sed command to remove first occurrence of a word










1















I want to know how to remove the first occurrence of a word in a file.



Example: I want to remove the admin, from the first occurrence only.



account required pam_opendirectory.so
account sufficient pam_self.so
account required pam_group.so no_warn group=admin,wheel fail_safe
account required pam_group.so no_warn deny group=admin,wheel ruser fail_safe


I have tried:



sudo sed -i.bak "s/admin,//1" /etc/pam.d/screensaver


But that removes both cases, any ideas?










share|improve this question


























    1















    I want to know how to remove the first occurrence of a word in a file.



    Example: I want to remove the admin, from the first occurrence only.



    account required pam_opendirectory.so
    account sufficient pam_self.so
    account required pam_group.so no_warn group=admin,wheel fail_safe
    account required pam_group.so no_warn deny group=admin,wheel ruser fail_safe


    I have tried:



    sudo sed -i.bak "s/admin,//1" /etc/pam.d/screensaver


    But that removes both cases, any ideas?










    share|improve this question
























      1












      1








      1








      I want to know how to remove the first occurrence of a word in a file.



      Example: I want to remove the admin, from the first occurrence only.



      account required pam_opendirectory.so
      account sufficient pam_self.so
      account required pam_group.so no_warn group=admin,wheel fail_safe
      account required pam_group.so no_warn deny group=admin,wheel ruser fail_safe


      I have tried:



      sudo sed -i.bak "s/admin,//1" /etc/pam.d/screensaver


      But that removes both cases, any ideas?










      share|improve this question














      I want to know how to remove the first occurrence of a word in a file.



      Example: I want to remove the admin, from the first occurrence only.



      account required pam_opendirectory.so
      account sufficient pam_self.so
      account required pam_group.so no_warn group=admin,wheel fail_safe
      account required pam_group.so no_warn deny group=admin,wheel ruser fail_safe


      I have tried:



      sudo sed -i.bak "s/admin,//1" /etc/pam.d/screensaver


      But that removes both cases, any ideas?







      macos sed






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 30 '15 at 21:03









      Technic1anTechnic1an

      1,16951317




      1,16951317






















          2 Answers
          2






          active

          oldest

          votes


















          4














          Using sed



          To remove the first occurrence in the file:



          $ sed -e ':a' -e '$!N;ba;' -e 's/admin,//1' file
          account required pam_opendirectory.so
          account sufficient pam_self.so
          account required pam_group.so no_warn group=wheel fail_safe
          account required pam_group.so no_warn deny group=admin,wheel ruser fail_safe


          (The above was tested with GNU sed.)



          How it works




          • -e ':a' -e '$!N;ba;'



            This reads the whole file in at once to the pattern space. (If your file is too large for memory, this is not a good approach.)




          • -e 's/admin,//1'



            This performs the substitution on the first occurrence of admin and only the first occurrence.



          Using BSD (OSX) sed



          Wintermute reports that BSD sed cannot do branch instructions in one-liners and suggests this alternative for changing the file in place:



          sed -i.bak -n '1h; 1!H; $ x; s/admin,//; p; ' file


          This reads the whole file in at once and then does the substitution once the last line has been read.



          In more detail:




          • -n



            By default, sed would print each line. This turns that off.




          • 1h



            This places the first line in the hold buffer.




          • 1!H



            For all subsequent lines, this appends them to the hold buffer.




          • $ x; s/admin,//; p;



            For the last line ($), this exchanges the hold and pattern buffer so that the pattern buffer now has the complete file. s/admin,// does the substitution and p prints the result.



          Using awk



          $ awk '/admin/ && !fsub(/admin,/, ""); f=1 1' file >file.tmp && mv file.tmp file


          This results in:



          account required pam_opendirectory.so
          account sufficient pam_self.so
          account required pam_group.so no_warn group=wheel fail_safe
          account required pam_group.so no_warn deny group=admin,wheel ruser fail_safe


          How it works




          • /admin,/ && !fsub(/admin,/, ""); f=1



            For each line, check to see if it contains the word admin, and if the flag f still has its default value of zero. If so, remove the first occurrence of admin, and set the flag to one.




