scala parse json objects in order
1
I have this following json input where I am trying to parse the name field in-order
scala> result
res6: play.api.libs.json.JsValue = "L0":
"name":"FASHION","id":"50000","L1":"name":"ACCESSORIES AND TRAVEL","id":"51000","L2":"name":"FASHION ACCESSORIES","id":"51001","L3":"name":"MENS FASHION ACCESSORIES","id":"51100","L4":"name":"MENS HATS","id":"51204"
scala> result \ "name"
res5: Seq[play.api.libs.json.JsValue] = List("ACCESSORIES AND TRAVEL", "MENS HATS", "MENS FASHION ACCESSORIES", "FASHION ACCESSORIES", "FASHION")
What I am trying is to get those names in-order like
List("FASHION", "ACCESSORIES AND TRAVEL", "FASHION ACCESSORIES", "MENS FASHION ACCESSORIES", "MENS HATS")
Is there a way to achieve that with play Json library?
scala play-json
asked Sep 20 '18 at 22:35
yalkrisyalkris
1,20231842
add a comment |
1
I have this following json input where I am trying to parse the name field in-order
scala> result
res6: play.api.libs.json.JsValue = "L0":
"name":"FASHION","id":"50000","L1":"name":"ACCESSORIES AND TRAVEL","id":"51000","L2":"name":"FASHION ACCESSORIES","id":"51001","L3":"name":"MENS FASHION ACCESSORIES","id":"51100","L4":"name":"MENS HATS","id":"51204"
scala> result \ "name"
res5: Seq[play.api.libs.json.JsValue] = List("ACCESSORIES AND TRAVEL", "MENS HATS", "MENS FASHION ACCESSORIES", "FASHION ACCESSORIES", "FASHION")
What I am trying is to get those names in-order like
List("FASHION", "ACCESSORIES AND TRAVEL", "FASHION ACCESSORIES", "MENS FASHION ACCESSORIES", "MENS HATS")
Is there a way to achieve that with play Json library?
scala play-json
asked Sep 20 '18 at 22:35
yalkrisyalkris
1,20231842
What have you tried by yourself?
– cchantep
Sep 20 '18 at 23:37
Yes. result \ "name" is what I have right now. I am trying to do it using a regex but I am wondering if there's an easy way with play Json library itself
– yalkris
Sep 21 '18 at 0:22
First have a look at the doc about how to parse/validate
– cchantep
Sep 21 '18 at 0:48
add a comment |
1
1
1
I have this following json input where I am trying to parse the name field in-order
scala> result
res6: play.api.libs.json.JsValue = "L0":
"name":"FASHION","id":"50000","L1":"name":"ACCESSORIES AND TRAVEL","id":"51000","L2":"name":"FASHION ACCESSORIES","id":"51001","L3":"name":"MENS FASHION ACCESSORIES","id":"51100","L4":"name":"MENS HATS","id":"51204"
scala> result \ "name"
res5: Seq[play.api.libs.json.JsValue] = List("ACCESSORIES AND TRAVEL", "MENS HATS", "MENS FASHION ACCESSORIES", "FASHION ACCESSORIES", "FASHION")
What I am trying is to get those names in-order like
List("FASHION", "ACCESSORIES AND TRAVEL", "FASHION ACCESSORIES", "MENS FASHION ACCESSORIES", "MENS HATS")
Is there a way to achieve that with play Json library?
scala play-json
asked Sep 20 '18 at 22:35
yalkrisyalkris
1,20231842
I have this following json input where I am trying to parse the name field in-order
scala> result
res6: play.api.libs.json.JsValue = "L0":
"name":"FASHION","id":"50000","L1":"name":"ACCESSORIES AND TRAVEL","id":"51000","L2":"name":"FASHION ACCESSORIES","id":"51001","L3":"name":"MENS FASHION ACCESSORIES","id":"51100","L4":"name":"MENS HATS","id":"51204"
scala> result \ "name"
res5: Seq[play.api.libs.json.JsValue] = List("ACCESSORIES AND TRAVEL", "MENS HATS", "MENS FASHION ACCESSORIES", "FASHION ACCESSORIES", "FASHION")
What I am trying is to get those names in-order like
List("FASHION", "ACCESSORIES AND TRAVEL", "FASHION ACCESSORIES", "MENS FASHION ACCESSORIES", "MENS HATS")
Is there a way to achieve that with play Json library?
