If humans were biologically immortal, but had an average lifespan of 100 years, what would the distribution of ages be?










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Let's say that humans were biologically immortal. Once they reach adulthood, they effectively stop aging. Due to disease though, the average lifespan is 100 years. (In practice, your access to healthcare would have a huge effect on your lifespan, but we'll ignore that for the purpose of this question, since it would make it much more difficult to answer.) For ease of answering this question, we'll say that distribution of lifespans is exactly an exponential distribution with mean 100 years.



Additionally, humans have hit the carrying capacity of the Earth, and so only reproduce to replace those who died. In particular, we'll assume that some sort of steady-state has been reached.



My question is, given these constraints, what would be the distribution of ages be? Basically what I'm looking for is an equation or graph that tells you how many people are at a given age.



Note that I'm talking about the current age, not the lifespan.






science-based immortality life







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  • 11




    $begingroup$
    "but we'll ignore that for the purpose of this question". You can't ignore it, since that's intrinsic to the answer. (Afghanistan and Monaco will have fundamentally different age-of-death distributions.)
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    – RonJohn
    Nov 13 '18 at 1:46






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    $begingroup$
    Just because you say to ignore a factor doesn't mean a reasonable answer can ignore that factor. (And "equal healthcare" doesn't say anything about the quality of the healthcare.)
    $endgroup$
    – RonJohn
    Nov 13 '18 at 2:17






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    at any rate, the longer one is alive, the likelier one is to contract a serious disease, just on the basis of extended risk. but the risk on any particular day is no more than any other (in contrast to mortals whose susceptibility increases). quantifying that would be way to much work for me, though. its an interesting question. i do expect that upon maturity, the probability graph is linear.
    $endgroup$
    – theRiley
    Nov 13 '18 at 4:25







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    Really interesting answers. But im not sure on how theres enough information to answer that question. Really curious.
    $endgroup$
    – user10645073
    Nov 13 '18 at 9:11






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    $begingroup$
    As it stands this question should be answered by a calculator or predictive modelling, not humans. You've declined or ruled out the factors that would make human interpretation useful.
    $endgroup$
    – nullpointer
    Nov 13 '18 at 13:02















2












$begingroup$


Let's say that humans were biologically immortal. Once they reach adulthood, they effectively stop aging. Due to disease though, the average lifespan is 100 years. (In practice, your access to healthcare would have a huge effect on your lifespan, but we'll ignore that for the purpose of this question, since it would make it much more difficult to answer.) For ease of answering this question, we'll say that distribution of lifespans is exactly an exponential distribution with mean 100 years.



Additionally, humans have hit the carrying capacity of the Earth, and so only reproduce to replace those who died. In particular, we'll assume that some sort of steady-state has been reached.



My question is, given these constraints, what would be the distribution of ages be? Basically what I'm looking for is an equation or graph that tells you how many people are at a given age.



Note that I'm talking about the current age, not the lifespan.






science-based immortality life







share|improve this question









$endgroup$







  • 11




    $begingroup$
    "but we'll ignore that for the purpose of this question". You can't ignore it, since that's intrinsic to the answer. (Afghanistan and Monaco will have fundamentally different age-of-death distributions.)
    $endgroup$
    – RonJohn
    Nov 13 '18 at 1:46






  • 2




    $begingroup$
    Just because you say to ignore a factor doesn't mean a reasonable answer can ignore that factor. (And "equal healthcare" doesn't say anything about the quality of the healthcare.)
    $endgroup$
    – RonJohn
    Nov 13 '18 at 2:17






  • 1




    $begingroup$
    at any rate, the longer one is alive, the likelier one is to contract a serious disease, just on the basis of extended risk. but the risk on any particular day is no more than any other (in contrast to mortals whose susceptibility increases). quantifying that would be way to much work for me, though. its an interesting question. i do expect that upon maturity, the probability graph is linear.
    $endgroup$
    – theRiley
    Nov 13 '18 at 4:25







  • 1




    $begingroup$
    Really interesting answers. But im not sure on how theres enough information to answer that question. Really curious.
    $endgroup$
    – user10645073
    Nov 13 '18 at 9:11






  • 1




    $begingroup$
    As it stands this question should be answered by a calculator or predictive modelling, not humans. You've declined or ruled out the factors that would make human interpretation useful.
    $endgroup$
    – nullpointer
    Nov 13 '18 at 13:02













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2








2


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$begingroup$


Let's say that humans were biologically immortal. Once they reach adulthood, they effectively stop aging. Due to disease though, the average lifespan is 100 years. (In practice, your access to healthcare would have a huge effect on your lifespan, but we'll ignore that for the purpose of this question, since it would make it much more difficult to answer.) For ease of answering this question, we'll say that distribution of lifespans is exactly an exponential distribution with mean 100 years.



Additionally, humans have hit the carrying capacity of the Earth, and so only reproduce to replace those who died. In particular, we'll assume that some sort of steady-state has been reached.



My question is, given these constraints, what would be the distribution of ages be? Basically what I'm looking for is an equation or graph that tells you how many people are at a given age.



Note that I'm talking about the current age, not the lifespan.






science-based immortality life







share|improve this question









$endgroup$




Let's say that humans were biologically immortal. Once they reach adulthood, they effectively stop aging. Due to disease though, the average lifespan is 100 years. (In practice, your access to healthcare would have a huge effect on your lifespan, but we'll ignore that for the purpose of this question, since it would make it much more difficult to answer.) For ease of answering this question, we'll say that distribution of lifespans is exactly an exponential distribution with mean 100 years.



Additionally, humans have hit the carrying capacity of the Earth, and so only reproduce to replace those who died. In particular, we'll assume that some sort of steady-state has been reached.



My question is, given these constraints, what would be the distribution of ages be? Basically what I'm looking for is an equation or graph that tells you how many people are at a given age.



Note that I'm talking about the current age, not the lifespan.






science-based immortality life




science-based immortality life






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 13 '18 at 1:18









PyRulezPyRulez

6,73233674




6,73233674







  • 11




    $begingroup$
    "but we'll ignore that for the purpose of this question". You can't ignore it, since that's intrinsic to the answer. (Afghanistan and Monaco will have fundamentally different age-of-death distributions.)
    $endgroup$
    – RonJohn
    Nov 13 '18 at 1:46






  • 2




    $begingroup$
    Just because you say to ignore a factor doesn't mean a reasonable answer can ignore that factor. (And "equal healthcare" doesn't say anything about the quality of the healthcare.)
    $endgroup$
    – RonJohn
    Nov 13 '18 at 2:17






  • 1




    $begingroup$
    at any rate, the longer one is alive, the likelier one is to contract a serious disease, just on the basis of extended risk. but the risk on any particular day is no more than any other (in contrast to mortals whose susceptibility increases). quantifying that would be way to much work for me, though. its an interesting question. i do expect that upon maturity, the probability graph is linear.
    $endgroup$
    – theRiley
    Nov 13 '18 at 4:25







  • 1




    $begingroup$
    Really interesting answers. But im not sure on how theres enough information to answer that question. Really curious.
    $endgroup$
    – user10645073
    Nov 13 '18 at 9:11






  • 1




    $begingroup$
    As it stands this question should be answered by a calculator or predictive modelling, not humans. You've declined or ruled out the factors that would make human interpretation useful.
    $endgroup$
    – nullpointer
    Nov 13 '18 at 13:02












  • 11




    $begingroup$
    "but we'll ignore that for the purpose of this question". You can't ignore it, since that's intrinsic to the answer. (Afghanistan and Monaco will have fundamentally different age-of-death distributions.)
    $endgroup$
    – RonJohn
    Nov 13 '18 at 1:46






  • 2




    $begingroup$
    Just because you say to ignore a factor doesn't mean a reasonable answer can ignore that factor. (And "equal healthcare" doesn't say anything about the quality of the healthcare.)
    $endgroup$
    – RonJohn
    Nov 13 '18 at 2:17






  • 1




    $begingroup$
    at any rate, the longer one is alive, the likelier one is to contract a serious disease, just on the basis of extended risk. but the risk on any particular day is no more than any other (in contrast to mortals whose susceptibility increases). quantifying that would be way to much work for me, though. its an interesting question. i do expect that upon maturity, the probability graph is linear.
    $endgroup$
    – theRiley
    Nov 13 '18 at 4:25







  • 1




    $begingroup$
    Really interesting answers. But im not sure on how theres enough information to answer that question. Really curious.
    $endgroup$
    – user10645073
    Nov 13 '18 at 9:11






  • 1




    $begingroup$
    As it stands this question should be answered by a calculator or predictive modelling, not humans. You've declined or ruled out the factors that would make human interpretation useful.
    $endgroup$
    – nullpointer
    Nov 13 '18 at 13:02







11




11




$begingroup$
"but we'll ignore that for the purpose of this question". You can't ignore it, since that's intrinsic to the answer. (Afghanistan and Monaco will have fundamentally different age-of-death distributions.)
$endgroup$
– RonJohn
Nov 13 '18 at 1:46




$begingroup$
"but we'll ignore that for the purpose of this question". You can't ignore it, since that's intrinsic to the answer. (Afghanistan and Monaco will have fundamentally different age-of-death distributions.)
$endgroup$
– RonJohn
Nov 13 '18 at 1:46




2




2




$begingroup$
Just because you say to ignore a factor doesn't mean a reasonable answer can ignore that factor. (And "equal healthcare" doesn't say anything about the quality of the healthcare.)
$endgroup$
– RonJohn
Nov 13 '18 at 2:17




$begingroup$
Just because you say to ignore a factor doesn't mean a reasonable answer can ignore that factor. (And "equal healthcare" doesn't say anything about the quality of the healthcare.)
$endgroup$
– RonJohn
Nov 13 '18 at 2:17




1




1




$begingroup$
at any rate, the longer one is alive, the likelier one is to contract a serious disease, just on the basis of extended risk. but the risk on any particular day is no more than any other (in contrast to mortals whose susceptibility increases). quantifying that would be way to much work for me, though. its an interesting question. i do expect that upon maturity, the probability graph is linear.
$endgroup$
– theRiley
Nov 13 '18 at 4:25





$begingroup$
at any rate, the longer one is alive, the likelier one is to contract a serious disease, just on the basis of extended risk. but the risk on any particular day is no more than any other (in contrast to mortals whose susceptibility increases). quantifying that would be way to much work for me, though. its an interesting question. i do expect that upon maturity, the probability graph is linear.
$endgroup$
– theRiley
Nov 13 '18 at 4:25





1




1




$begingroup$
Really interesting answers. But im not sure on how theres enough information to answer that question. Really curious.
$endgroup$
– user10645073
Nov 13 '18 at 9:11




$begingroup$
Really interesting answers. But im not sure on how theres enough information to answer that question. Really curious.
$endgroup$
– user10645073
Nov 13 '18 at 9:11




1




1




$begingroup$
As it stands this question should be answered by a calculator or predictive modelling, not humans. You've declined or ruled out the factors that would make human interpretation useful.
$endgroup$
– nullpointer
Nov 13 '18 at 13:02




$begingroup$
As it stands this question should be answered by a calculator or predictive modelling, not humans. You've declined or ruled out the factors that would make human interpretation useful.
$endgroup$
– nullpointer
Nov 13 '18 at 13:02










6 Answers
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Curve describing distribution of age of death is:
$$
frace^-fracx100100
$$
Use whatever plotting program you want to have it visualised



It's easily found by normalising to $1$, finding average and using preset average of 100:
$$
int_0^inftya*e^-x*b=fracab=1
$$
$$
fracint_0^infty a*x*e^-x*bint_0^inftya*e^-x*b = fracfracab^2fracab=frac1b=100
$$
hence $a=b$ and $b=frac1100$.