          • 1



            Print each line. 1 is awk's cryptic shorthand for print $0.







          share|improve this answer

























          • Gives me this error: sed: 2: "s/admin,//1 ": unexpected EOF (pending }'s)

            – Technic1an
            Mar 30 '15 at 21:28







          • 2





            OP is using MacOS X, which comes with BSD sed. With BSD sed, you cannot (or at least I have not found a way) use b instructions in one-liners. Try sed -i.bak -n '1h; 1!H; $ x; s/admin,//; p; ' file (that works essentially the same way but uses a different way to assemble the whole file before matching).

            – Wintermute
            Mar 30 '15 at 21:38







          • 1





            Either works. BSD sed does not accept just -i without an argument, though (but -i '' works). By the way: the reason b instructions don't work in one-liners in BSD sed is that something like ba; }; stuff takes everything after the b until the end of the line as a label name and attempts to jump to a label a; }; stuff. This is very silly because I don't think it is possible with BSD sed to declare labels that have a semicolon in their name, but I have the error message to prove it: sed 'ba; stuff' gives sed: 1: "ba; stuff": undefined label 'a; stuff'.

            – Wintermute
            Mar 30 '15 at 21:52






          • 2





            Chaining commands with ; in BSD sed is fine. Vis-a-vis , the thing to know is that with BSD sed, you need a ; before the } that GNU sed doesn't require (p vs. p;). As for the code: 1h copies the current line to the hold buffer if it is the first. 1!H appends it there if it isn't the first. $ ... does something if the current line is the last (at that point the whole file is in the hold buffer). x swaps hold buffer and pattern space, s/admin,// removes the first admin, from the PS, p prints the PS. The -n option disables auto-printing.

            – Wintermute
            Mar 30 '15 at 22:12






          • 1





            @Technic1an I added an explanation for Wintermute's command and updated the awk command to change the file in-place.

            – John1024
            Mar 30 '15 at 22:19


















          0














          Using sed, without reading the whole file:



          sed 's/admin,//;tl;b;:l;n;bl' file


          This waits for a successful substitution and then goes into a loop of printing the rest of the file.



          • s/admin,//;tl;b;: substitute admin with empty string, if substitution occurs jump to label l otherwise print the line and exit (next line will be processed the same way).


          • :l;n;bl: define label l, read line, jump to l.






          share|improve this answer






















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            2 Answers
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            active

            oldest

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            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            4














            Using sed



            To remove the first occurrence in the file:



            $ sed -e ':a' -e '$!N;ba;' -e 's/admin,//1' file
            account required pam_opendirectory.so
            account sufficient pam_self.so
            account required pam_group.so no_warn group=wheel fail_safe
            account required pam_group.so no_warn deny group=admin,wheel ruser fail_safe


            (The above was tested with GNU sed.)



            How it works




            • -e ':a' -e '$!N;ba;'



              This reads the whole file in at once to the pattern space. (If your file is too large for memory, this is not a good approach.)




            • -e 's/admin,//1'



              This performs the substitution on the first occurrence of admin and only the first occurrence.



            Using BSD (OSX) sed



            Wintermute reports that BSD sed cannot do branch instructions in one-liners and suggests this alternative for changing the file in place:



            sed -i.bak -n '1h; 1!H; $ x; s/admin,//; p; ' file


            This reads the whole file in at once and then does the substitution once the last line has been read.



            In more detail:




            • -n



              By default, sed would print each line. This turns that off.




            • 1h



              This places the first line in the hold buffer.




            • 1!H



              For all subsequent lines, this appends them to the hold buffer.




            • $ x; s/admin,//; p;



              For the last line ($), this exchanges the hold and pattern buffer so that the pattern buffer now has the complete file. s/admin,// does the substitution and p prints the result.