scala play-json
scala play-json
asked Sep 20 '18 at 22:35
yalkrisyalkris
1,20231842
asked Sep 20 '18 at 22:35
yalkrisyalkris
1,20231842
edited Sep 20 '18 at 22:52
yalkris
asked Sep 20 '18 at 22:35
yalkrisyalkris
1,20231842
asked Sep 20 '18 at 22:35
yalkrisyalkris
1,20231842
asked Sep 20 '18 at 22:35
yalkrisyalkris
1,20231842
1,20231842
What have you tried by yourself?
– cchantep
Sep 20 '18 at 23:37
Yes. result \ "name" is what I have right now. I am trying to do it using a regex but I am wondering if there's an easy way with play Json library itself
– yalkris
Sep 21 '18 at 0:22
First have a look at the doc about how to parse/validate
– cchantep
Sep 21 '18 at 0:48
add a comment |
What have you tried by yourself?
– cchantep
Sep 20 '18 at 23:37
Yes. result \ "name" is what I have right now. I am trying to do it using a regex but I am wondering if there's an easy way with play Json library itself
– yalkris
Sep 21 '18 at 0:22
First have a look at the doc about how to parse/validate
– cchantep
Sep 21 '18 at 0:48
What have you tried by yourself?
– cchantep
Sep 20 '18 at 23:37
What have you tried by yourself?
– cchantep
Sep 20 '18 at 23:37
Yes. result \ "name" is what I have right now. I am trying to do it using a regex but I am wondering if there's an easy way with play Json library itself
– yalkris
Sep 21 '18 at 0:22
Yes. result \ "name" is what I have right now. I am trying to do it using a regex but I am wondering if there's an easy way with play Json library itself
– yalkris
Sep 21 '18 at 0:22
First have a look at the doc about how to parse/validate
– cchantep
Sep 21 '18 at 0:48
First have a look at the doc about how to parse/validate
– cchantep
Sep 21 '18 at 0:48
add a comment |
1 Answer
1
active
oldest
votes
1
With Play JSON I always use case classes. So your example would look like:
import play.api.libs.json._
val json = """"L0":
"name":"FASHION","id":"50000","L1":"name":"ACCESSORIES AND TRAVEL","id":"51000","L2":"name":"FASHION ACCESSORIES","id":"51001","L3":"name":"MENS FASHION ACCESSORIES","id":"51100","L4":"name":"MENS HATS","id":"51204"
"""
case class Element(id: String, name: String)
object Element
implicit val jsonFormat: Format[Element] = Json.format[Element]
Json.parse(json).validate[Map[String, Element]] match
case JsSuccess(elems, _) => println(elems.toList.sortBy(_._1).map(e => e._2.name))
case other => println(s"Handle exception $other")
What this gives you, is that you can sort the result by the key - the info that is lost in your solution.
answered Nov 13 '18 at 15:57
pmepme
3,28211830
Wow. That's cool. Thanks a lot.
– yalkris
Nov 13 '18 at 22:41
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
With Play JSON I always use case classes. So your example would look like:
import play.api.libs.json._
val json = """"L0":
"name":"FASHION","id":"50000","L1":"name":"ACCESSORIES AND TRAVEL","id":"51000","L2":"name":"FASHION ACCESSORIES","id":"51001","L3":"name":"MENS FASHION ACCESSORIES","id":"51100","L4":"name":"MENS HATS","id":"51204"
"""
case class Element(id: String, name: String)
object Element
implicit val jsonFormat: Format[Element] = Json.format[Element]
Json.parse(json).validate[Map[String, Element]] match
case JsSuccess(elems, _) => println(elems.toList.sortBy(_._1).map(e => e._2.name))
case other => println(s"Handle exception $other")
What this gives you, is that you can sort the result by the key - the info that is lost in your solution.
answered Nov 13 '18 at 15:57
pmepme
3,28211830
Wow. That's cool. Thanks a lot.