Assuming that your population is stable and has not experienced any advancements in medicine in last 2000 years (assuming population of 1 billion, age of 1612 is moment when expected number of people drops below 1, so we can safely assume that no one survives to age of 2000), distribution of ages in population will look exactly like age of death distribution, just multiplied by population. For 7 billion, it's:
$$
7*10^7 e^-fracx100
$$
This is because you made some very simplifying assumptions, which you forgot to take to logical end. Making distributions of lifespans exponential you have de facto introduced yearly death rate (about 1%, because $frace^-frac1100100 approx 0.99$), independent to anything. Infant has same chance to die next year as 1500 years old great$^70$grandfather (or 1000000 years old). Every single person has same chance to die per year. Every generation will shrink by fraction equal to chance of death. It also means that total number of deaths is constant and equal to size of population times chance of death, and as infants born to replenish population age, they die off each year in exactly same exponential way, year younger bracket is smaller by chance of death fraction and year older group is larger by chance of death fraction. Because of that, age distribution is exact same as lifespan distribution.



If there have been any changes in medicine that might have impacted lifespan (or rather yearly chance of death, because that metric is more useful in your population) or any wars and catastrophes that might have killed abnormally many people, there is insufficient data to provide answer; you have to define those advancements and/or wars/catastrophes.






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    $begingroup$
    @PyRulez Please do not introduce errors when editing answers. You removed normalisation constant ($frac1100$) in your edit.
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    – M i ech
    Nov 13 '18 at 14:06






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    Oh whoops, sorry. Was not intentional.
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    – PyRulez
    Nov 13 '18 at 14:07










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    Also, "If there have been any changes in medicine that might have impacted lifespan (or rather yearly chance of death, because that metric is more useful in your population) or any wars and catastrophes that might have killed abnormally many people, there is insufficient data to provide answer; you have to define those advancements and/or wars/catastrophes." At that point, I would just do a discrete simulation myself. I'm not going to make worldbuilding.se do all my math.
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    – PyRulez
    Nov 13 '18 at 14:08










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    Also, its kinda counterintuitive that they are essentially the same. You'd think that average age would be less than average lifespan, since the age of any living person is less than their lifespan.
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    – PyRulez
    Nov 13 '18 at 14:52






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    @Arthur: If everyone dies at exactly 100 then your chance of dying isn't uniform, which is one of the constraints of the question and the one that makes that point work. Think of it as a sampling exercise. If the 'dead' people are sampled from the population of 'alive' people with a uniform chance of sampling then the 'dead' sample will inevitably look like the 'alive' distribution, as long as you have enough people and the 'alive' distribution doesn't change over time. If you only sample people at age 100 then of course the two won't look the same.
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    – Joe Bloggs
    Nov 13 '18 at 16:38


















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Since you want an exact Exponential Distribution with a mean of 100, I just found an online calculator and put in it for you. Just multiply the Y Axis by your total population.



I know this might be viewed as a tongue in cheek answer but you did literally say we'll say that distribution of lifespans is exactly an exponential distribution with mean 100 years and In particular, we'll assume that some sort of steady-state has been reached.



Now if you factored in something different, like the fatality rate from ages 0-5 is 500% higher and the fatality rate from ages 100+ is 500% higher, you might get some more interesting looking curves. But you have basically told us the answer in your question. An exponential distribution with mean 100 years.



https://mathcracker.com/exponential-probability-calculator.php#results



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    $begingroup$
    This. Exactly, in fact.
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    – Joe Bloggs
    Nov 13 '18 at 13:36










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    Sigh, the lifespan (i.e. age of death) follows an exponential distribution. I was asking about the current age.
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    – PyRulez
    Nov 13 '18 at 13:45










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    @PyRulez Your current rules specify an exponential distribution, and a mean age of 100 years. This predetermines the shape of the distribution to e^-(1/100). BUT: How many people are there in any given age group? This is not solveable unless you tell us how many people there are in total, which you did not do. You also did not specify whether this is steady-state or not (as the people stop aging in a fertile bracket, it would need some pretty good family planning to not be runaway...)
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    – bukwyrm
    Nov 13 '18 at 14:03










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    @bukwyrm The question said mean lifespan of 100 years, not mean age of 100 years.
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    – PyRulez
    Nov 13 '18 at 14:06










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    @PyRulez If, after a looong time, you ask everyone who lived how old they were when they died, and if this is a steady state, mean age is mean span. If this is not steady state, we need to know in what way - did immortality suddenly set on? at what historic population distribution & size? what was the breeding pattern afterwards?
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    – bukwyrm
    Nov 13 '18 at 14:17



















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Asymptotic curve



1% death rate



The average age of this population is 99.
I did this in a way I could wrap my head around it, using excel.



Imagine that each year 1% of each birth cohort dies of disease or accidents. You have a population of 1,000,000. Your biggest cohort is of course infants: you have 10000 of them and they are 1% of your population. 1% die and your population of 1 year olds is 9900. 1% die and your population of 2 year olds is 9801.



Each year, the 1% that is subtracted from the population is a smaller amount. That gives you an asymptotic curve as in the diagram above.



I wish my math were good enough to provide a multiplier such that for any age you could figure the # of individuals of that age in the population of 1,000,000. But I did it up in excel to make the graph. Lacking elegant math, I would make the graph and then use the curve to approximate number of individuals of any given age.



In my model (with average age 99; I think because of rounding) there were 3660 100 year old individuals comprising 0.366% of the population. There were 9 700 year olds and, of course, 1 1000 year old.






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    I'm not sure the actual numbers being presented here are either correct or relevant but the structure of the resulting population almost certainly is.
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    – Ash
    Nov 13 '18 at 9:41











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    This is known as a geometric distribution, with the parameter $p$ as the chance of dying in any specific year.
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    – A Simmons
    Nov 13 '18 at 9:48


















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I don't think there's enough information available to give a concrete answer to this. Maybe someone else can, but I don't think it's possible.



So much depends on things we don't know, such as how long this has been going on, and when/how this immortality began.



Here's what I mean: If this technology/magic were instituted immediately it means that, in general, we'd expect each person to die, a hundred years from their DOB. (As an average) If this took place in the modern U.S. the generations would be locked into rolling waves.



For example, according to wiki 1.8% of the population is 85 or older. Based on your criteria, when that generation dies, it is replaced with exactly the same number of new births.



So what happens is that the age distribution numbers are almost the same, but switch places. That 1.8% drops to the 'bottom' of the age distribution. 80-85 years later, the wave 'peaks' and what used to be 15-19 year olds at ~7% of the population are now all about 100 years old.



It won't be exact, but if that's close to how one scenario would play out. You'd have to remove the percentages of deaths that are from most 'natural causes' while keeping deaths by accident, contagious disease, homicide and suicide, you'd need some noise, and the math would be pretty granular, but stick to the general 'wave' pattern.



Or



It takes effect by socioeconomic strata, or by state mandate, etc. And depending on how long this has been going on, given the admitted population controls, it could be literally anything you wanted it to be. A society could have it locked at 1% birth rate, every year, into eternity.






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    But the world is living longer, and having fewer children. That's already changing the distribution.
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    – RonJohn
    Nov 13 '18 at 3:04










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    @RonJohn which is entirely irrelevant, if the premise of this question takes place immediately.
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    – user49466
    Nov 13 '18 at 3:51






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    why should we assume the change takes place immediately. why not assume a gaussian distribution, or even a flat distribution and let things equilibrate? i'm not a math wizard, though, so maybe i'm all wet here. that assumption just seems arbitrary. best of all would be an 'in the wild' human population in the pre-industrial age, or paleolithic age.
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    – theRiley
    Nov 13 '18 at 4:43










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    @Theriley I'm not assuming that. I stated that how the change takes place, how long it's been, etc, will effect the distribution, and used this as an example. It's up to the OP to set the ground rules.
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    – user49466
    Nov 13 '18 at 4:46










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    i see. thanks for the clarification.
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    – theRiley
    Nov 13 '18 at 5:44


















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The first thing we have to look at is a population pyramid. Below is the 2015 pyramid from CIA world factbook data.



Population pyramid 2015
https://www.indexmundi.com/world/age_structure.html



We currently have a hint of population growth at the bottom, then dropping off through to an upper limit of around 100. Median age of 30.4. (You've asked for average age rather than median age, this is far harder to calculate.)



Since you have stated a static population, with good healthcare in peacetime, the pyramid should be less of a pyramid and more of a column, starting to taper off where aggregate accident rates and incurable medical conditions start to kill people off.



An aging population would be narrow at the bottom with a bulge higher up. A growing population is more a classic pyramid.



A quick and dirty answer would be to extend the above pyramid age ranges 3fold, but of course this pyramid is limited by natural age limitations hence would not be valid.



The shape you're looking for is going to be a cumulative normal distribution of death rates rather than a clean exponential decay as others have suggested.






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    Lets say there a thousand humans (a really small earth).
    If we distributed them roughly across ages so they balance out at 100. I could have a:



    • very dense demographic with lots of 100 year olds.

    • a split demographic with many young individuals say 10-20, and many older individuals 180-190.

    • or some kind of flat demographic ~5 people of each age between 0 and 200.

    That is the distribution you've described. Take your pick.



    If you want something more realistic... (and grossly oversimplified).



    Then lets consider mortality. Without aging doing any killing by itself, you'll find that we die purely from disease and accidents. This probably won't change the mortality rate very much. I'll draw some figures from Australian adult deaths. So roughly 0.0468% to 0.0782% of the population dies due to something.



    That's about 46-78 dead humans a year (in our thousand human population). So about that many births per year.



    • 78 one year olds

    • 73 two year olds

    • 65 three year olds

    • 63 four year olds

    • 20 five year olds

    • 15 six year olds

    • 80 six year olds

    • 45 seven year olds

    • 46 eight year olds

    • 48 nine year olds

    • 20 ten year olds

    • 72 eleven year olds

    • 12 twelve year olds

    • 22 thirteen year olds

    • 46 fourteen year olds

    • 23 fifteen year olds

    • 31 sixteen year olds

    • 87 seventeen year olds

    • 44 eighteen year olds

    • 38 nineteen year olds

    • 22 twenty year olds

    • 56 twenty-one year olds

    • 64 twenty-two year olds

    and because of the small population cap, 51 people are executed at random. But if you raised it, to something more manageable, you'll see that this roughly makes a flat population that will slowly taper out (at the rate of a 5 hundredths of a percent).



    Lets see what this population looks like, but with no ritualised forced deaths, and every member living till natural causes (like accidents) kill them. Lets also keep that median straight on top of 100 (roughly speaking).



    • A is the number of 100 year olds

    • B is the total number of years past 100 that the oldest individual (roughly) is.

    • C is half the total population.

    • D is the death rate.

    • E is the eldest member.

    • Y is the total number of new borns.

    • X is the difference between the total 100 year olds, and the total newborns.


    • X = 100 * D


    • Y = A + X

    • A = B * D

    • C = 100 * X / 2 + 100 * A

    • C = A * B / 2

    • E = 100 + B

    This is represents two triangles and a rectangle like:



     *
     **
     * *
    X* *
     * *
     +****+
     * **
     * * *
    A* * *
     * * *
     * * *
     *****+******
     100 B


    So assuming D = 0.0005



    • X = 0.05

    • A = B * 0.0005

    • B = (1/0.0005) * A

    • B = 2000 * A

    • C = A * B / 2

    • C = A * (2000 * A) / 2

    • C = 1000 * A * A


    • C = 100 * 0.05 / 2 + 100 * A


    • C = 100 * A + 2.5


    • C = C


    • 100 * A + 2.5 = 1000 * A * A

    • 0 = 1000 * A * A - 100 * A - 2.5

    • A ~= 0.12071...


    • A = B * D


    • B = A / D

    • B ~= 0.12071 / 0.0005

    • B ~= 241.42


    • Y = A + X


    • Y ~= 0.12071 + 0.05


    • E = 100 + B


    • E = 100 + 241.42

    • E = 341.42

    So the oldest thing is roughly 341.42 years old.
    And their lives one 17th of a newborn. For a median age of 100. (Statistically speaking). That is a total average population of 341.42 * 0.17071 / 2 ~= 29.141 individuals.