            Using awk



            $ awk '/admin/ && !fsub(/admin,/, ""); f=1 1' file >file.tmp && mv file.tmp file


            This results in:



            account required pam_opendirectory.so
            account sufficient pam_self.so
            account required pam_group.so no_warn group=wheel fail_safe
            account required pam_group.so no_warn deny group=admin,wheel ruser fail_safe


            How it works




            • /admin,/ && !fsub(/admin,/, ""); f=1



              For each line, check to see if it contains the word admin, and if the flag f still has its default value of zero. If so, remove the first occurrence of admin, and set the flag to one.




            • 1



              Print each line. 1 is awk's cryptic shorthand for print $0.







            share|improve this answer

























            • Gives me this error: sed: 2: "s/admin,//1 ": unexpected EOF (pending }'s)

              – Technic1an
              Mar 30 '15 at 21:28







            • 2





              OP is using MacOS X, which comes with BSD sed. With BSD sed, you cannot (or at least I have not found a way) use b instructions in one-liners. Try sed -i.bak -n '1h; 1!H; $ x; s/admin,//; p; ' file (that works essentially the same way but uses a different way to assemble the whole file before matching).

              – Wintermute
              Mar 30 '15 at 21:38







            • 1





              Either works. BSD sed does not accept just -i without an argument, though (but -i '' works). By the way: the reason b instructions don't work in one-liners in BSD sed is that something like ba; }; stuff takes everything after the b until the end of the line as a label name and attempts to jump to a label a; }; stuff. This is very silly because I don't think it is possible with BSD sed to declare labels that have a semicolon in their name, but I have the error message to prove it: sed 'ba; stuff' gives sed: 1: "ba; stuff": undefined label 'a; stuff'.

              – Wintermute
              Mar 30 '15 at 21:52






            • 2





              Chaining commands with ; in BSD sed is fine. Vis-a-vis , the thing to know is that with BSD sed, you need a ; before the } that GNU sed doesn't require (p vs. p;). As for the code: 1h copies the current line to the hold buffer if it is the first. 1!H appends it there if it isn't the first. $ ... does something if the current line is the last (at that point the whole file is in the hold buffer). x swaps hold buffer and pattern space, s/admin,// removes the first admin, from the PS, p prints the PS. The -n option disables auto-printing.

              – Wintermute
              Mar 30 '15 at 22:12






            • 1





              @Technic1an I added an explanation for Wintermute's command and updated the awk command to change the file in-place.

              – John1024
              Mar 30 '15 at 22:19















            4














            Using sed



            To remove the first occurrence in the file:



            $ sed -e ':a' -e '$!N;ba;' -e 's/admin,//1' file
            account required pam_opendirectory.so
            account sufficient pam_self.so
            account required pam_group.so no_warn group=wheel fail_safe
            account required pam_group.so no_warn deny group=admin,wheel ruser fail_safe


            (The above was tested with GNU sed.)



            How it works




            • -e ':a' -e '$!N;ba;'



              This reads the whole file in at once to the pattern space. (If your file is too large for memory, this is not a good approach.)




            • -e 's/admin,//1'



              This performs the substitution on the first occurrence of admin and only the first occurrence.



            Using BSD (OSX) sed



            Wintermute reports that BSD sed cannot do branch instructions in one-liners and suggests this alternative for changing the file in place:



            sed -i.bak -n '1h; 1!H; $ x; s/admin,//; p; ' file


            This reads the whole file in at once and then does the substitution once the last line has been read.



            In more detail:




            • -n



              By default, sed would print each line. This turns that off.




            • 1h



              This places the first line in the hold buffer.




            • 1!H



              For all subsequent lines, this appends them to the hold buffer.




            • $ x; s/admin,//; p;



              For the last line ($), this exchanges the hold and pattern buffer so that the pattern buffer now has the complete file. s/admin,// does the substitution and p prints the result.



