Iteratively strip off simply connected edges in graph?









up vote
6
down vote

favorite
2












Consider a set of edges composing a directed graph. For example:



edges = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[3, 5], DirectedEdge[5, 6], DirectedEdge[6, 7];
Graph[edges]



enter image description here




I would like to have a function stripOff that iteratively strips off the outer edges that are simply connected to the rest, and returns them together with the remaining graph:



incoming1, outgoing1, remains1= stripOff[edges]
Graph[remains1]



DirectedEdge[1, 2],DirectedEdge[4, 3] ,



DirectedEdge[6, 7] ,



DirectedEdge[2, 3], DirectedEdge[3, 5], DirectedEdge[5, 6]
enter image description here




In the next iteration step it should give



incoming2, outgoing2, remains2= stripOff[remains1]
Graph[remains2]



DirectedEdge[2, 3] ,



DirectedEdge[5, 6] ,



DirectedEdge[3, 5]
enter image description here




And finally in the last iteration step



incoming3, outgoing3, remains3= stripOff[remains2]



DirectedEdge[3, 5] ,



,






Is there a quick way to construct such a stripOff function in mathematica? Thanks for any suggestion!



EDIT:



Note that I am trying to iteratively strip off external legs of the graph, which are connected to a vertex only on one side, not on both.



Even though the graph



edges = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[5, 4];
Graph[edges]



enter image description here




contains a sink in the middle, the function should not cut the graph in two, but only strip off outer legs:



incoming, outgoing, remains= stripOff[edges]



DirectedEdge[1, 2], DirectedEdge[5, 4] ,



,



DirectedEdge[2, 3], DirectedEdge[4, 3]











share|improve this question























  • shouldn't the last step give DirectedEdge[3, 5] ,DirectedEdge[3, 5] , ?
    – kglr
    2 days ago










  • @kglr I'd like all edges to be unique, without double counting. If an edge triggers for incoming classification, it is spent and is not available to be classified as outgoing any more.
    – Kagaratsch
    2 days ago














up vote
6
down vote

favorite
2












Consider a set of edges composing a directed graph. For example:



edges = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[3, 5], DirectedEdge[5, 6], DirectedEdge[6, 7];
Graph[edges]



enter image description here




I would like to have a function stripOff that iteratively strips off the outer edges that are simply connected to the rest, and returns them together with the remaining graph:



incoming1, outgoing1, remains1= stripOff[edges]
Graph[remains1]



DirectedEdge[1, 2],DirectedEdge[4, 3] ,



DirectedEdge[6, 7] ,



DirectedEdge[2, 3], DirectedEdge[3, 5], DirectedEdge[5, 6]
enter image description here




In the next iteration step it should give



incoming2, outgoing2, remains2= stripOff[remains1]
Graph[remains2]



DirectedEdge[2, 3] ,



DirectedEdge[5, 6] ,



DirectedEdge[3, 5]
enter image description here




And finally in the last iteration step



incoming3, outgoing3, remains3= stripOff[remains2]



DirectedEdge[3, 5] ,



,






Is there a quick way to construct such a stripOff function in mathematica? Thanks for any suggestion!



EDIT:



Note that I am trying to iteratively strip off external legs of the graph, which are connected to a vertex only on one side, not on both.



Even though the graph



edges = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[5, 4];
Graph[edges]



enter image description here




contains a sink in the middle, the function should not cut the graph in two, but only strip off outer legs:



incoming, outgoing, remains= stripOff[edges]



DirectedEdge[1, 2], DirectedEdge[5, 4] ,



,



DirectedEdge[2, 3], DirectedEdge[4, 3]











share|improve this question























  • shouldn't the last step give DirectedEdge[3, 5] ,DirectedEdge[3, 5] , ?
    – kglr
    2 days ago










  • @kglr I'd like all edges to be unique, without double counting. If an edge triggers for incoming classification, it is spent and is not available to be classified as outgoing any more.
    – Kagaratsch
    2 days ago












up vote
6
down vote

favorite
2









up vote
6
down vote

favorite
2






2





Consider a set of edges composing a directed graph. For example:



edges = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[3, 5], DirectedEdge[5, 6], DirectedEdge[6, 7];
Graph[edges]



enter image description here




I would like to have a function stripOff that iteratively strips off the outer edges that are simply connected to the rest, and returns them together with the remaining graph:



incoming1, outgoing1, remains1= stripOff[edges]
Graph[remains1]



DirectedEdge[1, 2],DirectedEdge[4, 3] ,



DirectedEdge[6, 7] ,



DirectedEdge[2, 3], DirectedEdge[3, 5], DirectedEdge[5, 6]
enter image description here




In the next iteration step it should give



incoming2, outgoing2, remains2= stripOff[remains1]
Graph[remains2]



DirectedEdge[2, 3] ,



DirectedEdge[5, 6] ,



DirectedEdge[3, 5]
enter image description here




And finally in the last iteration step



incoming3, outgoing3, remains3= stripOff[remains2]



DirectedEdge[3, 5] ,



,






Is there a quick way to construct such a stripOff function in mathematica? Thanks for any suggestion!



EDIT:



Note that I am trying to iteratively strip off external legs of the graph, which are connected to a vertex only on one side, not on both.



Even though the graph



edges = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[5, 4];
Graph[edges]



enter image description here




contains a sink in the middle, the function should not cut the graph in two, but only strip off outer legs:



incoming, outgoing, remains= stripOff[edges]



DirectedEdge[1, 2], DirectedEdge[5, 4] ,



,



DirectedEdge[2, 3], DirectedEdge[4, 3]











share|improve this question















Consider a set of edges composing a directed graph. For example:



edges = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[3, 5], DirectedEdge[5, 6], DirectedEdge[6, 7];
Graph[edges]



enter image description here




I would like to have a function stripOff that iteratively strips off the outer edges that are simply connected to the rest, and returns them together with the remaining graph:



incoming1, outgoing1, remains1= stripOff[edges]
Graph[remains1]



DirectedEdge[1, 2],DirectedEdge[4, 3] ,



DirectedEdge[6, 7] ,



DirectedEdge[2, 3], DirectedEdge[3, 5], DirectedEdge[5, 6]
enter image description here




In the next iteration step it should give



incoming2, outgoing2, remains2= stripOff[remains1]
Graph[remains2]



DirectedEdge[2, 3] ,



DirectedEdge[5, 6] ,



DirectedEdge[3, 5]
enter image description here




And finally in the last iteration step



incoming3, outgoing3, remains3= stripOff[remains2]



DirectedEdge[3, 5] ,



,






Is there a quick way to construct such a stripOff function in mathematica? Thanks for any suggestion!



EDIT:



Note that I am trying to iteratively strip off external legs of the graph, which are connected to a vertex only on one side, not on both.



