How to allocate memory for pointers to pointers?










0















I am struggling with dynamic memory allocation. I can't see any mistakes but still get segmentation fault. Any comments on how i can improve my code are welcome.



 char* balanceStatements(char* lst) 
{
<some code>
char** bad = malloc(sizeof(char*)); // the list of the bad parts of char* lst
char* badOrder = &lst[0]; // the pointer to the first character of the part in lst
<some code>
bad = includeOrder(badOrder, bad);


includeOrder:



char** includeOrder(char* order, char** list)

static int i = 0;
list = realloc(list, sizeof(list) + sizeof(char*)); //allocation of memory for a new pointer in the list
list[i++] = order;
printf("vad %cn", list[0][0]);
return list;



the input that causes segfault is ""ZNGA 1300 2.66, CLH15.NYM 50 56.32 B, OWW 1000 11.623 B, OGG 20 580.1 B", the first part of it (ZNGA 1300 2.66) is bad, the parts are splitted with ','. This input "GOOG 300 542.0 B,AAPL 50 145.0 B,CSCO 250.0 29 B,GOOG 200 580.0 S", with the part "CSCO 250.0 29 B" being bad, does not cause the segfault. So is the cause of segfault in the improper memory allocation? If so how it should be done properly?



full code:



#include <stdlib.h>
#include <string.h>

// result will be freed
char** includeOrder(char* order, char** list)

static int i = 0;
list = realloc(list, sizeof(list) + sizeof(char*)); //allocation of memory for a new pointer in the list
list[i++] = order;
printf("vad %cn", list[0][0]);
return list;




char* balanceStatements(char* lst)
char type = 0;
double buy = 0;
double sell = 0;
int i = 0;
char tempQ[100] = ;
char tempP[100] = ;
char** bad = malloc(sizeof(char*)); // the list of the bad parts of char* lst
int nword = 0;
int k = 0;
int j = 0;
int isComma = 0;
char* badOrder = &lst[0]; // the pointer to the first character of the part in lst
printf("badOrder1 %c", badOrder[0]);
char* res = malloc(1000*sizeof(char));
res[0]="A";
while (lst[i]!='')

printf("char %cn", lst[i]);
if (lst[i] == ',')

printf("bbbb");
if (nword != 3)

printf("bad order 2 %cn", badOrder);
bad = includeOrder(badOrder, bad);
printf("asdan");

printf("aaaa");
if (isComma)

if (type == 'B') buy += atoi(tempQ) * atof(tempP);
else sell += atoi(tempQ) * atof(tempP);

printf("sssss");
nword = 0;
badOrder=&lst[++i];
isComma = 0;
k = 0;
j = 0;

if (lst[i] == ' ')

nword++;
i++;

if (nword == 0) i++;
if (nword == 1)
lst[i]<'0')

printf("bad ordern");
bad = includeOrder(badOrder, bad);
printf("svad %cn", bad[0][0]);
while(lst[++i]!=',');

else

tempQ[k++] = lst[i++];



if (nword == 2)

if (nword == 3)

tempP[++j] = '';
printf("tempP %sn", tempP);
// sell
//fill in
if (lst[i] != 'B' && lst[i] !='S')

includeOrder(badOrder, bad);
while(lst[++i]!=',');

type = lst[i++];

/* if (nword == 4)

includeOrder(badOrder, bad);
while(lst[++i]!=',');
*/

if (type == 'S')

sell += atoi(tempQ) * atof(tempP);

else

buy += atoi(tempQ) * atof(tempP);

i=0;

// your code
printf("buy %fn", buy);
printf("sell %fn", sell);
printf("bad %cn", bad[0][0]);
int n = 0;
while (*(bad + n))

n++;

n--;
printf("size %in", n);
while (bad[0][i]!=',' && bad[0][i]!='')

printf("%c", bad[0][i++]);

sprintf(res, "Buy: %i Sell: %i", (int)buy, (int)sell);
if (bad)

res[strlen(res)]=';';
strcpy(&res[strlen(res)], " Badly formed ");
res[strlen(res)] = n+48;
res[strlen(res)] = ':';
res[strlen(res)] = ' ';
int i = 0;
while ( bad[0][i] != ',' )

res[strlen(res)] = bad[0][i++];

res[strlen(res)] = ' ';
res[strlen(res)] = ';';

return res;










share|improve this question


























    0















    I am struggling with dynamic memory allocation. I can't see any mistakes but still get segmentation fault. Any comments on how i can improve my code are welcome.



