How to draw disjoint Tori in latex?
3
I would like to draw the following diagram :
I have used the following code generated in Geogebra, but it does not make the diagram which I want.
begintikzpicture[line cap=round,line join=round,>=triangle 45,x=0.7cm,y=0.7cm]
draw (0,4)-- (4,0);
draw (4,0)-- (0,-4);
draw (0,-4)-- (-4,0);
draw (-4,0)-- (0,4);
draw (5.41,-0.03)-- (9.41,3.97);
draw (9.41,3.97)-- (13.41,-0.03);
draw (13.41,-0.03)-- (9.41,-4.03);
draw (9.41,-4.03)-- (5.41,-0.03);
draw [->] (2,2) -- (1.47,2.53);
draw [->] (-1.59,2.41) -- (-2.26,1.74);
draw [->] (2.5,-1.5) -- (1.81,-2.19);
draw [->] (-1.55,-2.45) -- (-2.34,-1.66);
draw [->] (7.11,1.66) -- (7.67,2.22);
draw [->] (11.29,-2.16) -- (11.85,-1.59);
draw [->] (11.26,2.12) -- (11.89,1.5);
draw [->] (6.9,-1.51) -- (7.98,-2.59);
draw [shift=(2.18,3.21)] plot[domain=4.22:5.23,variable=t](1*3.69*cos(t r)+0*3.69*sin(t r),0*3.69*cos(t r)+1*3.69*sin(t r));
draw [shift=(2.26,-2.4)] plot[domain=0.94:2.23,variable=t](1*2.97*cos(t r)+0*2.97*sin(t r),0*2.97*cos(t r)+1*2.97*sin(t r));
draw [shift=(7.17,-1.78)] plot[domain=0.81:2.36,variable=t](1*2.48*cos(t r)+0*2.48*sin(t r),0*2.48*cos(t r)+1*2.48*sin(t r));
draw [shift=(7.12,2.08)] plot[domain=4.03:5.42,variable=t](1*2.71*cos(t r)+0*2.71*sin(t r),0*2.71*cos(t r)+1*2.71*sin(t r));
draw (2.46,-2.36) node $b1$;
draw (2.67,2.47) node $a1$;
draw (-2.17,2.32) node $b1$;
draw (-2.44,-2.18) node $a1$;
draw (-2.13,0.07) node $T1$;
draw (7.39,2.26) node $b2$;
draw (12.1,-2.06) node $b2$;
draw (10.43,-0.69) node $T2$;
draw (11.98,2.38) node $a2$;
draw (7.17,-2.24) node $a2$;
endtikzpicture
It produces :
tikz-pgf diagrams
asked Nov 11 '18 at 9:01
H.S.H.S.
573
add a comment |
3
I would like to draw the following diagram :
I have used the following code generated in Geogebra, but it does not make the diagram which I want.
begintikzpicture[line cap=round,line join=round,>=triangle 45,x=0.7cm,y=0.7cm]
draw (0,4)-- (4,0);
draw (4,0)-- (0,-4);
draw (0,-4)-- (-4,0);
draw (-4,0)-- (0,4);
draw (5.41,-0.03)-- (9.41,3.97);
draw (9.41,3.97)-- (13.41,-0.03);
draw (13.41,-0.03)-- (9.41,-4.03);
draw (9.41,-4.03)-- (5.41,-0.03);
draw [->] (2,2) -- (1.47,2.53);
draw [->] (-1.59,2.41) -- (-2.26,1.74);
draw [->] (2.5,-1.5) -- (1.81,-2.19);
draw [->] (-1.55,-2.45) -- (-2.34,-1.66);
draw [->] (7.11,1.66) -- (7.67,2.22);
draw [->] (11.29,-2.16) -- (11.85,-1.59);
draw [->] (11.26,2.12) -- (11.89,1.5);
draw [->] (6.9,-1.51) -- (7.98,-2.59);
draw [shift=(2.18,3.21)] plot[domain=4.22:5.23,variable=t](1*3.69*cos(t r)+0*3.69*sin(t r),0*3.69*cos(t r)+1*3.69*sin(t r));
draw [shift=(2.26,-2.4)] plot[domain=0.94:2.23,variable=t](1*2.97*cos(t r)+0*2.97*sin(t r),0*2.97*cos(t r)+1*2.97*sin(t r));
draw [shift=(7.17,-1.78)] plot[domain=0.81:2.36,variable=t](1*2.48*cos(t r)+0*2.48*sin(t r),0*2.48*cos(t r)+1*2.48*sin(t r));
draw [shift=(7.12,2.08)] plot[domain=4.03:5.42,variable=t](1*2.71*cos(t r)+0*2.71*sin(t r),0*2.71*cos(t r)+1*2.71*sin(t r));
draw (2.46,-2.36) node $b1$;
draw (2.67,2.47) node $a1$;
draw (-2.17,2.32) node $b1$;
draw (-2.44,-2.18) node $a1$;
draw (-2.13,0.07) node $T1$;
draw (7.39,2.26) node $b2$;
draw (12.1,-2.06) node $b2$;
draw (10.43,-0.69) node $T2$;
draw (11.98,2.38) node $a2$;
draw (7.17,-2.24) node $a2$;
endtikzpicture
It produces :
tikz-pgf diagrams
asked Nov 11 '18 at 9:01
H.S.H.S.