    29 people isn't a satisfying population. Its an almost extinct one. Lets take the approximately 7 billion people alive today, and give them a shot of immortality. and institute the replacement only birth rate, with the constant death rate of 0.0005. (Lets say immortality makes people more adventurous and take on risks, without learning much about avoiding them). Fast forward many years and allow the natural randomness to even out a little, (so that I can use the simple triangle model and ignore every other event).



     *
     **
     * * C
    A* D*
     * *
     +****+
     B


    • D = 7,000,000,000

    • D = A * B / 2

    • C = A / B

    • C = 0.0005


    • A/B = 0.0005


    • A = 0.0005 * B

    • 7,000,000,000 = A * B / 2

    • 7,000,000,000 = 0.0005 * B * B / 2

    • 7,000,000,000 * 2 / 0.0005 = B * B

    • B * B = 28,000,000,000,000

    • B ~= 5,291,502.62

    • A = 0.0005 * B

    • A = 2645.75

    So natural causes gives the oldest person at about 5.3 million years old. Most people would have "accidentally" died by now.



    Also there are around 2645 new infants born every year. This means a mere 6 average-large sized schools of each level of education are sufficient for educating the entire population. Imagine that, overnight most of the worlds schools can just be shutdown. Of course there will now be a large upswing in golf-course requirements.



    Hope this helps paint a very crude picture.






    share|improve this answer









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      6 Answers
      6






      active

      oldest

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      6 Answers
      6






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      11












      $begingroup$

      Curve describing distribution of age of death is:
      $$
      frace^-fracx100100
      $$
      Use whatever plotting program you want to have it visualised



      It's easily found by normalising to $1$, finding average and using preset average of 100:
      $$
      int_0^inftya*e^-x*b=fracab=1
      $$
      $$
      fracint_0^infty a*x*e^-x*bint_0^inftya*e^-x*b = fracfracab^2fracab=frac1b=100
      $$
      hence $a=b$ and $b=frac1100$.



      Assuming that your population is stable and has not experienced any advancements in medicine in last 2000 years (assuming population of 1 billion, age of 1612 is moment when expected number of people drops below 1, so we can safely assume that no one survives to age of 2000), distribution of ages in population will look exactly like age of death distribution, just multiplied by population. For 7 billion, it's:
      $$
      7*10^7 e^-fracx100
      $$
      This is because you made some very simplifying assumptions, which you forgot to take to logical end. Making distributions of lifespans exponential you have de facto introduced yearly death rate (about 1%, because $frace^-frac1100100 approx 0.99$), independent to anything. Infant has same chance to die next year as 1500 years old great$^70$grandfather (or 1000000 years old). Every single person has same chance to die per year. Every generation will shrink by fraction equal to chance of death. It also means that total number of deaths is constant and equal to size of population times chance of death, and as infants born to replenish population age, they die off each year in exactly same exponential way, year younger bracket is smaller by chance of death fraction and year older group is larger by chance of death fraction. Because of that, age distribution is exact same as lifespan distribution.



      If there have been any changes in medicine that might have impacted lifespan (or rather yearly chance of death, because that metric is more useful in your population) or any wars and catastrophes that might have killed abnormally many people, there is insufficient data to provide answer; you have to define those advancements and/or wars/catastrophes.






      share|improve this answer











      $endgroup$








      • 2




        $begingroup$
        @PyRulez Please do not introduce errors when editing answers. You removed normalisation constant ($frac1100$) in your edit.
        $endgroup$
        – M i ech
        Nov 13 '18 at 14:06






      • 1




        $begingroup$
        Oh whoops, sorry. Was not intentional.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 14:07










      • $begingroup$
        Also, "If there have been any changes in medicine that might have impacted lifespan (or rather yearly chance of death, because that metric is more useful in your population) or any wars and catastrophes that might have killed abnormally many people, there is insufficient data to provide answer; you have to define those advancements and/or wars/catastrophes." At that point, I would just do a discrete simulation myself. I'm not going to make worldbuilding.se do all my math.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 14:08










      • $begingroup$
        Also, its kinda counterintuitive that they are essentially the same. You'd think that average age would be less than average lifespan, since the age of any living person is less than their lifespan.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 14:52






      • 2




        $begingroup$
        @Arthur: If everyone dies at exactly 100 then your chance of dying isn't uniform, which is one of the constraints of the question and the one that makes that point work. Think of it as a sampling exercise. If the 'dead' people are sampled from the population of 'alive' people with a uniform chance of sampling then the 'dead' sample will inevitably look like the 'alive' distribution, as long as you have enough people and the 'alive' distribution doesn't change over time. If you only sample people at age 100 then of course the two won't look the same.
        $endgroup$
        – Joe Bloggs
        Nov 13 '18 at 16:38















      11












      $begingroup$

      Curve describing distribution of age of death is:
      $$
      frace^-fracx100100
      $$
      Use whatever plotting program you want to have it visualised



      It's easily found by normalising to $1$, finding average and using preset average of 100:
      $$
      int_0^inftya*e^-x*b=fracab=1
      $$
      $$
      fracint_0^infty a*x*e^-x*bint_0^inftya*e^-x*b = fracfracab^2fracab=frac1b=100
      $$
      hence $a=b$ and $b=frac1100$.



      Assuming that your population is stable and has not experienced any advancements in medicine in last 2000 years (assuming population of 1 billion, age of 1612 is moment when expected number of people drops below 1, so we can safely assume that no one survives to age of 2000), distribution of ages in population will look exactly like age of death distribution, just multiplied by population. For 7 billion, it's:
      $$
      7*10^7 e^-fracx100
      $$
      This is because you made some very simplifying assumptions, which you forgot to take to logical end. Making distributions of lifespans exponential you have de facto introduced yearly death rate (about 1%, because $frace^-frac1100100 approx 0.99$), independent to anything. Infant has same chance to die next year as 1500 years old great$^70$grandfather (or 1000000 years old). Every single person has same chance to die per year. Every generation will shrink by fraction equal to chance of death. It also means that total number of deaths is constant and equal to size of population times chance of death, and as infants born to replenish population age, they die off each year in exactly same exponential way, year younger bracket is smaller by chance of death fraction and year older group is larger by chance of death fraction. Because of that, age distribution is exact same as lifespan distribution.



      If there have been any changes in medicine that might have impacted lifespan (or rather yearly chance of death, because that metric is more useful in your population) or any wars and catastrophes that might have killed abnormally many people, there is insufficient data to provide answer; you have to define those advancements and/or wars/catastrophes.






      share|improve this answer











      $endgroup$








      • 2




        $begingroup$
        @PyRulez Please do not introduce errors when editing answers. You removed normalisation constant ($frac1100$) in your edit.
        $endgroup$
        – M i ech
        Nov 13 '18 at 14:06






      • 1




        $begingroup$
        Oh whoops, sorry. Was not intentional.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 14:07










      • $begingroup$
        Also, "If there have been any changes in medicine that might have impacted lifespan (or rather yearly chance of death, because that metric is more useful in your population) or any wars and catastrophes that might have killed abnormally many people, there is insufficient data to provide answer; you have to define those advancements and/or wars/catastrophes." At that point, I would just do a discrete simulation myself. I'm not going to make worldbuilding.se do all my math.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 14:08










      • $begingroup$
        Also, its kinda counterintuitive that they are essentially the same. You'd think that average age would be less than average lifespan, since the age of any living person is less than their lifespan.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 14:52






      • 2




        $begingroup$
        @Arthur: If everyone dies at exactly 100 then your chance of dying isn't uniform, which is one of the constraints of the question and the one that makes that point work. Think of it as a sampling exercise. If the 'dead' people are sampled from the population of 'alive' people with a uniform chance of sampling then the 'dead' sample will inevitably look like the 'alive' distribution, as long as you have enough people and the 'alive' distribution doesn't change over time. If you only sample people at age 100 then of course the two won't look the same.
        $endgroup$
        – Joe Bloggs
        Nov 13 '18 at 16:38













      11












      11








      11





      $begingroup$

      Curve describing distribution of age of death is:
      $$
      frace^-fracx100100
      $$
      Use whatever plotting program you want to have it visualised



      It's easily found by normalising to $1$, finding average and using preset average of 100:
      $$
      int_0^inftya*e^-x*b=fracab=1
      $$
      $$
      fracint_0^infty a*x*e^-x*bint_0^inftya*e^-x*b = fracfracab^2fracab=frac1b=100
      $$
      hence $a=b$ and $b=frac1100$.



      Assuming that your population is stable and has not experienced any advancements in medicine in last 2000 years (assuming population of 1 billion, age of 1612 is moment when expected number of people drops below 1, so we can safely assume that no one survives to age of 2000), distribution of ages in population will look exactly like age of death distribution, just multiplied by population. For 7 billion, it's:
      $$
      7*10^7 e^-fracx100
      $$
      This is because you made some very simplifying assumptions, which you forgot to take to logical end. Making distributions of lifespans exponential you have de facto introduced yearly death rate (about 1%, because $frace^-frac1100100 approx 0.99$), independent to anything. Infant has same chance to die next year as 1500 years old great$^70$grandfather (or 1000000 years old). Every single person has same chance to die per year. Every generation will shrink by fraction equal to chance of death. It also means that total number of deaths is constant and equal to size of population times chance of death, and as infants born to replenish population age, they die off each year in exactly same exponential way, year younger bracket is smaller by chance of death fraction and year older group is larger by chance of death fraction. Because of that, age distribution is exact same as lifespan distribution.



      If there have been any changes in medicine that might have impacted lifespan (or rather yearly chance of death, because that metric is more useful in your population) or any wars and catastrophes that might have killed abnormally many people, there is insufficient data to provide answer; you have to define those advancements and/or wars/catastrophes.






      share|improve this answer











      $endgroup$



      Curve describing distribution of age of death is:
      $$
      frace^-fracx100100
      $$
      Use whatever plotting program you want to have it visualised



      It's easily found by normalising to $1$, finding average and using preset average of 100:
      $$
      int_0^inftya*e^-x*b=fracab=1
      $$
      $$
      fracint_0^infty a*x*e^-x*bint_0^inftya*e^-x*b = fracfracab^2fracab=frac1b=100
      $$
      hence $a=b$ and $b=frac1100$.



      Assuming that your population is stable and has not experienced any advancements in medicine in last 2000 years (assuming population of 1 billion, age of 1612 is moment when expected number of people drops below 1, so we can safely assume that no one survives to age of 2000), distribution of ages in population will look exactly like age of death distribution, just multiplied by population. For 7 billion, it's:
      $$
      7*10^7 e^-fracx100
      $$
      This is because you made some very simplifying assumptions, which you forgot to take to logical end. Making distributions of lifespans exponential you have de facto introduced yearly death rate (about 1%, because $frace^-frac1100100 approx 0.99$), independent to anything. Infant has same chance to die next year as 1500 years old great$^70$grandfather (or 1000000 years old). Every single person has same chance to die per year. Every generation will shrink by fraction equal to chance of death. It also means that total number of deaths is constant and equal to size of population times chance of death, and as infants born to replenish population age, they die off each year in exactly same exponential way, year younger bracket is smaller by chance of death fraction and year older group is larger by chance of death fraction. Because of that, age distribution is exact same as lifespan distribution.



      If there have been any changes in medicine that might have impacted lifespan (or rather yearly chance of death, because that metric is more useful in your population) or any wars and catastrophes that might have killed abnormally many people, there is insufficient data to provide answer; you have to define those advancements and/or wars/catastrophes.