     char* balanceStatements(char* lst) 
    {
    <some code>
    char** bad = malloc(sizeof(char*)); // the list of the bad parts of char* lst
    char* badOrder = &lst[0]; // the pointer to the first character of the part in lst
    <some code>
    bad = includeOrder(badOrder, bad);


    includeOrder:



    char** includeOrder(char* order, char** list)

    static int i = 0;
    list = realloc(list, sizeof(list) + sizeof(char*)); //allocation of memory for a new pointer in the list
    list[i++] = order;
    printf("vad %cn", list[0][0]);
    return list;



    the input that causes segfault is ""ZNGA 1300 2.66, CLH15.NYM 50 56.32 B, OWW 1000 11.623 B, OGG 20 580.1 B", the first part of it (ZNGA 1300 2.66) is bad, the parts are splitted with ','. This input "GOOG 300 542.0 B,AAPL 50 145.0 B,CSCO 250.0 29 B,GOOG 200 580.0 S", with the part "CSCO 250.0 29 B" being bad, does not cause the segfault. So is the cause of segfault in the improper memory allocation? If so how it should be done properly?



    full code:



    #include <stdlib.h>
    #include <string.h>

    // result will be freed
    char** includeOrder(char* order, char** list)

    static int i = 0;
    list = realloc(list, sizeof(list) + sizeof(char*)); //allocation of memory for a new pointer in the list
    list[i++] = order;
    printf("vad %cn", list[0][0]);
    return list;




    char* balanceStatements(char* lst)
    char type = 0;
    double buy = 0;
    double sell = 0;
    int i = 0;
    char tempQ[100] = ;
    char tempP[100] = ;
    char** bad = malloc(sizeof(char*)); // the list of the bad parts of char* lst
    int nword = 0;
    int k = 0;
    int j = 0;
    int isComma = 0;
    char* badOrder = &lst[0]; // the pointer to the first character of the part in lst
    printf("badOrder1 %c", badOrder[0]);
    char* res = malloc(1000*sizeof(char));
    res[0]="A";
    while (lst[i]!='')

    printf("char %cn", lst[i]);
    if (lst[i] == ',')

    printf("bbbb");
    if (nword != 3)

    printf("bad order 2 %cn", badOrder);
    bad = includeOrder(badOrder, bad);
    printf("asdan");

    printf("aaaa");
    if (isComma)

    if (type == 'B') buy += atoi(tempQ) * atof(tempP);
    else sell += atoi(tempQ) * atof(tempP);

    printf("sssss");
    nword = 0;
    badOrder=&lst[++i];
    isComma = 0;
    k = 0;
    j = 0;

    if (lst[i] == ' ')

    nword++;
    i++;

    if (nword == 0) i++;
    if (nword == 1)
    lst[i]<'0')

    printf("bad ordern");
    bad = includeOrder(badOrder, bad);
    printf("svad %cn", bad[0][0]);
    while(lst[++i]!=',');

    else

    tempQ[k++] = lst[i++];



    if (nword == 2)

    if (nword == 3)

    tempP[++j] = '';
    printf("tempP %sn", tempP);
    // sell
    //fill in
    if (lst[i] != 'B' && lst[i] !='S')

    includeOrder(badOrder, bad);
    while(lst[++i]!=',');

    type = lst[i++];

    /* if (nword == 4)

    includeOrder(badOrder, bad);
    while(lst[++i]!=',');
    */

    if (type == 'S')

    sell += atoi(tempQ) * atof(tempP);

    else

    buy += atoi(tempQ) * atof(tempP);

    i=0;