573
add a comment |
3
3
3
0
I would like to draw the following diagram :
I have used the following code generated in Geogebra, but it does not make the diagram which I want.
begintikzpicture[line cap=round,line join=round,>=triangle 45,x=0.7cm,y=0.7cm]
draw (0,4)-- (4,0);
draw (4,0)-- (0,-4);
draw (0,-4)-- (-4,0);
draw (-4,0)-- (0,4);
draw (5.41,-0.03)-- (9.41,3.97);
draw (9.41,3.97)-- (13.41,-0.03);
draw (13.41,-0.03)-- (9.41,-4.03);
draw (9.41,-4.03)-- (5.41,-0.03);
draw [->] (2,2) -- (1.47,2.53);
draw [->] (-1.59,2.41) -- (-2.26,1.74);
draw [->] (2.5,-1.5) -- (1.81,-2.19);
draw [->] (-1.55,-2.45) -- (-2.34,-1.66);
draw [->] (7.11,1.66) -- (7.67,2.22);
draw [->] (11.29,-2.16) -- (11.85,-1.59);
draw [->] (11.26,2.12) -- (11.89,1.5);
draw [->] (6.9,-1.51) -- (7.98,-2.59);
draw [shift=(2.18,3.21)] plot[domain=4.22:5.23,variable=t](1*3.69*cos(t r)+0*3.69*sin(t r),0*3.69*cos(t r)+1*3.69*sin(t r));
draw [shift=(2.26,-2.4)] plot[domain=0.94:2.23,variable=t](1*2.97*cos(t r)+0*2.97*sin(t r),0*2.97*cos(t r)+1*2.97*sin(t r));
draw [shift=(7.17,-1.78)] plot[domain=0.81:2.36,variable=t](1*2.48*cos(t r)+0*2.48*sin(t r),0*2.48*cos(t r)+1*2.48*sin(t r));
draw [shift=(7.12,2.08)] plot[domain=4.03:5.42,variable=t](1*2.71*cos(t r)+0*2.71*sin(t r),0*2.71*cos(t r)+1*2.71*sin(t r));
draw (2.46,-2.36) node $b1$;
draw (2.67,2.47) node $a1$;
draw (-2.17,2.32) node $b1$;
draw (-2.44,-2.18) node $a1$;
draw (-2.13,0.07) node $T1$;
draw (7.39,2.26) node $b2$;
draw (12.1,-2.06) node $b2$;
draw (10.43,-0.69) node $T2$;
draw (11.98,2.38) node $a2$;
draw (7.17,-2.24) node $a2$;
endtikzpicture
It produces :
tikz-pgf diagrams
asked Nov 11 '18 at 9:01
H.S.H.S.
573
I would like to draw the following diagram :
I have used the following code generated in Geogebra, but it does not make the diagram which I want.
begintikzpicture[line cap=round,line join=round,>=triangle 45,x=0.7cm,y=0.7cm]
draw (0,4)-- (4,0);
draw (4,0)-- (0,-4);
draw (0,-4)-- (-4,0);
draw (-4,0)-- (0,4);
draw (5.41,-0.03)-- (9.41,3.97);
draw (9.41,3.97)-- (13.41,-0.03);
draw (13.41,-0.03)-- (9.41,-4.03);
draw (9.41,-4.03)-- (5.41,-0.03);
draw [->] (2,2) -- (1.47,2.53);
draw [->] (-1.59,2.41) -- (-2.26,1.74);
draw [->] (2.5,-1.5) -- (1.81,-2.19);
draw [->] (-1.55,-2.45) -- (-2.34,-1.66);
draw [->] (7.11,1.66) -- (7.67,2.22);
draw [->] (11.29,-2.16) -- (11.85,-1.59);
draw [->] (11.26,2.12) -- (11.89,1.5);
draw [->] (6.9,-1.51) -- (7.98,-2.59);
draw [shift=(2.18,3.21)] plot[domain=4.22:5.23,variable=t](1*3.69*cos(t r)+0*3.69*sin(t r),0*3.69*cos(t r)+1*3.69*sin(t r));
draw [shift=(2.26,-2.4)] plot[domain=0.94:2.23,variable=t](1*2.97*cos(t r)+0*2.97*sin(t r),0*2.97*cos(t r)+1*2.97*sin(t r));
draw [shift=(7.17,-1.78)] plot[domain=0.81:2.36,variable=t](1*2.48*cos(t r)+0*2.48*sin(t r),0*2.48*cos(t r)+1*2.48*sin(t r));
draw [shift=(7.12,2.08)] plot[domain=4.03:5.42,variable=t](1*2.71*cos(t r)+0*2.71*sin(t r),0*2.71*cos(t r)+1*2.71*sin(t r));
draw (2.46,-2.36) node $b1$;
draw (2.67,2.47) node $a1$;
draw (-2.17,2.32) node $b1$;
draw (-2.44,-2.18) node $a1$;
draw (-2.13,0.07) node $T1$;
draw (7.39,2.26) node $b2$;
draw (12.1,-2.06) node $b2$;
draw (10.43,-0.69) node $T2$;
draw (11.98,2.38) node $a2$;
draw (7.17,-2.24) node $a2$;
endtikzpicture
It produces :
tikz-pgf diagrams
tikz-pgf diagrams
asked Nov 11 '18 at 9:01
H.S.H.S.