            Using awk



            $ awk '/admin/ && !fsub(/admin,/, ""); f=1 1' file >file.tmp && mv file.tmp file


            This results in:



            account required pam_opendirectory.so
            account sufficient pam_self.so
            account required pam_group.so no_warn group=wheel fail_safe
            account required pam_group.so no_warn deny group=admin,wheel ruser fail_safe


            How it works




            • /admin,/ && !fsub(/admin,/, ""); f=1



              For each line, check to see if it contains the word admin, and if the flag f still has its default value of zero. If so, remove the first occurrence of admin, and set the flag to one.




            • 1



              Print each line. 1 is awk's cryptic shorthand for print $0.







            share|improve this answer

























            • Gives me this error: sed: 2: "s/admin,//1 ": unexpected EOF (pending }'s)

              – Technic1an
              Mar 30 '15 at 21:28







            • 2





              OP is using MacOS X, which comes with BSD sed. With BSD sed, you cannot (or at least I have not found a way) use b instructions in one-liners. Try sed -i.bak -n '1h; 1!H; $ x; s/admin,//; p; ' file (that works essentially the same way but uses a different way to assemble the whole file before matching).

              – Wintermute
              Mar 30 '15 at 21:38







            • 1





              Either works. BSD sed does not accept just -i without an argument, though (but -i '' works). By the way: the reason b instructions don't work in one-liners in BSD sed is that something like ba; }; stuff takes everything after the b until the end of the line as a label name and attempts to jump to a label a; }; stuff. This is very silly because I don't think it is possible with BSD sed to declare labels that have a semicolon in their name, but I have the error message to prove it: sed 'ba; stuff' gives sed: 1: "ba; stuff": undefined label 'a; stuff'.

              – Wintermute
              Mar 30 '15 at 21:52






            • 2





              Chaining commands with ; in BSD sed is fine. Vis-a-vis , the thing to know is that with BSD sed, you need a ; before the } that GNU sed doesn't require (p vs. p;). As for the code: 1h copies the current line to the hold buffer if it is the first. 1!H appends it there if it isn't the first. $ ... does something if the current line is the last (at that point the whole file is in the hold buffer). x swaps hold buffer and pattern space, s/admin,// removes the first admin, from the PS, p prints the PS. The -n option disables auto-printing.

              – Wintermute
              Mar 30 '15 at 22:12






            • 1





              @Technic1an I added an explanation for Wintermute's command and updated the awk command to change the file in-place.

              – John1024
              Mar 30 '15 at 22:19













            4












            4








            4







            Using sed



            To remove the first occurrence in the file:



            $ sed -e ':a' -e '$!N;ba;' -e 's/admin,//1' file
            account required pam_opendirectory.so
            account sufficient pam_self.so
            account required pam_group.so no_warn group=wheel fail_safe
            account required pam_group.so no_warn deny group=admin,wheel ruser fail_safe


            (The above was tested with GNU sed.)



            How it works




            • -e ':a' -e '$!N;ba;'



              This reads the whole file in at once to the pattern space. (If your file is too large for memory, this is not a good approach.)




            • -e 's/admin,//1'



              This performs the substitution on the first occurrence of admin and only the first occurrence.



            Using BSD (OSX) sed



            Wintermute reports that BSD sed cannot do branch instructions in one-liners and suggests this alternative for changing the file in place:



            sed -i.bak -n '1h; 1!H; $ x; s/admin,//; p; ' file


            This reads the whole file in at once and then does the substitution once the last line has been read.



            In more detail:




            • -n



              By default, sed would print each line. This turns that off.




            • 1h



              This places the first line in the hold buffer.




            • 1!H



              For all subsequent lines, this appends them to the hold buffer.




            • $ x; s/admin,//; p;



              For the last line ($), this exchanges the hold and pattern buffer so that the pattern buffer now has the complete file. s/admin,// does the substitution and p prints the result.