    // your code
    printf("buy %fn", buy);
    printf("sell %fn", sell);
    printf("bad %cn", bad[0][0]);
    int n = 0;
    while (*(bad + n))

    n++;

    n--;
    printf("size %in", n);
    while (bad[0][i]!=',' && bad[0][i]!='')

    printf("%c", bad[0][i++]);

    sprintf(res, "Buy: %i Sell: %i", (int)buy, (int)sell);
    if (bad)

    res[strlen(res)]=';';
    strcpy(&res[strlen(res)], " Badly formed ");
    res[strlen(res)] = n+48;
    res[strlen(res)] = ':';
    res[strlen(res)] = ' ';
    int i = 0;
    while ( bad[0][i] != ',' )

    res[strlen(res)] = bad[0][i++];

    res[strlen(res)] = ' ';
    res[strlen(res)] = ';';

    return res;










    share|improve this question
























      0












      0








      0








      I am struggling with dynamic memory allocation. I can't see any mistakes but still get segmentation fault. Any comments on how i can improve my code are welcome.



       char* balanceStatements(char* lst) 
      {
      <some code>
      char** bad = malloc(sizeof(char*)); // the list of the bad parts of char* lst
      char* badOrder = &lst[0]; // the pointer to the first character of the part in lst
      <some code>
      bad = includeOrder(badOrder, bad);


      includeOrder:



      char** includeOrder(char* order, char** list)

      static int i = 0;
      list = realloc(list, sizeof(list) + sizeof(char*)); //allocation of memory for a new pointer in the list
      list[i++] = order;
      printf("vad %cn", list[0][0]);
      return list;



      the input that causes segfault is ""ZNGA 1300 2.66, CLH15.NYM 50 56.32 B, OWW 1000 11.623 B, OGG 20 580.1 B", the first part of it (ZNGA 1300 2.66) is bad, the parts are splitted with ','. This input "GOOG 300 542.0 B,AAPL 50 145.0 B,CSCO 250.0 29 B,GOOG 200 580.0 S", with the part "CSCO 250.0 29 B" being bad, does not cause the segfault. So is the cause of segfault in the improper memory allocation? If so how it should be done properly?



      full code:



      #include <stdlib.h>
      #include <string.h>

      // result will be freed
      char** includeOrder(char* order, char** list)

      static int i = 0;
      list = realloc(list, sizeof(list) + sizeof(char*)); //allocation of memory for a new pointer in the list
      list[i++] = order;
      printf("vad %cn", list[0][0]);
      return list;




      char* balanceStatements(char* lst)
      char type = 0;
      double buy = 0;
      double sell = 0;
      int i = 0;
      char tempQ[100] = ;
      char tempP[100] = ;
      char** bad = malloc(sizeof(char*)); // the list of the bad parts of char* lst
      int nword = 0;
      int k = 0;
      int j = 0;
      int isComma = 0;
      char* badOrder = &lst[0]; // the pointer to the first character of the part in lst
      printf("badOrder1 %c", badOrder[0]);
      char* res = malloc(1000*sizeof(char));
      res[0]="A";
      while (lst[i]!='')

      printf("char %cn", lst[i]);
      if (lst[i] == ',')

      printf("bbbb");
      if (nword != 3)

      printf("bad order 2 %cn", badOrder);
      bad = includeOrder(badOrder, bad);
      printf("asdan");

      printf("aaaa");
      if (isComma)

      if (type == 'B') buy += atoi(tempQ) * atof(tempP);
      else sell += atoi(tempQ) * atof(tempP);

      printf("sssss");
      nword = 0;
      badOrder=&lst[++i];
      isComma = 0;
      k = 0;
      j = 0;

      if (lst[i] == ' ')

      nword++;
      i++;

      if (nword == 0) i++;
      if (nword == 1)
      lst[i]<'0')

      printf("bad ordern");
      bad = includeOrder(badOrder, bad);
      printf("svad %cn", bad[0][0]);
      while(lst[++i]!=',');

      else

      tempQ[k++] = lst[i++];



      if (nword == 2)

      if (nword == 3)

      tempP[++j] = '';
      printf("tempP %sn", tempP);
      // sell
      //fill in
      if (lst[i] != 'B' && lst[i] !='S')

      includeOrder(badOrder, bad);
      while(lst[++i]!=',');

      type = lst[i++];

      /* if (nword == 4)

      includeOrder(badOrder, bad);
      while(lst[++i]!=',');
      */

      if (type == 'S')

      sell += atoi(tempQ) * atof(tempP);

      else

      buy += atoi(tempQ) * atof(tempP);

      i=0;