573
asked Nov 11 '18 at 9:01
H.S.H.S.
573
asked Nov 11 '18 at 9:01
H.S.H.S.
573
asked Nov 11 '18 at 9:01
H.S.H.S.
573
asked Nov 11 '18 at 9:01
H.S.H.S.
573
573
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
2
To draw this curve, I used the operation Curve-To (see p 149 of manual 3.0.1a).
draw [postaction=decorate](4,0)..controls +(-4,-2.5) and +(-4,2.5).. (4,0);
To place the arrow in the middle, I used the answer from @Caramdir TikZ: How to draw an arrow in the middle of the line?
It is possible to simplify your code. I didn't do it so you could understand the changes made. But it is always possible to do so if you wish.
documentclassarticle
usepackagetikz
usetikzlibraryarrows.meta
usetikzlibrarydecorations.markings
begindocument
begintikzpicture[line cap=round,line join=round,>=Triangle,scale=.7]
draw (0,4)-- (4,0);
draw (4,0)-- (0,-4);
draw (0,-4)-- (-4,0);
draw (-4,0)-- (0,4);
draw (5.41,-0.03)-- (9.41,3.97);
draw (9.41,3.97)-- (13.41,-0.03);
draw (13.41,-0.03)-- (9.41,-4.03);
draw (9.41,-4.03)-- (5.41,-0.03);
draw [->] (2,2) -- (1.47,2.53);
draw [->] (-1.59,2.41) -- (-2.26,1.74);
draw [->] (2.5,-1.5) -- (1.81,-2.19);
draw [->] (-1.55,-2.45) -- (-2.34,-1.66);
draw [->] (7.11,1.66) -- (7.67,2.22);
draw [->] (11.29,-2.16) -- (11.85,-1.59);
draw [->] (11.26,2.12) -- (11.89,1.5);
draw [->] (6.9,-1.51) -- (7.98,-2.59);
% arrow in the middle from https://tex.stackexchange.com/a/3172/138900
beginscope[decoration=markings,mark=at position 0.5 with arrow>]
draw [postaction=decorate,fill=gray!50](4,0)..controls +(-4,-2.5) and +(-4,2.5).. (4,0);
draw [postaction=decorate,fill=gray!50](5.41,-0.03)..controls +(4,-2.5) and +(4,2.5).. (5.41,-0.03);
endscope
draw (2.46,-2.36) node $b1$;
draw (2.67,2.47) node $a1$;
draw (-2.17,2.32) node $b1$;
draw (-2.44,-2.18) node $a1$;
draw (-2.13,0.07) node $T1$;
draw (7.39,2.26) node $b2$;
draw (12.1,-2.06) node $b2$;
draw (10.43,-0.69) node $T2$;
draw (11.98,2.38) node $a2$;
draw (7.17,-2.24) node $a2$;
endtikzpicture
enddocument
answered Nov 11 '18 at 9:36
AndréCAndréC
8,78411447
add a comment |
2
An alternative with the same idea as @AndréC answer but without scope and with to instead of controls
documentclassbook
usepackagetikz
usetikzlibraryarrows,decorations.markings
begindocument
begintikzpicture[line cap=round,line join=round,>=triangle 45,x=0.7cm,y=0.7cm, decoration=markings, mark=at position 0.52 with arrow>]
draw (0,4)-- (4,0);
draw (4,0)-- (0,-4);
draw (0,-4)-- (-4,0);
draw (-4,0)-- (0,4);
draw (5.41,-0.03)-- (9.41,3.97);
draw (9.41,3.97)-- (13.41,-0.03);
draw (13.41,-0.03)-- (9.41,-4.03);
draw (9.41,-4.03)-- (5.41,-0.03);
draw [->] (2,2) -- (1.47,2.53);
draw [->] (-1.59,2.41) -- (-2.26,1.74);
draw [->] (2.5,-1.5) -- (1.81,-2.19);
draw [->] (-1.55,-2.45) -- (-2.34,-1.66);
draw [->] (7.11,1.66) -- (7.67,2.22);
draw [->] (11.29,-2.16) -- (11.85,-1.59);
draw [->] (11.26,2.12) -- (11.89,1.5);
draw [->] (6.9,-1.51) -- (7.98,-2.59);
%draw [shift=(2.18,3.21)] plot[domain=4.22:5.23,variable=t](1*3.69*cos(t r)+0*3.69*sin(t r),0*3.69*cos(t r)+1*3.69*sin(t r));
%draw [shift=(2.26,-2.4)] plot[domain=0.94:2.23,variable=t](1*2.97*cos(t r)+0*2.97*sin(t r),0*2.97*cos(t r)+1*2.97*sin(t r));
%draw [shift=(7.17,-1.78)] plot[domain=0.81:2.36,variable=t](1*2.48*cos(t r)+0*2.48*sin(t r),0*2.48*cos(t r)+1*2.48*sin(t r));
%draw [shift=(7.12,2.08)] plot[domain=4.03:5.42,variable=t](1*2.71*cos(t r)+0*2.71*sin(t r),0*2.71*cos(t r)+1*2.71*sin(t r));
draw[fill=gray,,postaction=decorate] (4,0) to[in=270, out=225] (1,0) to[in=135, out=90] (4,0);
draw[fill=gray,,postaction=decorate] (5.42,0) to[in=270, out=315] (8.42,0) to[in=45, out=90] (5.42,0);
draw (2.46,-2.36) node $b1$;
draw (2.67,2.47) node $a1$;
draw (-2.17,2.32) node $b1$;
draw (-2.44,-2.18) node $a1$;
draw (-2.13,0.07) node $T1$;
draw (7.39,2.26) node $b2$;
draw (12.1,-2.06) node $b2$;
draw (10.43,-0.69) node $T2$;
draw (11.98,2.38) node $a2$;
draw (7.17,-2.24) node $a2$;
endtikzpicture
enddocument
PS: Please upvote his answer instead of mine because he answered before me, but his answer became visible to me after I had already created the code... and so, I decided to add it as an alternative.
