unable to properly escape double quotes in curl command in .bat file










1














I have the following curl command to upload a file to a cloud API.



curl -k -w %http_code -H "Content-Type:text/plain" --data-binary @\pathtofile.txt https://api.somesite.com/endpoint


This curl command works fine if I enter it into a cmd console directly. I need to get it working in a batch file, but when I put the command in the batch file as is, it cannot parse the command (no URL specified). This appears to be due to the double quotes around "Content-Type:text/plain". Having that in the command is critical to the api being able to process my file.



Based on the answers from this question I have tried a few different ways of escaping the double quotes. These are the results of various methods.



^"Content-Type:text/plain^" 


This does not upload the file, curl error: no URL specified!



"Content-Type:text/plain"


This uploads the file, curl reports success, but the api cannot recognize the file as plain text.



""Content-Type:text/plain""


This uploads the file, curl reports success, but the api cannot recognize the file as plain text.



""Content-Type:text/plain""


This does not upload the file, curl error: no URL specified!



So I have found many ways to fail but no combination that works for batch, curl and the api together. Are there other methods of escaping I can try or any other suggestions?










share|improve this question

















  • 2




    IMO the problem is elsewhere, you'll have to double the %% and I'd double quote nearly all args curl -k -w %%http_code -H "Content-Type:text/plain" --data-binary "@\pathtofile.txt" "https://api.somesite.com/endpoint"
    – LotPings
    Nov 9 at 20:06















1














I have the following curl command to upload a file to a cloud API.



curl -k -w %http_code -H "Content-Type:text/plain" --data-binary @\pathtofile.txt https://api.somesite.com/endpoint


This curl command works fine if I enter it into a cmd console directly. I need to get it working in a batch file, but when I put the command in the batch file as is, it cannot parse the command (no URL specified). This appears to be due to the double quotes around "Content-Type:text/plain". Having that in the command is critical to the api being able to process my file.



Based on the answers from this question I have tried a few different ways of escaping the double quotes. These are the results of various methods.



^"Content-Type:text/plain^" 


This does not upload the file, curl error: no URL specified!



"Content-Type:text/plain"


This uploads the file, curl reports success, but the api cannot recognize the file as plain text.



""Content-Type:text/plain""


This uploads the file, curl reports success, but the api cannot recognize the file as plain text.



""Content-Type:text/plain""


This does not upload the file, curl error: no URL specified!



So I have found many ways to fail but no combination that works for batch, curl and the api together. Are there other methods of escaping I can try or any other suggestions?










share|improve this question

















  • 2




    IMO the problem is elsewhere, you'll have to double the %% and I'd double quote nearly all args curl -k -w %%http_code -H "Content-Type:text/plain" --data-binary "@\pathtofile.txt" "https://api.somesite.com/endpoint"
    – LotPings
    Nov 9 at 20:06













1












1








1







I have the following curl command to upload a file to a cloud API.



curl -k -w %http_code -H "Content-Type:text/plain" --data-binary @\pathtofile.txt https://api.somesite.com/endpoint


This curl command works fine if I enter it into a cmd console directly. I need to get it working in a batch file, but when I put the command in the batch file as is, it cannot parse the command (no URL specified). This appears to be due to the double quotes around "Content-Type:text/plain". Having that in the command is critical to the api being able to process my file.



Based on the answers from this question I have tried a few different ways of escaping the double quotes. These are the results of various methods.



^"Content-Type:text/plain^" 


This does not upload the file, curl error: no URL specified!



"Content-Type:text/plain"


This uploads the file, curl reports success, but the api cannot recognize the file as plain text.



""Content-Type:text/plain""


This uploads the file, curl reports success, but the api cannot recognize the file as plain text.



""Content-Type:text/plain""


This does not upload the file, curl error: no URL specified!



So I have found many ways to fail but no combination that works for batch, curl and the api together. Are there other methods of escaping I can try or any other suggestions?










share|improve this question













I have the following curl command to upload a file to a cloud API.



curl -k -w %http_code -H "Content-Type:text/plain" --data-binary @\pathtofile.txt https://api.somesite.com/endpoint


This curl command works fine if I enter it into a cmd console directly. I need to get it working in a batch file, but when I put the command in the batch file as is, it cannot parse the command (no URL specified). This appears to be due to the double quotes around "Content-Type:text/plain". Having that in the command is critical to the api being able to process my file.



