Making a list of patterns of arbitrary length

Making a list of patterns of arbitrary length



I would like to create a list of arbitrary length:


x1_, x2_, ...



Where each of the elements of the list has the full form:


Pattern[xi, Blank]



This answer shows how to create a list of symbols:


x1, x2, ...



but I don't know how to adapt that to obtain the above.



I intend to use this list in the definition of a function as in here.




4 Answers
4


Array[ToExpression["x" <> ToString @ # <> "_"] &, 5]



x1_, x2_, x3_, x4_, x5_


FullForm @ %



List[Pattern[x1,Blank], Pattern[x2, Blank], Pattern[x3, Blank], Pattern[x4, Blank], Pattern[x5, Blank]]



Also


Thread[Pattern[Evaluate@Array[Symbol["x" <> ToString@#] &, 5], Blank]]



x1_, x2_, x3_, x4_, x5_



and


ToExpression[Table["x" <> i <> "_", i, ToString /@ Range[5]]]



x1_, x2_, x3_, x4_, x5_





The middle one will fail if x1=1.
– Kuba
Aug 28 at 7:37



x1=1





@Kuba, good point.
– kglr
Aug 28 at 8:09



If you construct a list of strings instead, you can take advantage of the fact that ToExpression is listable, and supports a 3rd argument that post-processes the output. For example:


ToExpression


ToExpression[
"x1", "x2", "x3",
StandardForm,
Pattern[#,Blank]&
]



x1_, x2_, x3_



Or, creating the list and converting:


ToExpression[
Table["x" <> ToString@i, i, 5],
StandardForm,
Pattern[#, Blank]&
]



x1_, x2_, x3_, x4_, x5_





It won't work if x1 = 1.
– Kuba
Aug 28 at 7:36


x1 = 1





Function[sym,Pattern[sym,Blank],HoldFirst] instead of Pattern[#,Blank]& as usual.
– Anton.Sakovich
Aug 28 at 7:44


Function[sym,Pattern[sym,Blank],HoldFirst]


Pattern[#,Blank]&





@Kuba what exactly do you mean by x1 = 1 ?
– Winkelried
Aug 28 at 8:57


x1 = 1





@Winkelried if any of xi have values prior to that evaluation then you will get e.g. Pattern[1, Blank]
– Kuba
Aug 28 at 8:58


xi


Pattern[1, Blank]



Nothing new but shorter:


StringTemplate["x``_"] /@ Range[10] // ToExpression


x1_, x2_, x3_, x4_, x5_, x6_, x7_, x8_, x9_, x10_



Here is an example of how to make the solution in the link work for this case:


patt = Table[
With[
s = Symbol["x" <> ToString[i]],
Pattern[s, Blank]
], i, 10];

Range[10] /. patt :> x5, x8



5, 8


5, 8



Using With here is a trick to insert the symbol into Pattern. Since Pattern has the attribute HoldFirst, it would not work to write e.g.


With


Pattern


Pattern


HoldFirst


Pattern[Symbol["x" <> ToString[i]], Blank]



because Symbol["x" <> ToString[i]] would not be evaluated before it was passed to Pattern, i.e. Pattern would not receive a string as is required.


Symbol["x" <> ToString[i]]


Pattern


Pattern





It won't work if x1 = 1
– Kuba
Aug 28 at 7:36


x1 = 1





@Kuba You mean if the symbols have values?
– C. E.
Aug 28 at 9:48





Yes, sorry for not being clear.
– Kuba
Aug 28 at 9:54





@Kuba Well, you are right. I wanted to show how to adapt the answer OP linked to, but it has this flaw.
– C. E.
Aug 28 at 10:40






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