answered Nov 11 '18 at 9:52
koleygrkoleygr
11.2k11038
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
To draw this curve, I used the operation Curve-To (see p 149 of manual 3.0.1a).
draw [postaction=decorate](4,0)..controls +(-4,-2.5) and +(-4,2.5).. (4,0);
To place the arrow in the middle, I used the answer from @Caramdir TikZ: How to draw an arrow in the middle of the line?
It is possible to simplify your code. I didn't do it so you could understand the changes made. But it is always possible to do so if you wish.
documentclassarticle
usepackagetikz
usetikzlibraryarrows.meta
usetikzlibrarydecorations.markings
begindocument
begintikzpicture[line cap=round,line join=round,>=Triangle,scale=.7]
draw (0,4)-- (4,0);
draw (4,0)-- (0,-4);
draw (0,-4)-- (-4,0);
draw (-4,0)-- (0,4);
draw (5.41,-0.03)-- (9.41,3.97);
draw (9.41,3.97)-- (13.41,-0.03);
draw (13.41,-0.03)-- (9.41,-4.03);
draw (9.41,-4.03)-- (5.41,-0.03);
draw [->] (2,2) -- (1.47,2.53);
draw [->] (-1.59,2.41) -- (-2.26,1.74);
draw [->] (2.5,-1.5) -- (1.81,-2.19);
draw [->] (-1.55,-2.45) -- (-2.34,-1.66);
draw [->] (7.11,1.66) -- (7.67,2.22);
draw [->] (11.29,-2.16) -- (11.85,-1.59);
draw [->] (11.26,2.12) -- (11.89,1.5);
draw [->] (6.9,-1.51) -- (7.98,-2.59);
% arrow in the middle from https://tex.stackexchange.com/a/3172/138900
beginscope[decoration=markings,mark=at position 0.5 with arrow>]
draw [postaction=decorate,fill=gray!50](4,0)..controls +(-4,-2.5) and +(-4,2.5).. (4,0);
draw [postaction=decorate,fill=gray!50](5.41,-0.03)..controls +(4,-2.5) and +(4,2.5).. (5.41,-0.03);
endscope
draw (2.46,-2.36) node $b1$;
draw (2.67,2.47) node $a1$;
draw (-2.17,2.32) node $b1$;
draw (-2.44,-2.18) node $a1$;
draw (-2.13,0.07) node $T1$;
draw (7.39,2.26) node $b2$;
draw (12.1,-2.06) node $b2$;
draw (10.43,-0.69) node $T2$;
draw (11.98,2.38) node $a2$;
draw (7.17,-2.24) node $a2$;
endtikzpicture
enddocument
answered Nov 11 '18 at 9:36
AndréCAndréC
8,78411447
add a comment |
2
To draw this curve, I used the operation Curve-To (see p 149 of manual 3.0.1a).
draw [postaction=decorate](4,0)..controls +(-4,-2.5) and +(-4,2.5).. (4,0);
To place the arrow in the middle, I used the answer from @Caramdir TikZ: How to draw an arrow in the middle of the line?