Based on the answers from this question I have tried a few different ways of escaping the double quotes. These are the results of various methods.



^"Content-Type:text/plain^" 


This does not upload the file, curl error: no URL specified!



"Content-Type:text/plain"


This uploads the file, curl reports success, but the api cannot recognize the file as plain text.



""Content-Type:text/plain""


This uploads the file, curl reports success, but the api cannot recognize the file as plain text.



""Content-Type:text/plain""


This does not upload the file, curl error: no URL specified!



So I have found many ways to fail but no combination that works for batch, curl and the api together. Are there other methods of escaping I can try or any other suggestions?







batch-file curl






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 9 at 19:49









Anonymous Man

6802628




6802628







  • 2




    IMO the problem is elsewhere, you'll have to double the %% and I'd double quote nearly all args curl -k -w %%http_code -H "Content-Type:text/plain" --data-binary "@\pathtofile.txt" "https://api.somesite.com/endpoint"
    – LotPings
    Nov 9 at 20:06












  • 2




    IMO the problem is elsewhere, you'll have to double the %% and I'd double quote nearly all args curl -k -w %%http_code -H "Content-Type:text/plain" --data-binary "@\pathtofile.txt" "https://api.somesite.com/endpoint"
    – LotPings
    Nov 9 at 20:06







2




2




IMO the problem is elsewhere, you'll have to double the %% and I'd double quote nearly all args curl -k -w %%http_code -H "Content-Type:text/plain" --data-binary "@\pathtofile.txt" "https://api.somesite.com/endpoint"
– LotPings
Nov 9 at 20:06




IMO the problem is elsewhere, you'll have to double the %% and I'd double quote nearly all args curl -k -w %%http_code -H "Content-Type:text/plain" --data-binary "@\pathtofile.txt" "https://api.somesite.com/endpoint"
– LotPings
Nov 9 at 20:06












1 Answer
1






active

oldest

votes


















2














Your problem are not the quotes, but the percent sign.



Inside a batch file, a percent sign that are not part of a value retrieve operation but a literal needs to be escaped by doubling them.



Try with



curl -k -w %%http_code -H "Content-Type:text/plain" --data-binary @\pathtofile.txt https://api.somesite.com/endpoint


The cmd parser sees the single % as the start of a variable value request and the text after the percent sign is seen as the variable name.



curl -k -w %http_code -H "Content-Type:text/plain" ....
^............................^
this is a failed variable retrieval operation


And this happens both in command line and inside batch files, but the default behaviour for non declared variables is different in both cases. In command line if we request a variable and it does not exist then the parser keeps the variable name, but inside batch files the parser replaces the variable request with an empty string.






share|improve this answer






















    Your Answer






    StackExchange.ifUsing("editor", function ()
    StackExchange.using("externalEditor", function ()
    StackExchange.using("snippets", function ()
    StackExchange.snippets.init();
    );
    );
    , "code-snippets");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "1"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53232397%2funable-to-properly-escape-double-quotes-in-curl-command-in-bat-file%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    Your problem are not the quotes, but the percent sign.



    Inside a batch file, a percent sign that are not part of a value retrieve operation but a literal needs to be escaped by doubling them.



    Try with



    curl -k -w %%http_code -H "Content-Type:text/plain" --data-binary @\pathtofile.txt https://api.somesite.com/endpoint


    The cmd parser sees the single % as the start of a variable value request and the text after the percent sign is seen as the variable name.



    curl -k -w %http_code -H "Content-Type:text/plain" ....
    ^............................^
    this is a failed variable retrieval operation


    And this happens both in command line and inside batch files, but the default behaviour for non declared variables is different in both cases. In command line if we request a variable and it does not exist then the parser keeps the variable name, but inside batch files the parser replaces the variable request with an empty string.






    share|improve this answer



























      2














      Your problem are not the quotes, but the percent sign.



      Inside a batch file, a percent sign that are not part of a value retrieve operation but a literal needs to be escaped by doubling them.