      // your code
      printf("buy %fn", buy);
      printf("sell %fn", sell);
      printf("bad %cn", bad[0][0]);
      int n = 0;
      while (*(bad + n))

      n++;

      n--;
      printf("size %in", n);
      while (bad[0][i]!=',' && bad[0][i]!='')

      printf("%c", bad[0][i++]);

      sprintf(res, "Buy: %i Sell: %i", (int)buy, (int)sell);
      if (bad)

      res[strlen(res)]=';';
      strcpy(&res[strlen(res)], " Badly formed ");
      res[strlen(res)] = n+48;
      res[strlen(res)] = ':';
      res[strlen(res)] = ' ';
      int i = 0;
      while ( bad[0][i] != ',' )

      res[strlen(res)] = bad[0][i++];

      res[strlen(res)] = ' ';
      res[strlen(res)] = ';';

      return res;










      share|improve this question














      I am struggling with dynamic memory allocation. I can't see any mistakes but still get segmentation fault. Any comments on how i can improve my code are welcome.



       char* balanceStatements(char* lst) 
      {
      <some code>
      char** bad = malloc(sizeof(char*)); // the list of the bad parts of char* lst
      char* badOrder = &lst[0]; // the pointer to the first character of the part in lst
      <some code>
      bad = includeOrder(badOrder, bad);


      includeOrder:



      char** includeOrder(char* order, char** list)

      static int i = 0;
      list = realloc(list, sizeof(list) + sizeof(char*)); //allocation of memory for a new pointer in the list
      list[i++] = order;
      printf("vad %cn", list[0][0]);
      return list;



      the input that causes segfault is ""ZNGA 1300 2.66, CLH15.NYM 50 56.32 B, OWW 1000 11.623 B, OGG 20 580.1 B", the first part of it (ZNGA 1300 2.66) is bad, the parts are splitted with ','. This input "GOOG 300 542.0 B,AAPL 50 145.0 B,CSCO 250.0 29 B,GOOG 200 580.0 S", with the part "CSCO 250.0 29 B" being bad, does not cause the segfault. So is the cause of segfault in the improper memory allocation? If so how it should be done properly?



      full code:



      #include <stdlib.h>
      #include <string.h>

      // result will be freed
      char** includeOrder(char* order, char** list)

      static int i = 0;
      list = realloc(list, sizeof(list) + sizeof(char*)); //allocation of memory for a new pointer in the list
      list[i++] = order;
      printf("vad %cn", list[0][0]);
      return list;




      char* balanceStatements(char* lst)
      char type = 0;
      double buy = 0;
      double sell = 0;
      int i = 0;
      char tempQ[100] = ;
      char tempP[100] = ;
      char** bad = malloc(sizeof(char*)); // the list of the bad parts of char* lst
      int nword = 0;
      int k = 0;
      int j = 0;
      int isComma = 0;
      char* badOrder = &lst[0]; // the pointer to the first character of the part in lst
      printf("badOrder1 %c", badOrder[0]);
      char* res = malloc(1000*sizeof(char));
      res[0]="A";
      while (lst[i]!='')

      printf("char %cn", lst[i]);
      if (lst[i] == ',')

      printf("bbbb");
      if (nword != 3)

      printf("bad order 2 %cn", badOrder);
      bad = includeOrder(badOrder, bad);
      printf("asdan");

      printf("aaaa");
      if (isComma)

      if (type == 'B') buy += atoi(tempQ) * atof(tempP);
      else sell += atoi(tempQ) * atof(tempP);

      printf("sssss");
      nword = 0;
      badOrder=&lst[++i];
      isComma = 0;
      k = 0;
      j = 0;

      if (lst[i] == ' ')

      nword++;
      i++;

      if (nword == 0) i++;
      if (nword == 1)
      lst[i]<'0')

      printf("bad ordern");
      bad = includeOrder(badOrder, bad);
      printf("svad %cn", bad[0][0]);
      while(lst[++i]!=',');

      else

      tempQ[k++] = lst[i++];



      if (nword == 2)

      if (nword == 3)

      tempP[++j] = '';
      printf("tempP %sn", tempP);
      // sell
      //fill in
      if (lst[i] != 'B' && lst[i] !='S')

      includeOrder(badOrder, bad);
      while(lst[++i]!=',');

      type = lst[i++];

