Ipv6 address format from struct.unpack










1














What would be the way to unpack and map to ipv6 address. I'm currently doing the following



In [3]: struct.unpack("!h",'*x00')
Out[3]: (10752,)

In [5]: ipaddress.IPv6Address(10752)
Out[5]: IPv6Address(u'::2a00')


but of course the end result i wish for is 2a00:: , i was expecting IPv6Address to return it but i'm missing something.



What i'm currently doing is unpacking as sting then to hex and append :: .



In [14]: struct.unpack("!2s",'*x00')
Out[14]: ('*x00',)

In [15]: '*x00'.encode("hex")
Out[15]: '2a00'

then append to hex and append

In [16]: '*x00'.encode("hex")+'::'
Out[16]: '2a00::'









share|improve this question





















  • I'm not following why you expect 2a00, that would be 55827575822966466661959896531774472192 (so shift it with 112 bits) that maps on 2a00::, since you could say that an IP address is "little endian"
    – Willem Van Onsem
    Nov 9 at 19:48











  • thanks for that. was hopping rather than expecting to be honest.what would be the way to shift this ? any module i can use.
    – Cmarv
    Nov 9 at 19:54










  • Just use binary operators, so ipaddress.IPv6Address(10752<<112), but note that this trick will only work for numbers up to 2^16 (65'536), since otherwise the value is "too large".
    – Willem Van Onsem
    Nov 9 at 19:55
















1














What would be the way to unpack and map to ipv6 address. I'm currently doing the following



In [3]: struct.unpack("!h",'*x00')
Out[3]: (10752,)

In [5]: ipaddress.IPv6Address(10752)
Out[5]: IPv6Address(u'::2a00')


but of course the end result i wish for is 2a00:: , i was expecting IPv6Address to return it but i'm missing something.



What i'm currently doing is unpacking as sting then to hex and append :: .



In [14]: struct.unpack("!2s",'*x00')
Out[14]: ('*x00',)

In [15]: '*x00'.encode("hex")
Out[15]: '2a00'

then append to hex and append

In [16]: '*x00'.encode("hex")+'::'
Out[16]: '2a00::'









share|improve this question





















  • I'm not following why you expect 2a00, that would be 55827575822966466661959896531774472192 (so shift it with 112 bits) that maps on 2a00::, since you could say that an IP address is "little endian"
    – Willem Van Onsem
    Nov 9 at 19:48











  • thanks for that. was hopping rather than expecting to be honest.what would be the way to shift this ? any module i can use.
    – Cmarv
    Nov 9 at 19:54










  • Just use binary operators, so ipaddress.IPv6Address(10752<<112), but note that this trick will only work for numbers up to 2^16 (65'536), since otherwise the value is "too large".
    – Willem Van Onsem
    Nov 9 at 19:55














1












1








1







What would be the way to unpack and map to ipv6 address. I'm currently doing the following



In [3]: struct.unpack("!h",'*x00')
Out[3]: (10752,)

In [5]: ipaddress.IPv6Address(10752)
Out[5]: IPv6Address(u'::2a00')


but of course the end result i wish for is 2a00:: , i was expecting IPv6Address to return it but i'm missing something.



What i'm currently doing is unpacking as sting then to hex and append :: .



In [14]: struct.unpack("!2s",'*x00')
Out[14]: ('*x00',)

In [15]: '*x00'.encode("hex")
Out[15]: '2a00'

then append to hex and append

In [16]: '*x00'.encode("hex")+'::'
Out[16]: '2a00::'









share|improve this question













What would be the way to unpack and map to ipv6 address. I'm currently doing the following



In [3]: struct.unpack("!h",'*x00')
Out[3]: (10752,)

In [5]: ipaddress.IPv6Address(10752)
Out[5]: IPv6Address(u'::2a00')


but of course the end result i wish for is 2a00:: , i was expecting IPv6Address to return it but i'm missing something.



What i'm currently doing is unpacking as sting then to hex and append :: .



