download image from restful webservice and display in razor use asp.net MVC










0















i try to get images from a url and show the image in razor.but i can not change byte to image and show this.



//this is a string contains 3name of image and i give each of them with this 
way
string imgname = user.Original_images.Split(',');
foreach (var item3 in imgname)

string url2 = "my URL" +
+ item3 + ".jpg";

//i download image successfully
webclient.Headers["Authorization"] = "Basic " +
Convert.ToBase64String(
Encoding.Default.GetBytes("Username:password"));

byte data = webclient.DownloadData(url2);

//i don't know what should i do after this...










share|improve this question




























    0















    i try to get images from a url and show the image in razor.but i can not change byte to image and show this.



    //this is a string contains 3name of image and i give each of them with this 
    way
    string imgname = user.Original_images.Split(',');
    foreach (var item3 in imgname)

    string url2 = "my URL" +
    + item3 + ".jpg";

    //i download image successfully
    webclient.Headers["Authorization"] = "Basic " +
    Convert.ToBase64String(
    Encoding.Default.GetBytes("Username:password"));

    byte data = webclient.DownloadData(url2);

    //i don't know what should i do after this...










    share|improve this question


























      0












      0








      0








      i try to get images from a url and show the image in razor.but i can not change byte to image and show this.



      //this is a string contains 3name of image and i give each of them with this 
      way
      string imgname = user.Original_images.Split(',');
      foreach (var item3 in imgname)

      string url2 = "my URL" +
      + item3 + ".jpg";

      //i download image successfully
      webclient.Headers["Authorization"] = "Basic " +
      Convert.ToBase64String(
      Encoding.Default.GetBytes("Username:password"));

      byte data = webclient.DownloadData(url2);

      //i don't know what should i do after this...










      share|improve this question
















      i try to get images from a url and show the image in razor.but i can not change byte to image and show this.



      //this is a string contains 3name of image and i give each of them with this 
      way
      string imgname = user.Original_images.Split(',');
      foreach (var item3 in imgname)

      string url2 = "my URL" +
      + item3 + ".jpg";

      //i download image successfully
      webclient.Headers["Authorization"] = "Basic " +
      Convert.ToBase64String(
      Encoding.Default.GetBytes("Username:password"));

      byte data = webclient.DownloadData(url2);

      //i don't know what should i do after this...







      asp.net-mvc webclient






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 16 '18 at 13:32









      tereško

      52.4k2078135




      52.4k2078135










      asked Nov 11 '18 at 14:32









      Zohreh ZamaniZohreh Zamani

      84




      84






















          2 Answers
          2






          active

          oldest

          votes


















          1














          You can use FileResult action:



          Remember you can only return one file result at a time, you can use multiple calls to controller for multiple images.



          //changed part
          return File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);

          public FileResult Download()

          //this is a string contains 3name of image and i give each of them with this
          way
          string imgname = user.Original_images.Split(',');
          foreach (var item3 in imgname)

          string url2 = "my URL" +
          + item3 + ".jpg";

          //i download image successfully
          webclient.Headers["Authorization"] = "Basic " +
          Convert.ToBase64String(
          Encoding.Default.GetBytes("Username:password"));

          byte data = webclient.DownloadData(url2);

          //i don't know what should i do after this...
          return File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);









          share|improve this answer























          • The code I wrote is in the middle of a method and i can't have return,and when i write this : user.img=File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);[user is an object of my viewmodel and the type of img is "object" ] but when i want show user.img in razor i see this ContentType application/octet-stream FileDownloadName !!

            – Zohreh Zamani
            Nov 12 '18 at 7:35












          • You can use controller to action method to retrieve the image.

            – Just code
            Nov 12 '18 at 7:55


















          0














          i solve my question



           string imgname = user.Original_images.Split(',');
          foreach (var item3 in imgname)

          string url2 = "my URL" +
          + item3 + ".jpg";

          //i download image successfully
          webclient.Headers["Authorization"] = "Basic " +
          Convert.ToBase64String(
          Encoding.Default.GetBytes("Username:password"));

          byte data = webclient.DownloadData(url2);

          //this is new
          string imageBase64Data = Convert.ToBase64String(imageByteData);
          string imageDataURL = string.Format("data:image/jpg;base64,0",
          imageBase64Data);
          ViewBag.ImageData = imageDataURL;



          and in razor i have this



          <img src="@ViewBag.ImageData" />





          share|improve this answer






















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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            You can use FileResult action:



            Remember you can only return one file result at a time, you can use multiple calls to controller for multiple images.



