avoid force unwrapping inside a filter closure in Swift 4

avoid force unwrapping inside a filter closure in Swift 4



I am trying to filter array of [String?] with "abc".


// keysForAutoComplete: [String?]
let tempFilteredResult = keysForAutoComplete.filter ($0?.contains("abc"))!



How can I avoid force unwrapping within the closure ? I know about if let and guard let statements, but not quite sure how to apply them here?





What are the contents of keysForAutoComplete?
– Carpsen90
Aug 25 at 14:57


keysForAutoComplete





@Carpsen90 optional string
– Ali_C
Aug 25 at 15:05





like ["abcd", "kjm", "babc", nil] ?
– Carpsen90
Aug 25 at 15:05





@Carpsen90 yes. vacawama's answer is what I was looking for.
– Ali_C
Aug 25 at 15:10




2 Answers
2



You can avoid force unwrapping by directly comparing to true:


true


let tempFilteredResult = keysForAutoComplete.filter $0?.contains("abc") == true



or by using the nil coalescing operator ??:


??


let tempFilteredResult = keysForAutoComplete.filter $0?.contains("abc") ?? false



Explanation:



$0?.contains("abc") is using optional chaining and the result is a Bool? which is nil if the element is nil or Optional(true) or Optional(false) depending on whether the String contains "abc". You can compare a Bool? to a Bool, so comparing to true will return true only when there is a String that contains "abc".


$0?.contains("abc")


Bool?


nil


nil


Optional(true)


Optional(false)


String


"abc"


Bool?


Bool


true


true


String


"abc"



The nil coalescing operator unwraps the value if it is not nil, or replaces it with the supplied default value if it is nil. Since you want a nil item to return false for the comparison, the way to safely unwrap is to use ?? false.


nil


nil


nil


false


?? false



If you'd like the result to be [String], you can use compactMap along with the trinary operator ?: to generate an array of [String]:


[String]


compactMap


?:


[String]


let tempFilteredResult = keysForAutoComplete.compactMap $0?.contains("abc") == true ? $0 : nil



Explanation:



Here, ?: is used to return the original value if it contains "abc" or nil if it does not. compactMap then eliminates the nil values and unwraps the String? to return a [String].


?:


"abc"


nil


compactMap


nil


String?


[String]





as the first syntax is more elegant and easier to follow, let say there a nil in the array and I use == true. What did you mean by saying ??false is safer? I tried using ==true on an array that had a nil value and it did not crash.
– Ali_C
Aug 25 at 15:53






Both are equally safe. The first isn't unwrapping the optional. It is comparing the optional to true to create a new Bool. ?? false unwraps the optional. Either work; use the one you like.
– vacawama
Aug 25 at 15:56


true


Bool


?? false



You can use compactMap operator to remove nil values and left your array as [String] type, so every element will be a non-optional value. After that, you can use filter on the new array. This way, you don't need to be worried about nil values, then unwrapping is no needed.


compactMap


nil


[String]


filter


let keysForAutoComplete = ["abc", "ab", nil, "bca", "abcd"]
let tempFilteredResult = keysForAutoComplete.compactMap$0.filter$0.contains("abc")






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