In [14]: struct.unpack("!2s",'*x00')
Out[14]: ('*x00',)

In [15]: '*x00'.encode("hex")
Out[15]: '2a00'

then append to hex and append

In [16]: '*x00'.encode("hex")+'::'
Out[16]: '2a00::'






python struct






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 9 at 19:44









Cmarv

375




375











  • I'm not following why you expect 2a00, that would be 55827575822966466661959896531774472192 (so shift it with 112 bits) that maps on 2a00::, since you could say that an IP address is "little endian"
    – Willem Van Onsem
    Nov 9 at 19:48











  • thanks for that. was hopping rather than expecting to be honest.what would be the way to shift this ? any module i can use.
    – Cmarv
    Nov 9 at 19:54










  • Just use binary operators, so ipaddress.IPv6Address(10752<<112), but note that this trick will only work for numbers up to 2^16 (65'536), since otherwise the value is "too large".
    – Willem Van Onsem
    Nov 9 at 19:55

















  • I'm not following why you expect 2a00, that would be 55827575822966466661959896531774472192 (so shift it with 112 bits) that maps on 2a00::, since you could say that an IP address is "little endian"
    – Willem Van Onsem
    Nov 9 at 19:48











  • thanks for that. was hopping rather than expecting to be honest.what would be the way to shift this ? any module i can use.
    – Cmarv
    Nov 9 at 19:54










  • Just use binary operators, so ipaddress.IPv6Address(10752<<112), but note that this trick will only work for numbers up to 2^16 (65'536), since otherwise the value is "too large".
    – Willem Van Onsem
    Nov 9 at 19:55
















I'm not following why you expect 2a00, that would be 55827575822966466661959896531774472192 (so shift it with 112 bits) that maps on 2a00::, since you could say that an IP address is "little endian"
– Willem Van Onsem
Nov 9 at 19:48





I'm not following why you expect 2a00, that would be 55827575822966466661959896531774472192 (so shift it with 112 bits) that maps on 2a00::, since you could say that an IP address is "little endian"
– Willem Van Onsem
Nov 9 at 19:48













thanks for that. was hopping rather than expecting to be honest.what would be the way to shift this ? any module i can use.
– Cmarv
Nov 9 at 19:54




thanks for that. was hopping rather than expecting to be honest.what would be the way to shift this ? any module i can use.
– Cmarv
Nov 9 at 19:54












Just use binary operators, so ipaddress.IPv6Address(10752<<112), but note that this trick will only work for numbers up to 2^16 (65'536), since otherwise the value is "too large".
– Willem Van Onsem
Nov 9 at 19:55





Just use binary operators, so ipaddress.IPv6Address(10752<<112), but note that this trick will only work for numbers up to 2^16 (65'536), since otherwise the value is "too large".
– Willem Van Onsem
Nov 9 at 19:55













1 Answer
1






active

oldest

votes


















2














The IP adress converts what we could see as a binary number into a 128-bit representation with hexadecimal numbers (and some other logic to compress zero sequenes).



The number 10752 is equivalent to:



00 00 00 00 00 00 00 (hex)
00 00 00 00 00 2a 00

00000000 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00101010 00000000


or thus with colons in between:



0000:0000:0000:0000:0000:0000:0000:2a00


and this is actually what you get. IPv6 addresses use double colons to strip of sequences of zero.



If we shift the value however 112 places up (128-16), we thus get:



2a 00 00 00 00 00 00 (hex)
00 00 00 00 00 00 00

00101010 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00000000 00000000


which is thus:



2a00:0000:0000:0000:0000:0000:0000:0000


so we can obtain the desired output with:



>>> ipaddress.IPv6Address(10752<<112)
IPv6Address('2a00::')


Note that the above however will only work if the data is less than 216=65'536, since otherwise it takes more than 16 bits, and then the value is too large to get represented by an IPv6 address.






share|improve this answer




















  • thanks for explaining and providing a solution !!
    – Cmarv
    Nov 9 at 20:03










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














The IP adress converts what we could see as a binary number into a 128-bit representation with hexadecimal numbers (and some other logic to compress zero sequenes).



The number 10752 is equivalent to:



00 00 00 00 00 00 00 (hex)
00 00 00 00 00 2a 00

00000000 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00101010 00000000


or thus with colons in between:



0000:0000:0000:0000:0000:0000:0000:2a00


and this is actually what you get. IPv6 addresses use double colons to strip of sequences of zero.