            Using awk



            $ awk '/admin/ && !fsub(/admin,/, ""); f=1 1' file >file.tmp && mv file.tmp file


            This results in:



            account required pam_opendirectory.so
            account sufficient pam_self.so
            account required pam_group.so no_warn group=wheel fail_safe
            account required pam_group.so no_warn deny group=admin,wheel ruser fail_safe


            How it works




            • /admin,/ && !fsub(/admin,/, ""); f=1



              For each line, check to see if it contains the word admin, and if the flag f still has its default value of zero. If so, remove the first occurrence of admin, and set the flag to one.




            • 1



              Print each line. 1 is awk's cryptic shorthand for print $0.







            share|improve this answer















            Using sed



            To remove the first occurrence in the file:



            $ sed -e ':a' -e '$!N;ba;' -e 's/admin,//1' file
            account required pam_opendirectory.so
            account sufficient pam_self.so
            account required pam_group.so no_warn group=wheel fail_safe
            account required pam_group.so no_warn deny group=admin,wheel ruser fail_safe


            (The above was tested with GNU sed.)



            How it works




            • -e ':a' -e '$!N;ba;'



              This reads the whole file in at once to the pattern space. (If your file is too large for memory, this is not a good approach.)




            • -e 's/admin,//1'



              This performs the substitution on the first occurrence of admin and only the first occurrence.



            Using BSD (OSX) sed



            Wintermute reports that BSD sed cannot do branch instructions in one-liners and suggests this alternative for changing the file in place:



            sed -i.bak -n '1h; 1!H; $ x; s/admin,//; p; ' file


            This reads the whole file in at once and then does the substitution once the last line has been read.



            In more detail:




            • -n



              By default, sed would print each line. This turns that off.




            • 1h



              This places the first line in the hold buffer.




            • 1!H



              For all subsequent lines, this appends them to the hold buffer.




            • $ x; s/admin,//; p;



              For the last line ($), this exchanges the hold and pattern buffer so that the pattern buffer now has the complete file. s/admin,// does the substitution and p prints the result.



            Using awk



            $ awk '/admin/ && !fsub(/admin,/, ""); f=1 1' file >file.tmp && mv file.tmp file


            This results in:



            account required pam_opendirectory.so
            account sufficient pam_self.so
            account required pam_group.so no_warn group=wheel fail_safe
            account required pam_group.so no_warn deny group=admin,wheel ruser fail_safe


            How it works




            • /admin,/ && !fsub(/admin,/, ""); f=1



              For each line, check to see if it contains the word admin, and if the flag f still has its default value of zero. If so, remove the first occurrence of admin, and set the flag to one.




            • 1



              Print each line. 1 is awk's cryptic shorthand for print $0.








            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Mar 30 '15 at 22:17

























            answered Mar 30 '15 at 21:25









            John1024John1024

            77.2k87198




            77.2k87198












            • Gives me this error: sed: 2: "s/admin,//1 ": unexpected EOF (pending }'s)

              – Technic1an
              Mar 30 '15 at 21:28







            • 2





              OP is using MacOS X, which comes with BSD sed. With BSD sed, you cannot (or at least I have not found a way) use b instructions in one-liners. Try sed -i.bak -n '1h; 1!H; $ x; s/admin,//; p; ' file (that works essentially the same way but uses a different way to assemble the whole file before matching).

              – Wintermute
              Mar 30 '15 at 21:38







            • 1





              Either works. BSD sed does not accept just -i without an argument, though (but -i '' works). By the way: the reason b instructions don't work in one-liners in BSD sed is that something like ba; }; stuff takes everything after the b until the end of the line as a label name and attempts to jump to a label a; }; stuff. This is very silly because I don't think it is possible with BSD sed to declare labels that have a semicolon in their name, but I have the error message to prove it: sed 'ba; stuff' gives sed: 1: "ba; stuff": undefined label 'a; stuff'.