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Nov 13 '18 at 14:15

























      answered Nov 13 '18 at 10:03









      M i echM i ech

      4,96911734




      4,96911734







      • 2




        $begingroup$
        @PyRulez Please do not introduce errors when editing answers. You removed normalisation constant ($frac1100$) in your edit.
        $endgroup$
        – M i ech
        Nov 13 '18 at 14:06






      • 1




        $begingroup$
        Oh whoops, sorry. Was not intentional.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 14:07










      • $begingroup$
        Also, "If there have been any changes in medicine that might have impacted lifespan (or rather yearly chance of death, because that metric is more useful in your population) or any wars and catastrophes that might have killed abnormally many people, there is insufficient data to provide answer; you have to define those advancements and/or wars/catastrophes." At that point, I would just do a discrete simulation myself. I'm not going to make worldbuilding.se do all my math.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 14:08










      • $begingroup$
        Also, its kinda counterintuitive that they are essentially the same. You'd think that average age would be less than average lifespan, since the age of any living person is less than their lifespan.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 14:52






      • 2




        $begingroup$
        @Arthur: If everyone dies at exactly 100 then your chance of dying isn't uniform, which is one of the constraints of the question and the one that makes that point work. Think of it as a sampling exercise. If the 'dead' people are sampled from the population of 'alive' people with a uniform chance of sampling then the 'dead' sample will inevitably look like the 'alive' distribution, as long as you have enough people and the 'alive' distribution doesn't change over time. If you only sample people at age 100 then of course the two won't look the same.
        $endgroup$
        – Joe Bloggs
        Nov 13 '18 at 16:38












      • 2




        $begingroup$
        @PyRulez Please do not introduce errors when editing answers. You removed normalisation constant ($frac1100$) in your edit.
        $endgroup$
        – M i ech
        Nov 13 '18 at 14:06






      • 1




        $begingroup$
        Oh whoops, sorry. Was not intentional.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 14:07










      • $begingroup$
        Also, "If there have been any changes in medicine that might have impacted lifespan (or rather yearly chance of death, because that metric is more useful in your population) or any wars and catastrophes that might have killed abnormally many people, there is insufficient data to provide answer; you have to define those advancements and/or wars/catastrophes." At that point, I would just do a discrete simulation myself. I'm not going to make worldbuilding.se do all my math.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 14:08










      • $begingroup$
        Also, its kinda counterintuitive that they are essentially the same. You'd think that average age would be less than average lifespan, since the age of any living person is less than their lifespan.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 14:52






      • 2




        $begingroup$
        @Arthur: If everyone dies at exactly 100 then your chance of dying isn't uniform, which is one of the constraints of the question and the one that makes that point work. Think of it as a sampling exercise. If the 'dead' people are sampled from the population of 'alive' people with a uniform chance of sampling then the 'dead' sample will inevitably look like the 'alive' distribution, as long as you have enough people and the 'alive' distribution doesn't change over time. If you only sample people at age 100 then of course the two won't look the same.
        $endgroup$
        – Joe Bloggs
        Nov 13 '18 at 16:38







      2




      2




      $begingroup$
      @PyRulez Please do not introduce errors when editing answers. You removed normalisation constant ($frac1100$) in your edit.
      $endgroup$
      – M i ech
      Nov 13 '18 at 14:06




      $begingroup$
      @PyRulez Please do not introduce errors when editing answers. You removed normalisation constant ($frac1100$) in your edit.
      $endgroup$
      – M i ech
      Nov 13 '18 at 14:06




      1




      1




      $begingroup$
      Oh whoops, sorry. Was not intentional.
      $endgroup$
      – PyRulez
      Nov 13 '18 at 14:07




      $begingroup$
      Oh whoops, sorry. Was not intentional.
      $endgroup$
      – PyRulez
      Nov 13 '18 at 14:07












      $begingroup$
      Also, "If there have been any changes in medicine that might have impacted lifespan (or rather yearly chance of death, because that metric is more useful in your population) or any wars and catastrophes that might have killed abnormally many people, there is insufficient data to provide answer; you have to define those advancements and/or wars/catastrophes." At that point, I would just do a discrete simulation myself. I'm not going to make worldbuilding.se do all my math.
      $endgroup$
      – PyRulez
      Nov 13 '18 at 14:08




      $begingroup$
      Also, "If there have been any changes in medicine that might have impacted lifespan (or rather yearly chance of death, because that metric is more useful in your population) or any wars and catastrophes that might have killed abnormally many people, there is insufficient data to provide answer; you have to define those advancements and/or wars/catastrophes." At that point, I would just do a discrete simulation myself. I'm not going to make worldbuilding.se do all my math.
      $endgroup$
      – PyRulez
      Nov 13 '18 at 14:08












      $begingroup$
      Also, its kinda counterintuitive that they are essentially the same. You'd think that average age would be less than average lifespan, since the age of any living person is less than their lifespan.
      $endgroup$
      – PyRulez
      Nov 13 '18 at 14:52




      $begingroup$
      Also, its kinda counterintuitive that they are essentially the same. You'd think that average age would be less than average lifespan, since the age of any living person is less than their lifespan.
      $endgroup$
      – PyRulez
      Nov 13 '18 at 14:52




      2




      2




      $begingroup$
      @Arthur: If everyone dies at exactly 100 then your chance of dying isn't uniform, which is one of the constraints of the question and the one that makes that point work. Think of it as a sampling exercise. If the 'dead' people are sampled from the population of 'alive' people with a uniform chance of sampling then the 'dead' sample will inevitably look like the 'alive' distribution, as long as you have enough people and the 'alive' distribution doesn't change over time. If you only sample people at age 100 then of course the two won't look the same.
      $endgroup$
      – Joe Bloggs
      Nov 13 '18 at 16:38




      $begingroup$
      @Arthur: If everyone dies at exactly 100 then your chance of dying isn't uniform, which is one of the constraints of the question and the one that makes that point work. Think of it as a sampling exercise. If the 'dead' people are sampled from the population of 'alive' people with a uniform chance of sampling then the 'dead' sample will inevitably look like the 'alive' distribution, as long as you have enough people and the 'alive' distribution doesn't change over time. If you only sample people at age 100 then of course the two won't look the same.
      $endgroup$
      – Joe Bloggs
      Nov 13 '18 at 16:38











      11












      $begingroup$

      Since you want an exact Exponential Distribution with a mean of 100, I just found an online calculator and put in it for you. Just multiply the Y Axis by your total population.



      I know this might be viewed as a tongue in cheek answer but you did literally say we'll say that distribution of lifespans is exactly an exponential distribution with mean 100 years and In particular, we'll assume that some sort of steady-state has been reached.



      Now if you factored in something different, like the fatality rate from ages 0-5 is 500% higher and the fatality rate from ages 100+ is 500% higher, you might get some more interesting looking curves. But you have basically told us the answer in your question. An exponential distribution with mean 100 years.



      https://mathcracker.com/exponential-probability-calculator.php#results



      ## Heading ##






      share|improve this answer









      $endgroup$








      • 3




        $begingroup$
        This. Exactly, in fact.
        $endgroup$
        – Joe Bloggs
        Nov 13 '18 at 13:36










      • $begingroup$
        Sigh, the lifespan (i.e. age of death) follows an exponential distribution. I was asking about the current age.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 13:45










      • $begingroup$
        @PyRulez Your current rules specify an exponential distribution, and a mean age of 100 years. This predetermines the shape of the distribution to e^-(1/100). BUT: How many people are there in any given age group? This is not solveable unless you tell us how many people there are in total, which you did not do. You also did not specify whether this is steady-state or not (as the people stop aging in a fertile bracket, it would need some pretty good family planning to not be runaway...)
        $endgroup$
        – bukwyrm
        Nov 13 '18 at 14:03










      • $begingroup$
        @bukwyrm The question said mean lifespan of 100 years, not mean age of 100 years.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 14:06










      • $begingroup$
        @PyRulez If, after a looong time, you ask everyone who lived how old they were when they died, and if this is a steady state, mean age is mean span. If this is not steady state, we need to know in what way - did immortality suddenly set on? at what historic population distribution & size? what was the breeding pattern afterwards?
        $endgroup$
        – bukwyrm
        Nov 13 '18 at 14:17
















      11












      $begingroup$

      Since you want an exact Exponential Distribution with a mean of 100, I just found an online calculator and put in it for you. Just multiply the Y Axis by your total population.



      I know this might be viewed as a tongue in cheek answer but you did literally say we'll say that distribution of lifespans is exactly an exponential distribution with mean 100 years and In particular, we'll assume that some sort of steady-state has been reached.



      Now if you factored in something different, like the fatality rate from ages 0-5 is 500% higher and the fatality rate from ages 100+ is 500% higher, you might get some more interesting looking curves. But you have basically told us the answer in your question. An exponential distribution with mean 100 years.



      https://mathcracker.com/exponential-probability-calculator.php#results



      ## Heading ##






      share|improve this answer









      $endgroup$








      • 3




        $begingroup$
        This. Exactly, in fact.
        $endgroup$
        – Joe Bloggs
        Nov 13 '18 at 13:36










      • $begingroup$
        Sigh, the lifespan (i.e. age of death) follows an exponential distribution. I was asking about the current age.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 13:45










      • $begingroup$
        @PyRulez Your current rules specify an exponential distribution, and a mean age of 100 years. This predetermines the shape of the distribution to e^-(1/100). BUT: How many people are there in any given age group? This is not solveable unless you tell us how many people there are in total, which you did not do. You also did not specify whether this is steady-state or not (as the people stop aging in a fertile bracket, it would need some pretty good family planning to not be runaway...)
        $endgroup$
        – bukwyrm
        Nov 13 '18 at 14:03










      • $begingroup$
        @bukwyrm The question said mean lifespan of 100 years, not mean age of 100 years.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 14:06










      • $begingroup$
        @PyRulez If, after a looong time, you ask everyone who lived how old they were when they died, and if this is a steady state, mean age is mean span. If this is not steady state, we need to know in what way - did immortality suddenly set on? at what historic population distribution & size? what was the breeding pattern afterwards?
        $endgroup$
        – bukwyrm
        Nov 13 '18 at 14:17














      11












      11








      11





      $begingroup$

      Since you want an exact Exponential Distribution with a mean of 100, I just found an online calculator and put in it for you. Just multiply the Y Axis by your total population.



      I know this might be viewed as a tongue in cheek answer but you did literally say we'll say that distribution of lifespans is exactly an exponential distribution with mean 100 years and In particular, we'll assume that some sort of steady-state has been reached.



      Now if you factored in something different, like the fatality rate from ages 0-5 is 500% higher and the fatality rate from ages 100+ is 500% higher, you might get some more interesting looking curves. But you have basically told us the answer in your question. An exponential distribution with mean 100 years.



      https://mathcracker.com/exponential-probability-calculator.php#results



      ## Heading ##






      share|improve this answer









      $endgroup$



      Since you want an exact Exponential Distribution with a mean of 100, I just found an online calculator and put in it for you. Just multiply the Y Axis by your total population.



      I know this might be viewed as a tongue in cheek answer but you did literally say we'll say that distribution of lifespans is exactly an exponential distribution with mean 100 years and In particular, we'll assume that some sort of steady-state has been reached.



