Drawing link with d3 and d3-flextree plugin
I'm (still) trying to make an orgchart with D3 and d3-flextree plugin. I struggle drawing the links between the nodes. The "equation" I use consider the middle of the node (as I understand it) whereas I'd like to draw from the end of a node.
I think my mistake is in my drawing-link function
function diagonal(s, d)
path = `M $s.x $s.y
L $s.x $(s.y + d.y) * 0.5,
$d.x $(s.y + d.y) * 0.5 ,
$d.x $d.y`
return path
It's hard to explain so I made a JSFiddle: https://jsfiddle.net/ymv5sr9k/11/
In this exemple all links are the way I want thanks to right padding, but as soon as the nodeSize change (see the big node) it's all broken. I guess I need a more general drawing-link function but I can't figure it out
Thanks for reading,
Zoom
d3.js
edited Nov 17 '18 at 6:53
Fuzzyma
3,22321540
asked Nov 13 '18 at 14:13
ZoomZoom
53
|
show 1 more comment
I'm (still) trying to make an orgchart with D3 and d3-flextree plugin. I struggle drawing the links between the nodes. The "equation" I use consider the middle of the node (as I understand it) whereas I'd like to draw from the end of a node.
I think my mistake is in my drawing-link function
function diagonal(s, d)
path = `M $s.x $s.y
L $s.x $(s.y + d.y) * 0.5,
$d.x $(s.y + d.y) * 0.5 ,
$d.x $d.y`
return path
It's hard to explain so I made a JSFiddle: https://jsfiddle.net/ymv5sr9k/11/
In this exemple all links are the way I want thanks to right padding, but as soon as the nodeSize change (see the big node) it's all broken. I guess I need a more general drawing-link function but I can't figure it out
Thanks for reading,
Zoom
d3.js
edited Nov 17 '18 at 6:53
Fuzzyma
3,22321540
asked Nov 13 '18 at 14:13
ZoomZoom
53
where is the mid bottom relative to the box center?
– rioV8
Nov 13 '18 at 15:37
I am not sure that I understand the question, when I said center it's because I multiply by 0.5 in the path equation. Is it what you talk about ?
– Zoom
Nov 13 '18 at 15:40
you calculate the mid point between the centers of the nodes, I talk about the node box
– rioV8
Nov 13 '18 at 16:05
I think I understood something ^^ What I do : I draw from nodeParent to nodeChild. this result in : topParentBox to topChildBox. So I know that I rather want => bottomParentBox to topChildBox. It's probably something like : (nodeParent + nodeSize) to nodeChild. But I dont successfully acces to nodeSize AND all my attempts to change the equation resulted in non-sense. I hope it's not to confuse... Thank you for your time, I'm really grateful !
– Zoom
Nov 13 '18 at 16:22
if you need some data in some objects put it in so you can use it in the link calculation
– rioV8
Nov 13 '18 at 19:00
|
show 1 more comment
I'm (still) trying to make an orgchart with D3 and d3-flextree plugin. I struggle drawing the links between the nodes. The "equation" I use consider the middle of the node (as I understand it) whereas I'd like to draw from the end of a node.
I think my mistake is in my drawing-link function
function diagonal(s, d)
path = `M $s.x $s.y
L $s.x $(s.y + d.y) * 0.5,
$d.x $(s.y + d.y) * 0.5 ,
$d.x $d.y`
return path
It's hard to explain so I made a JSFiddle: https://jsfiddle.net/ymv5sr9k/11/
In this exemple all links are the way I want thanks to right padding, but as soon as the nodeSize change (see the big node) it's all broken. I guess I need a more general drawing-link function but I can't figure it out
Thanks for reading,
Zoom
d3.js
edited Nov 17 '18 at 6:53
Fuzzyma
3,22321540
asked Nov 13 '18 at 14:13
ZoomZoom
53
I'm (still) trying to make an orgchart with D3 and d3-flextree plugin. I struggle drawing the links between the nodes. The "equation" I use consider the middle of the node (as I understand it) whereas I'd like to draw from the end of a node.
