Allow JSON fragments with Decodable










1















import UIKit

class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource
//@IBOutlet weak var ingredientText: UILabel!

struct Recipes: Decodable
let recipe_id:String?
let image_url:String?
let source_url:String?
let f2f_url:String?
let title:String?
let publisher:String?
let social_rank:Float64?
let page:Int?
let ingredients:[String]?

private enum CodingKeys: String, CodingKey
case recipe_id = "recipe_id"
case image_url = "image_url"
case source_url = "source_url"
case f2f_url = "f2f_url"
case title = "title"
case publisher = "publisher"
case social_rank = "social_rank"
case page = "page"
case ingredients = "ingredients"



var recipes = [Recipes]()
var food = "chicken"
var food2 = "peas"
var food3 = "onions"
//var recipeData = [Recipe]

@IBOutlet weak var tableView: UITableView!

fileprivate func getRecipes()
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9264045e3ff7b84ee346eb20e1642d9d9&food=chicken&food2=onions&food3=peas"

guard let url = URL(string: jsonURL) elsereturn

URLSession.shared.dataTask(with: url) (data, _ , err) in
DispatchQueue.main.async
if let err = err
print("failed to get data from URL",err)
return

guard let data = data elsereturn

do
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
self.recipes = try decoder.decode([Recipes].self, from: data)
self.tableView.reloadData()
catch let jsonERR
print("Failed to decode",jsonERR)


.resume()


func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int
return recipes.count


func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell
let cell = UITableViewCell(style: .subtitle, reuseIdentifier: "cell")

let recipe = recipes[indexPath.row]
cell.textLabel?.text = recipe.title
return cell


override func viewDidLoad()
super.viewDidLoad()
navigationController?.navigationBar.prefersLargeTitles = true
navigationItem.title = "Ingredients"
getRecipes()




I am getting the error:




JSON text did not start with array or object and option to allow fragments not set." UserInfo=NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.)))











share|improve this question
























  • Your URL gives 403 FORBIDDEN Error..... check status code....

    – Vishal Patel
    Nov 13 '18 at 6:05











  • Thanks Vishal. The wrong API key was given in the example.

    – Jonathan Jordan
    Nov 13 '18 at 6:20















1















import UIKit

class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource
//@IBOutlet weak var ingredientText: UILabel!

struct Recipes: Decodable
let recipe_id:String?
let image_url:String?
let source_url:String?
let f2f_url:String?
let title:String?
let publisher:String?
let social_rank:Float64?
let page:Int?
let ingredients:[String]?

private enum CodingKeys: String, CodingKey
case recipe_id = "recipe_id"
case image_url = "image_url"
case source_url = "source_url"
case f2f_url = "f2f_url"
case title = "title"
case publisher = "publisher"
case social_rank = "social_rank"
case page = "page"
case ingredients = "ingredients"



var recipes = [Recipes]()
var food = "chicken"
var food2 = "peas"
var food3 = "onions"
//var recipeData = [Recipe]

@IBOutlet weak var tableView: UITableView!

fileprivate func getRecipes()
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9264045e3ff7b84ee346eb20e1642d9d9&food=chicken&food2=onions&food3=peas"

guard let url = URL(string: jsonURL) elsereturn

URLSession.shared.dataTask(with: url) (data, _ , err) in
DispatchQueue.main.async
if let err = err
print("failed to get data from URL",err)
return

guard let data = data elsereturn

do
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
self.recipes = try decoder.decode([Recipes].self, from: data)
self.tableView.reloadData()
catch let jsonERR
print("Failed to decode",jsonERR)


.resume()


func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int
return recipes.count


func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell
let cell = UITableViewCell(style: .subtitle, reuseIdentifier: "cell")

let recipe = recipes[indexPath.row]
cell.textLabel?.text = recipe.title
return cell


override func viewDidLoad()
super.viewDidLoad()
navigationController?.navigationBar.prefersLargeTitles = true
navigationItem.title = "Ingredients"
getRecipes()




I am getting the error:




JSON text did not start with array or object and option to allow fragments not set." UserInfo=NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.)))











share|improve this question
























  • Your URL gives 403 FORBIDDEN Error..... check status code....

    – Vishal Patel
    Nov 13 '18 at 6:05











  • Thanks Vishal. The wrong API key was given in the example.