Even though the graph



edges = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[5, 4];
Graph[edges]



enter image description here




contains a sink in the middle, the function should not cut the graph in two, but only strip off outer legs:



incoming, outgoing, remains= stripOff[edges]



DirectedEdge[1, 2], DirectedEdge[5, 4] ,



,



DirectedEdge[2, 3], DirectedEdge[4, 3]








list-manipulation function-construction graphs-and-networks






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 2 days ago

























asked 2 days ago









Kagaratsch

4,53631246




4,53631246











  • shouldn't the last step give DirectedEdge[3, 5] ,DirectedEdge[3, 5] , ?
    – kglr
    2 days ago










  • @kglr I'd like all edges to be unique, without double counting. If an edge triggers for incoming classification, it is spent and is not available to be classified as outgoing any more.
    – Kagaratsch
    2 days ago
















  • shouldn't the last step give DirectedEdge[3, 5] ,DirectedEdge[3, 5] , ?
    – kglr
    2 days ago










  • @kglr I'd like all edges to be unique, without double counting. If an edge triggers for incoming classification, it is spent and is not available to be classified as outgoing any more.
    – Kagaratsch
    2 days ago















shouldn't the last step give DirectedEdge[3, 5] ,DirectedEdge[3, 5] , ?
– kglr
2 days ago




shouldn't the last step give DirectedEdge[3, 5] ,DirectedEdge[3, 5] , ?
– kglr
2 days ago












@kglr I'd like all edges to be unique, without double counting. If an edge triggers for incoming classification, it is spent and is not available to be classified as outgoing any more.
– Kagaratsch
2 days ago




@kglr I'd like all edges to be unique, without double counting. If an edge triggers for incoming classification, it is spent and is not available to be classified as outgoing any more.
– Kagaratsch
2 days ago










4 Answers
4






active

oldest

votes

















up vote
5
down vote



accepted










sourceEdges = IncidenceList[#, GeneralUtilities`GraphSources @ # ]&;
simpleSinks = Select[GeneralUtilities`GraphSinks[#],
Function[v, VertexInDegree[#, v] <= 1]] &;
sinkEdges = Complement[IncidenceList[#, simpleSinks @ #], sourceEdges @ #] &;
rest = Complement[#, sourceEdges @ #, sinkEdges @ #] &;
f = Rest @ NestWhileList[sourceEdges @ #[[3]], sinkEdges @ #[[3]], rest @ #[[3]]&,
, , #, #[[3]] =!= &]&;


Examples:



edges1 = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[3, 5],
DirectedEdge[5, 6], DirectedEdge[6, 7];
f @ edges1



1 -> 2, 4 -> 3, 6 -> 7, 2 -> 3, 3 -> 5, 5 -> 6,

2 -> 3, 5 -> 6, 3 -> 5,

3 -> 5, ,




g1 = Graph[edges1, VertexSize -> Large, 
VertexLabels -> Placed["Name", Center], ImageSize -> 200, 300];
Row[HighlightGraph[g1, #, PlotLabel -> Column[#]] & /@ f[edges1]]


enter image description here



edges2 = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], 
DirectedEdge[5, 4] ;
f @ edges2



1 -> 2, 5 -> 4, , 2 -> 3, 4 -> 3,

2 -> 3, 4 -> 3, ,




g2 = Graph[edges2, VertexSize -> Large, 
VertexLabels -> Placed["Name", Center], ImageSize -> 200, 300];
Row[HighlightGraph[g2, #, PlotLabel -> Column[#]] & /@ f[edges2]]


enter image description here



You can also use GraphComputation`SourceVertexList and GraphComputation`SinkVertexList for GeneralUtilities`GraphSources and GeneralUtilities`GraphSinks, respectively.






share|improve this answer






















  • I wonder if GeneralUtilities'GraphSinks would trigger on 2->3 and 4->3 in a situation like 1->2 , 2->3 , 4->3 , 5->4 , where 2->3 and 4->3 do point to a sink but are not simply connected to the rest of the graph? Asking, since I'd actually like to avoid this in my case.
    – Kagaratsch
    2 days ago











  • @Kagaratsch, not sure I understand el = 1->2 , 2->3 , 4->3 , 5->4 , but GeneralUtilities`GraphSinks @Flatten[el] gives 3.
    – kglr
    2 days ago











  • I see, that is what I was afraid of. In my application case I am only looking for sources and sinks which are simply connected to the rest of the graph.
    – Kagaratsch
    2 days ago











  • @Kagaratsch, sounds like the example in your question does not reflect your requirements accurately. Adding the example in your comment to your post with some explanation would be useful.
    – kglr
    2 days ago










  • Added an edit to the question.
    – Kagaratsch
    2 days ago

















up vote
4
down vote













g = Graph[edges, VertexLabels -> Automatic]


enter image description here



source[g_?GraphQ] := Pick[VertexList[g], VertexInDegree[g], 0]
sink[g_?GraphQ] := Pick[VertexList[g], VertexOutDegree[g], 0]

strip[g_] :=
With[so = source[g], si = sink[g],
Flatten[IncidenceList[g, #] & /@ so],
Flatten[IncidenceList[g, #] & /@ si],
VertexDelete[g, Join[so, si]]
]


enter image description here



There are minor issues, such as returning an edge twice at the last step, but that should be easy (if tedious) to fix.






share|improve this answer



























    up vote
    3
    down vote













    If you have a large graph, it will be faster to work with the vertex-edge incidence matrix instead of Graph objects. The edges you want to strip off will have either a 1 or a -1 depending on the direction of the directed edge. So, the simple edges you want to strip off will have a vertex with only a single 1 or -1 in the row. Let's take your example:



    m = IncidenceMatrix[edges];
    m //MatrixForm //TeXForm



    $left(
    beginarraycccccc
    -1 & 0 & 0 & 0 & 0 & 0 \
    1 & -1 & 0 & 0 & 0 & 0 \
    0 & 1 & 1 & -1 & 0 & 0 \
    0 & 0 & -1 & 0 & 0 & 0 \
    0 & 0 & 0 & 1 & -1 & 0 \
    0 & 0 & 0 & 0 & 1 & -1 \
    0 & 0 & 0 & 0 & 0 & 1 \
    endarray
    right)$




    The vertices that can be removed can be obtained with:



    v = Clip[Unitize[m] . ConstantArray[1, Length @ First @ m], 1, 1, 0, 0]



    1, 0, 0, 1, 0, 0, 1




    The corresponding edges can be found with:



    e = Unitize[v . Unitize[m]]



    1, 0, 1, 0, 0, 1




    The kind of edge can be determined using:



    v . Mod[m, 3] . DiagonalMatrix[e]



    2, 0, 2, 0, 0, 1




    where 1 is an outgoing edge, 2 is an incoming edge, and 3 would be both an incoming and outgoing edge.



