Ipv6 address format from struct.unpack










1














What would be the way to unpack and map to ipv6 address. I'm currently doing the following



In [3]: struct.unpack("!h",'*x00')
Out[3]: (10752,)

In [5]: ipaddress.IPv6Address(10752)
Out[5]: IPv6Address(u'::2a00')


but of course the end result i wish for is 2a00:: , i was expecting IPv6Address to return it but i'm missing something.



What i'm currently doing is unpacking as sting then to hex and append :: .



In [14]: struct.unpack("!2s",'*x00')
Out[14]: ('*x00',)

In [15]: '*x00'.encode("hex")
Out[15]: '2a00'

then append to hex and append

In [16]: '*x00'.encode("hex")+'::'
Out[16]: '2a00::'









share|improve this question





















  • I'm not following why you expect 2a00, that would be 55827575822966466661959896531774472192 (so shift it with 112 bits) that maps on 2a00::, since you could say that an IP address is "little endian"
    – Willem Van Onsem
    Nov 9 at 19:48











  • thanks for that. was hopping rather than expecting to be honest.what would be the way to shift this ? any module i can use.
    – Cmarv
    Nov 9 at 19:54










  • Just use binary operators, so ipaddress.IPv6Address(10752<<112), but note that this trick will only work for numbers up to 2^16 (65'536), since otherwise the value is "too large".
    – Willem Van Onsem
    Nov 9 at 19:55
















1














What would be the way to unpack and map to ipv6 address. I'm currently doing the following



In [3]: struct.unpack("!h",'*x00')
Out[3]: (10752,)

In [5]: ipaddress.IPv6Address(10752)
Out[5]: IPv6Address(u'::2a00')


but of course the end result i wish for is 2a00:: , i was expecting IPv6Address to return it but i'm missing something.



What i'm currently doing is unpacking as sting then to hex and append :: .



In [14]: struct.unpack("!2s",'*x00')
Out[14]: ('*x00',)

In [15]: '*x00'.encode("hex")
Out[15]: '2a00'

then append to hex and append

In [16]: '*x00'.encode("hex")+'::'
Out[16]: '2a00::'









share|improve this question





















  • I'm not following why you expect 2a00, that would be 55827575822966466661959896531774472192 (so shift it with 112 bits) that maps on 2a00::, since you could say that an IP address is "little endian"
    – Willem Van Onsem
    Nov 9 at 19:48











  • thanks for that. was hopping rather than expecting to be honest.what would be the way to shift this ? any module i can use.
    – Cmarv
    Nov 9 at 19:54










  • Just use binary operators, so ipaddress.IPv6Address(10752<<112), but note that this trick will only work for numbers up to 2^16 (65'536), since otherwise the value is "too large".
    – Willem Van Onsem
    Nov 9 at 19:55














1












1








1







What would be the way to unpack and map to ipv6 address. I'm currently doing the following



In [3]: struct.unpack("!h",'*x00')
Out[3]: (10752,)

In [5]: ipaddress.IPv6Address(10752)
Out[5]: IPv6Address(u'::2a00')


but of course the end result i wish for is 2a00:: , i was expecting IPv6Address to return it but i'm missing something.



What i'm currently doing is unpacking as sting then to hex and append :: .



In [14]: struct.unpack("!2s",'*x00')
Out[14]: ('*x00',)

In [15]: '*x00'.encode("hex")
Out[15]: '2a00'

then append to hex and append

In [16]: '*x00'.encode("hex")+'::'
Out[16]: '2a00::'









share|improve this question













What would be the way to unpack and map to ipv6 address. I'm currently doing the following



In [3]: struct.unpack("!h",'*x00')
Out[3]: (10752,)

In [5]: ipaddress.IPv6Address(10752)
Out[5]: IPv6Address(u'::2a00')


but of course the end result i wish for is 2a00:: , i was expecting IPv6Address to return it but i'm missing something.



What i'm currently doing is unpacking as sting then to hex and append :: .



In [14]: struct.unpack("!2s",'*x00')
Out[14]: ('*x00',)

In [15]: '*x00'.encode("hex")
Out[15]: '2a00'

then append to hex and append

In [16]: '*x00'.encode("hex")+'::'
Out[16]: '2a00::'






python struct






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 9 at 19:44









Cmarv

375




375











  • I'm not following why you expect 2a00, that would be 55827575822966466661959896531774472192 (so shift it with 112 bits) that maps on 2a00::, since you could say that an IP address is "little endian"
    – Willem Van Onsem
    Nov 9 at 19:48











  • thanks for that. was hopping rather than expecting to be honest.what would be the way to shift this ? any module i can use.
    – Cmarv
    Nov 9 at 19:54










