remove objects with a specific `key: value` from an array
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I have an array of object and need to use lodash to remove some of those objects with a specific key: value, for instance:
[
id:1,b:22,
id:2,b:44,
id:3,b:56,
id:4,b:-29
]
I need to remove all object with id of 1 and 3.
i know the way below but was wondering if there is a shorter way:
var array = [
id:1,b:22,
id:2,b:44,
id:3,b:56,
id:4,b:-29
];
_.remove(array, function(n)
return _.includes([ 1,3 ], n.id);
);
lodash
asked Nov 14 '18 at 0:14
farm commandfarm command
89111
add a comment |
I have an array of object and need to use lodash to remove some of those objects with a specific key: value, for instance:
[
id:1,b:22,
id:2,b:44,
id:3,b:56,
id:4,b:-29
]
I need to remove all object with id of 1 and 3.
i know the way below but was wondering if there is a shorter way:
var array = [
id:1,b:22,
id:2,b:44,
id:3,b:56,
id:4,b:-29
];
_.remove(array, function(n)
return _.includes([ 1,3 ], n.id);
);
lodash
asked Nov 14 '18 at 0:14
farm commandfarm command
89111
Do you really need to mutate the object? it's usually a better idea to work with immutable data.
– tokland
Nov 14 '18 at 19:17
add a comment |
I have an array of object and need to use lodash to remove some of those objects with a specific key: value, for instance:
[
id:1,b:22,
id:2,b:44,
id:3,b:56,
id:4,b:-29
]
I need to remove all object with id of 1 and 3.
i know the way below but was wondering if there is a shorter way:
var array = [
id:1,b:22,
id:2,b:44,
id:3,b:56,
id:4,b:-29
];
_.remove(array, function(n)
return _.includes([ 1,3 ], n.id);
);
lodash
asked Nov 14 '18 at 0:14
farm commandfarm command
89111
I have an array of object and need to use lodash to remove some of those objects with a specific key: value, for instance:
[
id:1,b:22,
id:2,b:44,
id:3,b:56,
id:4,b:-29
]
I need to remove all object with id of 1 and 3.
i know the way below but was wondering if there is a shorter way:
var array = [
id:1,b:22,
id:2,b:44,
id:3,b:56,
id:4,b:-29
];
_.remove(array, function(n)
return _.includes([ 1,3 ], n.id);
);
lodash
lodash
asked Nov 14 '18 at 0:14
farm commandfarm command
89111
asked Nov 14 '18 at 0:14
farm commandfarm command
89111
asked Nov 14 '18 at 0:14
farm commandfarm command
89111
asked Nov 14 '18 at 0:14
farm commandfarm command
89111
asked Nov 14 '18 at 0:14
farm commandfarm command
89111
89111
Do you really need to mutate the object? it's usually a better idea to work with immutable data.
– tokland
Nov 14 '18 at 19:17
add a comment |
Do you really need to mutate the object? it's usually a better idea to work with immutable data.
– tokland
Nov 14 '18 at 19:17
Do you really need to mutate the object? it's usually a better idea to work with immutable data.
– tokland
Nov 14 '18 at 19:17
Do you really need to mutate the object? it's usually a better idea to work with immutable data.
– tokland
Nov 14 '18 at 19:17
add a comment |
1 Answer
1
active
oldest
votes
You could use pullAllBy and provide the elements to be removed as the 2nd parameter.
let data = [id:1,b:22,id:2,b:44,id:3,b:56,id:4,b:-29]
const result = _.pullAllBy(data, [id:1,id:3], 'id')
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>Note that this method mutates the array. If you do not want that use _.differenceBy
Using ES6 and arrow functions + filter to get the values and not mutate the array will also get you somewhat of a short version:
let data = [ id: 1, b: 22 , id: 2, b: 44 , id: 3, b: 56 , id: 4, b: -29 ]
const result = data.filter(x => ![1,3].includes(x.id))
console.log(result)answered Nov 14 '18 at 0:49
AkrionAkrion
9,60011425
add a comment |
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1 Answer
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1 Answer
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active
oldest
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You could use pullAllBy and provide the elements to be removed as the 2nd parameter.