    The matrix after removing the above vertices and edges can be found from:



    m . DiagonalMatrix[1 - e] //MatrixForm //TeXForm



    $left(
    beginarraycccccc
    0 & 0 & 0 & 0 & 0 & 0 \
    0 & -1 & 0 & 0 & 0 & 0 \
    0 & 1 & 0 & -1 & 0 & 0 \
    0 & 0 & 0 & 0 & 0 & 0 \
    0 & 0 & 0 & 1 & -1 & 0 \
    0 & 0 & 0 & 0 & 1 & 0 \
    0 & 0 & 0 & 0 & 0 & 0 \
    endarray
    right)$




    Here is a function that does one iteration:



    iter[m_] := Module[u = Unitize[m], o, v, e,
    o = ConstantArray[1, Length @ First @ u];
    v = Clip[u . o, 1, 1, 0, 0];
    e = Unitize[v . Unitize[m]];

    v,
    v . Mod[m, 3] . SparseArray[Band[1,1] -> e],
    m . SparseArray[Band[1,1] -> 1 - e]

    ]


    For example:



    r = iter[m];
    r[[1]] (* removed vertices *)
    r[[2]] (* removed edges *)
    r[[3]] //MatrixForm //TeXForm



    1, 0, 0, 1, 0, 0, 1



    2, 0, 2, 0, 0, 1



    $left(
    beginarraycccccc
    0 & 0 & 0 & 0 & 0 & 0 \
    0 & -1 & 0 & 0 & 0 & 0 \
    0 & 1 & 0 & -1 & 0 & 0 \
    0 & 0 & 0 & 0 & 0 & 0 \
    0 & 0 & 0 & 1 & -1 & 0 \
    0 & 0 & 0 & 0 & 1 & 0 \
    0 & 0 & 0 & 0 & 0 & 0 \
    endarray
    right)$




    Putting the above together:



    res = NestWhileList[iter @* Last, iter[m], Positive @* Total @* First]


    enter image description here



    Deciding which edges are outgoing and incoming can be done with:



    KeyDrop[
    GroupBy[Thread[edges -> res[[1, 2]]], Last -> First],
    0
    ]



    <|2 -> 1 [DirectedEdge] 2, 4 [DirectedEdge] 3, 1 -> 6 [DirectedEdge] 7|>




    Converting the SparseArray back to a graph (the removed edges/vertices need to be eliminated from the sparse array) can be done with:



    With[

    v = Pick[Range @ Length @ res[[1, 1]], res[[1, 1]], 0],
    e = Pick[Range @ Length @ res[[1, 2]], res[[1, 2]], 0]
    ,

    IncidenceGraph[
    v,
    res[[1, 3]][[v, e]],
    VertexLabels->"Name"
    ]
    ]


    enter image description here



    Your second example:



    edges = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[5, 4];
    NestWhileList[
    iter @* Last,
    iter @ IncidenceMatrix[edges],
    Positive @* Total @* First
    ]


    enter image description here






    share|improve this answer



























      up vote
      2
      down vote













      What you're looking for is called a "kcore" of the graph: the set of vertices with at least k edges to other vertices of the core.



      Mathematica has a function that will find this for you:
      https://reference.wolfram.com/language/ref/KCoreComponents.html
      https://reference.wolfram.com/language/example/FindTheKCoreComponentsOfAGraph.html



      To find the removed edges (if the iteration in which they are removed is not important), simply iterate over the original edge list and count those which are not attached to a vertex in the 2-core.






      share|improve this answer










      New contributor




      geofurb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.

















        Your Answer





        StackExchange.ifUsing("editor", function ()
        return StackExchange.using("mathjaxEditing", function ()
        StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
        StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
        );
        );
        , "mathjax-editing");

        StackExchange.ready(function()
        var channelOptions =
        tags: "".split(" "),
        id: "387"
        ;
        initTagRenderer("".split(" "), "".split(" "), channelOptions);

        StackExchange.using("externalEditor", function()
        // Have to fire editor after snippets, if snippets enabled
        if (StackExchange.settings.snippets.snippetsEnabled)
        StackExchange.using("snippets", function()
        createEditor();
        );

        else
        createEditor();

        );

        function createEditor()
        StackExchange.prepareEditor(
        heartbeatType: 'answer',
        convertImagesToLinks: false,
        noModals: true,
        showLowRepImageUploadWarning: true,
        reputationToPostImages: null,
        bindNavPrevention: true,
        postfix: "",
        imageUploader:
        brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
        contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
        allowUrls: true
        ,
        onDemand: true,
        discardSelector: ".discard-answer"
        ,immediatelyShowMarkdownHelp:true
        );



        );













         

        draft saved


        draft discarded


















        StackExchange.ready(
        function ()
        StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f185556%2fiteratively-strip-off-simply-connected-edges-in-graph%23new-answer', 'question_page');

        );

        Post as a guest






























        4 Answers
        4






        active

        oldest

        votes








        4 Answers
        4






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes








        up vote
        5
        down vote



        accepted










        sourceEdges = IncidenceList[#, GeneralUtilities`GraphSources @ # ]&;
        simpleSinks = Select[GeneralUtilities`GraphSinks[#],
        Function[v, VertexInDegree[#, v] <= 1]] &;
        sinkEdges = Complement[IncidenceList[#, simpleSinks @ #], sourceEdges @ #] &;
        rest = Complement[#, sourceEdges @ #, sinkEdges @ #] &;
        f = Rest @ NestWhileList[sourceEdges @ #[[3]], sinkEdges @ #[[3]], rest @ #[[3]]&,
        , , #, #[[3]] =!= &]&;


        Examples:



        edges1 = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[3, 5],
        DirectedEdge[5, 6], DirectedEdge[6, 7];
        f @ edges1



        1 -> 2, 4 -> 3, 6 -> 7, 2 -> 3, 3 -> 5, 5 -> 6,

        2 -> 3, 5 -> 6, 3 -> 5,

        3 -> 5, ,




        g1 = Graph[edges1, VertexSize -> Large, 
        VertexLabels -> Placed["Name", Center], ImageSize -> 200, 300];
        Row[HighlightGraph[g1, #, PlotLabel -> Column[#]] & /@ f[edges1]]


        enter image description here



        edges2 = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], 
        DirectedEdge[5, 4] ;
        f @ edges2



        1 -> 2, 5 -> 4, , 2 -> 3, 4 -> 3,

        2 -> 3, 4 -> 3, ,




        g2 = Graph[edges2, VertexSize -> Large, 
        VertexLabels -> Placed["Name", Center], ImageSize -> 200, 300];
        Row[HighlightGraph[g2, #, PlotLabel -> Column[#]] & /@ f[edges2]]


        enter image description here



        You can also use GraphComputation`SourceVertexList and GraphComputation`SinkVertexList for GeneralUtilities`GraphSources and GeneralUtilities`GraphSinks, respectively.






        share|improve this answer






















        • I wonder if GeneralUtilities'GraphSinks would trigger on 2->3 and 4->3 in a situation like 1->2 , 2->3 , 4->3 , 5->4 , where 2->3 and 4->3 do point to a sink but are not simply connected to the rest of the graph? Asking, since I'd actually like to avoid this in my case.
          – Kagaratsch
          2 days ago











        • @Kagaratsch, not sure I understand el = 1->2 , 2->3 , 4->3 , 5->4 , but GeneralUtilities`GraphSinks @Flatten[el] gives 3.
          – kglr
          2 days ago











        • I see, that is what I was afraid of. In my application case I am only looking for sources and sinks which are simply connected to the rest of the graph.
          – Kagaratsch
          2 days ago











        • @Kagaratsch, sounds like the example in your question does not reflect your requirements accurately. Adding the example in your comment to your post with some explanation would be useful.
          – kglr
          2 days ago










