Optional parent properties interface
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I need to create an object from an interface which extends from another interface, but I need to set all the parents' properties and they are a lot of. Is it possible to make them optional?
Example:
interface Auto
radio: any;
interface Mazda extends Auto
// mazda properties
const m = <Mazda>
// just mazda properties
Actually I need that the parent properties mappend on the son to be optional, with Partial would be needed to create a property containing a parent object, but I want to extend and to have all the extended properties as optional.
typescript interface
asked Nov 8 at 20:18
Julian Torregrosa
13612
add a comment |
up vote
1
down vote
favorite
I need to create an object from an interface which extends from another interface, but I need to set all the parents' properties and they are a lot of. Is it possible to make them optional?
Example:
interface Auto
radio: any;
interface Mazda extends Auto
// mazda properties
const m = <Mazda>
// just mazda properties
Actually I need that the parent properties mappend on the son to be optional, with Partial would be needed to create a property containing a parent object, but I want to extend and to have all the extended properties as optional.
typescript interface
asked Nov 8 at 20:18
Julian Torregrosa
13612
Partial<Auto> & Pick<Mazda, Exclude<keyof Mazda, keyof Auto>>?
– jcalz
Nov 8 at 20:22
Possible duplicate of Make all properties within a Typescript interface optional
– Heretic Monkey
Nov 8 at 20:22
I think if you want a more meaningful answer, you'll need to flesh this question out into a full Minimal, Complete, and Verifiable example, including how you intend to use the type.
– jcalz
Nov 9 at 0:33
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I need to create an object from an interface which extends from another interface, but I need to set all the parents' properties and they are a lot of. Is it possible to make them optional?
Example:
interface Auto
radio: any;
interface Mazda extends Auto
// mazda properties
const m = <Mazda>
// just mazda properties
Actually I need that the parent properties mappend on the son to be optional, with Partial would be needed to create a property containing a parent object, but I want to extend and to have all the extended properties as optional.
typescript interface
asked Nov 8 at 20:18
Julian Torregrosa
13612
I need to create an object from an interface which extends from another interface, but I need to set all the parents' properties and they are a lot of. Is it possible to make them optional?
Example:
interface Auto
radio: any;
interface Mazda extends Auto
// mazda properties
const m = <Mazda>
// just mazda properties
Actually I need that the parent properties mappend on the son to be optional, with Partial would be needed to create a property containing a parent object, but I want to extend and to have all the extended properties as optional.
typescript interface
typescript interface
asked Nov 8 at 20:18
Julian Torregrosa
13612
asked Nov 8 at 20:18
Julian Torregrosa
13612
edited Nov 19 at 20:42
asked Nov 8 at 20:18
Julian Torregrosa
13612
asked Nov 8 at 20:18
Julian Torregrosa
13612
asked Nov 8 at 20:18
Julian Torregrosa
13612
13612
Partial<Auto> & Pick<Mazda, Exclude<keyof Mazda, keyof Auto>>?
– jcalz
Nov 8 at 20:22
Possible duplicate of Make all properties within a Typescript interface optional
– Heretic Monkey
Nov 8 at 20:22
I think if you want a more meaningful answer, you'll need to flesh this question out into a full Minimal, Complete, and Verifiable example, including how you intend to use the type.
– jcalz
Nov 9 at 0:33
add a comment |
Partial<Auto> & Pick<Mazda, Exclude<keyof Mazda, keyof Auto>>?
– jcalz
Nov 8 at 20:22
Possible duplicate of Make all properties within a Typescript interface optional
– Heretic Monkey
Nov 8 at 20:22
I think if you want a more meaningful answer, you'll need to flesh this question out into a full Minimal, Complete, and Verifiable example, including how you intend to use the type.
– jcalz
Nov 9 at 0:33
Partial<Auto> & Pick<Mazda, Exclude<keyof Mazda, keyof Auto>> ?– jcalz
Nov 8 at 20:22
Partial<Auto> & Pick<Mazda, Exclude<keyof Mazda, keyof Auto>> ?– jcalz
Nov 8 at 20:22
Possible duplicate of Make all properties within a Typescript interface optional
– Heretic Monkey
Nov 8 at 20:22
Possible duplicate of Make all properties within a Typescript interface optional
– Heretic Monkey
Nov 8 at 20:22
I think if you want a more meaningful answer, you'll need to flesh this question out into a full Minimal, Complete, and Verifiable example, including how you intend to use the type.
– jcalz
Nov 9 at 0:33
I think if you want a more meaningful answer, you'll need to flesh this question out into a full Minimal, Complete, and Verifiable example, including how you intend to use the type.
– jcalz
Nov 9 at 0:33
add a comment |
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Partial<Auto> & Pick<Mazda, Exclude<keyof Mazda, keyof Auto>>?– jcalz
Nov 8 at 20:22
Possible duplicate of Make all properties within a Typescript interface optional
– Heretic Monkey
Nov 8 at 20:22
I think if you want a more meaningful answer, you'll need to flesh this question out into a full Minimal, Complete, and Verifiable example, including how you intend to use the type.
– jcalz
Nov 9 at 0:33