It is possible to simplify your code. I didn't do it so you could understand the changes made. But it is always possible to do so if you wish.
documentclassarticle
usepackagetikz
usetikzlibraryarrows.meta
usetikzlibrarydecorations.markings
begindocument
begintikzpicture[line cap=round,line join=round,>=Triangle,scale=.7]
draw (0,4)-- (4,0);
draw (4,0)-- (0,-4);
draw (0,-4)-- (-4,0);
draw (-4,0)-- (0,4);
draw (5.41,-0.03)-- (9.41,3.97);
draw (9.41,3.97)-- (13.41,-0.03);
draw (13.41,-0.03)-- (9.41,-4.03);
draw (9.41,-4.03)-- (5.41,-0.03);
draw [->] (2,2) -- (1.47,2.53);
draw [->] (-1.59,2.41) -- (-2.26,1.74);
draw [->] (2.5,-1.5) -- (1.81,-2.19);
draw [->] (-1.55,-2.45) -- (-2.34,-1.66);
draw [->] (7.11,1.66) -- (7.67,2.22);
draw [->] (11.29,-2.16) -- (11.85,-1.59);
draw [->] (11.26,2.12) -- (11.89,1.5);
draw [->] (6.9,-1.51) -- (7.98,-2.59);
% arrow in the middle from https://tex.stackexchange.com/a/3172/138900
beginscope[decoration=markings,mark=at position 0.5 with arrow>]
draw [postaction=decorate,fill=gray!50](4,0)..controls +(-4,-2.5) and +(-4,2.5).. (4,0);
draw [postaction=decorate,fill=gray!50](5.41,-0.03)..controls +(4,-2.5) and +(4,2.5).. (5.41,-0.03);
endscope
draw (2.46,-2.36) node $b1$;
draw (2.67,2.47) node $a1$;
draw (-2.17,2.32) node $b1$;
draw (-2.44,-2.18) node $a1$;
draw (-2.13,0.07) node $T1$;
draw (7.39,2.26) node $b2$;
draw (12.1,-2.06) node $b2$;
draw (10.43,-0.69) node $T2$;
draw (11.98,2.38) node $a2$;
draw (7.17,-2.24) node $a2$;
endtikzpicture
enddocument
answered Nov 11 '18 at 9:36
AndréCAndréC
8,78411447
add a comment |
2
2
2
To draw this curve, I used the operation Curve-To (see p 149 of manual 3.0.1a).
draw [postaction=decorate](4,0)..controls +(-4,-2.5) and +(-4,2.5).. (4,0);
To place the arrow in the middle, I used the answer from @Caramdir TikZ: How to draw an arrow in the middle of the line?
It is possible to simplify your code. I didn't do it so you could understand the changes made. But it is always possible to do so if you wish.
documentclassarticle
usepackagetikz
usetikzlibraryarrows.meta
usetikzlibrarydecorations.markings
begindocument
begintikzpicture[line cap=round,line join=round,>=Triangle,scale=.7]
draw (0,4)-- (4,0);
draw (4,0)-- (0,-4);
draw (0,-4)-- (-4,0);
draw (-4,0)-- (0,4);
draw (5.41,-0.03)-- (9.41,3.97);
draw (9.41,3.97)-- (13.41,-0.03);
draw (13.41,-0.03)-- (9.41,-4.03);
draw (9.41,-4.03)-- (5.41,-0.03);
draw [->] (2,2) -- (1.47,2.53);
draw [->] (-1.59,2.41) -- (-2.26,1.74);
draw [->] (2.5,-1.5) -- (1.81,-2.19);
draw [->] (-1.55,-2.45) -- (-2.34,-1.66);
draw [->] (7.11,1.66) -- (7.67,2.22);
draw [->] (11.29,-2.16) -- (11.85,-1.59);
draw [->] (11.26,2.12) -- (11.89,1.5);
draw [->] (6.9,-1.51) -- (7.98,-2.59);
% arrow in the middle from https://tex.stackexchange.com/a/3172/138900
beginscope[decoration=markings,mark=at position 0.5 with arrow>]
draw [postaction=decorate,fill=gray!50](4,0)..controls +(-4,-2.5) and +(-4,2.5).. (4,0);
draw [postaction=decorate,fill=gray!50](5.41,-0.03)..controls +(4,-2.5) and +(4,2.5).. (5.41,-0.03);
endscope
draw (2.46,-2.36) node $b1$;
draw (2.67,2.47) node $a1$;
draw (-2.17,2.32) node $b1$;
draw (-2.44,-2.18) node $a1$;
draw (-2.13,0.07) node $T1$;
draw (7.39,2.26) node $b2$;
draw (12.1,-2.06) node $b2$;
draw (10.43,-0.69) node $T2$;
draw (11.98,2.38) node $a2$;
draw (7.17,-2.24) node $a2$;
endtikzpicture
enddocument
answered Nov 11 '18 at 9:36
AndréCAndréC
8,78411447
To draw this curve, I used the operation Curve-To (see p 149 of manual 3.0.1a).
draw [postaction=decorate](4,0)..controls +(-4,-2.5) and +(-4,2.5).. (4,0);
To place the arrow in the middle, I used the answer from @Caramdir TikZ: How to draw an arrow in the middle of the line?