              – Wintermute
              Mar 30 '15 at 21:52






            • 2





              Chaining commands with ; in BSD sed is fine. Vis-a-vis , the thing to know is that with BSD sed, you need a ; before the } that GNU sed doesn't require (p vs. p;). As for the code: 1h copies the current line to the hold buffer if it is the first. 1!H appends it there if it isn't the first. $ ... does something if the current line is the last (at that point the whole file is in the hold buffer). x swaps hold buffer and pattern space, s/admin,// removes the first admin, from the PS, p prints the PS. The -n option disables auto-printing.

              – Wintermute
              Mar 30 '15 at 22:12






            • 1





              @Technic1an I added an explanation for Wintermute's command and updated the awk command to change the file in-place.

              – John1024
              Mar 30 '15 at 22:19

















            • Gives me this error: sed: 2: "s/admin,//1 ": unexpected EOF (pending }'s)

              – Technic1an
              Mar 30 '15 at 21:28







            • 2





              OP is using MacOS X, which comes with BSD sed. With BSD sed, you cannot (or at least I have not found a way) use b instructions in one-liners. Try sed -i.bak -n '1h; 1!H; $ x; s/admin,//; p; ' file (that works essentially the same way but uses a different way to assemble the whole file before matching).

              – Wintermute
              Mar 30 '15 at 21:38







            • 1





              Either works. BSD sed does not accept just -i without an argument, though (but -i '' works). By the way: the reason b instructions don't work in one-liners in BSD sed is that something like ba; }; stuff takes everything after the b until the end of the line as a label name and attempts to jump to a label a; }; stuff. This is very silly because I don't think it is possible with BSD sed to declare labels that have a semicolon in their name, but I have the error message to prove it: sed 'ba; stuff' gives sed: 1: "ba; stuff": undefined label 'a; stuff'.

              – Wintermute
              Mar 30 '15 at 21:52






            • 2





              Chaining commands with ; in BSD sed is fine. Vis-a-vis , the thing to know is that with BSD sed, you need a ; before the } that GNU sed doesn't require (p vs. p;). As for the code: 1h copies the current line to the hold buffer if it is the first. 1!H appends it there if it isn't the first. $ ... does something if the current line is the last (at that point the whole file is in the hold buffer). x swaps hold buffer and pattern space, s/admin,// removes the first admin, from the PS, p prints the PS. The -n option disables auto-printing.

              – Wintermute
              Mar 30 '15 at 22:12






            • 1





              @Technic1an I added an explanation for Wintermute's command and updated the awk command to change the file in-place.

              – John1024
              Mar 30 '15 at 22:19
















            Gives me this error: sed: 2: "s/admin,//1 ": unexpected EOF (pending }'s)

            – Technic1an
            Mar 30 '15 at 21:28






            Gives me this error: sed: 2: "s/admin,//1 ": unexpected EOF (pending }'s)

            – Technic1an
            Mar 30 '15 at 21:28





            2




            2





            OP is using MacOS X, which comes with BSD sed. With BSD sed, you cannot (or at least I have not found a way) use b instructions in one-liners. Try sed -i.bak -n '1h; 1!H; $ x; s/admin,//; p; ' file (that works essentially the same way but uses a different way to assemble the whole file before matching).

            – Wintermute
            Mar 30 '15 at 21:38






            OP is using MacOS X, which comes with BSD sed. With BSD sed, you cannot (or at least I have not found a way) use b instructions in one-liners. Try sed -i.bak -n '1h; 1!H; $ x; s/admin,//; p; ' file (that works essentially the same way but uses a different way to assemble the whole file before matching).

            – Wintermute
            Mar 30 '15 at 21:38





            1




            1





            Either works. BSD sed does not accept just -i without an argument, though (but -i '' works). By the way: the reason b instructions don't work in one-liners in BSD sed is that something like ba; }; stuff takes everything after the b until the end of the line as a label name and attempts to jump to a label a; }; stuff. This is very silly because I don't think it is possible with BSD sed to declare labels that have a semicolon in their name, but I have the error message to prove it: sed 'ba; stuff' gives sed: 1: "ba; stuff": undefined label 'a; stuff'.