    – Jonathan Jordan
    Nov 13 '18 at 6:20













1












1








1








import UIKit

class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource
//@IBOutlet weak var ingredientText: UILabel!

struct Recipes: Decodable
let recipe_id:String?
let image_url:String?
let source_url:String?
let f2f_url:String?
let title:String?
let publisher:String?
let social_rank:Float64?
let page:Int?
let ingredients:[String]?

private enum CodingKeys: String, CodingKey
case recipe_id = "recipe_id"
case image_url = "image_url"
case source_url = "source_url"
case f2f_url = "f2f_url"
case title = "title"
case publisher = "publisher"
case social_rank = "social_rank"
case page = "page"
case ingredients = "ingredients"



var recipes = [Recipes]()
var food = "chicken"
var food2 = "peas"
var food3 = "onions"
//var recipeData = [Recipe]

@IBOutlet weak var tableView: UITableView!

fileprivate func getRecipes()
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9264045e3ff7b84ee346eb20e1642d9d9&food=chicken&food2=onions&food3=peas"

guard let url = URL(string: jsonURL) elsereturn

URLSession.shared.dataTask(with: url) (data, _ , err) in
DispatchQueue.main.async
if let err = err
print("failed to get data from URL",err)
return

guard let data = data elsereturn

do
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
self.recipes = try decoder.decode([Recipes].self, from: data)
self.tableView.reloadData()
catch let jsonERR
print("Failed to decode",jsonERR)


.resume()


func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int
return recipes.count


func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell
let cell = UITableViewCell(style: .subtitle, reuseIdentifier: "cell")

let recipe = recipes[indexPath.row]
cell.textLabel?.text = recipe.title
return cell


override func viewDidLoad()
super.viewDidLoad()
navigationController?.navigationBar.prefersLargeTitles = true
navigationItem.title = "Ingredients"
getRecipes()




I am getting the error:




JSON text did not start with array or object and option to allow fragments not set." UserInfo=NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.)))











share|improve this question
















import UIKit

class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource
//@IBOutlet weak var ingredientText: UILabel!

struct Recipes: Decodable
let recipe_id:String?
let image_url:String?
let source_url:String?
let f2f_url:String?
let title:String?
let publisher:String?
let social_rank:Float64?
let page:Int?
let ingredients:[String]?

private enum CodingKeys: String, CodingKey
case recipe_id = "recipe_id"
case image_url = "image_url"
case source_url = "source_url"
case f2f_url = "f2f_url"
case title = "title"
case publisher = "publisher"
case social_rank = "social_rank"
case page = "page"
case ingredients = "ingredients"



var recipes = [Recipes]()
var food = "chicken"
var food2 = "peas"
var food3 = "onions"
//var recipeData = [Recipe]

@IBOutlet weak var tableView: UITableView!

fileprivate func getRecipes()
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9264045e3ff7b84ee346eb20e1642d9d9&food=chicken&food2=onions&food3=peas"

guard let url = URL(string: jsonURL) elsereturn

URLSession.shared.dataTask(with: url) (data, _ , err) in
DispatchQueue.main.async
if let err = err
print("failed to get data from URL",err)
return

guard let data = data elsereturn

do
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
self.recipes = try decoder.decode([Recipes].self, from: data)
self.tableView.reloadData()
catch let jsonERR
print("Failed to decode",jsonERR)


.resume()


func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int
return recipes.count


func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell
let cell = UITableViewCell(style: .subtitle, reuseIdentifier: "cell")

let recipe = recipes[indexPath.row]
cell.textLabel?.text = recipe.title
return cell


override func viewDidLoad()
super.viewDidLoad()
navigationController?.navigationBar.prefersLargeTitles = true
navigationItem.title = "Ingredients"
getRecipes()




I am getting the error:




JSON text did not start with array or object and option to allow fragments not set." UserInfo=NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.)))








json swift






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 '18 at 5:45









rmaddy

245k27324388




245k27324388










asked Nov 13 '18 at 5:30









Jonathan JordanJonathan Jordan

12




12












  • Your URL gives 403 FORBIDDEN Error..... check status code....

    – Vishal Patel
    Nov 13 '18 at 6:05











  • Thanks Vishal. The wrong API key was given in the example.

    – Jonathan Jordan
    Nov 13 '18 at 6:20

















  • Your URL gives 403 FORBIDDEN Error..... check status code....

    – Vishal Patel
    Nov 13 '18 at 6:05











  • Thanks Vishal. The wrong API key was given in the example.

    – Jonathan Jordan
    Nov 13 '18 at 6:20
















Your URL gives 403 FORBIDDEN Error..... check status code....