      /* if (nword == 4)

      includeOrder(badOrder, bad);
      while(lst[++i]!=',');
      */

      if (type == 'S')

      sell += atoi(tempQ) * atof(tempP);

      else

      buy += atoi(tempQ) * atof(tempP);

      i=0;

      // your code
      printf("buy %fn", buy);
      printf("sell %fn", sell);
      printf("bad %cn", bad[0][0]);
      int n = 0;
      while (*(bad + n))

      n++;

      n--;
      printf("size %in", n);
      while (bad[0][i]!=',' && bad[0][i]!='')

      printf("%c", bad[0][i++]);

      sprintf(res, "Buy: %i Sell: %i", (int)buy, (int)sell);
      if (bad)

      res[strlen(res)]=';';
      strcpy(&res[strlen(res)], " Badly formed ");
      res[strlen(res)] = n+48;
      res[strlen(res)] = ':';
      res[strlen(res)] = ' ';
      int i = 0;
      while ( bad[0][i] != ',' )

      res[strlen(res)] = bad[0][i++];

      res[strlen(res)] = ' ';
      res[strlen(res)] = ';';

      return res;







      c memory-management






      share|improve this question













      share|improve this question











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      asked Nov 11 '18 at 11:22









      norvdnorvd

      32




      32






















          2 Answers
          2






          active

          oldest

          votes


















          0














          The most obvious error that will crash this program is in this line:



          list = realloc(list, sizeof(list) + sizeof(char*));


          sizeof() is a compile time operator (except for variable lenght arrays (VLA), but these are not here), that returns the size in bytes of the type of the argument. So sizeof(list) return the size of a char**, not the allocated size of the object. There is not a function that returns the allocated size of a dynamic memory block in C, you have to keep track of that yourself, in an additional variable.



          char** includeOrder(char* order, char** list, size_t *list_len)

          list = realloc(list, *list_len + sizeof(char*));
          ...
          return list;



          And then in the main function:



          size_t list_len = sizeof(char*); //0 is also valid
          char** bad = malloc(list_len);
          ...
          bad = includeOrder(badOrder, bad, &list_len);


          Now that you are into pass-by-pointer functions you could do the same for the list variable:



          void includeOrder(char* order, char*** list, size_t *list_len)

          *list = realloc(*list, *list_len + sizeof(char*));
          ...






          share|improve this answer

























          • ok, got it, the static int i looks like a good option for it, what if i use it like list = realloc(list, (i + 1) * sizeof(char*));?

            – norvd
            Nov 11 '18 at 11:35











          • @norvd: Usually the size of the list should be in the same place as the list itself. If bad is a local variable, then bad_len should be a local variable, too. Also think if you want it as number of bytes or number of elements. My code assumed number of bytes but your comment is number of elements; either one is good.

            – rodrigo
            Nov 11 '18 at 11:38











          • @norvd: A sensible approach would be to create a type struct string_list char **ptr; size_t len; and a function string_list_add() that does the hard work.

            – rodrigo
            Nov 11 '18 at 11:39


















          0














          Your problem is a misunderstanding of sizeof(list). sizeof returns the memory size of list, i.e. the size of a char**. It doesn't take into consideration the number of elements in your list.



          Keep in mind that sizeof isn't a function that is executed during runtime. It is a compile time unary operator.






          share|improve this answer






















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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            0














            The most obvious error that will crash this program is in this line:



            list = realloc(list, sizeof(list) + sizeof(char*));


            sizeof() is a compile time operator (except for variable lenght arrays (VLA), but these are not here), that returns the size in bytes of the type of the argument. So sizeof(list) return the size of a char**, not the allocated size of the object. There is not a function that returns the allocated size of a dynamic memory block in C, you have to keep track of that yourself, in an additional variable.



            char** includeOrder(char* order, char** list, size_t *list_len)

            list = realloc(list, *list_len + sizeof(char*));
            ...
            return list;



            And then in the main function:



            size_t list_len = sizeof(char*); //0 is also valid
            char** bad = malloc(list_len);
            ...
            bad = includeOrder(badOrder, bad, &list_len);


            Now that you are into pass-by-pointer functions you could do the same for the list variable:



            void includeOrder(char* order, char*** list, size_t *list_len)

            *list = realloc(*list, *list_len + sizeof(char*));
            ...






            share|improve this answer

























            • ok, got it, the static int i looks like a good option for it, what if i use it like list = realloc(list, (i + 1) * sizeof(char*));?

