Regex excluding catches that ending with a dot

First of all, I don't need full e-mail address validation, my given task doesn't require it. I just want to upgrade my current regex code so that it won't match addresses ending with a dot.

My current code: [0-9A-Za-z.]+[@][0-9A-Za-z.]+

[0-9A-Za-z.]+[@][0-9A-Za-z.]+

It catches both "user@exampe.com", "user@example.com."

user@exampe.com

user@example.com

I'd like it to catch only from the string that ends without the dot. user@exampe.com

user@exampe.com

Example string:

dasd.fas@fsaf.dfas.dsa, zghs@gas.gsq, adg32.dsa12@cas, ksak@c.csa., gs32.basaa@scaa.upc.

dasd.fas@fsaf.dfas.dsa

zghs@gas.gsq

adg32.dsa12@cas

I'd like to catch the strings marked as code in the example.

Edit: I have only one line with multiple e-mail addresses separated with a , and a space after them.

,

space

[^.]$

^YOUR-REb$

4 Answers
4

You might add [0-9A-Za-z]after your regex to end with what you want to match in your character class without the dot followed by a positive lookahead (?=, |$) that asserts what follows is either a comma followed by a whitespace or the end of the string.

[0-9A-Za-z]

(?=, |$)

[0-9A-Za-z.]+@[0-9A-Za-z.]+[0-9A-Za-z](?=, |$)

[0-9A-Za-z.]+@[0-9A-Za-z.]+[0-9A-Za-z](?=, |$)

Regex Demo

([0-9A-z.]+@(?:.?[0-9A-z]+)+)(?=,|$)

([0-9A-z.]+@(?:.?[0-9A-z]+)+)(?=,|$)

.

Just slightly modify your pattern: [0-9A-Za-z.]+[@](?:[a-zA-Z]|.(?=[a-zA-Z]))+.

[0-9A-Za-z.]+[@](?:[a-zA-Z]|.(?=[a-zA-Z]))+

It uses alternation after @ to match one or more: letters OR dot, if it's followed by another letter, thanks to positive lookahead: .(?=[a-zA-Z]).

@

.(?=[a-zA-Z])

Demo

Try this one:

just capture , , $ and group them in non-capturing group except end .

,

$

.

[0-9A-Za-z.]+[@][0-9A-Za-z.]+[0-9A-Za-z](?:(,|$))


demo here

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