            //changed part
            return File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);

            public FileResult Download()

            //this is a string contains 3name of image and i give each of them with this
            way
            string imgname = user.Original_images.Split(',');
            foreach (var item3 in imgname)

            string url2 = "my URL" +
            + item3 + ".jpg";

            //i download image successfully
            webclient.Headers["Authorization"] = "Basic " +
            Convert.ToBase64String(
            Encoding.Default.GetBytes("Username:password"));

            byte data = webclient.DownloadData(url2);

            //i don't know what should i do after this...
            return File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);









            share|improve this answer























            • The code I wrote is in the middle of a method and i can't have return,and when i write this : user.img=File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);[user is an object of my viewmodel and the type of img is "object" ] but when i want show user.img in razor i see this ContentType application/octet-stream FileDownloadName !!

              – Zohreh Zamani
              Nov 12 '18 at 7:35












            • You can use controller to action method to retrieve the image.

              – Just code
              Nov 12 '18 at 7:55















            1














            You can use FileResult action:



            Remember you can only return one file result at a time, you can use multiple calls to controller for multiple images.



            //changed part
            return File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);

            public FileResult Download()

            //this is a string contains 3name of image and i give each of them with this
            way
            string imgname = user.Original_images.Split(',');
            foreach (var item3 in imgname)

            string url2 = "my URL" +
            + item3 + ".jpg";

            //i download image successfully
            webclient.Headers["Authorization"] = "Basic " +
            Convert.ToBase64String(
            Encoding.Default.GetBytes("Username:password"));

            byte data = webclient.DownloadData(url2);

            //i don't know what should i do after this...
            return File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);









            share|improve this answer























            • The code I wrote is in the middle of a method and i can't have return,and when i write this : user.img=File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);[user is an object of my viewmodel and the type of img is "object" ] but when i want show user.img in razor i see this ContentType application/octet-stream FileDownloadName !!

              – Zohreh Zamani
              Nov 12 '18 at 7:35












            • You can use controller to action method to retrieve the image.

              – Just code
              Nov 12 '18 at 7:55













            1












            1








            1







            You can use FileResult action:



            Remember you can only return one file result at a time, you can use multiple calls to controller for multiple images.



            //changed part
            return File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);

            public FileResult Download()

            //this is a string contains 3name of image and i give each of them with this
            way
            string imgname = user.Original_images.Split(',');
            foreach (var item3 in imgname)

            string url2 = "my URL" +
            + item3 + ".jpg";

            //i download image successfully
            webclient.Headers["Authorization"] = "Basic " +
            Convert.ToBase64String(
            Encoding.Default.GetBytes("Username:password"));

            byte data = webclient.DownloadData(url2);

            //i don't know what should i do after this...
            return File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);









            share|improve this answer













            You can use FileResult action:



            Remember you can only return one file result at a time, you can use multiple calls to controller for multiple images.



            //changed part
            return File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);

            public FileResult Download()

            //this is a string contains 3name of image and i give each of them with this
            way
            string imgname = user.Original_images.Split(',');
            foreach (var item3 in imgname)

            string url2 = "my URL" +
            + item3 + ".jpg";

            //i download image successfully
            webclient.Headers["Authorization"] = "Basic " +
            Convert.ToBase64String(
            Encoding.Default.GetBytes("Username:password"));

            byte data = webclient.DownloadData(url2);

            //i don't know what should i do after this...
            return File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);










            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 12 '18 at 7:17









            Just codeJust code

            10.4k53066




            10.4k53066












            • The code I wrote is in the middle of a method and i can't have return,and when i write this : user.img=File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);[user is an object of my viewmodel and the type of img is "object" ] but when i want show user.img in razor i see this ContentType application/octet-stream FileDownloadName !!

              – Zohreh Zamani
              Nov 12 '18 at 7:35












            • You can use controller to action method to retrieve the image.