      Now if you factored in something different, like the fatality rate from ages 0-5 is 500% higher and the fatality rate from ages 100+ is 500% higher, you might get some more interesting looking curves. But you have basically told us the answer in your question. An exponential distribution with mean 100 years.



      https://mathcracker.com/exponential-probability-calculator.php#results



      ## Heading ##







      share|improve this answer












      share|improve this answer



      share|improve this answer










      answered Nov 13 '18 at 5:01









      ShadowzeeShadowzee

      9,4781843




      9,4781843







      • 3




        $begingroup$
        This. Exactly, in fact.
        $endgroup$
        – Joe Bloggs
        Nov 13 '18 at 13:36










      • $begingroup$
        Sigh, the lifespan (i.e. age of death) follows an exponential distribution. I was asking about the current age.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 13:45










      • $begingroup$
        @PyRulez Your current rules specify an exponential distribution, and a mean age of 100 years. This predetermines the shape of the distribution to e^-(1/100). BUT: How many people are there in any given age group? This is not solveable unless you tell us how many people there are in total, which you did not do. You also did not specify whether this is steady-state or not (as the people stop aging in a fertile bracket, it would need some pretty good family planning to not be runaway...)
        $endgroup$
        – bukwyrm
        Nov 13 '18 at 14:03










      • $begingroup$
        @bukwyrm The question said mean lifespan of 100 years, not mean age of 100 years.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 14:06










      • $begingroup$
        @PyRulez If, after a looong time, you ask everyone who lived how old they were when they died, and if this is a steady state, mean age is mean span. If this is not steady state, we need to know in what way - did immortality suddenly set on? at what historic population distribution & size? what was the breeding pattern afterwards?
        $endgroup$
        – bukwyrm
        Nov 13 '18 at 14:17













      • 3




        $begingroup$
        This. Exactly, in fact.
        $endgroup$
        – Joe Bloggs
        Nov 13 '18 at 13:36










      • $begingroup$
        Sigh, the lifespan (i.e. age of death) follows an exponential distribution. I was asking about the current age.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 13:45










      • $begingroup$
        @PyRulez Your current rules specify an exponential distribution, and a mean age of 100 years. This predetermines the shape of the distribution to e^-(1/100). BUT: How many people are there in any given age group? This is not solveable unless you tell us how many people there are in total, which you did not do. You also did not specify whether this is steady-state or not (as the people stop aging in a fertile bracket, it would need some pretty good family planning to not be runaway...)
        $endgroup$
        – bukwyrm
        Nov 13 '18 at 14:03










      • $begingroup$
        @bukwyrm The question said mean lifespan of 100 years, not mean age of 100 years.
        $endgroup$
        – PyRulez
        Nov 13 '18 at 14:06










      • $begingroup$
        @PyRulez If, after a looong time, you ask everyone who lived how old they were when they died, and if this is a steady state, mean age is mean span. If this is not steady state, we need to know in what way - did immortality suddenly set on? at what historic population distribution & size? what was the breeding pattern afterwards?
        $endgroup$
        – bukwyrm
        Nov 13 '18 at 14:17








      3




      3




      $begingroup$
      This. Exactly, in fact.
      $endgroup$
      – Joe Bloggs
      Nov 13 '18 at 13:36




      $begingroup$
      This. Exactly, in fact.
      $endgroup$
      – Joe Bloggs
      Nov 13 '18 at 13:36












      $begingroup$
      Sigh, the lifespan (i.e. age of death) follows an exponential distribution. I was asking about the current age.
      $endgroup$
      – PyRulez
      Nov 13 '18 at 13:45




      $begingroup$
      Sigh, the lifespan (i.e. age of death) follows an exponential distribution. I was asking about the current age.
      $endgroup$
      – PyRulez
      Nov 13 '18 at 13:45












      $begingroup$
      @PyRulez Your current rules specify an exponential distribution, and a mean age of 100 years. This predetermines the shape of the distribution to e^-(1/100). BUT: How many people are there in any given age group? This is not solveable unless you tell us how many people there are in total, which you did not do. You also did not specify whether this is steady-state or not (as the people stop aging in a fertile bracket, it would need some pretty good family planning to not be runaway...)
      $endgroup$
      – bukwyrm
      Nov 13 '18 at 14:03




      $begingroup$
      @PyRulez Your current rules specify an exponential distribution, and a mean age of 100 years. This predetermines the shape of the distribution to e^-(1/100). BUT: How many people are there in any given age group? This is not solveable unless you tell us how many people there are in total, which you did not do. You also did not specify whether this is steady-state or not (as the people stop aging in a fertile bracket, it would need some pretty good family planning to not be runaway...)
      $endgroup$
      – bukwyrm
      Nov 13 '18 at 14:03












      $begingroup$
      @bukwyrm The question said mean lifespan of 100 years, not mean age of 100 years.
      $endgroup$
      – PyRulez
      Nov 13 '18 at 14:06




      $begingroup$
      @bukwyrm The question said mean lifespan of 100 years, not mean age of 100 years.
      $endgroup$
      – PyRulez
      Nov 13 '18 at 14:06












      $begingroup$
      @PyRulez If, after a looong time, you ask everyone who lived how old they were when they died, and if this is a steady state, mean age is mean span. If this is not steady state, we need to know in what way - did immortality suddenly set on? at what historic population distribution & size? what was the breeding pattern afterwards?
      $endgroup$
      – bukwyrm
      Nov 13 '18 at 14:17





      $begingroup$
      @PyRulez If, after a looong time, you ask everyone who lived how old they were when they died, and if this is a steady state, mean age is mean span. If this is not steady state, we need to know in what way - did immortality suddenly set on? at what historic population distribution & size? what was the breeding pattern afterwards?
      $endgroup$
      – bukwyrm
      Nov 13 '18 at 14:17












      6












      $begingroup$

      Asymptotic curve



      1% death rate



      The average age of this population is 99.
      I did this in a way I could wrap my head around it, using excel.



      Imagine that each year 1% of each birth cohort dies of disease or accidents. You have a population of 1,000,000. Your biggest cohort is of course infants: you have 10000 of them and they are 1% of your population. 1% die and your population of 1 year olds is 9900. 1% die and your population of 2 year olds is 9801.



      Each year, the 1% that is subtracted from the population is a smaller amount. That gives you an asymptotic curve as in the diagram above.



      I wish my math were good enough to provide a multiplier such that for any age you could figure the # of individuals of that age in the population of 1,000,000. But I did it up in excel to make the graph. Lacking elegant math, I would make the graph and then use the curve to approximate number of individuals of any given age.



      In my model (with average age 99; I think because of rounding) there were 3660 100 year old individuals comprising 0.366% of the population. There were 9 700 year olds and, of course, 1 1000 year old.






      share|improve this answer









      $endgroup$








      • 2




        $begingroup$
        I'm not sure the actual numbers being presented here are either correct or relevant but the structure of the resulting population almost certainly is.
        $endgroup$
        – Ash
        Nov 13 '18 at 9:41











      • $begingroup$
        This is known as a geometric distribution, with the parameter $p$ as the chance of dying in any specific year.
        $endgroup$
        – A Simmons
        Nov 13 '18 at 9:48















      6












      $begingroup$

      Asymptotic curve



      1% death rate



      The average age of this population is 99.
      I did this in a way I could wrap my head around it, using excel.



      Imagine that each year 1% of each birth cohort dies of disease or accidents. You have a population of 1,000,000. Your biggest cohort is of course infants: you have 10000 of them and they are 1% of your population. 1% die and your population of 1 year olds is 9900. 1% die and your population of 2 year olds is 9801.



      Each year, the 1% that is subtracted from the population is a smaller amount. That gives you an asymptotic curve as in the diagram above.



      I wish my math were good enough to provide a multiplier such that for any age you could figure the # of individuals of that age in the population of 1,000,000. But I did it up in excel to make the graph. Lacking elegant math, I would make the graph and then use the curve to approximate number of individuals of any given age.



      In my model (with average age 99; I think because of rounding) there were 3660 100 year old individuals comprising 0.366% of the population. There were 9 700 year olds and, of course, 1 1000 year old.






      share|improve this answer









      $endgroup$








      • 2




        $begingroup$
        I'm not sure the actual numbers being presented here are either correct or relevant but the structure of the resulting population almost certainly is.
        $endgroup$
        – Ash
        Nov 13 '18 at 9:41











      • $begingroup$
        This is known as a geometric distribution, with the parameter $p$ as the chance of dying in any specific year.
        $endgroup$
        – A Simmons
        Nov 13 '18 at 9:48













      6












      6








      6





      $begingroup$

      Asymptotic curve



      1% death rate



      The average age of this population is 99.
      I did this in a way I could wrap my head around it, using excel.



      Imagine that each year 1% of each birth cohort dies of disease or accidents. You have a population of 1,000,000. Your biggest cohort is of course infants: you have 10000 of them and they are 1% of your population. 1% die and your population of 1 year olds is 9900. 1% die and your population of 2 year olds is 9801.



      Each year, the 1% that is subtracted from the population is a smaller amount. That gives you an asymptotic curve as in the diagram above.



      I wish my math were good enough to provide a multiplier such that for any age you could figure the # of individuals of that age in the population of 1,000,000. But I did it up in excel to make the graph. Lacking elegant math, I would make the graph and then use the curve to approximate number of individuals of any given age.



      In my model (with average age 99; I think because of rounding) there were 3660 100 year old individuals comprising 0.366% of the population. There were 9 700 year olds and, of course, 1 1000 year old.






      share|improve this answer









      $endgroup$



      Asymptotic curve



      1% death rate



      The average age of this population is 99.
      I did this in a way I could wrap my head around it, using excel.



      Imagine that each year 1% of each birth cohort dies of disease or accidents. You have a population of 1,000,000. Your biggest cohort is of course infants: you have 10000 of them and they are 1% of your population. 1% die and your population of 1 year olds is 9900. 1% die and your population of 2 year olds is 9801.



      Each year, the 1% that is subtracted from the population is a smaller amount. That gives you an asymptotic curve as in the diagram above.



      I wish my math were good enough to provide a multiplier such that for any age you could figure the # of individuals of that age in the population of 1,000,000. But I did it up in excel to make the graph. Lacking elegant math, I would make the graph and then use the curve to approximate number of individuals of any given age.



      In my model (with average age 99; I think because of rounding) there were 3660 100 year old individuals comprising 0.366% of the population. There were 9 700 year olds and, of course, 1 1000 year old.







      share|improve this answer












      share|improve this answer



      share|improve this answer










      answered Nov 13 '18 at 3:25









      WillkWillk

      113k27212476




      113k27212476







      • 2




        $begingroup$
        I'm not sure the actual numbers being presented here are either correct or relevant but the structure of the resulting population almost certainly is.
        $endgroup$
        – Ash
        Nov 13 '18 at 9:41











      • $begingroup$
        This is known as a geometric distribution, with the parameter $p$ as the chance of dying in any specific year.
        $endgroup$
        – A Simmons
        Nov 13 '18 at 9:48












      • 2




        $begingroup$
        I'm not sure the actual numbers being presented here are either correct or relevant but the structure of the resulting population almost certainly is.
        $endgroup$
        – Ash
        Nov 13 '18 at 9:41











      • $begingroup$
        This is known as a geometric distribution, with the parameter $p$ as the chance of dying in any specific year.
        $endgroup$
        – A Simmons
        Nov 13 '18 at 9:48







      2




      2




      $begingroup$
      I'm not sure the actual numbers being presented here are either correct or relevant but the structure of the resulting population almost certainly is.
      $endgroup$
      – Ash
      Nov 13 '18 at 9:41





      $begingroup$
      I'm not sure the actual numbers being presented here are either correct or relevant but the structure of the resulting population almost certainly is.
      $endgroup$
      – Ash
      Nov 13 '18 at 9:41













      $begingroup$
      This is known as a geometric distribution, with the parameter $p$ as the chance of dying in any specific year.
      $endgroup$
      – A Simmons
      Nov 13 '18 at 9:48




      $begingroup$
      This is known as a geometric distribution, with the parameter $p$ as the chance of dying in any specific year.
      $endgroup$
      – A Simmons
      Nov 13 '18 at 9:48











      1












      $begingroup$

      I don't think there's enough information available to give a concrete answer to this. Maybe someone else can, but I don't think it's possible.



      So much depends on things we don't know, such as how long this has been going on, and when/how this immortality began.



      Here's what I mean: If this technology/magic were instituted immediately it means that, in general, we'd expect each person to die, a hundred years from their DOB. (As an average) If this took place in the modern U.S. the generations would be locked into rolling waves.



      For example, according to wiki 1.8% of the population is 85 or older. Based on your criteria, when that generation dies, it is replaced with exactly the same number of new births.



      So what happens is that the age distribution numbers are almost the same, but switch places. That 1.8% drops to the 'bottom' of the age distribution. 80-85 years later, the wave 'peaks' and what used to be 15-19 year olds at ~7% of the population are now all about 100 years old.



      It won't be exact, but if that's close to how one scenario would play out. You'd have to remove the percentages of deaths that are from most 'natural causes' while keeping deaths by accident, contagious disease, homicide and suicide, you'd need some noise, and the math would be pretty granular, but stick to the general 'wave' pattern.