– Vishal Patel
Nov 13 '18 at 6:05





Your URL gives 403 FORBIDDEN Error..... check status code....

– Vishal Patel
Nov 13 '18 at 6:05













Thanks Vishal. The wrong API key was given in the example.

– Jonathan Jordan
Nov 13 '18 at 6:20





Thanks Vishal. The wrong API key was given in the example.

– Jonathan Jordan
Nov 13 '18 at 6:20












2 Answers
2






active

oldest

votes


















0














JSONDecoder doesn't provide any JSONSerialization.ReadingOptions.



You could make a manual check whether the first byte of the data is an opening square bracket <5b> or brace <7b>



guard let data = data, let firstByte = data.first else return 
guard firstByte == 0x5b || firstByte == 0x7b else
let string = String(data: data, encoding: .utf8)!
print(string)
return



However I'd recommend to use the response parameter to check for status code 200



URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200
print(response.statusCode)
return

...


Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase you are encouraged to name the struct members recipeId, imageUrl, sourceUrl etc.






share|improve this answer

























  • Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))

    – Jonathan Jordan
    Nov 13 '18 at 6:17












  • If the root object is a dictionary you have to decode Recipes.self

    – vadian
    Nov 13 '18 at 7:34











  • The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.

    – Jonathan Jordan
    Nov 13 '18 at 7:51











  • In terms of Decodable every dictionary is a struct. So you need an extra struct for the root object.

    – vadian
    Nov 13 '18 at 7:54











  • Thank you for your help. I will try this.

    – Jonathan Jordan
    Nov 13 '18 at 7:56


















0














You want to decode [Recipe], that is, an Array of Recipe. That mean the first (non-whitespace) character in data has to be [ (to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data to a String and printing it:



print(String(data: data, encoding: .utf8))





share|improve this answer























  • I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.

    – Jonathan Jordan
    Nov 13 '18 at 6:43










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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














JSONDecoder doesn't provide any JSONSerialization.ReadingOptions.



You could make a manual check whether the first byte of the data is an opening square bracket <5b> or brace <7b>



guard let data = data, let firstByte = data.first else return 
guard firstByte == 0x5b || firstByte == 0x7b else
let string = String(data: data, encoding: .utf8)!
print(string)
return



However I'd recommend to use the response parameter to check for status code 200



URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200
print(response.statusCode)
return

...


Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase you are encouraged to name the struct members recipeId, imageUrl, sourceUrl etc.






share|improve this answer

























  • Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))

    – Jonathan Jordan
    Nov 13 '18 at 6:17












  • If the root object is a dictionary you have to decode Recipes.self

    – vadian
    Nov 13 '18 at 7:34











  • The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.

    – Jonathan Jordan
    Nov 13 '18 at 7:51











  • In terms of Decodable every dictionary is a struct. So you need an extra struct for the root object.

    – vadian
    Nov 13 '18 at 7:54











  • Thank you for your help. I will try this.

    – Jonathan Jordan
    Nov 13 '18 at 7:56















0














JSONDecoder doesn't provide any JSONSerialization.ReadingOptions.



You could make a manual check whether the first byte of the data is an opening square bracket <5b> or brace <7b>



guard let data = data, let firstByte = data.first else return 
guard firstByte == 0x5b || firstByte == 0x7b else
let string = String(data: data, encoding: .utf8)!
print(string)
return



However I'd recommend to use the response parameter to check for status code 200



URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200
print(response.statusCode)
return

...


Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase you are encouraged to name the struct members recipeId, imageUrl, sourceUrl etc.






share|improve this answer

























  • Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))

    – Jonathan Jordan
    Nov 13 '18 at 6:17












  • If the root object is a dictionary you have to decode Recipes.self

    – vadian
    Nov 13 '18 at 7:34











  • The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.

    – Jonathan Jordan
    Nov 13 '18 at 7:51











  • In terms of Decodable every dictionary is a struct. So you need an extra struct for the root object.

    – vadian
    Nov 13 '18 at 7:54











  • Thank you for your help. I will try this.

    – Jonathan Jordan
    Nov 13 '18 at 7:56













0












0








0







JSONDecoder doesn't provide any JSONSerialization.ReadingOptions.



You could make a manual check whether the first byte of the data is an opening square bracket <5b> or brace <7b>



guard let data = data, let firstByte = data.first else return 
guard firstByte == 0x5b || firstByte == 0x7b else
let string = String(data: data, encoding: .utf8)!
print(string)
return



However I'd recommend to use the response parameter to check for status code 200



URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200
print(response.statusCode)
return

...


Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase you are encouraged to name the struct members recipeId, imageUrl, sourceUrl etc.






share|improve this answer















JSONDecoder doesn't provide any JSONSerialization.ReadingOptions.



You could make a manual check whether the first byte of the data is an opening square bracket <5b> or brace <7b>



guard let data = data, let firstByte = data.first else return 
guard firstByte == 0x5b || firstByte == 0x7b else
let string = String(data: data, encoding: .utf8)!
print(string)
return



However I'd recommend to use the response parameter to check for status code 200



URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200
print(response.statusCode)
return

...


Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase you are encouraged to name the struct members recipeId, imageUrl, sourceUrl etc.







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 13 '18 at 6:12

























answered Nov 13 '18 at 5:59









vadianvadian

153k17163189




153k17163189












  • Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))

    – Jonathan Jordan
    Nov 13 '18 at 6:17












  • If the root object is a dictionary you have to decode Recipes.self

    – vadian
    Nov 13 '18 at 7:34











  • The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.

    – Jonathan Jordan
    Nov 13 '18 at 7:51











  • In terms of Decodable every dictionary is a struct. So you need an extra struct for the root object.

    – vadian
    Nov 13 '18 at 7:54











  • Thank you for your help. I will try this.

    – Jonathan Jordan
    Nov 13 '18 at 7:56

















  • Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))

    – Jonathan Jordan
    Nov 13 '18 at 6:17












  • If the root object is a dictionary you have to decode Recipes.self

    – vadian
    Nov 13 '18 at 7:34











  • The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.

    – Jonathan Jordan
    Nov 13 '18 at 7:51











  • In terms of Decodable every dictionary is a struct. So you need an extra struct for the root object.

    – vadian
    Nov 13 '18 at 7:54











  • Thank you for your help. I will try this.

    – Jonathan Jordan
    Nov 13 '18 at 7:56
















Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))

– Jonathan Jordan
Nov 13 '18 at 6:17






Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))

– Jonathan Jordan
Nov 13 '18 at 6:17














If the root object is a dictionary you have to decode Recipes.self

– vadian
Nov 13 '18 at 7:34





If the root object is a dictionary you have to decode Recipes.self

– vadian
Nov 13 '18 at 7:34













The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.

– Jonathan Jordan
Nov 13 '18 at 7:51





The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.

– Jonathan Jordan
Nov 13 '18 at 7:51













In terms of Decodable every dictionary is a struct. So you need an extra struct for the root object.

– vadian
Nov 13 '18 at 7:54





In terms of Decodable every dictionary is a struct. So you need an extra struct for the root object.

– vadian
Nov 13 '18 at 7:54













Thank you for your help. I will try this.

– Jonathan Jordan
Nov 13 '18 at 7:56





Thank you for your help. I will try this.

– Jonathan Jordan
Nov 13 '18 at 7:56













0














You want to decode [Recipe], that is, an Array of Recipe. That mean the first (non-whitespace) character in data has to be [ (to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data to a String and printing it:



print(String(data: data, encoding: .utf8))





share|improve this answer























  • I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.

    – Jonathan Jordan
    Nov 13 '18 at 6:43















0














You want to decode [Recipe], that is, an Array of Recipe. That mean the first (non-whitespace) character in data has to be [ (to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data to a String and printing it:



print(String(data: data, encoding: .utf8))





share|improve this answer























  • I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.

    – Jonathan Jordan
    Nov 13 '18 at 6:43













0












0








0







You want to decode [Recipe], that is, an Array of Recipe. That mean the first (non-whitespace) character in data has to be [ (to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data to a String and printing it:



print(String(data: data, encoding: .utf8))





share|improve this answer













You want to decode [Recipe], that is, an Array of Recipe. That mean the first (non-whitespace) character in data has to be [ (to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data to a String and printing it:



print(String(data: data, encoding: .utf8))






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 13 '18 at 6:04









rob mayoffrob mayoff

296k42598645




296k42598645












  • I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.

    – Jonathan Jordan
    Nov 13 '18 at 6:43

















  • I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.

    – Jonathan Jordan
    Nov 13 '18 at 6:43
















I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.

– Jonathan Jordan
Nov 13 '18 at 6:43





I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.

– Jonathan Jordan
Nov 13 '18 at 6:43

















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