Dfyjkt

I am currently implementing a Spring Boot application with an SPA React front-end. To route every every request which is not exactly mapped to a route I use the following controller to forward the requests to my React application (as seen here: https://stackoverflow.com/a/40769350/4454752 with a little change to also support not mapped requests to URL of the form /a/b/c/...):

@Controller
public class BaseController 

 private static final Logger LOGGER = LogManager.getLogger(BaseController.class);


 // Match everything without a suffix (so not a static resource)
 @RequestMapping(value = "/**/[path:[^\.]*")
 public String redirect() 
 LOGGER.info("Redirect request to React app");

 // Forward to home page so that route is preserved.
 return "forward:/";
 

In addition to that I want to a have a plain Websocket route at /socket which handles both text and binary Websocket messages. I do not want to use the STOMP protocol at this endpoint.

I configured my Websockets like so:

@Configuration
@EnableWebSocket
@CrossOrigin(origins = "*")
public class WebSocketConfiguration implements WebSocketConfigurer 


 @Override
 public void registerWebSocketHandlers(WebSocketHandlerRegistry registry) 
 registry.addHandler(new MyWebsocketHandler(), "/socket").setAllowedOrigins("*").withSockJS();
 

The problem I have is that Websocket requests made to the /socket endpoint are getting mapped to the BaseController#redirect() and so the Websocket client does not get a valid connection.

The question I have is, how can I exclude the /socket route from the mapping rule of the BaseController ? I thought if a route is already mapped it will not get picked up the BaseController. Or do I have to lower the precedence of the BaseController in some way?

If anyone knows a method on how to accomplish this I would be very happy.
Thanks in advance :)