Getting all Buildings in range of 5 miles from specified coordinates

Getting all Buildings in range of 5 miles from specified coordinates



I have database table Building with these columns: name, lat, lng


Building


name


lat


lng



How can I get all Buildings in range of 5 miles from specified coordinates, for example these:


Buildings



-84.38653999999998



33.72024



My try but it does not work:


SELECT ST_CONTAINS(
SELECT ST_BUFFER(ST_Point(-84.38653999999998,33.72024), 5),
SELECT ST_POINT(lat,lng) FROM "my_db"."Building" LIMIT 50
);



https://docs.aws.amazon.com/athena/latest/ug/geospatial-functions-list.html






Do you want answer compatibile with postgis or athena ? Athena is rather very, very simple spatial tool without many usefull functions.

– Grzegorz Grabek
Aug 17 '18 at 12:05






are you using PostGIS or Athena or PrestoDB?

– Evan Carroll
Sep 8 '18 at 15:45






AWS Athena database

– paul
Sep 18 '18 at 10:13




2 Answers
2



Why are you storing x,y in separated columns? I would sincerely recommend you to store them as geometry or geography to avoid the casting overhead in query time.


geometry


geography



That being said, you can compute the distance in miles using something like this:



(Test data)


CREATE TEMPORARY TABLE building (name text, lat numeric, long numeric);
INSERT INTO building VALUES ('foo',7.52,51.96);
INSERT INTO building VALUES ('bar',7.62,51.94);
INSERT INTO building VALUES ('far away ... ',10.62,59.94);



The function ST_Distance (with geography type parameters) will return the distance in meters. All you have to do is to convert meters to miles in the end. Something like:


ST_Distance


geography


SELECT *, ST_Distance(ST_GeographyFromText('POINT(7.62 51.93)'),
ST_MakePoint(lat,long)) * 0.000621371 AS distance
FROM building
WHERE
ST_Distance(ST_GeographyFromText('POINT(7.62 51.93)'),
ST_MakePoint(lat,long)) * 0.000621371 > 5

name | lat | long | distance
---------------+-------+-------+------------------
far away ... | 10.62 | 59.94 | 566.123267141404
(1 Zeile)



EDIT- Amazon Athena equivalent (distance in degrees):


SELECT *, ST_DISTANCE(ST_GEOMETRY_FROM_TEXT('POINT(-84.386330 33.753746)'),
ST_POINT(lat,long)) AS distance
FROM building
WHERE
ST_Distance(ST_GEOMETRY_FROM_TEXT('POINT(-84.386330 33.753746)'),
ST_POINT(lat,long)) > 5;






thanks, I just changed a few things since Athena doesn't have for example ST_MakePoint' - dpaste.de/6o91 but when I run query I can't see any results

– paul
Aug 17 '18 at 7:08



ST_MakePoint'






The function ST_Distance in PostGIS, when used with geography parameters (not geometry), it returns the distance in meters, otherwise you might get the values in degrees (depending on the SRS). As I see, the function ST_GEOMETRY_FROM_TEXT returns geometry, as its name suggests... this might become an issue for this approach.

– Jim Jones
Aug 17 '18 at 7:24


ST_Distance


geography


geometry


ST_GEOMETRY_FROM_TEXT


geometry






meh, that's right, I'll figure out how to solve this

– paul
Aug 17 '18 at 7:27






In this case, if possible, try to work with degrees instead of miles. I honestly never worked with Athena and I'm not sure if the geography data type is supported :-(

– Jim Jones
Aug 17 '18 at 7:42



geography






@JimJones my bad, on first lookI thought that you convert degree to miles not meters to miles facepalm. Shame on me :)

– Grzegorz Grabek
Aug 17 '18 at 13:04



First thing first. If possible use Postgis not amazon-athena. Looking on documentation athena looks like the castrated version of a spatial tool.



First - Install postgis.


CREATE EXTENSION postgis SCHEMA public;



Now create geometry(if you want to use metric SRID like 3857 for example) or geography (if you want use degree SRID like 4326) column for your data.


alter table building add column geog geography;



Then transform your point data (lat,long) data to geometry/geography:


update building
set geog=(ST_SetSRID(ST_MakePoint(lat,long),4326)::geography)



Next create spatial index on it


create index on buildings using gist(geog);



Now you are ready for action


select *,
st_distance(geog, ST_makePoint(-84.386,33.72024))/1609.34 dist_miles
from building
where st_dwithin(geog, ST_makePoint(-84.38653999999998,33.72024),5*1609.34);



Few words of explenations:
Index is useful if you have many records in your table.
ST_Dwithin uses index when st_distance doesn't so ST_dwithin will make your query much faster on big data sets.



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