Variable variables in JavaScript within a loop
Variable variables in JavaScript within a loop
var x = 1;
var ctr = 5;
while (x<=ctr)
var ss_+x = $('input[name=IDMenu_'+x+']').val();
x++;
As you can see above I have a loop that will iterate through input fields with the name IDMenu_1 through to IDMenu_5. I attempted to make the variable names themselves variable by using the syntax var ss_+x; however this is incorrect and does not work.
IDMenu_1
IDMenu_5
var ss_+x
If I were to not use a loop, this is what I would be doing:
var ss_1 = $('input[name=IDMenu_1]').val();
var ss_2 = $('input[name=IDMenu_2]').val();
var ss_3 = $('input[name=IDMenu_3]').val();
var ss_4 = $('input[name=IDMenu_4]').val();
var ss_5 = $('input[name=IDMenu_5]').val();
Is it possible to accomplish this within a loop?
var ss_+x
simply make the var an array and push the values to it.
var ss = ; - then ss.push($('input....val());– Jeff
Sep 10 '18 at 8:55
var ss = ;
ss.push($('input....val());
Possible duplicate of Variable variables in JavaScript
– Scoots
Sep 10 '18 at 9:48
2 Answers
2
You're trying to create variables with dynamic names so you could use window[variable_name].
window[variable_name]
NOTE: IMO you could use an array of values instead in this case.
var x = 1;
var ctr = 5;
while (x <= ctr)
window["ss_" + x] = $('input[name=IDMenu_' + x + ']').val();
x++;
console.log(ss_1, ss_2, ss_3, ss_4, ss_5);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input name="IDMenu_1" value="10">
<input name="IDMenu_2" value="20">
<input name="IDMenu_3" value="30">
<input name="IDMenu_4" value="40">
<input name="IDMenu_5" value="50">
This is working and I prefer this one than using array, I don't know which is better but for me this is more simple than using array. Thanks.
– ICG DEVS
Sep 10 '18 at 9:08
Welcome, Glad I could help.
– Zakaria Acharki
Sep 10 '18 at 9:14
@ICGDEVS Also, you could consider not putting all your variables in the global scope, only create one
ss object that will contain your properties, by doing the following : var ss = ; while(...) ss[x] = ...; and then access them with ss.1, ss.2, ...– Logar
Sep 10 '18 at 9:47
ss
var ss = ; while(...) ss[x] = ...;
ss.1, ss.2, ...
It'd be better to make the var an array, then push the items to it.
var x = 1;
var ctr = 5;
var ss = ;
while (x<=ctr)
ss.push($('input[name=IDMenu_'+x+']').val());
x++;
You'll then have the values in
console.log(ss[0]);
console.log(ss[1]);
// ...
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var ss_+x- what should that do? Have you had a look at your browser's error console while running the above code?– Nico Haase
Sep 10 '18 at 8:55