        • Added an edit to the question.
          – Kagaratsch
          2 days ago














        up vote
        5
        down vote



        accepted










        sourceEdges = IncidenceList[#, GeneralUtilities`GraphSources @ # ]&;
        simpleSinks = Select[GeneralUtilities`GraphSinks[#],
        Function[v, VertexInDegree[#, v] <= 1]] &;
        sinkEdges = Complement[IncidenceList[#, simpleSinks @ #], sourceEdges @ #] &;
        rest = Complement[#, sourceEdges @ #, sinkEdges @ #] &;
        f = Rest @ NestWhileList[sourceEdges @ #[[3]], sinkEdges @ #[[3]], rest @ #[[3]]&,
        , , #, #[[3]] =!= &]&;


        Examples:



        edges1 = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[3, 5],
        DirectedEdge[5, 6], DirectedEdge[6, 7];
        f @ edges1



        1 -> 2, 4 -> 3, 6 -> 7, 2 -> 3, 3 -> 5, 5 -> 6,

        2 -> 3, 5 -> 6, 3 -> 5,

        3 -> 5, ,




        g1 = Graph[edges1, VertexSize -> Large, 
        VertexLabels -> Placed["Name", Center], ImageSize -> 200, 300];
        Row[HighlightGraph[g1, #, PlotLabel -> Column[#]] & /@ f[edges1]]


        enter image description here



        edges2 = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], 
        DirectedEdge[5, 4] ;
        f @ edges2



        1 -> 2, 5 -> 4, , 2 -> 3, 4 -> 3,

        2 -> 3, 4 -> 3, ,




        g2 = Graph[edges2, VertexSize -> Large, 
        VertexLabels -> Placed["Name", Center], ImageSize -> 200, 300];
        Row[HighlightGraph[g2, #, PlotLabel -> Column[#]] & /@ f[edges2]]


        enter image description here



        You can also use GraphComputation`SourceVertexList and GraphComputation`SinkVertexList for GeneralUtilities`GraphSources and GeneralUtilities`GraphSinks, respectively.






        share|improve this answer






















        • I wonder if GeneralUtilities'GraphSinks would trigger on 2->3 and 4->3 in a situation like 1->2 , 2->3 , 4->3 , 5->4 , where 2->3 and 4->3 do point to a sink but are not simply connected to the rest of the graph? Asking, since I'd actually like to avoid this in my case.
          – Kagaratsch
          2 days ago











        • @Kagaratsch, not sure I understand el = 1->2 , 2->3 , 4->3 , 5->4 , but GeneralUtilities`GraphSinks @Flatten[el] gives 3.
          – kglr
          2 days ago











        • I see, that is what I was afraid of. In my application case I am only looking for sources and sinks which are simply connected to the rest of the graph.
          – Kagaratsch
          2 days ago











        • @Kagaratsch, sounds like the example in your question does not reflect your requirements accurately. Adding the example in your comment to your post with some explanation would be useful.
          – kglr
          2 days ago










        • Added an edit to the question.
          – Kagaratsch
          2 days ago












        up vote
        5
        down vote



        accepted







        up vote
        5
        down vote



        accepted






        sourceEdges = IncidenceList[#, GeneralUtilities`GraphSources @ # ]&;
        simpleSinks = Select[GeneralUtilities`GraphSinks[#],
        Function[v, VertexInDegree[#, v] <= 1]] &;
        sinkEdges = Complement[IncidenceList[#, simpleSinks @ #], sourceEdges @ #] &;
        rest = Complement[#, sourceEdges @ #, sinkEdges @ #] &;
        f = Rest @ NestWhileList[sourceEdges @ #[[3]], sinkEdges @ #[[3]], rest @ #[[3]]&,
        , , #, #[[3]] =!= &]&;


        Examples:



        edges1 = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[3, 5],
        DirectedEdge[5, 6], DirectedEdge[6, 7];
        f @ edges1



        1 -> 2, 4 -> 3, 6 -> 7, 2 -> 3, 3 -> 5, 5 -> 6,

        2 -> 3, 5 -> 6, 3 -> 5,

        3 -> 5, ,




        g1 = Graph[edges1, VertexSize -> Large, 
        VertexLabels -> Placed["Name", Center], ImageSize -> 200, 300];
        Row[HighlightGraph[g1, #, PlotLabel -> Column[#]] & /@ f[edges1]]


        enter image description here



        edges2 = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], 
        DirectedEdge[5, 4] ;
        f @ edges2



        1 -> 2, 5 -> 4, , 2 -> 3, 4 -> 3,

        2 -> 3, 4 -> 3, ,




        g2 = Graph[edges2, VertexSize -> Large, 
        VertexLabels -> Placed["Name", Center], ImageSize -> 200, 300];
        Row[HighlightGraph[g2, #, PlotLabel -> Column[#]] & /@ f[edges2]]


        enter image description here



        You can also use GraphComputation`SourceVertexList and GraphComputation`SinkVertexList for GeneralUtilities`GraphSources and GeneralUtilities`GraphSinks, respectively.






        share|improve this answer














        sourceEdges = IncidenceList[#, GeneralUtilities`GraphSources @ # ]&;
        simpleSinks = Select[GeneralUtilities`GraphSinks[#],
        Function[v, VertexInDegree[#, v] <= 1]] &;
        sinkEdges = Complement[IncidenceList[#, simpleSinks @ #], sourceEdges @ #] &;
        rest = Complement[#, sourceEdges @ #, sinkEdges @ #] &;
        f = Rest @ NestWhileList[sourceEdges @ #[[3]], sinkEdges @ #[[3]], rest @ #[[3]]&,
        , , #, #[[3]] =!= &]&;


        Examples:



        edges1 = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[3, 5],
        DirectedEdge[5, 6], DirectedEdge[6, 7];
        f @ edges1



        1 -> 2, 4 -> 3, 6 -> 7, 2 -> 3, 3 -> 5, 5 -> 6,

        2 -> 3, 5 -> 6, 3 -> 5,

        3 -> 5, ,




        g1 = Graph[edges1, VertexSize -> Large, 
        VertexLabels -> Placed["Name", Center], ImageSize -> 200, 300];
        Row[HighlightGraph[g1, #, PlotLabel -> Column[#]] & /@ f[edges1]]


        enter image description here



        edges2 = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], 
        DirectedEdge[5, 4] ;
        f @ edges2



        1 -> 2, 5 -> 4, , 2 -> 3, 4 -> 3,

        2 -> 3, 4 -> 3, ,




        g2 = Graph[edges2, VertexSize -> Large, 
        VertexLabels -> Placed["Name", Center], ImageSize -> 200, 300];
        Row[HighlightGraph[g2, #, PlotLabel -> Column[#]] & /@ f[edges2]]


        enter image description here



        You can also use GraphComputation`SourceVertexList and GraphComputation`SinkVertexList for GeneralUtilities`GraphSources and GeneralUtilities`GraphSinks, respectively.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited yesterday

























        answered 2 days ago









        kglr

        170k8193397




        170k8193397











        • I wonder if GeneralUtilities'GraphSinks would trigger on 2->3 and 4->3 in a situation like 1->2 , 2->3 , 4->3 , 5->4 , where 2->3 and 4->3 do point to a sink but are not simply connected to the rest of the graph? Asking, since I'd actually like to avoid this in my case.
          – Kagaratsch
          2 days ago











        • @Kagaratsch, not sure I understand el = 1->2 , 2->3 , 4->3 , 5->4 , but GeneralUtilities`GraphSinks @Flatten[el] gives 3.
          – kglr
          2 days ago