– yalkris
Nov 13 '18 at 22:41
add a comment |
1
With Play JSON I always use case classes. So your example would look like:
import play.api.libs.json._
val json = """"L0":
"name":"FASHION","id":"50000","L1":"name":"ACCESSORIES AND TRAVEL","id":"51000","L2":"name":"FASHION ACCESSORIES","id":"51001","L3":"name":"MENS FASHION ACCESSORIES","id":"51100","L4":"name":"MENS HATS","id":"51204"
"""
case class Element(id: String, name: String)
object Element
implicit val jsonFormat: Format[Element] = Json.format[Element]
Json.parse(json).validate[Map[String, Element]] match
case JsSuccess(elems, _) => println(elems.toList.sortBy(_._1).map(e => e._2.name))
case other => println(s"Handle exception $other")
What this gives you, is that you can sort the result by the key - the info that is lost in your solution.
answered Nov 13 '18 at 15:57
pmepme
3,28211830
Wow. That's cool. Thanks a lot.
– yalkris
Nov 13 '18 at 22:41
add a comment |
1
1
1
With Play JSON I always use case classes. So your example would look like:
import play.api.libs.json._
val json = """"L0":
"name":"FASHION","id":"50000","L1":"name":"ACCESSORIES AND TRAVEL","id":"51000","L2":"name":"FASHION ACCESSORIES","id":"51001","L3":"name":"MENS FASHION ACCESSORIES","id":"51100","L4":"name":"MENS HATS","id":"51204"
"""
case class Element(id: String, name: String)
object Element
implicit val jsonFormat: Format[Element] = Json.format[Element]
Json.parse(json).validate[Map[String, Element]] match
case JsSuccess(elems, _) => println(elems.toList.sortBy(_._1).map(e => e._2.name))
case other => println(s"Handle exception $other")
What this gives you, is that you can sort the result by the key - the info that is lost in your solution.
answered Nov 13 '18 at 15:57
pmepme
3,28211830
With Play JSON I always use case classes. So your example would look like:
import play.api.libs.json._
val json = """"L0":
"name":"FASHION","id":"50000","L1":"name":"ACCESSORIES AND TRAVEL","id":"51000","L2":"name":"FASHION ACCESSORIES","id":"51001","L3":"name":"MENS FASHION ACCESSORIES","id":"51100","L4":"name":"MENS HATS","id":"51204"
"""
case class Element(id: String, name: String)
object Element
implicit val jsonFormat: Format[Element] = Json.format[Element]
Json.parse(json).validate[Map[String, Element]] match
case JsSuccess(elems, _) => println(elems.toList.sortBy(_._1).map(e => e._2.name))
case other => println(s"Handle exception $other")
What this gives you, is that you can sort the result by the key - the info that is lost in your solution.
answered Nov 13 '18 at 15:57
pmepme
3,28211830
answered Nov 13 '18 at 15:57
pmepme
3,28211830
answered Nov 13 '18 at 15:57
pmepme
3,28211830
answered Nov 13 '18 at 15:57
pmepme
3,28211830
3,28211830
Wow. That's cool. Thanks a lot.
– yalkris
Nov 13 '18 at 22:41
add a comment |
Wow. That's cool. Thanks a lot.
– yalkris
Nov 13 '18 at 22:41
Wow. That's cool. Thanks a lot.
– yalkris
Nov 13 '18 at 22:41
Wow. That's cool. Thanks a lot.
– yalkris
Nov 13 '18 at 22:41
add a comment |
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What have you tried by yourself?
– cchantep
Sep 20 '18 at 23:37
Yes. result \ "name" is what I have right now. I am trying to do it using a regex but I am wondering if there's an easy way with play Json library itself
– yalkris
Sep 21 '18 at 0:22
First have a look at the doc about how to parse/validate
– cchantep
Sep 21 '18 at 0:48