Extract substring in R using grepl

Extract substring in R using grepl



I have a table with a string column formatted like this


abcdWorkstart.csv
abcdWorkcomplete.csv



And I would like to extract the last word in that filename. So I think the beginning pattern would be the word "Work" and ending pattern would be ".csv". I wrote something using grepl but not working.


grepl("Work*.csv", data$filename)



Basically I want to extract whatever between Work and .csv



desired outcome:


start
complete





please have a look at my edit @ajax2000. It's always a good practice to add the desired outcome to your question. This makes everything so much easier and ppl know exactly what you want. I encourage you to do this in your next question ;-).
– Andre Elrico
Aug 28 at 15:20




4 Answers
4



Just as an alternative way, remove everything you don't want.


x <- c("abcdWorkstart.csv", "abcdWorkcomplete.csv")

gsub("^.*Work|\.csv$", "", x)
#[1] "start" "complete"



please note:
I have to use gsub. Because I first remove ^.*Work then \.csv$.


gsub


^.*Work


\.csv$



For [\s\S] or \d\D ... (does not work with [g]?sub)


[\s\S]


\d\D



https://regex101.com/r/wFgkgG/1



Works with akruns approach:



regmatches(v1, regexpr("(?<=Work)[\s\S]+(?=[.]csv)", v1, perl = T))


regmatches(v1, regexpr("(?<=Work)[\s\S]+(?=[.]csv)", v1, perl = T))


str1<-
'12
.2
12'

gsub("[^.]","m",str1,perl=T)
gsub(".","m",str1,perl=T)
gsub(".","m",str1,perl=F)



. matches also n when using the R engine.


.


n





pretty much all the solutions work, but i think this is more concise. thanks
– ajax2000
Sep 5 at 13:04



I think you need sub or gsub (substitute/extract) instead of grepl (find if match exists). Note that when not found, it will return the entire string unmodified:


sub


gsub


grepl


fn <- c('abcdWorkstart.csv', 'abcdWorkcomplete.csv', 'abcdNothing.csv')
out <- sub(".*Work(.*)\.csv$", "\1", fn)
out
# [1] "start" "complete" "abcdNothing.csv"



You can work around this by filtering out the unchanged ones:


out[ out != fn ]
# [1] "start" "complete"



Or marking them invalid with NA (or something else):


NA


out[ out == fn ] <- NA
out
# [1] "start" "complete" NA



With str_extract from stringr. This uses positive lookarounds to match any character one or more times (.+) between "Work" and ".csv":


str_extract


stringr


x <- c("abcdWorkstart.csv", "abcdWorkcomplete.csv")

library(stringr)
str_extract(x, "(?<=Work).+(?=\.csv)")
# [1] "start" "complete"



Here is an option using regmatches/regexpr from base R. Using a regex lookaround to match all characters that are not a . after the string 'Work', extract with regmatches


regmatches/regexpr


base R


.


regmatches


regmatches(v1, regexpr("(?<=Work)[^.]+(?=[.]csv)", v1, perl = TRUE))
#[1] "start" "complete"


v1 <- c('abcdWorkstart.csv', 'abcdWorkcomplete.csv', 'abcdNothing.csv')





To be more precise, you can use "(?<=Work).*(?=.csv)".
– r2evans
Aug 28 at 15:18


"(?<=Work).*(?=.csv)"





@avid_useR But, I am using regmatches/regexpr
– akrun
Aug 28 at 15:24


regmatches/regexpr





@avid_useR Okay, that is right
– akrun
Aug 28 at 15:25





@AndreElrico, doesn't [\s\S] match any character? Isn't is more concise to use .?
– r2evans
Aug 28 at 15:32


[\s\S]


.





@r2evans I use both [.] or \., though I feel easier to type the former.
– akrun
Aug 28 at 15:35


[.]


\.






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