How to add polygon properly in leaflet.js
When using leaflet.js to render polygon.
The following examples have different results.
Example 1
const map = L.map('map',
preferCanvas: true,
zoomControl: false,
attributionControl: false
);
const latlngs = [
[
6,
5
],
[
7,
1
],
[
9,
2
]
];
const polygon = L.polygon(latlngs, color: 'red').addTo(map);
map.fitBounds(polygon.getBounds());
Example 2
...
const latlngs = [
[
116,
115
],
[
117,
111
],
[
119,
112
]
];
const polygon = L.polygon(latlngs, color: 'red').addTo(map);
map.fitBounds(polygon.getBounds());
Why is that?
And what can I do if I have to set latlngs data like Example 2.
leaflet
asked Nov 11 '18 at 8:52
Jesse LuoJesse Luo
355
add a comment |
When using leaflet.js to render polygon.
The following examples have different results.
Example 1
const map = L.map('map',
preferCanvas: true,
zoomControl: false,
attributionControl: false
);
const latlngs = [
[
6,
5
],
[
7,
1
],
[
9,
2
]
];
const polygon = L.polygon(latlngs, color: 'red').addTo(map);
map.fitBounds(polygon.getBounds());
Example 2
...
const latlngs = [
[
116,
115
],
[
117,
111
],
[
119,
112
]
];
const polygon = L.polygon(latlngs, color: 'red').addTo(map);
map.fitBounds(polygon.getBounds());
Why is that?
And what can I do if I have to set latlngs data like Example 2.
leaflet
asked Nov 11 '18 at 8:52
Jesse LuoJesse Luo
355
add a comment |
When using leaflet.js to render polygon.
The following examples have different results.
Example 1
const map = L.map('map',
preferCanvas: true,
zoomControl: false,
attributionControl: false
);
const latlngs = [
[
6,
5
],
[
7,
1
],
[
9,
2
]
];
const polygon = L.polygon(latlngs, color: 'red').addTo(map);
map.fitBounds(polygon.getBounds());
Example 2
...
const latlngs = [
[
116,
115
],
[
117,
111
],
[
119,
112
]
];
const polygon = L.polygon(latlngs, color: 'red').addTo(map);
map.fitBounds(polygon.getBounds());
Why is that?
And what can I do if I have to set latlngs data like Example 2.
leaflet
asked Nov 11 '18 at 8:52
Jesse LuoJesse Luo
355
When using leaflet.js to render polygon.
The following examples have different results.
Example 1
const map = L.map('map',
preferCanvas: true,
zoomControl: false,
attributionControl: false
);
const latlngs = [
[
6,
5
],
[
7,
1
],
[
9,
2
]
];
const polygon = L.polygon(latlngs, color: 'red').addTo(map);
map.fitBounds(polygon.getBounds());
Example 2
...
const latlngs = [
[
116,
115
],
[
117,
111
],
[
119,
112
]
];
const polygon = L.polygon(latlngs, color: 'red').addTo(map);
map.fitBounds(polygon.getBounds());
Why is that?
And what can I do if I have to set latlngs data like Example 2.
leaflet
leaflet
asked Nov 11 '18 at 8:52
Jesse LuoJesse Luo
355
asked Nov 11 '18 at 8:52
Jesse LuoJesse Luo
355
asked Nov 11 '18 at 8:52
Jesse LuoJesse Luo
355
asked Nov 11 '18 at 8:52
Jesse LuoJesse Luo
355
asked Nov 11 '18 at 8:52
Jesse LuoJesse Luo
355
355
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
The reason is that Leaflet uses latitude and longitude by default and projects it on a plane using a Web Mercator projection. On your second polygon, the coordinates are out of bounds for latitude.
If you just need to draw a triangle in "pixel" coordinates, you can use CRS.Simple.
const map = L.map('map',
preferCanvas: true,
zoomControl: false,
attributionControl: false,
// Add this line:
crs: L.CRS.Simple
);
See JSFiddle: http://jsfiddle.net/ekqvwo76/
answered Nov 11 '18 at 9:07
thibautgthibautg
1,0291510
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The reason is that Leaflet uses latitude and longitude by default and projects it on a plane using a Web Mercator projection. On your second polygon, the coordinates are out of bounds for latitude.
If you just need to draw a triangle in "pixel" coordinates, you can use CRS.Simple.
const map = L.map('map',
preferCanvas: true,
zoomControl: false,
attributionControl: false,
// Add this line:
crs: L.CRS.Simple
);
See JSFiddle: http://jsfiddle.net/ekqvwo76/
answered Nov 11 '18 at 9:07
thibautgthibautg
1,0291510
add a comment |
The reason is that Leaflet uses latitude and longitude by default and projects it on a plane using a Web Mercator projection. On your second polygon, the coordinates are out of bounds for latitude.
If you just need to draw a triangle in "pixel" coordinates, you can use CRS.Simple.
const map = L.map('map',
preferCanvas: true,
zoomControl: false,
attributionControl: false,
// Add this line:
crs: L.CRS.Simple
);
See JSFiddle: http://jsfiddle.net/ekqvwo76/
answered Nov 11 '18 at 9:07
thibautgthibautg
1,0291510
add a comment |
The reason is that Leaflet uses latitude and longitude by default and projects it on a plane using a Web Mercator projection. On your second polygon, the coordinates are out of bounds for latitude.
If you just need to draw a triangle in "pixel" coordinates, you can use CRS.Simple.
const map = L.map('map',
preferCanvas: true,
zoomControl: false,
attributionControl: false,
// Add this line:
crs: L.CRS.Simple
);
See JSFiddle: http://jsfiddle.net/ekqvwo76/
answered Nov 11 '18 at 9:07
thibautgthibautg
1,0291510
The reason is that Leaflet uses latitude and longitude by default and projects it on a plane using a Web Mercator projection. On your second polygon, the coordinates are out of bounds for latitude.
If you just need to draw a triangle in "pixel" coordinates, you can use CRS.Simple.
const map = L.map('map',
preferCanvas: true,
zoomControl: false,
attributionControl: false,
// Add this line:
crs: L.CRS.Simple
);
See JSFiddle: http://jsfiddle.net/ekqvwo76/
answered Nov 11 '18 at 9:07
thibautgthibautg
1,0291510
answered Nov 11 '18 at 9:07
thibautgthibautg
1,0291510
answered Nov 11 '18 at 9:07
thibautgthibautg
1,0291510
answered Nov 11 '18 at 9:07
thibautgthibautg
1,0291510
1,0291510
add a comment |
add a comment |
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