  • Just use binary operators, so ipaddress.IPv6Address(10752<<112), but note that this trick will only work for numbers up to 2^16 (65'536), since otherwise the value is "too large".
    – Willem Van Onsem
    Nov 9 at 19:55

















  • I'm not following why you expect 2a00, that would be 55827575822966466661959896531774472192 (so shift it with 112 bits) that maps on 2a00::, since you could say that an IP address is "little endian"
    – Willem Van Onsem
    Nov 9 at 19:48











  • thanks for that. was hopping rather than expecting to be honest.what would be the way to shift this ? any module i can use.
    – Cmarv
    Nov 9 at 19:54










  • Just use binary operators, so ipaddress.IPv6Address(10752<<112), but note that this trick will only work for numbers up to 2^16 (65'536), since otherwise the value is "too large".
    – Willem Van Onsem
    Nov 9 at 19:55
















I'm not following why you expect 2a00, that would be 55827575822966466661959896531774472192 (so shift it with 112 bits) that maps on 2a00::, since you could say that an IP address is "little endian"
– Willem Van Onsem
Nov 9 at 19:48





I'm not following why you expect 2a00, that would be 55827575822966466661959896531774472192 (so shift it with 112 bits) that maps on 2a00::, since you could say that an IP address is "little endian"
– Willem Van Onsem
Nov 9 at 19:48













thanks for that. was hopping rather than expecting to be honest.what would be the way to shift this ? any module i can use.
– Cmarv
Nov 9 at 19:54




thanks for that. was hopping rather than expecting to be honest.what would be the way to shift this ? any module i can use.
– Cmarv
Nov 9 at 19:54












Just use binary operators, so ipaddress.IPv6Address(10752<<112), but note that this trick will only work for numbers up to 2^16 (65'536), since otherwise the value is "too large".
– Willem Van Onsem
Nov 9 at 19:55





Just use binary operators, so ipaddress.IPv6Address(10752<<112), but note that this trick will only work for numbers up to 2^16 (65'536), since otherwise the value is "too large".
– Willem Van Onsem
Nov 9 at 19:55













1 Answer
1






active

oldest

votes


















2














The IP adress converts what we could see as a binary number into a 128-bit representation with hexadecimal numbers (and some other logic to compress zero sequenes).



The number 10752 is equivalent to:



00 00 00 00 00 00 00 (hex)
00 00 00 00 00 2a 00

00000000 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00101010 00000000


or thus with colons in between:



0000:0000:0000:0000:0000:0000:0000:2a00


and this is actually what you get. IPv6 addresses use double colons to strip of sequences of zero.



If we shift the value however 112 places up (128-16), we thus get:



2a 00 00 00 00 00 00 (hex)
00 00 00 00 00 00 00

00101010 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00000000 00000000


which is thus:



2a00:0000:0000:0000:0000:0000:0000:0000


so we can obtain the desired output with:



>>> ipaddress.IPv6Address(10752<<112)
IPv6Address('2a00::')


Note that the above however will only work if the data is less than 216=65'536, since otherwise it takes more than 16 bits, and then the value is too large to get represented by an IPv6 address.






share|improve this answer




















  • thanks for explaining and providing a solution !!
    – Cmarv
    Nov 9 at 20:03










Your Answer






StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);













draft saved

draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53232339%2fipv6-address-format-from-struct-unpack%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














The IP adress converts what we could see as a binary number into a 128-bit representation with hexadecimal numbers (and some other logic to compress zero sequenes).



The number 10752 is equivalent to:



00 00 00 00 00 00 00 (hex)
00 00 00 00 00 2a 00

00000000 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00101010 00000000


or thus with colons in between:



0000:0000:0000:0000:0000:0000:0000:2a00


and this is actually what you get. IPv6 addresses use double colons to strip of sequences of zero.



If we shift the value however 112 places up (128-16), we thus get:



2a 00 00 00 00 00 00 (hex)
00 00 00 00 00 00 00

00101010 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00000000 00000000


which is thus:



2a00:0000:0000:0000:0000:0000:0000:0000


so we can obtain the desired output with:



>>> ipaddress.IPv6Address(10752<<112)
IPv6Address('2a00::')


Note that the above however will only work if the data is less than 216=65'536, since otherwise it takes more than 16 bits, and then the value is too large to get represented by an IPv6 address.






share|improve this answer




















  • thanks for explaining and providing a solution !!
    – Cmarv
    Nov 9 at 20:03















2














The IP adress converts what we could see as a binary number into a 128-bit representation with hexadecimal numbers (and some other logic to compress zero sequenes).



The number 10752 is equivalent to:



00 00 00 00 00 00 00 (hex)
00 00 00 00 00 2a 00

00000000 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00101010 00000000


or thus with colons in between:



0000:0000:0000:0000:0000:0000:0000:2a00


and this is actually what you get. IPv6 addresses use double colons to strip of sequences of zero.



