The rate at which the value of a definite integral increases

The rate at which the value of a definite integral increases



Say I had a function $f(x) = x^2$ ,how could I find the rate at which $$int_0^ax^2dx$$ increases for $a$, or more generally for any function.



Also, is this equivalent to $fracddaf(x)$?





$begingroup$
math.stackexchange.com/questions/1261432/…
$endgroup$
– Ahmed S. Attaalla
Sep 9 '18 at 6:44




1 Answer
1



Use the fact that



$$int_0^ax^2dx=frac13a^3$$



More generally,



$$fracddtint_a(t)^b(t)f(x)dx=fracddt(F(b(t))-F(a(t)))=b'(t)f(b(t))-a'(t)f(a(t))$$



where $F(t)$ is the anti-derivative of $F$, i.e. $F'=f$. Note that you don't need to know $F$ to calculate the derivative of an integral with varying bounds with respect to the variable $t$.



Thanks for contributing an answer to Mathematics Stack Exchange!



But avoid …



Use MathJax to format equations. MathJax reference.



To learn more, see our tips on writing great answers.



Required, but never shown



Required, but never shown




By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.

Popular posts from this blog

Malaysia to Papua New Guinea by motorcycle?

.name

List of Bhojpuri films