NumberFormatter string(from:NSNumber) method has issues with decimal places










1















Here is my code



let ns = NumberFormatter.init()
ns.allowsFloats = true
ns.maximumFractionDigits = 18 //This is a variable value
ns.minimumFractionDigits = 18 //This is a variable value
ns.roundingMode = .floor
ns.numberStyle = .decimal
let doubleValueOfDecimal : Double = 12.95699999999998
let numb = NSNumber.init(value: doubleValueOfDecimal)
print(numb)
let string = ns.string(from: numb)
print(string)


The following is the output and input

doubleValueOfDecimal = 2.95699999999998
Output
2.95699999999998
Optional("2.956999999999980000")

But if I input



doubleValueOfDecimal = 12.95699999999998


The output is



12.95699999999998
Optional("12.957000000000000000")


The string conversion rounds up the value.
Can someone explain me how this works?



The string conversion is rounding up the decimal places when I want it to show the exact number.










share|improve this question
























  • Can you edit your question and add the declaration, and inferred type if it's not explicit, of doubleValueOfDecimal?

    – CRD
    Nov 12 '18 at 8:10











  • Possible duplicate of Is floating point math broken?

    – Gereon
    Nov 12 '18 at 9:31















1















Here is my code



let ns = NumberFormatter.init()
ns.allowsFloats = true
ns.maximumFractionDigits = 18 //This is a variable value
ns.minimumFractionDigits = 18 //This is a variable value
ns.roundingMode = .floor
ns.numberStyle = .decimal
let doubleValueOfDecimal : Double = 12.95699999999998
let numb = NSNumber.init(value: doubleValueOfDecimal)
print(numb)
let string = ns.string(from: numb)
print(string)


The following is the output and input

doubleValueOfDecimal = 2.95699999999998
Output
2.95699999999998
Optional("2.956999999999980000")

But if I input



doubleValueOfDecimal = 12.95699999999998


The output is



12.95699999999998
Optional("12.957000000000000000")


The string conversion rounds up the value.
Can someone explain me how this works?



The string conversion is rounding up the decimal places when I want it to show the exact number.










share|improve this question
























  • Can you edit your question and add the declaration, and inferred type if it's not explicit, of doubleValueOfDecimal?

    – CRD
    Nov 12 '18 at 8:10











  • Possible duplicate of Is floating point math broken?

    – Gereon
    Nov 12 '18 at 9:31













1












1








1








Here is my code



let ns = NumberFormatter.init()
ns.allowsFloats = true
ns.maximumFractionDigits = 18 //This is a variable value
ns.minimumFractionDigits = 18 //This is a variable value
ns.roundingMode = .floor
ns.numberStyle = .decimal
let doubleValueOfDecimal : Double = 12.95699999999998
let numb = NSNumber.init(value: doubleValueOfDecimal)
print(numb)
let string = ns.string(from: numb)
print(string)


The following is the output and input

doubleValueOfDecimal = 2.95699999999998
Output
2.95699999999998
Optional("2.956999999999980000")

But if I input



doubleValueOfDecimal = 12.95699999999998


The output is



12.95699999999998
Optional("12.957000000000000000")


The string conversion rounds up the value.
Can someone explain me how this works?



The string conversion is rounding up the decimal places when I want it to show the exact number.










share|improve this question
















Here is my code



let ns = NumberFormatter.init()
ns.allowsFloats = true
ns.maximumFractionDigits = 18 //This is a variable value
ns.minimumFractionDigits = 18 //This is a variable value
ns.roundingMode = .floor
ns.numberStyle = .decimal
let doubleValueOfDecimal : Double = 12.95699999999998
let numb = NSNumber.init(value: doubleValueOfDecimal)
print(numb)
let string = ns.string(from: numb)
print(string)


The following is the output and input

doubleValueOfDecimal = 2.95699999999998
Output
2.95699999999998
Optional("2.956999999999980000")

But if I input



doubleValueOfDecimal = 12.95699999999998


The output is



12.95699999999998
Optional("12.957000000000000000")


The string conversion rounds up the value.
Can someone explain me how this works?



The string conversion is rounding up the decimal places when I want it to show the exact number.







ios swift decimal nsnumberformatter nsdecimalnumber






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 12 '18 at 8:13







AjinkyaSharma

















asked Nov 12 '18 at 7:03









AjinkyaSharmaAjinkyaSharma

414312




414312












  • Can you edit your question and add the declaration, and inferred type if it's not explicit, of doubleValueOfDecimal?

    – CRD
    Nov 12 '18 at 8:10











  • Possible duplicate of Is floating point math broken?

    – Gereon
    Nov 12 '18 at 9:31

















  • Can you edit your question and add the declaration, and inferred type if it's not explicit, of doubleValueOfDecimal?

    – CRD
    Nov 12 '18 at 8:10











  • Possible duplicate of Is floating point math broken?

    – Gereon
    Nov 12 '18 at 9:31
















Can you edit your question and add the declaration, and inferred type if it's not explicit, of doubleValueOfDecimal?