            – Wintermute
            Mar 30 '15 at 21:52





            Either works. BSD sed does not accept just -i without an argument, though (but -i '' works). By the way: the reason b instructions don't work in one-liners in BSD sed is that something like ba; }; stuff takes everything after the b until the end of the line as a label name and attempts to jump to a label a; }; stuff. This is very silly because I don't think it is possible with BSD sed to declare labels that have a semicolon in their name, but I have the error message to prove it: sed 'ba; stuff' gives sed: 1: "ba; stuff": undefined label 'a; stuff'.

            – Wintermute
            Mar 30 '15 at 21:52




            2




            2





            Chaining commands with ; in BSD sed is fine. Vis-a-vis , the thing to know is that with BSD sed, you need a ; before the } that GNU sed doesn't require (p vs. p;). As for the code: 1h copies the current line to the hold buffer if it is the first. 1!H appends it there if it isn't the first. $ ... does something if the current line is the last (at that point the whole file is in the hold buffer). x swaps hold buffer and pattern space, s/admin,// removes the first admin, from the PS, p prints the PS. The -n option disables auto-printing.

            – Wintermute
            Mar 30 '15 at 22:12





            Chaining commands with ; in BSD sed is fine. Vis-a-vis , the thing to know is that with BSD sed, you need a ; before the } that GNU sed doesn't require (p vs. p;). As for the code: 1h copies the current line to the hold buffer if it is the first. 1!H appends it there if it isn't the first. $ ... does something if the current line is the last (at that point the whole file is in the hold buffer). x swaps hold buffer and pattern space, s/admin,// removes the first admin, from the PS, p prints the PS. The -n option disables auto-printing.

            – Wintermute
            Mar 30 '15 at 22:12




            1




            1





            @Technic1an I added an explanation for Wintermute's command and updated the awk command to change the file in-place.

            – John1024
            Mar 30 '15 at 22:19





            @Technic1an I added an explanation for Wintermute's command and updated the awk command to change the file in-place.

            – John1024
            Mar 30 '15 at 22:19













            0














            Using sed, without reading the whole file:



            sed 's/admin,//;tl;b;:l;n;bl' file


            This waits for a successful substitution and then goes into a loop of printing the rest of the file.



            • s/admin,//;tl;b;: substitute admin with empty string, if substitution occurs jump to label l otherwise print the line and exit (next line will be processed the same way).


            • :l;n;bl: define label l, read line, jump to l.






            share|improve this answer



























              0














              Using sed, without reading the whole file:



              sed 's/admin,//;tl;b;:l;n;bl' file


              This waits for a successful substitution and then goes into a loop of printing the rest of the file.



              • s/admin,//;tl;b;: substitute admin with empty string, if substitution occurs jump to label l otherwise print the line and exit (next line will be processed the same way).


              • :l;n;bl: define label l, read line, jump to l.






              share|improve this answer

























                0












                0








                0







                Using sed, without reading the whole file:



                sed 's/admin,//;tl;b;:l;n;bl' file


                This waits for a successful substitution and then goes into a loop of printing the rest of the file.



                • s/admin,//;tl;b;: substitute admin with empty string, if substitution occurs jump to label l otherwise print the line and exit (next line will be processed the same way).


                • :l;n;bl: define label l, read line, jump to l.






                share|improve this answer













                Using sed, without reading the whole file:



                sed 's/admin,//;tl;b;:l;n;bl' file


                This waits for a successful substitution and then goes into a loop of printing the rest of the file.



                • s/admin,//;tl;b;: substitute admin with empty string, if substitution occurs jump to label l otherwise print the line and exit (next line will be processed the same way).


                • :l;n;bl: define label l, read line, jump to l.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 13 '18 at 12:19









                perrealperreal

                72.8k10111140




                72.8k10111140



























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