How to search for contacts in android with partial phone number

How to search for contacts in android with partial phone number



I am trying to do fuzzy search of contacts in my android application with partial phone number, with below code. But my search function always ends in no result.



For example,



I have contact with phone number 1234567890 with name as "example".



fuzzySearch("4567"); should have return with contact named "example".


fuzzySearch("4567");



Can some please point me where am I wrong? I have checked here. But ended in run-time sql query error.


public ArrayList<Contact> fuzzySearch(String match)
private static final String SELECTION = Phone.NUMBER + " LIKE ? COLLATE NOCASE";

Uri uri = Uri.withAppendedPath(ContactsContract.CommonDataKinds.Phone.CONTENT_FILTER_URI, Uri.encode(match));

String projectionFields = new StringContactsContract.Contacts._ID, Phone.NUMBER;

CursorLoader cursorLoader = null;

ArrayList<Contact> listContacts = new ArrayList<>();

if(match.trim().length() == 0)
return listContacts;
else
cursorLoader = new CursorLoader(context, uri, projectionFields, SELECTION, new String"%"+match+"%", Phone.NUMBER);


Cursor c = cursorLoader.loadInBackground();

final Map<String, Contact> contactsMap = new HashMap<>(c.getCount());

if (c.moveToFirst())
int idIndex = c.getColumnIndex(ContactsContract.Contacts._ID);
int nameIndex = c.getColumnIndex(Phone.NUMBER);

do
String contactId = c.getString(idIndex);
String contactDisplayName = c.getString(nameIndex);
Contact contact = new Contact(contactId, contactDisplayName);
contactsMap.put(contactId, contact);
listContacts.add(contact);
while (c.moveToNext());


c.close();
return listContacts;




1 Answer
1



use PhoneLookup instead of phone.
because you already encode the search key into the URL, you don't need SELECTION, remove it.


Uri uri = Uri.withAppendedPath(PhoneLookup.CONTENT_FILTER_URI, Uri.encode(match));
Cursor cur = resolver.query(uri, new StringPhoneLookup.DISPLAY_NAME,PhoneLookup.NUMBER, PhoneLookup.CONTACT_ID, null, null, null);






I tried this, but did not work :(

– Sandy
Sep 10 '18 at 5:42



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