              – Just code
              Nov 12 '18 at 7:55

















            • The code I wrote is in the middle of a method and i can't have return,and when i write this : user.img=File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);[user is an object of my viewmodel and the type of img is "object" ] but when i want show user.img in razor i see this ContentType application/octet-stream FileDownloadName !!

              – Zohreh Zamani
              Nov 12 '18 at 7:35












            • You can use controller to action method to retrieve the image.

              – Just code
              Nov 12 '18 at 7:55
















            The code I wrote is in the middle of a method and i can't have return,and when i write this : user.img=File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);[user is an object of my viewmodel and the type of img is "object" ] but when i want show user.img in razor i see this ContentType application/octet-stream FileDownloadName !!

            – Zohreh Zamani
            Nov 12 '18 at 7:35






            The code I wrote is in the middle of a method and i can't have return,and when i write this : user.img=File(data , System.Net.Mime.MediaTypeNames.Application.Octet, item3);[user is an object of my viewmodel and the type of img is "object" ] but when i want show user.img in razor i see this ContentType application/octet-stream FileDownloadName !!

            – Zohreh Zamani
            Nov 12 '18 at 7:35














            You can use controller to action method to retrieve the image.

            – Just code
            Nov 12 '18 at 7:55





            You can use controller to action method to retrieve the image.

            – Just code
            Nov 12 '18 at 7:55













            0














            i solve my question



             string imgname = user.Original_images.Split(',');
            foreach (var item3 in imgname)

            string url2 = "my URL" +
            + item3 + ".jpg";

            //i download image successfully
            webclient.Headers["Authorization"] = "Basic " +
            Convert.ToBase64String(
            Encoding.Default.GetBytes("Username:password"));

            byte data = webclient.DownloadData(url2);

            //this is new
            string imageBase64Data = Convert.ToBase64String(imageByteData);
            string imageDataURL = string.Format("data:image/jpg;base64,0",
            imageBase64Data);
            ViewBag.ImageData = imageDataURL;



            and in razor i have this



            <img src="@ViewBag.ImageData" />





            share|improve this answer



























              0














              i solve my question



               string imgname = user.Original_images.Split(',');
              foreach (var item3 in imgname)

              string url2 = "my URL" +
              + item3 + ".jpg";

              //i download image successfully
              webclient.Headers["Authorization"] = "Basic " +
              Convert.ToBase64String(
              Encoding.Default.GetBytes("Username:password"));

              byte data = webclient.DownloadData(url2);

              //this is new
              string imageBase64Data = Convert.ToBase64String(imageByteData);
              string imageDataURL = string.Format("data:image/jpg;base64,0",
              imageBase64Data);
              ViewBag.ImageData = imageDataURL;



              and in razor i have this



              <img src="@ViewBag.ImageData" />





              share|improve this answer

























                0












                0








                0







                i solve my question



                 string imgname = user.Original_images.Split(',');
                foreach (var item3 in imgname)

                string url2 = "my URL" +
                + item3 + ".jpg";

                //i download image successfully
                webclient.Headers["Authorization"] = "Basic " +
                Convert.ToBase64String(
                Encoding.Default.GetBytes("Username:password"));

                byte data = webclient.DownloadData(url2);

                //this is new
                string imageBase64Data = Convert.ToBase64String(imageByteData);
                string imageDataURL = string.Format("data:image/jpg;base64,0",
                imageBase64Data);
                ViewBag.ImageData = imageDataURL;



                and in razor i have this



                <img src="@ViewBag.ImageData" />





                share|improve this answer













                i solve my question



                 string imgname = user.Original_images.Split(',');
                foreach (var item3 in imgname)

                string url2 = "my URL" +
                + item3 + ".jpg";

                //i download image successfully
                webclient.Headers["Authorization"] = "Basic " +
                Convert.ToBase64String(
                Encoding.Default.GetBytes("Username:password"));

                byte data = webclient.DownloadData(url2);

                //this is new
                string imageBase64Data = Convert.ToBase64String(imageByteData);
                string imageDataURL = string.Format("data:image/jpg;base64,0",
                imageBase64Data);
                ViewBag.ImageData = imageDataURL;



                and in razor i have this



                <img src="@ViewBag.ImageData" />






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 12 '18 at 7:49









                Zohreh ZamaniZohreh Zamani

                84




                84



























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