It is possible to simplify your code. I didn't do it so you could understand the changes made. But it is always possible to do so if you wish.
documentclassarticle
usepackagetikz
usetikzlibraryarrows.meta
usetikzlibrarydecorations.markings
begindocument
begintikzpicture[line cap=round,line join=round,>=Triangle,scale=.7]
draw (0,4)-- (4,0);
draw (4,0)-- (0,-4);
draw (0,-4)-- (-4,0);
draw (-4,0)-- (0,4);
draw (5.41,-0.03)-- (9.41,3.97);
draw (9.41,3.97)-- (13.41,-0.03);
draw (13.41,-0.03)-- (9.41,-4.03);
draw (9.41,-4.03)-- (5.41,-0.03);
draw [->] (2,2) -- (1.47,2.53);
draw [->] (-1.59,2.41) -- (-2.26,1.74);
draw [->] (2.5,-1.5) -- (1.81,-2.19);
draw [->] (-1.55,-2.45) -- (-2.34,-1.66);
draw [->] (7.11,1.66) -- (7.67,2.22);
draw [->] (11.29,-2.16) -- (11.85,-1.59);
draw [->] (11.26,2.12) -- (11.89,1.5);
draw [->] (6.9,-1.51) -- (7.98,-2.59);
% arrow in the middle from https://tex.stackexchange.com/a/3172/138900
beginscope[decoration=markings,mark=at position 0.5 with arrow>]
draw [postaction=decorate,fill=gray!50](4,0)..controls +(-4,-2.5) and +(-4,2.5).. (4,0);
draw [postaction=decorate,fill=gray!50](5.41,-0.03)..controls +(4,-2.5) and +(4,2.5).. (5.41,-0.03);
endscope
draw (2.46,-2.36) node $b1$;
draw (2.67,2.47) node $a1$;
draw (-2.17,2.32) node $b1$;
draw (-2.44,-2.18) node $a1$;
draw (-2.13,0.07) node $T1$;
draw (7.39,2.26) node $b2$;
draw (12.1,-2.06) node $b2$;
draw (10.43,-0.69) node $T2$;
draw (11.98,2.38) node $a2$;
draw (7.17,-2.24) node $a2$;
endtikzpicture
enddocument
answered Nov 11 '18 at 9:36
AndréCAndréC
8,78411447
edited Nov 11 '18 at 10:16
answered Nov 11 '18 at 9:36
AndréCAndréC
8,78411447
answered Nov 11 '18 at 9:36
AndréCAndréC
8,78411447
answered Nov 11 '18 at 9:36
AndréCAndréC
8,78411447
8,78411447
add a comment |
add a comment |
2
An alternative with the same idea as @AndréC answer but without scope and with to instead of controls
documentclassbook
usepackagetikz
usetikzlibraryarrows,decorations.markings
begindocument
begintikzpicture[line cap=round,line join=round,>=triangle 45,x=0.7cm,y=0.7cm, decoration=markings, mark=at position 0.52 with arrow>]
draw (0,4)-- (4,0);
draw (4,0)-- (0,-4);
draw (0,-4)-- (-4,0);
draw (-4,0)-- (0,4);
draw (5.41,-0.03)-- (9.41,3.97);
draw (9.41,3.97)-- (13.41,-0.03);
draw (13.41,-0.03)-- (9.41,-4.03);
draw (9.41,-4.03)-- (5.41,-0.03);
draw [->] (2,2) -- (1.47,2.53);
draw [->] (-1.59,2.41) -- (-2.26,1.74);
draw [->] (2.5,-1.5) -- (1.81,-2.19);
draw [->] (-1.55,-2.45) -- (-2.34,-1.66);
draw [->] (7.11,1.66) -- (7.67,2.22);
draw [->] (11.29,-2.16) -- (11.85,-1.59);
draw [->] (11.26,2.12) -- (11.89,1.5);
draw [->] (6.9,-1.51) -- (7.98,-2.59);
%draw [shift=(2.18,3.21)] plot[domain=4.22:5.23,variable=t](1*3.69*cos(t r)+0*3.69*sin(t r),0*3.69*cos(t r)+1*3.69*sin(t r));
%draw [shift=(2.26,-2.4)] plot[domain=0.94:2.23,variable=t](1*2.97*cos(t r)+0*2.97*sin(t r),0*2.97*cos(t r)+1*2.97*sin(t r));
%draw [shift=(7.17,-1.78)] plot[domain=0.81:2.36,variable=t](1*2.48*cos(t r)+0*2.48*sin(t r),0*2.48*cos(t r)+1*2.48*sin(t r));
%draw [shift=(7.12,2.08)] plot[domain=4.03:5.42,variable=t](1*2.71*cos(t r)+0*2.71*sin(t r),0*2.71*cos(t r)+1*2.71*sin(t r));
draw[fill=gray,,postaction=decorate] (4,0) to[in=270, out=225] (1,0) to[in=135, out=90] (4,0);
draw[fill=gray,,postaction=decorate] (5.42,0) to[in=270, out=315] (8.42,0) to[in=45, out=90] (5.42,0);
draw (2.46,-2.36) node $b1$;
draw (2.67,2.47) node $a1$;
draw (-2.17,2.32) node $b1$;
draw (-2.44,-2.18) node $a1$;
draw (-2.13,0.07) node $T1$;
draw (7.39,2.26) node $b2$;
draw (12.1,-2.06) node $b2$;
draw (10.43,-0.69) node $T2$;
draw (11.98,2.38) node $a2$;
draw (7.17,-2.24) node $a2$;
endtikzpicture
enddocument
PS: Please upvote his answer instead of mine because he answered before me, but his answer became visible to me after I had already created the code... and so, I decided to add it as an alternative.