              – norvd
              Nov 11 '18 at 11:35











            • @norvd: Usually the size of the list should be in the same place as the list itself. If bad is a local variable, then bad_len should be a local variable, too. Also think if you want it as number of bytes or number of elements. My code assumed number of bytes but your comment is number of elements; either one is good.

              – rodrigo
              Nov 11 '18 at 11:38











            • @norvd: A sensible approach would be to create a type struct string_list char **ptr; size_t len; and a function string_list_add() that does the hard work.

              – rodrigo
              Nov 11 '18 at 11:39















            0














            The most obvious error that will crash this program is in this line:



            list = realloc(list, sizeof(list) + sizeof(char*));


            sizeof() is a compile time operator (except for variable lenght arrays (VLA), but these are not here), that returns the size in bytes of the type of the argument. So sizeof(list) return the size of a char**, not the allocated size of the object. There is not a function that returns the allocated size of a dynamic memory block in C, you have to keep track of that yourself, in an additional variable.



            char** includeOrder(char* order, char** list, size_t *list_len)

            list = realloc(list, *list_len + sizeof(char*));
            ...
            return list;



            And then in the main function:



            size_t list_len = sizeof(char*); //0 is also valid
            char** bad = malloc(list_len);
            ...
            bad = includeOrder(badOrder, bad, &list_len);


            Now that you are into pass-by-pointer functions you could do the same for the list variable:



            void includeOrder(char* order, char*** list, size_t *list_len)

            *list = realloc(*list, *list_len + sizeof(char*));
            ...






            share|improve this answer

























            • ok, got it, the static int i looks like a good option for it, what if i use it like list = realloc(list, (i + 1) * sizeof(char*));?

              – norvd
              Nov 11 '18 at 11:35











            • @norvd: Usually the size of the list should be in the same place as the list itself. If bad is a local variable, then bad_len should be a local variable, too. Also think if you want it as number of bytes or number of elements. My code assumed number of bytes but your comment is number of elements; either one is good.

              – rodrigo
              Nov 11 '18 at 11:38











            • @norvd: A sensible approach would be to create a type struct string_list char **ptr; size_t len; and a function string_list_add() that does the hard work.

              – rodrigo
              Nov 11 '18 at 11:39













            0












            0








            0







            The most obvious error that will crash this program is in this line:



            list = realloc(list, sizeof(list) + sizeof(char*));


            sizeof() is a compile time operator (except for variable lenght arrays (VLA), but these are not here), that returns the size in bytes of the type of the argument. So sizeof(list) return the size of a char**, not the allocated size of the object. There is not a function that returns the allocated size of a dynamic memory block in C, you have to keep track of that yourself, in an additional variable.



            char** includeOrder(char* order, char** list, size_t *list_len)

            list = realloc(list, *list_len + sizeof(char*));
            ...
            return list;



            And then in the main function:



            size_t list_len = sizeof(char*); //0 is also valid
            char** bad = malloc(list_len);
            ...
            bad = includeOrder(badOrder, bad, &list_len);


            Now that you are into pass-by-pointer functions you could do the same for the list variable:



            void includeOrder(char* order, char*** list, size_t *list_len)

            *list = realloc(*list, *list_len + sizeof(char*));
            ...






            share|improve this answer















            The most obvious error that will crash this program is in this line:



            list = realloc(list, sizeof(list) + sizeof(char*));


            sizeof() is a compile time operator (except for variable lenght arrays (VLA), but these are not here), that returns the size in bytes of the type of the argument. So sizeof(list) return the size of a char**, not the allocated size of the object. There is not a function that returns the allocated size of a dynamic memory block in C, you have to keep track of that yourself, in an additional variable.



            char** includeOrder(char* order, char** list, size_t *list_len)

            list = realloc(list, *list_len + sizeof(char*));
            ...
            return list;



            And then in the main function:



            size_t list_len = sizeof(char*); //0 is also valid
            char** bad = malloc(list_len);
            ...
            bad = includeOrder(badOrder, bad, &list_len);


            Now that you are into pass-by-pointer functions you could do the same for the list variable:



            void includeOrder(char* order, char*** list, size_t *list_len)

            *list = realloc(*list, *list_len + sizeof(char*));
            ...







