how to get near time for the present time [Android Studio]

i have 5 times
example:

4:21 AM

12:1 PM

3:32 PM

6:30 PM

8:4 PM

and the current time is

10:4 AM

I want to do a comparison
What is the next time closest to the current time

the result will be:

NEXT TIME : 12:1 PM

12:1 PM

12:10 PM

12:01 PM

3 Answers
3

You can turn a time to a date object and then into a long (milliseconds since Jan 1, 1970), and calculate the difference in milliseconds

long diffInMs = currentDate.getTime() - anotherDate.getTime();


And then check which has the smallest difference, but being also equal to or greater than zero. Negative difference means old date and you want the next closest date

To convert the times to dates check this: https://stackoverflow.com/a/8826392/2597775

Basically, it says:

SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS");
sdf.setTimeZone(TimeZone.getTimeZone("UTC"));

String inputString = "00:01:30.500";

Date date = sdf.parse("1970-01-01 " + inputString);


Update: Added logic to rollover at midnight, and added alternative using binary search.

First parse the inputs to a time in milliseconds of the day, by parsing the time string as if it's in UTC time zone.

Then find the smallest value on or after the "current" value, or just smallest value if no value is on or after the "current" value (rollover).

Example:

public static String findNext(String current, String... times) throws ParseException
SimpleDateFormat fmt = new SimpleDateFormat("hh:mm a");
fmt.setTimeZone(TimeZone.getTimeZone("UTC"));
long currentMillis = fmt.parse(current).getTime();
long bestMillis = 0, minMillis = 0;
String bestTime = null, minTime = null;
for (String time : times) millis < bestMillis))
bestMillis = millis;
bestTime = time;

if (minTime == null
return (bestTime != null ? bestTime : minTime);



Test

System.out.println(findNext("10:4 AM",
"4:21 AM", "12:1 PM", "3:32 PM", "6:30 PM", "8:4 PM"));
System.out.println(findNext("10:4 PM",
"4:21 AM", "12:1 PM", "3:32 PM", "6:30 PM", "8:4 PM"));


Output

12:1 PM
4:21 AM


If the given times are guaranteed to already be sorted, then it can be done with a binary search:

public static String findNext(String current, String... times)
SimpleDateFormat fmt = new SimpleDateFormat("hh:mm a");
fmt.setTimeZone(TimeZone.getTimeZone("UTC"));
int idx = Arrays.binarySearch(times, current, new Comparator<String>()
@Override
public int compare(String s1, String s2)
try
return fmt.parse(s1).compareTo(fmt.parse(s2));
catch (ParseException e)
throw new RuntimeException(e);


);
if (idx < 0)
idx = -idx - 1;
return times[idx < times.length ? idx : 0];



findNext

10:4 PM

null

4:21 AM

if(bestTime == null) return times[0];

times

i specially design a function to solve your problem , use function as you needed.

it will works for you surely.

/**
*
* @author Niravdas
*/
public class TimeDiff
String times = "04:21 AM", "12:01 PM", "03:32 PM", "06:30 PM", "08:04 PM";
String findingafter="10:04 AM";

public TimeDiff()

int time=nextTimeArrayIndex(findingafter,times);
if(time>=0)
System.out.println("NEXT TIME: "+times[time]);


public static void main(String argv)

new TimeDiff();

int nextTimeArrayIndex(String Finding,String fromArray)

int shortest=-1,shortestsec=-1;
long minsecdif=(24*60*60+1),minsec=(24*60*60+1);
int hr=Integer.parseInt(Finding.substring(0, 2));
int min=Integer.parseInt(Finding.substring(3, 5));
long seconds = convertToSec(hr, min, 0, Finding.substring(Finding.length()-2));
System.out.println("seconds :" + seconds);
for(int i=0;i<fromArray.length;i++)

int temphr=Integer.parseInt(fromArray[i].substring(0, 2));
int tempmin = Integer.parseInt(fromArray[i].substring(3,5));
long tempsec = convertToSec(temphr, tempmin, 0, fromArray[i].substring(Finding.length()-2));
System.out.println("Compared to :" + tempsec);
if((tempsec - seconds) > 0 && minsecdif > (tempsec - seconds))

minsecdif = (tempsec - seconds);
shortest = i;

if(minsec > tempsec)

minsec = tempsec;
shortestsec=i;


if(shortest >=0)

return shortest;

else

return shortestsec;




long convertToSec(int hr,int min,int sec,String AMorPM)

if(hr==12)

hr=0;

long secs = (hr*60*60) + (min*60) + (sec*60);
if(AMorPM.equalsIgnoreCase("PM"))

secs += (12*60*60);

return secs;






i hope it will solve your problem.

Thanks for contributing an answer to Stack Overflow!

But avoid …

To learn more, see our tips on writing great answers.

Required, but never shown

Required, but never shown

By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.