Incorrect if-else statements

I've been trying to write a function that will ask for a number between 1-11 and will randomly choose a number and will compare between them.
I can't figure out why no matter what number I type in (equals or smaller or bigger) it will always type the "Your number is less" message.

def loto():
_number = int(input("Enter any number between 1-10: "))
import random
for x in range(1):
print ("Python chose: " + str(random.randint(1,11)))
if ("_number" == "random"):
print ("You Won! :)")
if ("_number" < "random"):
print ("Your number is less")
if ("_number" > "random"):
print ("Your number is more")
else:
print ("You Lost :(")

loto()


I'm using Python 3.

Thanks:)

elif

if

You Lost

_number > random

_number

number

for x in range(1):

x

x

_number == random

_number

random

2 Answers
2

Your first problem is that you're comparing the strings "_number" and "random". ASCIIbetically (or, rather, Unicoderifically), "_number" < "random", because the _ character is #95 and the r character is #114.

"_number"

"random"

"_number" < "random"

_

r

If you want to compare two variables, you just refer to the variables, not strings that happen to be the same as the names of those variables.

Your second problem is that random isn't your random number, it's the module you used to create that number. And, more seriously, you aren't storing that number anywhere—you're just converting it to a string to print it out and then throwing it away.

random

Your third problem is that you need to change those ifs to elifs. Otherwise, the You Lost message gets printed whenever _number > random is not true, instead of only whenever all of the three comparisons are not true.

if

elif

You Lost

_number > random

Putting that all together:

choice = random.randint(1,11)
for x in range(1):
print ("Python chose: " + str(choice))
if (_number == choice):
print ("You Won! :)")
elif (_number < choice):
print ("Your number is less")
elif (_number > choice):
print ("Your number is more")
else:
print ("You Lost :(")


Of course there's no way to actually lose your game—one of the three conditions is always going to be true. (If you were using complex numbers, or floats including NaN, you could input a number that wasn't comparable in any way to the selected one, but you're not.)

While we're at it:

_number

number

for x in range(1):

x

print

So:

import random

def loto():
number = int(input("Enter any number between 1-10: "))
choice = random.randint(1, 11)
print("Python chose:", choice)
if number == choice:
print("You Won! :)")
elif number < choice:
print("Your number is less")
elif number > choice:
print("Your number is more")
else:
print("You Lost :(")

loto()


You were comparing strings not variables, you need to remove quotes, and you not saved random number into a variable. The for loop is making one repetition only, you can remove it.
Update your cod like this:

import random
def loto():
_number = int(input("Enter any number between 1-10: "))

rand_number = random.randint(1,11) # can't had the same name as random
if (_number == rand_number):
print ("You Won! :)")
elif (_number < rand_number):
print ("Your number is less")
elif (_number > rand_number):
print ("Your number is more")
else:
print ("You Lost :(")

loto()


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