      Try with



      curl -k -w %%http_code -H "Content-Type:text/plain" --data-binary @\pathtofile.txt https://api.somesite.com/endpoint


      The cmd parser sees the single % as the start of a variable value request and the text after the percent sign is seen as the variable name.



      curl -k -w %http_code -H "Content-Type:text/plain" ....
      ^............................^
      this is a failed variable retrieval operation


      And this happens both in command line and inside batch files, but the default behaviour for non declared variables is different in both cases. In command line if we request a variable and it does not exist then the parser keeps the variable name, but inside batch files the parser replaces the variable request with an empty string.






      share|improve this answer

























        2












        2








        2






        Your problem are not the quotes, but the percent sign.



        Inside a batch file, a percent sign that are not part of a value retrieve operation but a literal needs to be escaped by doubling them.



        Try with



        curl -k -w %%http_code -H "Content-Type:text/plain" --data-binary @\pathtofile.txt https://api.somesite.com/endpoint


        The cmd parser sees the single % as the start of a variable value request and the text after the percent sign is seen as the variable name.



        curl -k -w %http_code -H "Content-Type:text/plain" ....
        ^............................^
        this is a failed variable retrieval operation


        And this happens both in command line and inside batch files, but the default behaviour for non declared variables is different in both cases. In command line if we request a variable and it does not exist then the parser keeps the variable name, but inside batch files the parser replaces the variable request with an empty string.






        share|improve this answer














        Your problem are not the quotes, but the percent sign.



        Inside a batch file, a percent sign that are not part of a value retrieve operation but a literal needs to be escaped by doubling them.



        Try with



        curl -k -w %%http_code -H "Content-Type:text/plain" --data-binary @\pathtofile.txt https://api.somesite.com/endpoint


        The cmd parser sees the single % as the start of a variable value request and the text after the percent sign is seen as the variable name.



        curl -k -w %http_code -H "Content-Type:text/plain" ....
        ^............................^
        this is a failed variable retrieval operation


        And this happens both in command line and inside batch files, but the default behaviour for non declared variables is different in both cases. In command line if we request a variable and it does not exist then the parser keeps the variable name, but inside batch files the parser replaces the variable request with an empty string.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 9 at 20:13

























        answered Nov 9 at 20:06









        MC ND

        58.2k54778




        58.2k54778



























            draft saved

            draft discarded
















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            To learn more, see our tips on writing great answers.





            Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


            Please pay close attention to the following guidance:


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53232397%2funable-to-properly-escape-double-quotes-in-curl-command-in-bat-file%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            𛂒𛀶,𛀽𛀑𛂀𛃧𛂓𛀙𛃆𛃑𛃷𛂟𛁡𛀢𛀟𛁤𛂽𛁕𛁪𛂟𛂯,𛁞𛂧𛀴𛁄𛁠𛁼𛂿𛀤 𛂘,𛁺𛂾𛃭𛃭𛃵𛀺,𛂣𛃍𛂖𛃶 𛀸𛃀𛂖𛁶𛁏𛁚 𛂢𛂞 𛁰𛂆𛀔,𛁸𛀽𛁓𛃋𛂇𛃧𛀧𛃣𛂐𛃇,𛂂𛃻𛃲𛁬𛃞𛀧𛃃𛀅 𛂭𛁠𛁡𛃇𛀷𛃓𛁥,𛁙𛁘𛁞𛃸𛁸𛃣𛁜,𛂛,𛃿,𛁯𛂘𛂌𛃛𛁱𛃌𛂈𛂇 𛁊𛃲,𛀕𛃴𛀜 𛀶𛂆𛀶𛃟𛂉𛀣,𛂐𛁞𛁾 𛁷𛂑𛁳𛂯𛀬𛃅,𛃶𛁼

            ャフサォクコ ケウ,コ,ワ メ,ロスョノ゙,クネ,フムカヤヲニ,エコ゚ツ ウイオン゙ケワサネォキモュキォウイノンコチ゚メヌナイゥフュ,カヒウネェ ネ,ホノケ,ムュキ ッボーミュハ,チ ツス ィ メウイマヤ,゙ウチ ヅ ロ,ォジヌェ ャヌット ェ,マャ,チナエヒネソキツテ トホヲヲミーァ

            Node.js puppeteer - Use values from array in a loop to cycle through pages