I think my mistake is in my drawing-link function
function diagonal(s, d)
path = `M $s.x $s.y
L $s.x $(s.y + d.y) * 0.5,
$d.x $(s.y + d.y) * 0.5 ,
$d.x $d.y`
return path
It's hard to explain so I made a JSFiddle: https://jsfiddle.net/ymv5sr9k/11/
In this exemple all links are the way I want thanks to right padding, but as soon as the nodeSize change (see the big node) it's all broken. I guess I need a more general drawing-link function but I can't figure it out
Thanks for reading,
Zoom
d3.js
d3.js
edited Nov 17 '18 at 6:53
Fuzzyma
3,22321540
asked Nov 13 '18 at 14:13
ZoomZoom
53
edited Nov 17 '18 at 6:53
Fuzzyma
3,22321540
asked Nov 13 '18 at 14:13
ZoomZoom
53
edited Nov 17 '18 at 6:53
Fuzzyma
3,22321540
edited Nov 17 '18 at 6:53
Fuzzyma
3,22321540
edited Nov 17 '18 at 6:53
Fuzzyma
3,22321540
3,22321540
asked Nov 13 '18 at 14:13
ZoomZoom
53
asked Nov 13 '18 at 14:13
ZoomZoom
53
asked Nov 13 '18 at 14:13
ZoomZoom
53
53
where is the mid bottom relative to the box center?
– rioV8
Nov 13 '18 at 15:37
I am not sure that I understand the question, when I said center it's because I multiply by 0.5 in the path equation. Is it what you talk about ?
– Zoom
Nov 13 '18 at 15:40
you calculate the mid point between the centers of the nodes, I talk about the node box
– rioV8
Nov 13 '18 at 16:05
I think I understood something ^^ What I do : I draw from nodeParent to nodeChild. this result in : topParentBox to topChildBox. So I know that I rather want => bottomParentBox to topChildBox. It's probably something like : (nodeParent + nodeSize) to nodeChild. But I dont successfully acces to nodeSize AND all my attempts to change the equation resulted in non-sense. I hope it's not to confuse... Thank you for your time, I'm really grateful !
– Zoom
Nov 13 '18 at 16:22
if you need some data in some objects put it in so you can use it in the link calculation
– rioV8
Nov 13 '18 at 19:00
|
show 1 more comment
where is the mid bottom relative to the box center?
– rioV8
Nov 13 '18 at 15:37
I am not sure that I understand the question, when I said center it's because I multiply by 0.5 in the path equation. Is it what you talk about ?
– Zoom
Nov 13 '18 at 15:40
you calculate the mid point between the centers of the nodes, I talk about the node box
– rioV8
Nov 13 '18 at 16:05
I think I understood something ^^ What I do : I draw from nodeParent to nodeChild. this result in : topParentBox to topChildBox. So I know that I rather want => bottomParentBox to topChildBox. It's probably something like : (nodeParent + nodeSize) to nodeChild. But I dont successfully acces to nodeSize AND all my attempts to change the equation resulted in non-sense. I hope it's not to confuse... Thank you for your time, I'm really grateful !
– Zoom
Nov 13 '18 at 16:22
if you need some data in some objects put it in so you can use it in the link calculation
– rioV8
Nov 13 '18 at 19:00
where is the mid bottom relative to the box center?
– rioV8
Nov 13 '18 at 15:37
where is the mid bottom relative to the box center?
– rioV8
Nov 13 '18 at 15:37
I am not sure that I understand the question, when I said center it's because I multiply by 0.5 in the path equation. Is it what you talk about ?
– Zoom
Nov 13 '18 at 15:40
I am not sure that I understand the question, when I said center it's because I multiply by 0.5 in the path equation. Is it what you talk about ?
– Zoom
Nov 13 '18 at 15:40
you calculate the mid point between the centers of the nodes, I talk about the node box
– rioV8
Nov 13 '18 at 16:05
you calculate the mid point between the centers of the nodes, I talk about the node box
– rioV8
Nov 13 '18 at 16:05
I think I understood something ^^ What I do : I draw from nodeParent to nodeChild. this result in : topParentBox to topChildBox. So I know that I rather want => bottomParentBox to topChildBox. It's probably something like : (nodeParent + nodeSize) to nodeChild. But I dont successfully acces to nodeSize AND all my attempts to change the equation resulted in non-sense. I hope it's not to confuse... Thank you for your time, I'm really grateful !
– Zoom
Nov 13 '18 at 16:22
I think I understood something ^^ What I do : I draw from nodeParent to nodeChild. this result in : topParentBox to topChildBox. So I know that I rather want => bottomParentBox to topChildBox. It's probably something like : (nodeParent + nodeSize) to nodeChild. But I dont successfully acces to nodeSize AND all my attempts to change the equation resulted in non-sense. I hope it's not to confuse... Thank you for your time, I'm really grateful !