– CRD
Nov 12 '18 at 8:10





Can you edit your question and add the declaration, and inferred type if it's not explicit, of doubleValueOfDecimal?

– CRD
Nov 12 '18 at 8:10













Possible duplicate of Is floating point math broken?

– Gereon
Nov 12 '18 at 9:31





Possible duplicate of Is floating point math broken?

– Gereon
Nov 12 '18 at 9:31












2 Answers
2






active

oldest

votes


















0














Use wrapper method of NSNumber class. `




 print(numb.stringValue)



let ns = NumberFormatter.init()
ns.allowsFloats = true
ns.maximumFractionDigits = 18
ns.minimumFractionDigits = 18
ns.roundingMode = .floor
ns.numberStyle = .decimal
let numb = NSNumber.init(value: doubleValueOfDecimal)
print(numb)
let string = ns.string(from: numb)
print(numb.stringValue)



Below Output for 2.95699999999998 , 12.95699999999998 values.




Output



2.95699999999998



2.95699999999998



12.95699999999998



12.95699999999998






share|improve this answer























  • I have used NumberFormatter class for a reason. The maximumFractionDigits and minimumFractionDigits are variables and not constants. So I can't ditch the whole setup for Formatter and directly use the stringValue

    – AjinkyaSharma
    Nov 12 '18 at 7:45


















0














You are falling down the cracks between the expectations of the behaviour of decimal numbers and the reality that Float and Double are binary floating-point, that is the fractional part decimal numbers as sums of 1/10's, 1/100's etc. while for binary numbers it is sums of 1/2's, 1/4's etc. and some values exact in one are inexact in the other and vice-versa.



Change your code to include:



let doubleValueOfDecimal : Decimal = Decimal(string:"12.95699999999998")!
let numb = doubleValueOfDecimal as NSDecimalNumber


and the output is probably what you expect:



12.95699999999998
12.956999999999980000


The Decimal type is a decimal floating-point value type, NSDecimalNumber is a subclass of NSNumber which holds a Decimal value.



HTH



(Note: you have to initialise the Decimal from a string as the using a numeric literal appears to involve the Swift compiler using binary floating point at some point in the process...)






share|improve this answer






















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    2 Answers
    2






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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    Use wrapper method of NSNumber class. `




     print(numb.stringValue)



    let ns = NumberFormatter.init()
    ns.allowsFloats = true
    ns.maximumFractionDigits = 18
    ns.minimumFractionDigits = 18
    ns.roundingMode = .floor
    ns.numberStyle = .decimal
    let numb = NSNumber.init(value: doubleValueOfDecimal)
    print(numb)
    let string = ns.string(from: numb)
    print(numb.stringValue)



    Below Output for 2.95699999999998 , 12.95699999999998 values.




    Output



    2.95699999999998



    2.95699999999998



    12.95699999999998



    12.95699999999998






    share|improve this answer























    • I have used NumberFormatter class for a reason. The maximumFractionDigits and minimumFractionDigits are variables and not constants. So I can't ditch the whole setup for Formatter and directly use the stringValue

      – AjinkyaSharma
      Nov 12 '18 at 7:45















    0














    Use wrapper method of NSNumber class. `




     print(numb.stringValue)



    let ns = NumberFormatter.init()
    ns.allowsFloats = true
    ns.maximumFractionDigits = 18
    ns.minimumFractionDigits = 18
    ns.roundingMode = .floor
    ns.numberStyle = .decimal
    let numb = NSNumber.init(value: doubleValueOfDecimal)
    print(numb)
    let string = ns.string(from: numb)
    print(numb.stringValue)



    Below Output for 2.95699999999998 , 12.95699999999998 values.




    Output



    2.95699999999998



    2.95699999999998



    12.95699999999998



    12.95699999999998






    share|improve this answer























    • I have used NumberFormatter class for a reason. The maximumFractionDigits and minimumFractionDigits are variables and not constants. So I can't ditch the whole setup for Formatter and directly use the stringValue

      – AjinkyaSharma
      Nov 12 '18 at 7:45













    0












    0








    0







    Use wrapper method of NSNumber class. `




     print(numb.stringValue)



    let ns = NumberFormatter.init()
    ns.allowsFloats = true
    ns.maximumFractionDigits = 18
    ns.minimumFractionDigits = 18
    ns.roundingMode = .floor
    ns.numberStyle = .decimal
    let numb = NSNumber.init(value: doubleValueOfDecimal)
    print(numb)
    let string = ns.string(from: numb)
    print(numb.stringValue)



    Below Output for 2.95699999999998 , 12.95699999999998 values.




    Output



    2.95699999999998



    2.95699999999998



    12.95699999999998



    12.95699999999998






    share|improve this answer













    Use wrapper method of NSNumber class. `




     print(numb.stringValue)



    let ns = NumberFormatter.init()
    ns.allowsFloats = true
    ns.maximumFractionDigits = 18
    ns.minimumFractionDigits = 18
    ns.roundingMode = .floor
    ns.numberStyle = .decimal
    let numb = NSNumber.init(value: doubleValueOfDecimal)
    print(numb)
    let string = ns.string(from: numb)
    print(numb.stringValue)



    Below Output for 2.95699999999998 , 12.95699999999998 values.