        • I see, that is what I was afraid of. In my application case I am only looking for sources and sinks which are simply connected to the rest of the graph.
          – Kagaratsch
          2 days ago











        • @Kagaratsch, sounds like the example in your question does not reflect your requirements accurately. Adding the example in your comment to your post with some explanation would be useful.
          – kglr
          2 days ago










        • Added an edit to the question.
          – Kagaratsch
          2 days ago
















        • I wonder if GeneralUtilities'GraphSinks would trigger on 2->3 and 4->3 in a situation like 1->2 , 2->3 , 4->3 , 5->4 , where 2->3 and 4->3 do point to a sink but are not simply connected to the rest of the graph? Asking, since I'd actually like to avoid this in my case.
          – Kagaratsch
          2 days ago











        • @Kagaratsch, not sure I understand el = 1->2 , 2->3 , 4->3 , 5->4 , but GeneralUtilities`GraphSinks @Flatten[el] gives 3.
          – kglr
          2 days ago











        • I see, that is what I was afraid of. In my application case I am only looking for sources and sinks which are simply connected to the rest of the graph.
          – Kagaratsch
          2 days ago











        • @Kagaratsch, sounds like the example in your question does not reflect your requirements accurately. Adding the example in your comment to your post with some explanation would be useful.
          – kglr
          2 days ago










        • Added an edit to the question.
          – Kagaratsch
          2 days ago















        I wonder if GeneralUtilities'GraphSinks would trigger on 2->3 and 4->3 in a situation like 1->2 , 2->3 , 4->3 , 5->4 , where 2->3 and 4->3 do point to a sink but are not simply connected to the rest of the graph? Asking, since I'd actually like to avoid this in my case.
        – Kagaratsch
        2 days ago





        I wonder if GeneralUtilities'GraphSinks would trigger on 2->3 and 4->3 in a situation like 1->2 , 2->3 , 4->3 , 5->4 , where 2->3 and 4->3 do point to a sink but are not simply connected to the rest of the graph? Asking, since I'd actually like to avoid this in my case.
        – Kagaratsch
        2 days ago













        @Kagaratsch, not sure I understand el = 1->2 , 2->3 , 4->3 , 5->4 , but GeneralUtilities`GraphSinks @Flatten[el] gives 3.
        – kglr
        2 days ago





        @Kagaratsch, not sure I understand el = 1->2 , 2->3 , 4->3 , 5->4 , but GeneralUtilities`GraphSinks @Flatten[el] gives 3.
        – kglr
        2 days ago













        I see, that is what I was afraid of. In my application case I am only looking for sources and sinks which are simply connected to the rest of the graph.
        – Kagaratsch
        2 days ago





        I see, that is what I was afraid of. In my application case I am only looking for sources and sinks which are simply connected to the rest of the graph.
        – Kagaratsch
        2 days ago













        @Kagaratsch, sounds like the example in your question does not reflect your requirements accurately. Adding the example in your comment to your post with some explanation would be useful.
        – kglr
        2 days ago




        @Kagaratsch, sounds like the example in your question does not reflect your requirements accurately. Adding the example in your comment to your post with some explanation would be useful.
        – kglr
        2 days ago












        Added an edit to the question.
        – Kagaratsch
        2 days ago




        Added an edit to the question.
        – Kagaratsch
        2 days ago










        up vote
        4
        down vote













        g = Graph[edges, VertexLabels -> Automatic]


        enter image description here



        source[g_?GraphQ] := Pick[VertexList[g], VertexInDegree[g], 0]
        sink[g_?GraphQ] := Pick[VertexList[g], VertexOutDegree[g], 0]

        strip[g_] :=
        With[so = source[g], si = sink[g],
        Flatten[IncidenceList[g, #] & /@ so],
        Flatten[IncidenceList[g, #] & /@ si],
        VertexDelete[g, Join[so, si]]
        ]


        enter image description here



        There are minor issues, such as returning an edge twice at the last step, but that should be easy (if tedious) to fix.






        share|improve this answer
























          up vote
          4
          down vote













          g = Graph[edges, VertexLabels -> Automatic]


          enter image description here



          source[g_?GraphQ] := Pick[VertexList[g], VertexInDegree[g], 0]
          sink[g_?GraphQ] := Pick[VertexList[g], VertexOutDegree[g], 0]

          strip[g_] :=
          With[so = source[g], si = sink[g],
          Flatten[IncidenceList[g, #] & /@ so],
          Flatten[IncidenceList[g, #] & /@ si],
          VertexDelete[g, Join[so, si]]
          ]


          enter image description here



          There are minor issues, such as returning an edge twice at the last step, but that should be easy (if tedious) to fix.






          share|improve this answer






















            up vote
            4
            down vote










            up vote
            4
            down vote









            g = Graph[edges, VertexLabels -> Automatic]


            enter image description here



            source[g_?GraphQ] := Pick[VertexList[g], VertexInDegree[g], 0]
            sink[g_?GraphQ] := Pick[VertexList[g], VertexOutDegree[g], 0]

            strip[g_] :=
            With[so = source[g], si = sink[g],
            Flatten[IncidenceList[g, #] & /@ so],
            Flatten[IncidenceList[g, #] & /@ si],
            VertexDelete[g, Join[so, si]]
            ]


            enter image description here



            There are minor issues, such as returning an edge twice at the last step, but that should be easy (if tedious) to fix.






            share|improve this answer












            g = Graph[edges, VertexLabels -> Automatic]


            enter image description here



            source[g_?GraphQ] := Pick[VertexList[g], VertexInDegree[g], 0]
            sink[g_?GraphQ] := Pick[VertexList[g], VertexOutDegree[g], 0]

            strip[g_] :=
            With[so = source[g], si = sink[g],
            Flatten[IncidenceList[g, #] & /@ so],
            Flatten[IncidenceList[g, #] & /@ si],
            VertexDelete[g, Join[so, si]]
            ]


            enter image description here



            There are minor issues, such as returning an edge twice at the last step, but that should be easy (if tedious) to fix.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 2 days ago









            Szabolcs

            156k13423912




            156k13423912




















                up vote
                3
                down vote













                If you have a large graph, it will be faster to work with the vertex-edge incidence matrix instead of Graph objects. The edges you want to strip off will have either a 1 or a -1 depending on the direction of the directed edge. So, the simple edges you want to strip off will have a vertex with only a single 1 or -1 in the row. Let's take your example:



                m = IncidenceMatrix[edges];
                m //MatrixForm //TeXForm



                $left(
                beginarraycccccc
                -1 & 0 & 0 & 0 & 0 & 0 \
                1 & -1 & 0 & 0 & 0 & 0 \
                0 & 1 & 1 & -1 & 0 & 0 \
                0 & 0 & -1 & 0 & 0 & 0 \
                0 & 0 & 0 & 1 & -1 & 0 \
                0 & 0 & 0 & 0 & 1 & -1 \
                0 & 0 & 0 & 0 & 0 & 1 \
                endarray
                right)$




                The vertices that can be removed can be obtained with:



                v = Clip[Unitize[m] . ConstantArray[1, Length @ First @ m], 1, 1, 0, 0]



                1, 0, 0, 1, 0, 0, 1




                The corresponding edges can be found with:



                e = Unitize[v . Unitize[m]]



                1, 0, 1, 0, 0, 1




                The kind of edge can be determined using:



                v . Mod[m, 3] . DiagonalMatrix[e]



                2, 0, 2, 0, 0, 1




                where 1 is an outgoing edge, 2 is an incoming edge, and 3 would be both an incoming and outgoing edge.