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 11 '18 at 11:36

























            answered Nov 11 '18 at 11:32









            rodrigorodrigo

            63.6k493129




            63.6k493129












            • ok, got it, the static int i looks like a good option for it, what if i use it like list = realloc(list, (i + 1) * sizeof(char*));?

              – norvd
              Nov 11 '18 at 11:35











            • @norvd: Usually the size of the list should be in the same place as the list itself. If bad is a local variable, then bad_len should be a local variable, too. Also think if you want it as number of bytes or number of elements. My code assumed number of bytes but your comment is number of elements; either one is good.

              – rodrigo
              Nov 11 '18 at 11:38











            • @norvd: A sensible approach would be to create a type struct string_list char **ptr; size_t len; and a function string_list_add() that does the hard work.

              – rodrigo
              Nov 11 '18 at 11:39

















            • ok, got it, the static int i looks like a good option for it, what if i use it like list = realloc(list, (i + 1) * sizeof(char*));?

              – norvd
              Nov 11 '18 at 11:35











            • @norvd: Usually the size of the list should be in the same place as the list itself. If bad is a local variable, then bad_len should be a local variable, too. Also think if you want it as number of bytes or number of elements. My code assumed number of bytes but your comment is number of elements; either one is good.

              – rodrigo
              Nov 11 '18 at 11:38











            • @norvd: A sensible approach would be to create a type struct string_list char **ptr; size_t len; and a function string_list_add() that does the hard work.

              – rodrigo
              Nov 11 '18 at 11:39
















            ok, got it, the static int i looks like a good option for it, what if i use it like list = realloc(list, (i + 1) * sizeof(char*));?

            – norvd
            Nov 11 '18 at 11:35





            ok, got it, the static int i looks like a good option for it, what if i use it like list = realloc(list, (i + 1) * sizeof(char*));?

            – norvd
            Nov 11 '18 at 11:35













            @norvd: Usually the size of the list should be in the same place as the list itself. If bad is a local variable, then bad_len should be a local variable, too. Also think if you want it as number of bytes or number of elements. My code assumed number of bytes but your comment is number of elements; either one is good.

            – rodrigo
            Nov 11 '18 at 11:38





            @norvd: Usually the size of the list should be in the same place as the list itself. If bad is a local variable, then bad_len should be a local variable, too. Also think if you want it as number of bytes or number of elements. My code assumed number of bytes but your comment is number of elements; either one is good.

            – rodrigo
            Nov 11 '18 at 11:38













            @norvd: A sensible approach would be to create a type struct string_list char **ptr; size_t len; and a function string_list_add() that does the hard work.

            – rodrigo
            Nov 11 '18 at 11:39





            @norvd: A sensible approach would be to create a type struct string_list char **ptr; size_t len; and a function string_list_add() that does the hard work.

            – rodrigo
            Nov 11 '18 at 11:39













            0














            Your problem is a misunderstanding of sizeof(list). sizeof returns the memory size of list, i.e. the size of a char**. It doesn't take into consideration the number of elements in your list.



            Keep in mind that sizeof isn't a function that is executed during runtime. It is a compile time unary operator.






            share|improve this answer



























              0














              Your problem is a misunderstanding of sizeof(list). sizeof returns the memory size of list, i.e. the size of a char**. It doesn't take into consideration the number of elements in your list.



              Keep in mind that sizeof isn't a function that is executed during runtime. It is a compile time unary operator.






              share|improve this answer

























                0












                0








                0







                Your problem is a misunderstanding of sizeof(list). sizeof returns the memory size of list, i.e. the size of a char**. It doesn't take into consideration the number of elements in your list.



                Keep in mind that sizeof isn't a function that is executed during runtime. It is a compile time unary operator.






                share|improve this answer













                Your problem is a misunderstanding of sizeof(list). sizeof returns the memory size of list, i.e. the size of a char**. It doesn't take into consideration the number of elements in your list.



                Keep in mind that sizeof isn't a function that is executed during runtime. It is a compile time unary operator.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 11 '18 at 11:28









                Maxime ChéramyMaxime Chéramy

                9,71043160




                9,71043160



























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