preg_replace('#<s*img.*?src="(?:[^"]+/)?(.*?)".*?>#s', $replace, $content);
php preg-replace
asked Nov 9 at 4:01
Cristal
218110
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I have the below code. I am trying to append a element before image tag. It works, but it always replace previous content with the last content. I tried to use $i to separate the content. But, I am not quite sure how to implement it. Any suggestion?
preg_match_all('#src="(?:.*/)?(.*?)"#', $content, $match);
foreach($match[0] as $k => $v)
$replace = '<a href="'.$v.'"><img src="'.$v.'" /></a>';
$content = preg_replace('#<s*img.*?src="(?:[^"]+/)?(.*?)".*?>#s', $replace, $content);
php preg-replace
asked Nov 9 at 4:01
Cristal
218110
I have the below code. I am trying to append a element before image tag. It works, but it always replace previous content with the last content. I tried to use $i to separate the content. But, I am not quite sure how to implement it. Any suggestion?
preg_match_all('#src="(?:.*/)?(.*?)"#', $content, $match);
foreach($match[0] as $k => $v)
$replace = '<a href="'.$v.'"><img src="'.$v.'" /></a>';
$content = preg_replace('#<s*img.*?src="(?:[^"]+/)?(.*?)".*?>#s', $replace, $content);
php preg-replace
php preg-replace
asked Nov 9 at 4:01
Cristal
218110
asked Nov 9 at 4:01
Cristal
218110
asked Nov 9 at 4:01
Cristal
218110
asked Nov 9 at 4:01
Cristal
218110
asked Nov 9 at 4:01
Cristal
218110
218110
add a comment |
add a comment |
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