      Or



      It takes effect by socioeconomic strata, or by state mandate, etc. And depending on how long this has been going on, given the admitted population controls, it could be literally anything you wanted it to be. A society could have it locked at 1% birth rate, every year, into eternity.






      share|improve this answer









      $endgroup$












      • $begingroup$
        But the world is living longer, and having fewer children. That's already changing the distribution.
        $endgroup$
        – RonJohn
        Nov 13 '18 at 3:04










      • $begingroup$
        @RonJohn which is entirely irrelevant, if the premise of this question takes place immediately.
        $endgroup$
        – user49466
        Nov 13 '18 at 3:51






      • 1




        $begingroup$
        why should we assume the change takes place immediately. why not assume a gaussian distribution, or even a flat distribution and let things equilibrate? i'm not a math wizard, though, so maybe i'm all wet here. that assumption just seems arbitrary. best of all would be an 'in the wild' human population in the pre-industrial age, or paleolithic age.
        $endgroup$
        – theRiley
        Nov 13 '18 at 4:43










      • $begingroup$
        @Theriley I'm not assuming that. I stated that how the change takes place, how long it's been, etc, will effect the distribution, and used this as an example. It's up to the OP to set the ground rules.
        $endgroup$
        – user49466
        Nov 13 '18 at 4:46










      • $begingroup$
        i see. thanks for the clarification.
        $endgroup$
        – theRiley
        Nov 13 '18 at 5:44















      1












      $begingroup$

      I don't think there's enough information available to give a concrete answer to this. Maybe someone else can, but I don't think it's possible.



      So much depends on things we don't know, such as how long this has been going on, and when/how this immortality began.



      Here's what I mean: If this technology/magic were instituted immediately it means that, in general, we'd expect each person to die, a hundred years from their DOB. (As an average) If this took place in the modern U.S. the generations would be locked into rolling waves.



      For example, according to wiki 1.8% of the population is 85 or older. Based on your criteria, when that generation dies, it is replaced with exactly the same number of new births.



      So what happens is that the age distribution numbers are almost the same, but switch places. That 1.8% drops to the 'bottom' of the age distribution. 80-85 years later, the wave 'peaks' and what used to be 15-19 year olds at ~7% of the population are now all about 100 years old.



      It won't be exact, but if that's close to how one scenario would play out. You'd have to remove the percentages of deaths that are from most 'natural causes' while keeping deaths by accident, contagious disease, homicide and suicide, you'd need some noise, and the math would be pretty granular, but stick to the general 'wave' pattern.



      Or



      It takes effect by socioeconomic strata, or by state mandate, etc. And depending on how long this has been going on, given the admitted population controls, it could be literally anything you wanted it to be. A society could have it locked at 1% birth rate, every year, into eternity.






      share|improve this answer









      $endgroup$












      • $begingroup$
        But the world is living longer, and having fewer children. That's already changing the distribution.
        $endgroup$
        – RonJohn
        Nov 13 '18 at 3:04










      • $begingroup$
        @RonJohn which is entirely irrelevant, if the premise of this question takes place immediately.
        $endgroup$
        – user49466
        Nov 13 '18 at 3:51






      • 1




        $begingroup$
        why should we assume the change takes place immediately. why not assume a gaussian distribution, or even a flat distribution and let things equilibrate? i'm not a math wizard, though, so maybe i'm all wet here. that assumption just seems arbitrary. best of all would be an 'in the wild' human population in the pre-industrial age, or paleolithic age.
        $endgroup$
        – theRiley
        Nov 13 '18 at 4:43










      • $begingroup$
        @Theriley I'm not assuming that. I stated that how the change takes place, how long it's been, etc, will effect the distribution, and used this as an example. It's up to the OP to set the ground rules.
        $endgroup$
        – user49466
        Nov 13 '18 at 4:46










      • $begingroup$
        i see. thanks for the clarification.
        $endgroup$
        – theRiley
        Nov 13 '18 at 5:44













      1












      1








      1





      $begingroup$

      I don't think there's enough information available to give a concrete answer to this. Maybe someone else can, but I don't think it's possible.



      So much depends on things we don't know, such as how long this has been going on, and when/how this immortality began.



      Here's what I mean: If this technology/magic were instituted immediately it means that, in general, we'd expect each person to die, a hundred years from their DOB. (As an average) If this took place in the modern U.S. the generations would be locked into rolling waves.



      For example, according to wiki 1.8% of the population is 85 or older. Based on your criteria, when that generation dies, it is replaced with exactly the same number of new births.



      So what happens is that the age distribution numbers are almost the same, but switch places. That 1.8% drops to the 'bottom' of the age distribution. 80-85 years later, the wave 'peaks' and what used to be 15-19 year olds at ~7% of the population are now all about 100 years old.



      It won't be exact, but if that's close to how one scenario would play out. You'd have to remove the percentages of deaths that are from most 'natural causes' while keeping deaths by accident, contagious disease, homicide and suicide, you'd need some noise, and the math would be pretty granular, but stick to the general 'wave' pattern.



      Or



      It takes effect by socioeconomic strata, or by state mandate, etc. And depending on how long this has been going on, given the admitted population controls, it could be literally anything you wanted it to be. A society could have it locked at 1% birth rate, every year, into eternity.






      share|improve this answer









      $endgroup$



      I don't think there's enough information available to give a concrete answer to this. Maybe someone else can, but I don't think it's possible.



      So much depends on things we don't know, such as how long this has been going on, and when/how this immortality began.



      Here's what I mean: If this technology/magic were instituted immediately it means that, in general, we'd expect each person to die, a hundred years from their DOB. (As an average) If this took place in the modern U.S. the generations would be locked into rolling waves.



      For example, according to wiki 1.8% of the population is 85 or older. Based on your criteria, when that generation dies, it is replaced with exactly the same number of new births.



      So what happens is that the age distribution numbers are almost the same, but switch places. That 1.8% drops to the 'bottom' of the age distribution. 80-85 years later, the wave 'peaks' and what used to be 15-19 year olds at ~7% of the population are now all about 100 years old.



      It won't be exact, but if that's close to how one scenario would play out. You'd have to remove the percentages of deaths that are from most 'natural causes' while keeping deaths by accident, contagious disease, homicide and suicide, you'd need some noise, and the math would be pretty granular, but stick to the general 'wave' pattern.



      Or



      It takes effect by socioeconomic strata, or by state mandate, etc. And depending on how long this has been going on, given the admitted population controls, it could be literally anything you wanted it to be. A society could have it locked at 1% birth rate, every year, into eternity.







      share|improve this answer












      share|improve this answer



      share|improve this answer










      answered Nov 13 '18 at 2:05









      user49466user49466

      1,648219




      1,648219











      • $begingroup$
        But the world is living longer, and having fewer children. That's already changing the distribution.
        $endgroup$
        – RonJohn
        Nov 13 '18 at 3:04










      • $begingroup$
        @RonJohn which is entirely irrelevant, if the premise of this question takes place immediately.
        $endgroup$
        – user49466
        Nov 13 '18 at 3:51






      • 1




        $begingroup$
        why should we assume the change takes place immediately. why not assume a gaussian distribution, or even a flat distribution and let things equilibrate? i'm not a math wizard, though, so maybe i'm all wet here. that assumption just seems arbitrary. best of all would be an 'in the wild' human population in the pre-industrial age, or paleolithic age.
        $endgroup$
        – theRiley
        Nov 13 '18 at 4:43










      • $begingroup$
        @Theriley I'm not assuming that. I stated that how the change takes place, how long it's been, etc, will effect the distribution, and used this as an example. It's up to the OP to set the ground rules.
        $endgroup$
        – user49466
        Nov 13 '18 at 4:46










      • $begingroup$
        i see. thanks for the clarification.
        $endgroup$
        – theRiley
        Nov 13 '18 at 5:44
















      • $begingroup$
        But the world is living longer, and having fewer children. That's already changing the distribution.
        $endgroup$
        – RonJohn
        Nov 13 '18 at 3:04










      • $begingroup$
        @RonJohn which is entirely irrelevant, if the premise of this question takes place immediately.
        $endgroup$
        – user49466
        Nov 13 '18 at 3:51






      • 1




        $begingroup$
        why should we assume the change takes place immediately. why not assume a gaussian distribution, or even a flat distribution and let things equilibrate? i'm not a math wizard, though, so maybe i'm all wet here. that assumption just seems arbitrary. best of all would be an 'in the wild' human population in the pre-industrial age, or paleolithic age.
        $endgroup$
        – theRiley
        Nov 13 '18 at 4:43










      • $begingroup$
        @Theriley I'm not assuming that. I stated that how the change takes place, how long it's been, etc, will effect the distribution, and used this as an example. It's up to the OP to set the ground rules.
        $endgroup$
        – user49466
        Nov 13 '18 at 4:46










      • $begingroup$
        i see. thanks for the clarification.
        $endgroup$
        – theRiley
        Nov 13 '18 at 5:44















      $begingroup$
      But the world is living longer, and having fewer children. That's already changing the distribution.
      $endgroup$
      – RonJohn
      Nov 13 '18 at 3:04




      $begingroup$
      But the world is living longer, and having fewer children. That's already changing the distribution.
      $endgroup$
      – RonJohn
      Nov 13 '18 at 3:04












      $begingroup$
      @RonJohn which is entirely irrelevant, if the premise of this question takes place immediately.
      $endgroup$
      – user49466
      Nov 13 '18 at 3:51




      $begingroup$
      @RonJohn which is entirely irrelevant, if the premise of this question takes place immediately.
      $endgroup$
      – user49466
      Nov 13 '18 at 3:51




      1




      1




      $begingroup$
      why should we assume the change takes place immediately. why not assume a gaussian distribution, or even a flat distribution and let things equilibrate? i'm not a math wizard, though, so maybe i'm all wet here. that assumption just seems arbitrary. best of all would be an 'in the wild' human population in the pre-industrial age, or paleolithic age.
      $endgroup$
      – theRiley
      Nov 13 '18 at 4:43




      $begingroup$
      why should we assume the change takes place immediately. why not assume a gaussian distribution, or even a flat distribution and let things equilibrate? i'm not a math wizard, though, so maybe i'm all wet here. that assumption just seems arbitrary. best of all would be an 'in the wild' human population in the pre-industrial age, or paleolithic age.
      $endgroup$
      – theRiley
      Nov 13 '18 at 4:43












      $begingroup$
      @Theriley I'm not assuming that. I stated that how the change takes place, how long it's been, etc, will effect the distribution, and used this as an example. It's up to the OP to set the ground rules.
      $endgroup$
      – user49466
      Nov 13 '18 at 4:46




      $begingroup$
      @Theriley I'm not assuming that. I stated that how the change takes place, how long it's been, etc, will effect the distribution, and used this as an example. It's up to the OP to set the ground rules.
      $endgroup$
      – user49466
      Nov 13 '18 at 4:46












      $begingroup$
      i see. thanks for the clarification.
      $endgroup$
      – theRiley
      Nov 13 '18 at 5:44




      $begingroup$
      i see. thanks for the clarification.
      $endgroup$
      – theRiley
      Nov 13 '18 at 5:44











      1












      $begingroup$

      The first thing we have to look at is a population pyramid. Below is the 2015 pyramid from CIA world factbook data.



      Population pyramid 2015
      https://www.indexmundi.com/world/age_structure.html



      We currently have a hint of population growth at the bottom, then dropping off through to an upper limit of around 100. Median age of 30.4. (You've asked for average age rather than median age, this is far harder to calculate.)



      Since you have stated a static population, with good healthcare in peacetime, the pyramid should be less of a pyramid and more of a column, starting to taper off where aggregate accident rates and incurable medical conditions start to kill people off.



      An aging population would be narrow at the bottom with a bulge higher up. A growing population is more a classic pyramid.



      A quick and dirty answer would be to extend the above pyramid age ranges 3fold, but of course this pyramid is limited by natural age limitations hence would not be valid.