                The matrix after removing the above vertices and edges can be found from:



                m . DiagonalMatrix[1 - e] //MatrixForm //TeXForm



                $left(
                beginarraycccccc
                0 & 0 & 0 & 0 & 0 & 0 \
                0 & -1 & 0 & 0 & 0 & 0 \
                0 & 1 & 0 & -1 & 0 & 0 \
                0 & 0 & 0 & 0 & 0 & 0 \
                0 & 0 & 0 & 1 & -1 & 0 \
                0 & 0 & 0 & 0 & 1 & 0 \
                0 & 0 & 0 & 0 & 0 & 0 \
                endarray
                right)$




                Here is a function that does one iteration:



                iter[m_] := Module[u = Unitize[m], o, v, e,
                o = ConstantArray[1, Length @ First @ u];
                v = Clip[u . o, 1, 1, 0, 0];
                e = Unitize[v . Unitize[m]];

                v,
                v . Mod[m, 3] . SparseArray[Band[1,1] -> e],
                m . SparseArray[Band[1,1] -> 1 - e]

                ]


                For example:



                r = iter[m];
                r[[1]] (* removed vertices *)
                r[[2]] (* removed edges *)
                r[[3]] //MatrixForm //TeXForm



                1, 0, 0, 1, 0, 0, 1



                2, 0, 2, 0, 0, 1



                $left(
                beginarraycccccc
                0 & 0 & 0 & 0 & 0 & 0 \
                0 & -1 & 0 & 0 & 0 & 0 \
                0 & 1 & 0 & -1 & 0 & 0 \
                0 & 0 & 0 & 0 & 0 & 0 \
                0 & 0 & 0 & 1 & -1 & 0 \
                0 & 0 & 0 & 0 & 1 & 0 \
                0 & 0 & 0 & 0 & 0 & 0 \
                endarray
                right)$




                Putting the above together:



                res = NestWhileList[iter @* Last, iter[m], Positive @* Total @* First]


                enter image description here



                Deciding which edges are outgoing and incoming can be done with:



                KeyDrop[
                GroupBy[Thread[edges -> res[[1, 2]]], Last -> First],
                0
                ]



                <|2 -> 1 [DirectedEdge] 2, 4 [DirectedEdge] 3, 1 -> 6 [DirectedEdge] 7|>




                Converting the SparseArray back to a graph (the removed edges/vertices need to be eliminated from the sparse array) can be done with:



                With[

                v = Pick[Range @ Length @ res[[1, 1]], res[[1, 1]], 0],
                e = Pick[Range @ Length @ res[[1, 2]], res[[1, 2]], 0]
                ,

                IncidenceGraph[
                v,
                res[[1, 3]][[v, e]],
                VertexLabels->"Name"
                ]
                ]


                enter image description here



                Your second example:



                edges = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[5, 4];
                NestWhileList[
                iter @* Last,
                iter @ IncidenceMatrix[edges],
                Positive @* Total @* First
                ]


                enter image description here






                share|improve this answer
























                  up vote
                  3
                  down vote













                  If you have a large graph, it will be faster to work with the vertex-edge incidence matrix instead of Graph objects. The edges you want to strip off will have either a 1 or a -1 depending on the direction of the directed edge. So, the simple edges you want to strip off will have a vertex with only a single 1 or -1 in the row. Let's take your example:



                  m = IncidenceMatrix[edges];
                  m //MatrixForm //TeXForm



                  $left(
                  beginarraycccccc
                  -1 & 0 & 0 & 0 & 0 & 0 \
                  1 & -1 & 0 & 0 & 0 & 0 \
                  0 & 1 & 1 & -1 & 0 & 0 \
                  0 & 0 & -1 & 0 & 0 & 0 \
                  0 & 0 & 0 & 1 & -1 & 0 \
                  0 & 0 & 0 & 0 & 1 & -1 \
                  0 & 0 & 0 & 0 & 0 & 1 \
                  endarray
                  right)$




                  The vertices that can be removed can be obtained with:



                  v = Clip[Unitize[m] . ConstantArray[1, Length @ First @ m], 1, 1, 0, 0]



                  1, 0, 0, 1, 0, 0, 1




                  The corresponding edges can be found with:



                  e = Unitize[v . Unitize[m]]



                  1, 0, 1, 0, 0, 1




                  The kind of edge can be determined using:



                  v . Mod[m, 3] . DiagonalMatrix[e]



                  2, 0, 2, 0, 0, 1




                  where 1 is an outgoing edge, 2 is an incoming edge, and 3 would be both an incoming and outgoing edge.



                  The matrix after removing the above vertices and edges can be found from:



                  m . DiagonalMatrix[1 - e] //MatrixForm //TeXForm



                  $left(
                  beginarraycccccc
                  0 & 0 & 0 & 0 & 0 & 0 \
                  0 & -1 & 0 & 0 & 0 & 0 \
                  0 & 1 & 0 & -1 & 0 & 0 \
                  0 & 0 & 0 & 0 & 0 & 0 \
                  0 & 0 & 0 & 1 & -1 & 0 \
                  0 & 0 & 0 & 0 & 1 & 0 \
                  0 & 0 & 0 & 0 & 0 & 0 \
                  endarray
                  right)$




                  Here is a function that does one iteration:



                  iter[m_] := Module[u = Unitize[m], o, v, e,
                  o = ConstantArray[1, Length @ First @ u];
                  v = Clip[u . o, 1, 1, 0, 0];
                  e = Unitize[v . Unitize[m]];

                  v,
                  v . Mod[m, 3] . SparseArray[Band[1,1] -> e],
                  m . SparseArray[Band[1,1] -> 1 - e]

                  ]


                  For example:



                  r = iter[m];
                  r[[1]] (* removed vertices *)
                  r[[2]] (* removed edges *)
                  r[[3]] //MatrixForm //TeXForm



                  1, 0, 0, 1, 0, 0, 1



                  2, 0, 2, 0, 0, 1



                  $left(
                  beginarraycccccc
                  0 & 0 & 0 & 0 & 0 & 0 \
                  0 & -1 & 0 & 0 & 0 & 0 \
                  0 & 1 & 0 & -1 & 0 & 0 \
                  0 & 0 & 0 & 0 & 0 & 0 \
                  0 & 0 & 0 & 1 & -1 & 0 \
                  0 & 0 & 0 & 0 & 1 & 0 \
                  0 & 0 & 0 & 0 & 0 & 0 \
                  endarray
                  right)$




                  Putting the above together:



                  res = NestWhileList[iter @* Last, iter[m], Positive @* Total @* First]


                  enter image description here



                  Deciding which edges are outgoing and incoming can be done with:



                  KeyDrop[
                  GroupBy[Thread[edges -> res[[1, 2]]], Last -> First],
                  0
                  ]



                  <|2 -> 1 [DirectedEdge] 2, 4 [DirectedEdge] 3, 1 -> 6 [DirectedEdge] 7|>




                  Converting the SparseArray back to a graph (the removed edges/vertices need to be eliminated from the sparse array) can be done with:



                  With[

                  v = Pick[Range @ Length @ res[[1, 1]], res[[1, 1]], 0],
                  e = Pick[Range @ Length @ res[[1, 2]], res[[1, 2]], 0]
                  ,

                  IncidenceGraph[
                  v,
                  res[[1, 3]][[v, e]],
                  VertexLabels->"Name"
                  ]
                  ]


                  enter image description here



                  Your second example:



                  edges = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[5, 4];
                  NestWhileList[
                  iter @* Last,
                  iter @ IncidenceMatrix[edges],
                  Positive @* Total @* First
                  ]


                  enter image description here






                  share|improve this answer






















                    up vote
                    3
                    down vote










                    up vote
                    3
                    down vote









                    If you have a large graph, it will be faster to work with the vertex-edge incidence matrix instead of Graph objects. The edges you want to strip off will have either a 1 or a -1 depending on the direction of the directed edge. So, the simple edges you want to strip off will have a vertex with only a single 1 or -1 in the row. Let's take your example:



                    m = IncidenceMatrix[edges];
                    m //MatrixForm //TeXForm



                    $left(
                    beginarraycccccc
                    -1 & 0 & 0 & 0 & 0 & 0 \
                    1 & -1 & 0 & 0 & 0 & 0 \
                    0 & 1 & 1 & -1 & 0 & 0 \
                    0 & 0 & -1 & 0 & 0 & 0 \
                    0 & 0 & 0 & 1 & -1 & 0 \
                    0 & 0 & 0 & 0 & 1 & -1 \
                    0 & 0 & 0 & 0 & 0 & 1 \
                    endarray
                    right)$




                    The vertices that can be removed can be obtained with:



                    v = Clip[Unitize[m] . ConstantArray[1, Length @ First @ m], 1, 1, 0, 0]



                    1, 0, 0, 1, 0, 0, 1




                    The corresponding edges can be found with:



                    e = Unitize[v . Unitize[m]]



                    1, 0, 1, 0, 0, 1




                    The kind of edge can be determined using:



                    v . Mod[m, 3] . DiagonalMatrix[e]



                    2, 0, 2, 0, 0, 1




                    where 1 is an outgoing edge, 2 is an incoming edge, and 3 would be both an incoming and outgoing edge.



                    The matrix after removing the above vertices and edges can be found from:



                    m . DiagonalMatrix[1 - e] //MatrixForm //TeXForm



                    $left(
                    beginarraycccccc
                    0 & 0 & 0 & 0 & 0 & 0 \
                    0 & -1 & 0 & 0 & 0 & 0 \
                    0 & 1 & 0 & -1 & 0 & 0 \
                    0 & 0 & 0 & 0 & 0 & 0 \
                    0 & 0 & 0 & 1 & -1 & 0 \
                    0 & 0 & 0 & 0 & 1 & 0 \
                    0 & 0 & 0 & 0 & 0 & 0 \
                    endarray
                    right)$




                    Here is a function that does one iteration:



                    iter[m_] := Module[u = Unitize[m], o, v, e,
                    o = ConstantArray[1, Length @ First @ u];
                    v = Clip[u . o, 1, 1, 0, 0];
                    e = Unitize[v . Unitize[m]];

                    v,
                    v . Mod[m, 3] . SparseArray[Band[1,1] -> e],
                    m . SparseArray[Band[1,1] -> 1 - e]

                    ]


                    For example:



                    r = iter[m];
                    r[[1]] (* removed vertices *)
                    r[[2]] (* removed edges *)
                    r[[3]] //MatrixForm //TeXForm



                    1, 0, 0, 1, 0, 0, 1



                    2, 0, 2, 0, 0, 1



                    $left(
                    beginarraycccccc
                    0 & 0 & 0 & 0 & 0 & 0 \
                    0 & -1 & 0 & 0 & 0 & 0 \
                    0 & 1 & 0 & -1 & 0 & 0 \
                    0 & 0 & 0 & 0 & 0 & 0 \
                    0 & 0 & 0 & 1 & -1 & 0 \
                    0 & 0 & 0 & 0 & 1 & 0 \
                    0 & 0 & 0 & 0 & 0 & 0 \
                    endarray
                    right)$




                    Putting the above together:



                    res = NestWhileList[iter @* Last, iter[m], Positive @* Total @* First]


                    enter image description here



                    Deciding which edges are outgoing and incoming can be done with:



                    KeyDrop[
                    GroupBy[Thread[edges -> res[[1, 2]]], Last -> First],
                    0
                    ]



                    <|2 -> 1 [DirectedEdge] 2, 4 [DirectedEdge] 3, 1 -> 6 [DirectedEdge] 7|>




                    Converting the SparseArray back to a graph (the removed edges/vertices need to be eliminated from the sparse array) can be done with:



                    With[

                    v = Pick[Range @ Length @ res[[1, 1]], res[[1, 1]], 0],
                    e = Pick[Range @ Length @ res[[1, 2]], res[[1, 2]], 0]
                    ,

                    IncidenceGraph[
                    v,
                    res[[1, 3]][[v, e]],
                    VertexLabels->"Name"
                    ]
                    ]


                    enter image description here



                    Your second example:



                    edges = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[5, 4];
                    NestWhileList[
                    iter @* Last,
                    iter @ IncidenceMatrix[edges],
                    Positive @* Total @* First
                    ]


                    enter image description here






                    share|improve this answer












                    If you have a large graph, it will be faster to work with the vertex-edge incidence matrix instead of Graph objects. The edges you want to strip off will have either a 1 or a -1 depending on the direction of the directed edge. So, the simple edges you want to strip off will have a vertex with only a single 1 or -1 in the row. Let's take your example:



                    m = IncidenceMatrix[edges];
                    m //MatrixForm //TeXForm



                    $left(
                    beginarraycccccc
                    -1 & 0 & 0 & 0 & 0 & 0 \
                    1 & -1 & 0 & 0 & 0 & 0 \
                    0 & 1 & 1 & -1 & 0 & 0 \
                    0 & 0 & -1 & 0 & 0 & 0 \
                    0 & 0 & 0 & 1 & -1 & 0 \
                    0 & 0 & 0 & 0 & 1 & -1 \
                    0 & 0 & 0 & 0 & 0 & 1 \
                    endarray
                    right)$




                    The vertices that can be removed can be obtained with:



                    v = Clip[Unitize[m] . ConstantArray[1, Length @ First @ m], 1, 1, 0, 0]



                    1, 0, 0, 1, 0, 0, 1




                    The corresponding edges can be found with:



                    e = Unitize[v . Unitize[m]]



                    1, 0, 1, 0, 0, 1




                    The kind of edge can be determined using:



                    v . Mod[m, 3] . DiagonalMatrix[e]



                    2, 0, 2, 0, 0, 1




                    where 1 is an outgoing edge, 2 is an incoming edge, and 3 would be both an incoming and outgoing edge.



