How do I create multiple answers in the output?

I have written a small bit of code that computes on equation for the given number, x. But, when I want to try and duplicate this code it doesn't work. It says "redeclaration of result with no linkage." What I want to do is make an output in the console for when x=0, x=10 and x=-10. Here is my code:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <math.h>
int main()

float x = 0.0, result;
result = 1/(1+exp(x));
printf("Exponential of %f = %f", x, result);
return 0;



It works for just one, but when I duplicate it won't work. What I want to do is just duplicate that so it outputs three calculations for the numbers in the console. Thank you <3

3 Answers
3

"redeclaration" means you make copy of line

float x = 0.0, result;


if you want just to make from

float x = 0.0, result;
result = 1/(1+exp(x));
printf("Exponential of %f = %f", x, result);


something to calculate result for different x, jut make as follows:

x

float x = 0.0, result; // declaration - only once
result = 1/(1+exp(x));
printf("Exponential of %f = %f", x, result);
x = 0.5; // new value for the same variable
result = 1/(1+exp(x)); // new value for the same variable
printf("Exponential of %f = %f", x, result);


Also consider making of loop to exclude copying the code. Common approach is like:

x

start

end

for

while

dowhile

float x = 0.0
printf("Exponential of %f = %fn", x, 1/(1+exp(x));

x = 10.0
printf("Exponential of %f = %fn", x, 1/(1+exp(x));

x = -10.0
printf("Exponential of %f = %fn", x, 1/(1+exp(x));


In c language, you cannot redeclare a variable, but you can re-assign variable.

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <math.h>
int main()

float x = 0.0, result;
result = 1/(1+exp(x));
printf("Exponential of %f = %fn", x, result);

x=10.0;
result = 1/(1+exp(x));
printf("Exponential of %f = %fn", x, result);

x=-10.0;
result = 1/(1+exp(x));
printf("Exponential of %f = %fn", x, result);

return 0;



Hope this helped.

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