      The shape you're looking for is going to be a cumulative normal distribution of death rates rather than a clean exponential decay as others have suggested.






      share|improve this answer









      $endgroup$

















        1












        $begingroup$

        The first thing we have to look at is a population pyramid. Below is the 2015 pyramid from CIA world factbook data.



        Population pyramid 2015
        https://www.indexmundi.com/world/age_structure.html



        We currently have a hint of population growth at the bottom, then dropping off through to an upper limit of around 100. Median age of 30.4. (You've asked for average age rather than median age, this is far harder to calculate.)



        Since you have stated a static population, with good healthcare in peacetime, the pyramid should be less of a pyramid and more of a column, starting to taper off where aggregate accident rates and incurable medical conditions start to kill people off.



        An aging population would be narrow at the bottom with a bulge higher up. A growing population is more a classic pyramid.



        A quick and dirty answer would be to extend the above pyramid age ranges 3fold, but of course this pyramid is limited by natural age limitations hence would not be valid.



        The shape you're looking for is going to be a cumulative normal distribution of death rates rather than a clean exponential decay as others have suggested.






        share|improve this answer









        $endgroup$















          1












          1








          1





          $begingroup$

          The first thing we have to look at is a population pyramid. Below is the 2015 pyramid from CIA world factbook data.



          Population pyramid 2015
          https://www.indexmundi.com/world/age_structure.html



          We currently have a hint of population growth at the bottom, then dropping off through to an upper limit of around 100. Median age of 30.4. (You've asked for average age rather than median age, this is far harder to calculate.)



          Since you have stated a static population, with good healthcare in peacetime, the pyramid should be less of a pyramid and more of a column, starting to taper off where aggregate accident rates and incurable medical conditions start to kill people off.



          An aging population would be narrow at the bottom with a bulge higher up. A growing population is more a classic pyramid.



          A quick and dirty answer would be to extend the above pyramid age ranges 3fold, but of course this pyramid is limited by natural age limitations hence would not be valid.



          The shape you're looking for is going to be a cumulative normal distribution of death rates rather than a clean exponential decay as others have suggested.






          share|improve this answer









          $endgroup$



          The first thing we have to look at is a population pyramid. Below is the 2015 pyramid from CIA world factbook data.



          Population pyramid 2015
          https://www.indexmundi.com/world/age_structure.html



          We currently have a hint of population growth at the bottom, then dropping off through to an upper limit of around 100. Median age of 30.4. (You've asked for average age rather than median age, this is far harder to calculate.)



          Since you have stated a static population, with good healthcare in peacetime, the pyramid should be less of a pyramid and more of a column, starting to taper off where aggregate accident rates and incurable medical conditions start to kill people off.



          An aging population would be narrow at the bottom with a bulge higher up. A growing population is more a classic pyramid.



          A quick and dirty answer would be to extend the above pyramid age ranges 3fold, but of course this pyramid is limited by natural age limitations hence would not be valid.



          The shape you're looking for is going to be a cumulative normal distribution of death rates rather than a clean exponential decay as others have suggested.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 13 '18 at 11:38









          SeparatrixSeparatrix

          84.4k31196327




          84.4k31196327





















              0












              $begingroup$

              Lets say there a thousand humans (a really small earth).
              If we distributed them roughly across ages so they balance out at 100. I could have a:



              • very dense demographic with lots of 100 year olds.

              • a split demographic with many young individuals say 10-20, and many older individuals 180-190.

              • or some kind of flat demographic ~5 people of each age between 0 and 200.

              That is the distribution you've described. Take your pick.



              If you want something more realistic... (and grossly oversimplified).



              Then lets consider mortality. Without aging doing any killing by itself, you'll find that we die purely from disease and accidents. This probably won't change the mortality rate very much. I'll draw some figures from Australian adult deaths. So roughly 0.0468% to 0.0782% of the population dies due to something.



              That's about 46-78 dead humans a year (in our thousand human population). So about that many births per year.



              • 78 one year olds

              • 73 two year olds

              • 65 three year olds

              • 63 four year olds

              • 20 five year olds

              • 15 six year olds

              • 80 six year olds

              • 45 seven year olds

              • 46 eight year olds

              • 48 nine year olds

              • 20 ten year olds

              • 72 eleven year olds

              • 12 twelve year olds

              • 22 thirteen year olds

              • 46 fourteen year olds

              • 23 fifteen year olds

              • 31 sixteen year olds

              • 87 seventeen year olds

              • 44 eighteen year olds

              • 38 nineteen year olds

              • 22 twenty year olds

              • 56 twenty-one year olds

              • 64 twenty-two year olds

              and because of the small population cap, 51 people are executed at random. But if you raised it, to something more manageable, you'll see that this roughly makes a flat population that will slowly taper out (at the rate of a 5 hundredths of a percent).



              Lets see what this population looks like, but with no ritualised forced deaths, and every member living till natural causes (like accidents) kill them. Lets also keep that median straight on top of 100 (roughly speaking).



              • A is the number of 100 year olds

              • B is the total number of years past 100 that the oldest individual (roughly) is.

              • C is half the total population.

              • D is the death rate.

              • E is the eldest member.

              • Y is the total number of new borns.

              • X is the difference between the total 100 year olds, and the total newborns.


              • X = 100 * D


              • Y = A + X

              • A = B * D

              • C = 100 * X / 2 + 100 * A

              • C = A * B / 2

              • E = 100 + B

              This is represents two triangles and a rectangle like:



               *
               **
               * *
              X* *
               * *
               +****+
               * **
               * * *
              A* * *
               * * *
               * * *
               *****+******
               100 B


              So assuming D = 0.0005



              • X = 0.05

              • A = B * 0.0005

              • B = (1/0.0005) * A

              • B = 2000 * A

              • C = A * B / 2

              • C = A * (2000 * A) / 2

              • C = 1000 * A * A


              • C = 100 * 0.05 / 2 + 100 * A


              • C = 100 * A + 2.5


              • C = C


              • 100 * A + 2.5 = 1000 * A * A

              • 0 = 1000 * A * A - 100 * A - 2.5

              • A ~= 0.12071...


              • A = B * D


              • B = A / D

              • B ~= 0.12071 / 0.0005

              • B ~= 241.42


              • Y = A + X


              • Y ~= 0.12071 + 0.05


              • E = 100 + B


              • E = 100 + 241.42

              • E = 341.42

              So the oldest thing is roughly 341.42 years old.
              And their lives one 17th of a newborn. For a median age of 100. (Statistically speaking). That is a total average population of 341.42 * 0.17071 / 2 ~= 29.141 individuals.



              29 people isn't a satisfying population. Its an almost extinct one. Lets take the approximately 7 billion people alive today, and give them a shot of immortality. and institute the replacement only birth rate, with the constant death rate of 0.0005. (Lets say immortality makes people more adventurous and take on risks, without learning much about avoiding them). Fast forward many years and allow the natural randomness to even out a little, (so that I can use the simple triangle model and ignore every other event).



               *
               **
               * * C
              A* D*
               * *
               +****+
               B


              • D = 7,000,000,000

              • D = A * B / 2

              • C = A / B

              • C = 0.0005


              • A/B = 0.0005


              • A = 0.0005 * B

              • 7,000,000,000 = A * B / 2

              • 7,000,000,000 = 0.0005 * B * B / 2

              • 7,000,000,000 * 2 / 0.0005 = B * B

              • B * B = 28,000,000,000,000

              • B ~= 5,291,502.62

              • A = 0.0005 * B

              • A = 2645.75

              So natural causes gives the oldest person at about 5.3 million years old. Most people would have "accidentally" died by now.



              Also there are around 2645 new infants born every year. This means a mere 6 average-large sized schools of each level of education are sufficient for educating the entire population. Imagine that, overnight most of the worlds schools can just be shutdown. Of course there will now be a large upswing in golf-course requirements.



              Hope this helps paint a very crude picture.






              share|improve this answer









              $endgroup$

















                0












                $begingroup$

                Lets say there a thousand humans (a really small earth).
                If we distributed them roughly across ages so they balance out at 100. I could have a:



                • very dense demographic with lots of 100 year olds.

                • a split demographic with many young individuals say 10-20, and many older individuals 180-190.

                • or some kind of flat demographic ~5 people of each age between 0 and 200.

                That is the distribution you've described. Take your pick.



                If you want something more realistic... (and grossly oversimplified).



                Then lets consider mortality. Without aging doing any killing by itself, you'll find that we die purely from disease and accidents. This probably won't change the mortality rate very much. I'll draw some figures from Australian adult deaths. So roughly 0.0468% to 0.0782% of the population dies due to something.



                That's about 46-78 dead humans a year (in our thousand human population). So about that many births per year.



                • 78 one year olds

                • 73 two year olds

                • 65 three year olds

                • 63 four year olds

                • 20 five year olds

                • 15 six year olds

                • 80 six year olds

                • 45 seven year olds

                • 46 eight year olds

                • 48 nine year olds

                • 20 ten year olds

                • 72 eleven year olds

                • 12 twelve year olds

                • 22 thirteen year olds

                • 46 fourteen year olds

                • 23 fifteen year olds

                • 31 sixteen year olds

                • 87 seventeen year olds

                • 44 eighteen year olds

                • 38 nineteen year olds

                • 22 twenty year olds

                • 56 twenty-one year olds

                • 64 twenty-two year olds

                and because of the small population cap, 51 people are executed at random. But if you raised it, to something more manageable, you'll see that this roughly makes a flat population that will slowly taper out (at the rate of a 5 hundredths of a percent).



                Lets see what this population looks like, but with no ritualised forced deaths, and every member living till natural causes (like accidents) kill them. Lets also keep that median straight on top of 100 (roughly speaking).



                • A is the number of 100 year olds

                • B is the total number of years past 100 that the oldest individual (roughly) is.

                • C is half the total population.

                • D is the death rate.

                • E is the eldest member.

                • Y is the total number of new borns.

                • X is the difference between the total 100 year olds, and the total newborns.


                • X = 100 * D


                • Y = A + X

                • A = B * D

                • C = 100 * X / 2 + 100 * A

                • C = A * B / 2

                • E = 100 + B

                This is represents two triangles and a rectangle like:



                 *
                 **
                 * *
                X* *
                 * *
                 +****+
                 * **
                 * * *
                A* * *
                 * * *
                 * * *
                 *****+******
                 100 B


                So assuming D = 0.0005



                • X = 0.05

                • A = B * 0.0005

                • B = (1/0.0005) * A

                • B = 2000 * A

                • C = A * B / 2

                • C = A * (2000 * A) / 2

                • C = 1000 * A * A


                • C = 100 * 0.05 / 2 + 100 * A


                • C = 100 * A + 2.5


                • C = C


                • 100 * A + 2.5 = 1000 * A * A

                • 0 = 1000 * A * A - 100 * A - 2.5

                • A ~= 0.12071...


                • A = B * D


                • B = A / D

                • B ~= 0.12071 / 0.0005

                • B ~= 241.42


                • Y = A + X


                • Y ~= 0.12071 + 0.05


                • E = 100 + B


                • E = 100 + 241.42

                • E = 341.42

                So the oldest thing is roughly 341.42 years old.
                And their lives one 17th of a newborn. For a median age of 100. (Statistically speaking). That is a total average population of 341.42 * 0.17071 / 2 ~= 29.141 individuals.



                29 people isn't a satisfying population. Its an almost extinct one. Lets take the approximately 7 billion people alive today, and give them a shot of immortality. and institute the replacement only birth rate, with the constant death rate of 0.0005. (Lets say immortality makes people more adventurous and take on risks, without learning much about avoiding them). Fast forward many years and allow the natural randomness to even out a little, (so that I can use the simple triangle model and ignore every other event).