answered Nov 11 '18 at 9:52
koleygrkoleygr
11.2k11038
add a comment |
2
An alternative with the same idea as @AndréC answer but without scope and with to instead of controls
documentclassbook
usepackagetikz
usetikzlibraryarrows,decorations.markings
begindocument
begintikzpicture[line cap=round,line join=round,>=triangle 45,x=0.7cm,y=0.7cm, decoration=markings, mark=at position 0.52 with arrow>]
draw (0,4)-- (4,0);
draw (4,0)-- (0,-4);
draw (0,-4)-- (-4,0);
draw (-4,0)-- (0,4);
draw (5.41,-0.03)-- (9.41,3.97);
draw (9.41,3.97)-- (13.41,-0.03);
draw (13.41,-0.03)-- (9.41,-4.03);
draw (9.41,-4.03)-- (5.41,-0.03);
draw [->] (2,2) -- (1.47,2.53);
draw [->] (-1.59,2.41) -- (-2.26,1.74);
draw [->] (2.5,-1.5) -- (1.81,-2.19);
draw [->] (-1.55,-2.45) -- (-2.34,-1.66);
draw [->] (7.11,1.66) -- (7.67,2.22);
draw [->] (11.29,-2.16) -- (11.85,-1.59);
draw [->] (11.26,2.12) -- (11.89,1.5);
draw [->] (6.9,-1.51) -- (7.98,-2.59);
%draw [shift=(2.18,3.21)] plot[domain=4.22:5.23,variable=t](1*3.69*cos(t r)+0*3.69*sin(t r),0*3.69*cos(t r)+1*3.69*sin(t r));
%draw [shift=(2.26,-2.4)] plot[domain=0.94:2.23,variable=t](1*2.97*cos(t r)+0*2.97*sin(t r),0*2.97*cos(t r)+1*2.97*sin(t r));
%draw [shift=(7.17,-1.78)] plot[domain=0.81:2.36,variable=t](1*2.48*cos(t r)+0*2.48*sin(t r),0*2.48*cos(t r)+1*2.48*sin(t r));
%draw [shift=(7.12,2.08)] plot[domain=4.03:5.42,variable=t](1*2.71*cos(t r)+0*2.71*sin(t r),0*2.71*cos(t r)+1*2.71*sin(t r));
draw[fill=gray,,postaction=decorate] (4,0) to[in=270, out=225] (1,0) to[in=135, out=90] (4,0);
draw[fill=gray,,postaction=decorate] (5.42,0) to[in=270, out=315] (8.42,0) to[in=45, out=90] (5.42,0);
draw (2.46,-2.36) node $b1$;
draw (2.67,2.47) node $a1$;
draw (-2.17,2.32) node $b1$;
draw (-2.44,-2.18) node $a1$;
draw (-2.13,0.07) node $T1$;
draw (7.39,2.26) node $b2$;
draw (12.1,-2.06) node $b2$;
draw (10.43,-0.69) node $T2$;
draw (11.98,2.38) node $a2$;
draw (7.17,-2.24) node $a2$;
endtikzpicture
enddocument
PS: Please upvote his answer instead of mine because he answered before me, but his answer became visible to me after I had already created the code... and so, I decided to add it as an alternative.
answered Nov 11 '18 at 9:52
koleygrkoleygr
11.2k11038
add a comment |
2
2
2
An alternative with the same idea as @AndréC answer but without scope and with to instead of controls
documentclassbook
usepackagetikz
usetikzlibraryarrows,decorations.markings
begindocument
begintikzpicture[line cap=round,line join=round,>=triangle 45,x=0.7cm,y=0.7cm, decoration=markings, mark=at position 0.52 with arrow>]
draw (0,4)-- (4,0);
draw (4,0)-- (0,-4);
draw (0,-4)-- (-4,0);
draw (-4,0)-- (0,4);
draw (5.41,-0.03)-- (9.41,3.97);
draw (9.41,3.97)-- (13.41,-0.03);
draw (13.41,-0.03)-- (9.41,-4.03);
draw (9.41,-4.03)-- (5.41,-0.03);
draw [->] (2,2) -- (1.47,2.53);
draw [->] (-1.59,2.41) -- (-2.26,1.74);
draw [->] (2.5,-1.5) -- (1.81,-2.19);
draw [->] (-1.55,-2.45) -- (-2.34,-1.66);
draw [->] (7.11,1.66) -- (7.67,2.22);
draw [->] (11.29,-2.16) -- (11.85,-1.59);
draw [->] (11.26,2.12) -- (11.89,1.5);
draw [->] (6.9,-1.51) -- (7.98,-2.59);
%draw [shift=(2.18,3.21)] plot[domain=4.22:5.23,variable=t](1*3.69*cos(t r)+0*3.69*sin(t r),0*3.69*cos(t r)+1*3.69*sin(t r));
%draw [shift=(2.26,-2.4)] plot[domain=0.94:2.23,variable=t](1*2.97*cos(t r)+0*2.97*sin(t r),0*2.97*cos(t r)+1*2.97*sin(t r));
%draw [shift=(7.17,-1.78)] plot[domain=0.81:2.36,variable=t](1*2.48*cos(t r)+0*2.48*sin(t r),0*2.48*cos(t r)+1*2.48*sin(t r));
%draw [shift=(7.12,2.08)] plot[domain=4.03:5.42,variable=t](1*2.71*cos(t r)+0*2.71*sin(t r),0*2.71*cos(t r)+1*2.71*sin(t r));
draw[fill=gray,,postaction=decorate] (4,0) to[in=270, out=225] (1,0) to[in=135, out=90] (4,0);
draw[fill=gray,,postaction=decorate] (5.42,0) to[in=270, out=315] (8.42,0) to[in=45, out=90] (5.42,0);
draw (2.46,-2.36) node $b1$;
draw (2.67,2.47) node $a1$;
draw (-2.17,2.32) node $b1$;
draw (-2.44,-2.18) node $a1$;
draw (-2.13,0.07) node $T1$;
draw (7.39,2.26) node $b2$;
draw (12.1,-2.06) node $b2$;
draw (10.43,-0.69) node $T2$;
draw (11.98,2.38) node $a2$;
draw (7.17,-2.24) node $a2$;
endtikzpicture
enddocument
PS: Please upvote his answer instead of mine because he answered before me, but his answer became visible to me after I had already created the code... and so, I decided to add it as an alternative.