– Zoom
Nov 13 '18 at 16:22
if you need some data in some objects put it in so you can use it in the link calculation
– rioV8
Nov 13 '18 at 19:00
if you need some data in some objects put it in so you can use it in the link calculation
– rioV8
Nov 13 '18 at 19:00
|
show 1 more comment
1 Answer
1
active
oldest
votes
Problem solved! As i said in the comments, I needed to move the horizontal line. I added nodeSize in my two y "control points". And nodeSize is actually source.y - destination.y - padding. This is my final equation:
function diagonal(s, d)
var nodeSize = s.y - d.y - 30
return "M" + s.x + "," + s.y
+ "L" + s.x + "," + (d.y + s.y + nodeSize) / 2
+ " " + d.x + "," + (d.y + s.y + nodeSize) / 2
+ " " + d.x + "," + d.y;
;
Thank you for your time!
edited Nov 14 '18 at 11:54
bfontaine
9,34674474
answered Nov 14 '18 at 10:13
ZoomZoom
53
add a comment |
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Problem solved! As i said in the comments, I needed to move the horizontal line. I added nodeSize in my two y "control points". And nodeSize is actually source.y - destination.y - padding. This is my final equation:
function diagonal(s, d)
var nodeSize = s.y - d.y - 30
return "M" + s.x + "," + s.y
+ "L" + s.x + "," + (d.y + s.y + nodeSize) / 2
+ " " + d.x + "," + (d.y + s.y + nodeSize) / 2
+ " " + d.x + "," + d.y;
;
Thank you for your time!
edited Nov 14 '18 at 11:54
bfontaine
9,34674474
answered Nov 14 '18 at 10:13
ZoomZoom
53
add a comment |
Problem solved! As i said in the comments, I needed to move the horizontal line. I added nodeSize in my two y "control points". And nodeSize is actually source.y - destination.y - padding. This is my final equation:
function diagonal(s, d)
var nodeSize = s.y - d.y - 30
return "M" + s.x + "," + s.y
+ "L" + s.x + "," + (d.y + s.y + nodeSize) / 2
+ " " + d.x + "," + (d.y + s.y + nodeSize) / 2
+ " " + d.x + "," + d.y;
;
Thank you for your time!
edited Nov 14 '18 at 11:54
bfontaine
9,34674474
answered Nov 14 '18 at 10:13
ZoomZoom
53
add a comment |
Problem solved! As i said in the comments, I needed to move the horizontal line. I added nodeSize in my two y "control points". And nodeSize is actually source.y - destination.y - padding. This is my final equation:
function diagonal(s, d)
var nodeSize = s.y - d.y - 30
return "M" + s.x + "," + s.y
+ "L" + s.x + "," + (d.y + s.y + nodeSize) / 2
+ " " + d.x + "," + (d.y + s.y + nodeSize) / 2
+ " " + d.x + "," + d.y;
;
Thank you for your time!
edited Nov 14 '18 at 11:54
bfontaine
9,34674474
answered Nov 14 '18 at 10:13
ZoomZoom
53
Problem solved! As i said in the comments, I needed to move the horizontal line. I added nodeSize in my two y "control points". And nodeSize is actually source.y - destination.y - padding. This is my final equation:
function diagonal(s, d)
var nodeSize = s.y - d.y - 30
return "M" + s.x + "," + s.y
+ "L" + s.x + "," + (d.y + s.y + nodeSize) / 2
+ " " + d.x + "," + (d.y + s.y + nodeSize) / 2
+ " " + d.x + "," + d.y;
;
Thank you for your time!
edited Nov 14 '18 at 11:54
bfontaine
9,34674474
answered Nov 14 '18 at 10:13
ZoomZoom
53
edited Nov 14 '18 at 11:54
bfontaine
9,34674474
edited Nov 14 '18 at 11:54
bfontaine
9,34674474
edited Nov 14 '18 at 11:54
bfontaine
9,34674474
9,34674474
answered Nov 14 '18 at 10:13
ZoomZoom
53
answered Nov 14 '18 at 10:13
ZoomZoom
53
answered Nov 14 '18 at 10:13
ZoomZoom
53
53
add a comment |
add a comment |
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where is the mid bottom relative to the box center?
– rioV8
Nov 13 '18 at 15:37
I am not sure that I understand the question, when I said center it's because I multiply by 0.5 in the path equation. Is it what you talk about ?
– Zoom
Nov 13 '18 at 15:40
you calculate the mid point between the centers of the nodes, I talk about the node box
– rioV8
Nov 13 '18 at 16:05
I think I understood something ^^ What I do : I draw from nodeParent to nodeChild. this result in : topParentBox to topChildBox. So I know that I rather want => bottomParentBox to topChildBox. It's probably something like : (nodeParent + nodeSize) to nodeChild. But I dont successfully acces to nodeSize AND all my attempts to change the equation resulted in non-sense. I hope it's not to confuse... Thank you for your time, I'm really grateful !
– Zoom
Nov 13 '18 at 16:22
if you need some data in some objects put it in so you can use it in the link calculation
– rioV8
Nov 13 '18 at 19:00