    Output



    2.95699999999998



    2.95699999999998



    12.95699999999998



    12.95699999999998







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 12 '18 at 7:29









    Pratik SodhaPratik Sodha

    537415




    537415












    • I have used NumberFormatter class for a reason. The maximumFractionDigits and minimumFractionDigits are variables and not constants. So I can't ditch the whole setup for Formatter and directly use the stringValue

      – AjinkyaSharma
      Nov 12 '18 at 7:45

















    • I have used NumberFormatter class for a reason. The maximumFractionDigits and minimumFractionDigits are variables and not constants. So I can't ditch the whole setup for Formatter and directly use the stringValue

      – AjinkyaSharma
      Nov 12 '18 at 7:45
















    I have used NumberFormatter class for a reason. The maximumFractionDigits and minimumFractionDigits are variables and not constants. So I can't ditch the whole setup for Formatter and directly use the stringValue

    – AjinkyaSharma
    Nov 12 '18 at 7:45





    I have used NumberFormatter class for a reason. The maximumFractionDigits and minimumFractionDigits are variables and not constants. So I can't ditch the whole setup for Formatter and directly use the stringValue

    – AjinkyaSharma
    Nov 12 '18 at 7:45













    0














    You are falling down the cracks between the expectations of the behaviour of decimal numbers and the reality that Float and Double are binary floating-point, that is the fractional part decimal numbers as sums of 1/10's, 1/100's etc. while for binary numbers it is sums of 1/2's, 1/4's etc. and some values exact in one are inexact in the other and vice-versa.



    Change your code to include:



    let doubleValueOfDecimal : Decimal = Decimal(string:"12.95699999999998")!
    let numb = doubleValueOfDecimal as NSDecimalNumber


    and the output is probably what you expect:



    12.95699999999998
    12.956999999999980000


    The Decimal type is a decimal floating-point value type, NSDecimalNumber is a subclass of NSNumber which holds a Decimal value.



    HTH



    (Note: you have to initialise the Decimal from a string as the using a numeric literal appears to involve the Swift compiler using binary floating point at some point in the process...)






    share|improve this answer



























      0














      You are falling down the cracks between the expectations of the behaviour of decimal numbers and the reality that Float and Double are binary floating-point, that is the fractional part decimal numbers as sums of 1/10's, 1/100's etc. while for binary numbers it is sums of 1/2's, 1/4's etc. and some values exact in one are inexact in the other and vice-versa.



      Change your code to include:



      let doubleValueOfDecimal : Decimal = Decimal(string:"12.95699999999998")!
      let numb = doubleValueOfDecimal as NSDecimalNumber


      and the output is probably what you expect:



      12.95699999999998
      12.956999999999980000


      The Decimal type is a decimal floating-point value type, NSDecimalNumber is a subclass of NSNumber which holds a Decimal value.



      HTH



      (Note: you have to initialise the Decimal from a string as the using a numeric literal appears to involve the Swift compiler using binary floating point at some point in the process...)






      share|improve this answer

























        0












        0








        0







        You are falling down the cracks between the expectations of the behaviour of decimal numbers and the reality that Float and Double are binary floating-point, that is the fractional part decimal numbers as sums of 1/10's, 1/100's etc. while for binary numbers it is sums of 1/2's, 1/4's etc. and some values exact in one are inexact in the other and vice-versa.



        Change your code to include:



        let doubleValueOfDecimal : Decimal = Decimal(string:"12.95699999999998")!
        let numb = doubleValueOfDecimal as NSDecimalNumber


        and the output is probably what you expect:



        12.95699999999998
        12.956999999999980000


        The Decimal type is a decimal floating-point value type, NSDecimalNumber is a subclass of NSNumber which holds a Decimal value.



        HTH



        (Note: you have to initialise the Decimal from a string as the using a numeric literal appears to involve the Swift compiler using binary floating point at some point in the process...)






        share|improve this answer













        You are falling down the cracks between the expectations of the behaviour of decimal numbers and the reality that Float and Double are binary floating-point, that is the fractional part decimal numbers as sums of 1/10's, 1/100's etc. while for binary numbers it is sums of 1/2's, 1/4's etc. and some values exact in one are inexact in the other and vice-versa.



        Change your code to include:



        let doubleValueOfDecimal : Decimal = Decimal(string:"12.95699999999998")!
        let numb = doubleValueOfDecimal as NSDecimalNumber


        and the output is probably what you expect:



        12.95699999999998
        12.956999999999980000


        The Decimal type is a decimal floating-point value type, NSDecimalNumber is a subclass of NSNumber which holds a Decimal value.



        HTH



        (Note: you have to initialise the Decimal from a string as the using a numeric literal appears to involve the Swift compiler using binary floating point at some point in the process...)







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 12 '18 at 9:26









        CRDCRD

        45k44870




        45k44870



























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