If we shift the value however 112 places up (128-16), we thus get:



2a 00 00 00 00 00 00 (hex)
00 00 00 00 00 00 00

00101010 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00000000 00000000


which is thus:



2a00:0000:0000:0000:0000:0000:0000:0000


so we can obtain the desired output with:



>>> ipaddress.IPv6Address(10752<<112)
IPv6Address('2a00::')


Note that the above however will only work if the data is less than 216=65'536, since otherwise it takes more than 16 bits, and then the value is too large to get represented by an IPv6 address.






share|improve this answer




















  • thanks for explaining and providing a solution !!
    – Cmarv
    Nov 9 at 20:03













2












2








2






The IP adress converts what we could see as a binary number into a 128-bit representation with hexadecimal numbers (and some other logic to compress zero sequenes).



The number 10752 is equivalent to:



00 00 00 00 00 00 00 (hex)
00 00 00 00 00 2a 00

00000000 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00101010 00000000


or thus with colons in between:



0000:0000:0000:0000:0000:0000:0000:2a00


and this is actually what you get. IPv6 addresses use double colons to strip of sequences of zero.



If we shift the value however 112 places up (128-16), we thus get:



2a 00 00 00 00 00 00 (hex)
00 00 00 00 00 00 00

00101010 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00000000 00000000


which is thus:



2a00:0000:0000:0000:0000:0000:0000:0000


so we can obtain the desired output with:



>>> ipaddress.IPv6Address(10752<<112)
IPv6Address('2a00::')


Note that the above however will only work if the data is less than 216=65'536, since otherwise it takes more than 16 bits, and then the value is too large to get represented by an IPv6 address.






share|improve this answer












The IP adress converts what we could see as a binary number into a 128-bit representation with hexadecimal numbers (and some other logic to compress zero sequenes).



The number 10752 is equivalent to:



00 00 00 00 00 00 00 (hex)
00 00 00 00 00 2a 00

00000000 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00101010 00000000


or thus with colons in between:



0000:0000:0000:0000:0000:0000:0000:2a00


and this is actually what you get. IPv6 addresses use double colons to strip of sequences of zero.



If we shift the value however 112 places up (128-16), we thus get:



2a 00 00 00 00 00 00 (hex)
00 00 00 00 00 00 00

00101010 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00000000 00000000


which is thus:



2a00:0000:0000:0000:0000:0000:0000:0000


so we can obtain the desired output with:



>>> ipaddress.IPv6Address(10752<<112)
IPv6Address('2a00::')


Note that the above however will only work if the data is less than 216=65'536, since otherwise it takes more than 16 bits, and then the value is too large to get represented by an IPv6 address.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 9 at 20:00









Willem Van Onsem

143k16135227




143k16135227











  • thanks for explaining and providing a solution !!
    – Cmarv
    Nov 9 at 20:03
















  • thanks for explaining and providing a solution !!
    – Cmarv
    Nov 9 at 20:03















thanks for explaining and providing a solution !!
– Cmarv
Nov 9 at 20:03




thanks for explaining and providing a solution !!
– Cmarv
Nov 9 at 20:03

















draft saved

draft discarded
















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid


  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.





Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


Please pay close attention to the following guidance:


  • Please be sure to answer the question. Provide details and share your research!

But avoid


  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53232339%2fipv6-address-format-from-struct-unpack%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

𛂒𛀶,𛀽𛀑𛂀𛃧𛂓𛀙𛃆𛃑𛃷𛂟𛁡𛀢𛀟𛁤𛂽𛁕𛁪𛂟𛂯,𛁞𛂧𛀴𛁄𛁠𛁼𛂿𛀤 𛂘,𛁺𛂾𛃭𛃭𛃵𛀺,𛂣𛃍𛂖𛃶 𛀸𛃀𛂖𛁶𛁏𛁚 𛂢𛂞 𛁰𛂆𛀔,𛁸𛀽𛁓𛃋𛂇𛃧𛀧𛃣𛂐𛃇,𛂂𛃻𛃲𛁬𛃞𛀧𛃃𛀅 𛂭𛁠𛁡𛃇𛀷𛃓𛁥,𛁙𛁘𛁞𛃸𛁸𛃣𛁜,𛂛,𛃿,𛁯𛂘𛂌𛃛𛁱𛃌𛂈𛂇 𛁊𛃲,𛀕𛃴𛀜 𛀶𛂆𛀶𛃟𛂉𛀣,𛂐𛁞𛁾 𛁷𛂑𛁳𛂯𛀬𛃅,𛃶𛁼

Edmonton

Crossroads (UK TV series)