                    The matrix after removing the above vertices and edges can be found from:



                    m . DiagonalMatrix[1 - e] //MatrixForm //TeXForm



                    $left(
                    beginarraycccccc
                    0 & 0 & 0 & 0 & 0 & 0 \
                    0 & -1 & 0 & 0 & 0 & 0 \
                    0 & 1 & 0 & -1 & 0 & 0 \
                    0 & 0 & 0 & 0 & 0 & 0 \
                    0 & 0 & 0 & 1 & -1 & 0 \
                    0 & 0 & 0 & 0 & 1 & 0 \
                    0 & 0 & 0 & 0 & 0 & 0 \
                    endarray
                    right)$




                    Here is a function that does one iteration:



                    iter[m_] := Module[u = Unitize[m], o, v, e,
                    o = ConstantArray[1, Length @ First @ u];
                    v = Clip[u . o, 1, 1, 0, 0];
                    e = Unitize[v . Unitize[m]];

                    v,
                    v . Mod[m, 3] . SparseArray[Band[1,1] -> e],
                    m . SparseArray[Band[1,1] -> 1 - e]

                    ]


                    For example:



                    r = iter[m];
                    r[[1]] (* removed vertices *)
                    r[[2]] (* removed edges *)
                    r[[3]] //MatrixForm //TeXForm



                    1, 0, 0, 1, 0, 0, 1



                    2, 0, 2, 0, 0, 1



                    $left(
                    beginarraycccccc
                    0 & 0 & 0 & 0 & 0 & 0 \
                    0 & -1 & 0 & 0 & 0 & 0 \
                    0 & 1 & 0 & -1 & 0 & 0 \
                    0 & 0 & 0 & 0 & 0 & 0 \
                    0 & 0 & 0 & 1 & -1 & 0 \
                    0 & 0 & 0 & 0 & 1 & 0 \
                    0 & 0 & 0 & 0 & 0 & 0 \
                    endarray
                    right)$




                    Putting the above together:



                    res = NestWhileList[iter @* Last, iter[m], Positive @* Total @* First]


                    enter image description here



                    Deciding which edges are outgoing and incoming can be done with:



                    KeyDrop[
                    GroupBy[Thread[edges -> res[[1, 2]]], Last -> First],
                    0
                    ]



                    <|2 -> 1 [DirectedEdge] 2, 4 [DirectedEdge] 3, 1 -> 6 [DirectedEdge] 7|>




                    Converting the SparseArray back to a graph (the removed edges/vertices need to be eliminated from the sparse array) can be done with:



                    With[

                    v = Pick[Range @ Length @ res[[1, 1]], res[[1, 1]], 0],
                    e = Pick[Range @ Length @ res[[1, 2]], res[[1, 2]], 0]
                    ,

                    IncidenceGraph[
                    v,
                    res[[1, 3]][[v, e]],
                    VertexLabels->"Name"
                    ]
                    ]


                    enter image description here



                    Your second example:



                    edges = DirectedEdge[1, 2], DirectedEdge[2, 3], DirectedEdge[4, 3], DirectedEdge[5, 4];
                    NestWhileList[
                    iter @* Last,
                    iter @ IncidenceMatrix[edges],
                    Positive @* Total @* First
                    ]


                    enter image description here







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered yesterday









                    Carl Woll

                    64.4k284167




                    64.4k284167




















                        up vote
                        2
                        down vote













                        What you're looking for is called a "kcore" of the graph: the set of vertices with at least k edges to other vertices of the core.



                        Mathematica has a function that will find this for you:
                        https://reference.wolfram.com/language/ref/KCoreComponents.html
                        https://reference.wolfram.com/language/example/FindTheKCoreComponentsOfAGraph.html



                        To find the removed edges (if the iteration in which they are removed is not important), simply iterate over the original edge list and count those which are not attached to a vertex in the 2-core.






                        share|improve this answer










                        New contributor




                        geofurb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                        Check out our Code of Conduct.





















                          up vote
                          2
                          down vote













                          What you're looking for is called a "kcore" of the graph: the set of vertices with at least k edges to other vertices of the core.



                          Mathematica has a function that will find this for you:
                          https://reference.wolfram.com/language/ref/KCoreComponents.html
                          https://reference.wolfram.com/language/example/FindTheKCoreComponentsOfAGraph.html



                          To find the removed edges (if the iteration in which they are removed is not important), simply iterate over the original edge list and count those which are not attached to a vertex in the 2-core.






                          share|improve this answer










                          New contributor




                          geofurb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.



















                            up vote
                            2
                            down vote










                            up vote
                            2
                            down vote









                            What you're looking for is called a "kcore" of the graph: the set of vertices with at least k edges to other vertices of the core.



                            Mathematica has a function that will find this for you:
                            https://reference.wolfram.com/language/ref/KCoreComponents.html
                            https://reference.wolfram.com/language/example/FindTheKCoreComponentsOfAGraph.html



                            To find the removed edges (if the iteration in which they are removed is not important), simply iterate over the original edge list and count those which are not attached to a vertex in the 2-core.






                            share|improve this answer










                            New contributor




                            geofurb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.









                            What you're looking for is called a "kcore" of the graph: the set of vertices with at least k edges to other vertices of the core.



                            Mathematica has a function that will find this for you:
                            https://reference.wolfram.com/language/ref/KCoreComponents.html
                            https://reference.wolfram.com/language/example/FindTheKCoreComponentsOfAGraph.html



                            To find the removed edges (if the iteration in which they are removed is not important), simply iterate over the original edge list and count those which are not attached to a vertex in the 2-core.







                            share|improve this answer










                            New contributor




                            geofurb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.









                            share|improve this answer



                            share|improve this answer








                            edited yesterday





















                            New contributor




                            geofurb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.









                            answered yesterday









                            geofurb

                            212




                            212




                            New contributor




                            geofurb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.





                            New contributor





                            geofurb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.






                            geofurb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.



























                                 

                                draft saved


                                draft discarded















































                                 


                                draft saved


                                draft discarded














                                StackExchange.ready(
                                function ()
                                StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f185556%2fiteratively-strip-off-simply-connected-edges-in-graph%23new-answer', 'question_page');

                                );

                                Post as a guest














































































                                Popular posts from this blog

                                𛂒𛀶,𛀽𛀑𛂀𛃧𛂓𛀙𛃆𛃑𛃷𛂟𛁡𛀢𛀟𛁤𛂽𛁕𛁪𛂟𛂯,𛁞𛂧𛀴𛁄𛁠𛁼𛂿𛀤 𛂘,𛁺𛂾𛃭𛃭𛃵𛀺,𛂣𛃍𛂖𛃶 𛀸𛃀𛂖𛁶𛁏𛁚 𛂢𛂞 𛁰𛂆𛀔,𛁸𛀽𛁓𛃋𛂇𛃧𛀧𛃣𛂐𛃇,𛂂𛃻𛃲𛁬𛃞𛀧𛃃𛀅 𛂭𛁠𛁡𛃇𛀷𛃓𛁥,𛁙𛁘𛁞𛃸𛁸𛃣𛁜,𛂛,𛃿,𛁯𛂘𛂌𛃛𛁱𛃌𛂈𛂇 𛁊𛃲,𛀕𛃴𛀜 𛀶𛂆𛀶𛃟𛂉𛀣,𛂐𛁞𛁾 𛁷𛂑𛁳𛂯𛀬𛃅,𛃶𛁼

                                Edmonton

                                Crossroads (UK TV series)