answered Nov 11 '18 at 9:52
koleygrkoleygr
11.2k11038
An alternative with the same idea as @AndréC answer but without scope and with to instead of controls
documentclassbook
usepackagetikz
usetikzlibraryarrows,decorations.markings
begindocument
begintikzpicture[line cap=round,line join=round,>=triangle 45,x=0.7cm,y=0.7cm, decoration=markings, mark=at position 0.52 with arrow>]
draw (0,4)-- (4,0);
draw (4,0)-- (0,-4);
draw (0,-4)-- (-4,0);
draw (-4,0)-- (0,4);
draw (5.41,-0.03)-- (9.41,3.97);
draw (9.41,3.97)-- (13.41,-0.03);
draw (13.41,-0.03)-- (9.41,-4.03);
draw (9.41,-4.03)-- (5.41,-0.03);
draw [->] (2,2) -- (1.47,2.53);
draw [->] (-1.59,2.41) -- (-2.26,1.74);
draw [->] (2.5,-1.5) -- (1.81,-2.19);
draw [->] (-1.55,-2.45) -- (-2.34,-1.66);
draw [->] (7.11,1.66) -- (7.67,2.22);
draw [->] (11.29,-2.16) -- (11.85,-1.59);
draw [->] (11.26,2.12) -- (11.89,1.5);
draw [->] (6.9,-1.51) -- (7.98,-2.59);
%draw [shift=(2.18,3.21)] plot[domain=4.22:5.23,variable=t](1*3.69*cos(t r)+0*3.69*sin(t r),0*3.69*cos(t r)+1*3.69*sin(t r));
%draw [shift=(2.26,-2.4)] plot[domain=0.94:2.23,variable=t](1*2.97*cos(t r)+0*2.97*sin(t r),0*2.97*cos(t r)+1*2.97*sin(t r));
%draw [shift=(7.17,-1.78)] plot[domain=0.81:2.36,variable=t](1*2.48*cos(t r)+0*2.48*sin(t r),0*2.48*cos(t r)+1*2.48*sin(t r));
%draw [shift=(7.12,2.08)] plot[domain=4.03:5.42,variable=t](1*2.71*cos(t r)+0*2.71*sin(t r),0*2.71*cos(t r)+1*2.71*sin(t r));
draw[fill=gray,,postaction=decorate] (4,0) to[in=270, out=225] (1,0) to[in=135, out=90] (4,0);
draw[fill=gray,,postaction=decorate] (5.42,0) to[in=270, out=315] (8.42,0) to[in=45, out=90] (5.42,0);
draw (2.46,-2.36) node $b1$;
draw (2.67,2.47) node $a1$;
draw (-2.17,2.32) node $b1$;
draw (-2.44,-2.18) node $a1$;
draw (-2.13,0.07) node $T1$;
draw (7.39,2.26) node $b2$;
draw (12.1,-2.06) node $b2$;
draw (10.43,-0.69) node $T2$;
draw (11.98,2.38) node $a2$;
draw (7.17,-2.24) node $a2$;
endtikzpicture
enddocument
PS: Please upvote his answer instead of mine because he answered before me, but his answer became visible to me after I had already created the code... and so, I decided to add it as an alternative.
answered Nov 11 '18 at 9:52
koleygrkoleygr
11.2k11038
answered Nov 11 '18 at 9:52
koleygrkoleygr
11.2k11038
answered Nov 11 '18 at 9:52
koleygrkoleygr
11.2k11038
answered Nov 11 '18 at 9:52
koleygrkoleygr
11.2k11038
11.2k11038
add a comment |
add a comment |
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