                 *
                 **
                 * * C
                A* D*
                 * *
                 +****+
                 B


                • D = 7,000,000,000

                • D = A * B / 2

                • C = A / B

                • C = 0.0005


                • A/B = 0.0005


                • A = 0.0005 * B

                • 7,000,000,000 = A * B / 2

                • 7,000,000,000 = 0.0005 * B * B / 2

                • 7,000,000,000 * 2 / 0.0005 = B * B

                • B * B = 28,000,000,000,000

                • B ~= 5,291,502.62

                • A = 0.0005 * B

                • A = 2645.75

                So natural causes gives the oldest person at about 5.3 million years old. Most people would have "accidentally" died by now.



                Also there are around 2645 new infants born every year. This means a mere 6 average-large sized schools of each level of education are sufficient for educating the entire population. Imagine that, overnight most of the worlds schools can just be shutdown. Of course there will now be a large upswing in golf-course requirements.



                Hope this helps paint a very crude picture.






                share|improve this answer









                $endgroup$















                  0












                  0








                  0





                  $begingroup$

                  Lets say there a thousand humans (a really small earth).
                  If we distributed them roughly across ages so they balance out at 100. I could have a:



                  • very dense demographic with lots of 100 year olds.

                  • a split demographic with many young individuals say 10-20, and many older individuals 180-190.

                  • or some kind of flat demographic ~5 people of each age between 0 and 200.

                  That is the distribution you've described. Take your pick.



                  If you want something more realistic... (and grossly oversimplified).



                  Then lets consider mortality. Without aging doing any killing by itself, you'll find that we die purely from disease and accidents. This probably won't change the mortality rate very much. I'll draw some figures from Australian adult deaths. So roughly 0.0468% to 0.0782% of the population dies due to something.



                  That's about 46-78 dead humans a year (in our thousand human population). So about that many births per year.



                  • 78 one year olds

                  • 73 two year olds

                  • 65 three year olds

                  • 63 four year olds

                  • 20 five year olds

                  • 15 six year olds

                  • 80 six year olds

                  • 45 seven year olds

                  • 46 eight year olds

                  • 48 nine year olds

                  • 20 ten year olds

                  • 72 eleven year olds

                  • 12 twelve year olds

                  • 22 thirteen year olds

                  • 46 fourteen year olds

                  • 23 fifteen year olds

                  • 31 sixteen year olds

                  • 87 seventeen year olds

                  • 44 eighteen year olds

                  • 38 nineteen year olds

                  • 22 twenty year olds

                  • 56 twenty-one year olds

                  • 64 twenty-two year olds

                  and because of the small population cap, 51 people are executed at random. But if you raised it, to something more manageable, you'll see that this roughly makes a flat population that will slowly taper out (at the rate of a 5 hundredths of a percent).



                  Lets see what this population looks like, but with no ritualised forced deaths, and every member living till natural causes (like accidents) kill them. Lets also keep that median straight on top of 100 (roughly speaking).



                  • A is the number of 100 year olds

                  • B is the total number of years past 100 that the oldest individual (roughly) is.

                  • C is half the total population.

                  • D is the death rate.

                  • E is the eldest member.

                  • Y is the total number of new borns.

                  • X is the difference between the total 100 year olds, and the total newborns.


                  • X = 100 * D


                  • Y = A + X

                  • A = B * D

                  • C = 100 * X / 2 + 100 * A

                  • C = A * B / 2

                  • E = 100 + B

                  This is represents two triangles and a rectangle like:



                   *
                   **
                   * *
                  X* *
                   * *
                   +****+
                   * **
                   * * *
                  A* * *
                   * * *
                   * * *
                   *****+******
                   100 B


                  So assuming D = 0.0005



                  • X = 0.05

                  • A = B * 0.0005

                  • B = (1/0.0005) * A

                  • B = 2000 * A

                  • C = A * B / 2

                  • C = A * (2000 * A) / 2

                  • C = 1000 * A * A


                  • C = 100 * 0.05 / 2 + 100 * A


                  • C = 100 * A + 2.5


                  • C = C


                  • 100 * A + 2.5 = 1000 * A * A

                  • 0 = 1000 * A * A - 100 * A - 2.5

                  • A ~= 0.12071...


                  • A = B * D


                  • B = A / D

                  • B ~= 0.12071 / 0.0005

                  • B ~= 241.42


                  • Y = A + X


                  • Y ~= 0.12071 + 0.05


                  • E = 100 + B


                  • E = 100 + 241.42

                  • E = 341.42

                  So the oldest thing is roughly 341.42 years old.
                  And their lives one 17th of a newborn. For a median age of 100. (Statistically speaking). That is a total average population of 341.42 * 0.17071 / 2 ~= 29.141 individuals.



                  29 people isn't a satisfying population. Its an almost extinct one. Lets take the approximately 7 billion people alive today, and give them a shot of immortality. and institute the replacement only birth rate, with the constant death rate of 0.0005. (Lets say immortality makes people more adventurous and take on risks, without learning much about avoiding them). Fast forward many years and allow the natural randomness to even out a little, (so that I can use the simple triangle model and ignore every other event).



                   *
                   **
                   * * C
                  A* D*
                   * *
                   +****+
                   B


                  • D = 7,000,000,000

                  • D = A * B / 2

                  • C = A / B

                  • C = 0.0005


                  • A/B = 0.0005


                  • A = 0.0005 * B

                  • 7,000,000,000 = A * B / 2

                  • 7,000,000,000 = 0.0005 * B * B / 2

                  • 7,000,000,000 * 2 / 0.0005 = B * B

                  • B * B = 28,000,000,000,000

                  • B ~= 5,291,502.62

                  • A = 0.0005 * B

                  • A = 2645.75

                  So natural causes gives the oldest person at about 5.3 million years old. Most people would have "accidentally" died by now.



                  Also there are around 2645 new infants born every year. This means a mere 6 average-large sized schools of each level of education are sufficient for educating the entire population. Imagine that, overnight most of the worlds schools can just be shutdown. Of course there will now be a large upswing in golf-course requirements.



                  Hope this helps paint a very crude picture.






                  share|improve this answer









                  $endgroup$



                  Lets say there a thousand humans (a really small earth).
                  If we distributed them roughly across ages so they balance out at 100. I could have a:



                  • very dense demographic with lots of 100 year olds.

                  • a split demographic with many young individuals say 10-20, and many older individuals 180-190.

                  • or some kind of flat demographic ~5 people of each age between 0 and 200.

                  That is the distribution you've described. Take your pick.



                  If you want something more realistic... (and grossly oversimplified).



                  Then lets consider mortality. Without aging doing any killing by itself, you'll find that we die purely from disease and accidents. This probably won't change the mortality rate very much. I'll draw some figures from Australian adult deaths. So roughly 0.0468% to 0.0782% of the population dies due to something.



                  That's about 46-78 dead humans a year (in our thousand human population). So about that many births per year.



                  • 78 one year olds

                  • 73 two year olds

                  • 65 three year olds

                  • 63 four year olds

                  • 20 five year olds

                  • 15 six year olds

                  • 80 six year olds

                  • 45 seven year olds

                  • 46 eight year olds

                  • 48 nine year olds

                  • 20 ten year olds

                  • 72 eleven year olds

                  • 12 twelve year olds

                  • 22 thirteen year olds

                  • 46 fourteen year olds

                  • 23 fifteen year olds

                  • 31 sixteen year olds

                  • 87 seventeen year olds

                  • 44 eighteen year olds

                  • 38 nineteen year olds

                  • 22 twenty year olds

                  • 56 twenty-one year olds

                  • 64 twenty-two year olds

                  and because of the small population cap, 51 people are executed at random. But if you raised it, to something more manageable, you'll see that this roughly makes a flat population that will slowly taper out (at the rate of a 5 hundredths of a percent).



                  Lets see what this population looks like, but with no ritualised forced deaths, and every member living till natural causes (like accidents) kill them. Lets also keep that median straight on top of 100 (roughly speaking).



                  • A is the number of 100 year olds

                  • B is the total number of years past 100 that the oldest individual (roughly) is.

                  • C is half the total population.

                  • D is the death rate.

                  • E is the eldest member.

                  • Y is the total number of new borns.

                  • X is the difference between the total 100 year olds, and the total newborns.


                  • X = 100 * D


                  • Y = A + X

                  • A = B * D

                  • C = 100 * X / 2 + 100 * A

                  • C = A * B / 2

                  • E = 100 + B

                  This is represents two triangles and a rectangle like:



                   *
                   **
                   * *
                  X* *
                   * *
                   +****+
                   * **
                   * * *
                  A* * *
                   * * *
                   * * *
                   *****+******
                   100 B


                  So assuming D = 0.0005



                  • X = 0.05

                  • A = B * 0.0005

                  • B = (1/0.0005) * A

                  • B = 2000 * A

                  • C = A * B / 2

                  • C = A * (2000 * A) / 2

                  • C = 1000 * A * A


                  • C = 100 * 0.05 / 2 + 100 * A


                  • C = 100 * A + 2.5


                  • C = C


                  • 100 * A + 2.5 = 1000 * A * A

                  • 0 = 1000 * A * A - 100 * A - 2.5

                  • A ~= 0.12071...


                  • A = B * D


                  • B = A / D

                  • B ~= 0.12071 / 0.0005

                  • B ~= 241.42


                  • Y = A + X


                  • Y ~= 0.12071 + 0.05


                  • E = 100 + B


                  • E = 100 + 241.42

                  • E = 341.42

                  So the oldest thing is roughly 341.42 years old.
                  And their lives one 17th of a newborn. For a median age of 100. (Statistically speaking). That is a total average population of 341.42 * 0.17071 / 2 ~= 29.141 individuals.



                  29 people isn't a satisfying population. Its an almost extinct one. Lets take the approximately 7 billion people alive today, and give them a shot of immortality. and institute the replacement only birth rate, with the constant death rate of 0.0005. (Lets say immortality makes people more adventurous and take on risks, without learning much about avoiding them). Fast forward many years and allow the natural randomness to even out a little, (so that I can use the simple triangle model and ignore every other event).



                   *
                   **
                   * * C
                  A* D*
                   * *
                   +****+
                   B


                  • D = 7,000,000,000

                  • D = A * B / 2

                  • C = A / B

                  • C = 0.0005


                  • A/B = 0.0005


                  • A = 0.0005 * B

                  • 7,000,000,000 = A * B / 2

                  • 7,000,000,000 = 0.0005 * B * B / 2

                  • 7,000,000,000 * 2 / 0.0005 = B * B

                  • B * B = 28,000,000,000,000

                  • B ~= 5,291,502.62

                  • A = 0.0005 * B

                  • A = 2645.75

                  So natural causes gives the oldest person at about 5.3 million years old. Most people would have "accidentally" died by now.



                  Also there are around 2645 new infants born every year. This means a mere 6 average-large sized schools of each level of education are sufficient for educating the entire population. Imagine that, overnight most of the worlds schools can just be shutdown. Of course there will now be a large upswing in golf-course requirements.



                  Hope this helps paint a very crude picture.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 13 '18 at 4:33









                  Kain0_0Kain0_0

                  1,9529




                  1,9529



























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                      Crossroads (UK TV series)

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                      [dummy-text] Crossroads (UK TV series) From Wikipedia, the free encyclopedia Jump to navigation Jump to search For other uses, see Crossroads (disambiguation). "Crossroads Motel" redirects here. For the album by the Sonny Moorman Group, see Crossroads Motel (album). Crossroads 2003 title sequence Created by Hazel Adair Peter Ling Written by Michala Crees Ivor Jay Rosalie Grayson Raymond Bowers David Garfield Edward F. Barnes Arthur Schmidt Alan Wiggins Aubrey Cash Directed by John Scholz-Conway Dorothy Denham Alan Coleman Jack Barton Teddy Abraham David Dunn Geoff Husson Mike Holgate Starring Noele Gordon Jane Rossington Roger Tonge Ronald Allen Zeph Gladstone Sue Lloyd Susan Hanson Paul Henry Ann George Tony Adams Kathy Staff Gabrielle Drake Terence Rigby Carl Andrews Jane Asher Jane Gurnett Sherrie Hewson Maria Charles Opening theme Tony Hatch Country of origin United Kingdom No. of episodes Original Series: 4510
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