let data = [id:1,b:22,id:2,b:44,id:3,b:56,id:4,b:-29]
const result = _.pullAllBy(data, [id:1,id:3], 'id')
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>Note that this method mutates the array. If you do not want that use _.differenceBy
Using ES6 and arrow functions + filter to get the values and not mutate the array will also get you somewhat of a short version:
let data = [ id: 1, b: 22 , id: 2, b: 44 , id: 3, b: 56 , id: 4, b: -29 ]
const result = data.filter(x => ![1,3].includes(x.id))
console.log(result)answered Nov 14 '18 at 0:49
AkrionAkrion
9,60011425
add a comment |
You could use pullAllBy and provide the elements to be removed as the 2nd parameter.
let data = [id:1,b:22,id:2,b:44,id:3,b:56,id:4,b:-29]
const result = _.pullAllBy(data, [id:1,id:3], 'id')
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>Note that this method mutates the array. If you do not want that use _.differenceBy
Using ES6 and arrow functions + filter to get the values and not mutate the array will also get you somewhat of a short version:
let data = [ id: 1, b: 22 , id: 2, b: 44 , id: 3, b: 56 , id: 4, b: -29 ]
const result = data.filter(x => ![1,3].includes(x.id))
console.log(result)answered Nov 14 '18 at 0:49
AkrionAkrion
9,60011425
add a comment |
You could use pullAllBy and provide the elements to be removed as the 2nd parameter.
let data = [id:1,b:22,id:2,b:44,id:3,b:56,id:4,b:-29]
const result = _.pullAllBy(data, [id:1,id:3], 'id')
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>Note that this method mutates the array. If you do not want that use _.differenceBy
Using ES6 and arrow functions + filter to get the values and not mutate the array will also get you somewhat of a short version:
let data = [ id: 1, b: 22 , id: 2, b: 44 , id: 3, b: 56 , id: 4, b: -29 ]
const result = data.filter(x => ![1,3].includes(x.id))
console.log(result)answered Nov 14 '18 at 0:49
AkrionAkrion
9,60011425
You could use pullAllBy and provide the elements to be removed as the 2nd parameter.
let data = [id:1,b:22,id:2,b:44,id:3,b:56,id:4,b:-29]
const result = _.pullAllBy(data, [id:1,id:3], 'id')
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>Note that this method mutates the array. If you do not want that use _.differenceBy
Using ES6 and arrow functions + filter to get the values and not mutate the array will also get you somewhat of a short version:
let data = [ id: 1, b: 22 , id: 2, b: 44 , id: 3, b: 56 , id: 4, b: -29 ]
const result = data.filter(x => ![1,3].includes(x.id))
console.log(result)let data = [id:1,b:22,id:2,b:44,id:3,b:56,id:4,b:-29]
const result = _.pullAllBy(data, [id:1,id:3], 'id')
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>let data = [id:1,b:22,id:2,b:44,id:3,b:56,id:4,b:-29]
const result = _.pullAllBy(data, [id:1,id:3], 'id')
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>let data = [ id: 1, b: 22 , id: 2, b: 44 , id: 3, b: 56 , id: 4, b: -29 ]
const result = data.filter(x => ![1,3].includes(x.id))
console.log(result)let data = [ id: 1, b: 22 , id: 2, b: 44 , id: 3, b: 56 , id: 4, b: -29 ]
const result = data.filter(x => ![1,3].includes(x.id))
console.log(result)answered Nov 14 '18 at 0:49
AkrionAkrion
9,60011425
edited Nov 14 '18 at 17:29
answered Nov 14 '18 at 0:49
AkrionAkrion
9,60011425
answered Nov 14 '18 at 0:49
AkrionAkrion
9,60011425
answered Nov 14 '18 at 0:49
AkrionAkrion
9,60011425
9,60011425
add a comment |
add a comment |
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Do you really need to mutate the object? it's usually a better idea to work with immutable data.
– tokland
Nov 14 '18 at 19:17