If we shift the value however 112 places up (128-16), we thus get:



2a 00 00 00 00 00 00 (hex)
00 00 00 00 00 00 00

00101010 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00000000 00000000


which is thus:



2a00:0000:0000:0000:0000:0000:0000:0000


so we can obtain the desired output with:



>>> ipaddress.IPv6Address(10752<<112)
IPv6Address('2a00::')


Note that the above however will only work if the data is less than 216=65'536, since otherwise it takes more than 16 bits, and then the value is too large to get represented by an IPv6 address.






share|improve this answer




















  • thanks for explaining and providing a solution !!
    – Cmarv
    Nov 9 at 20:03















2














The IP adress converts what we could see as a binary number into a 128-bit representation with hexadecimal numbers (and some other logic to compress zero sequenes).



The number 10752 is equivalent to:



00 00 00 00 00 00 00 (hex)
00 00 00 00 00 2a 00

00000000 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00101010 00000000


or thus with colons in between:



0000:0000:0000:0000:0000:0000:0000:2a00


and this is actually what you get. IPv6 addresses use double colons to strip of sequences of zero.



If we shift the value however 112 places up (128-16), we thus get:



2a 00 00 00 00 00 00 (hex)
00 00 00 00 00 00 00

00101010 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00000000 00000000


which is thus:



2a00:0000:0000:0000:0000:0000:0000:0000


so we can obtain the desired output with:



>>> ipaddress.IPv6Address(10752<<112)
IPv6Address('2a00::')


Note that the above however will only work if the data is less than 216=65'536, since otherwise it takes more than 16 bits, and then the value is too large to get represented by an IPv6 address.






share|improve this answer




















  • thanks for explaining and providing a solution !!
    – Cmarv
    Nov 9 at 20:03













2












2








2






The IP adress converts what we could see as a binary number into a 128-bit representation with hexadecimal numbers (and some other logic to compress zero sequenes).



The number 10752 is equivalent to:



00 00 00 00 00 00 00 (hex)
00 00 00 00 00 2a 00

00000000 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00101010 00000000


or thus with colons in between:



0000:0000:0000:0000:0000:0000:0000:2a00


and this is actually what you get. IPv6 addresses use double colons to strip of sequences of zero.



If we shift the value however 112 places up (128-16), we thus get:



2a 00 00 00 00 00 00 (hex)
00 00 00 00 00 00 00

00101010 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00000000 00000000


which is thus:



2a00:0000:0000:0000:0000:0000:0000:0000


so we can obtain the desired output with:



>>> ipaddress.IPv6Address(10752<<112)
IPv6Address('2a00::')


Note that the above however will only work if the data is less than 216=65'536, since otherwise it takes more than 16 bits, and then the value is too large to get represented by an IPv6 address.






share|improve this answer












The IP adress converts what we could see as a binary number into a 128-bit representation with hexadecimal numbers (and some other logic to compress zero sequenes).



The number 10752 is equivalent to:



00 00 00 00 00 00 00 (hex)
00 00 00 00 00 2a 00

00000000 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00101010 00000000


or thus with colons in between:



0000:0000:0000:0000:0000:0000:0000:2a00


and this is actually what you get. IPv6 addresses use double colons to strip of sequences of zero.



If we shift the value however 112 places up (128-16), we thus get:



2a 00 00 00 00 00 00 (hex)
00 00 00 00 00 00 00

00101010 00000000 00000000 00000000 00000000 00000000 00000000 (bin)
00000000 00000000 00000000 00000000 00000000 00000000 00000000


which is thus:



2a00:0000:0000:0000:0000:0000:0000:0000


so we can obtain the desired output with:



>>> ipaddress.IPv6Address(10752<<112)
IPv6Address('2a00::')


Note that the above however will only work if the data is less than 216=65'536, since otherwise it takes more than 16 bits, and then the value is too large to get represented by an IPv6 address.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 9 at 20:00









Willem Van Onsem

143k16135227




143k16135227











  • thanks for explaining and providing a solution !!
    – Cmarv
    Nov 9 at 20:03
















  • thanks for explaining and providing a solution !!
    – Cmarv
    Nov 9 at 20:03















thanks for explaining and providing a solution !!
– Cmarv
Nov 9 at 20:03




thanks for explaining and providing a solution !!
– Cmarv
Nov 9 at 20:03

















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