many to many field django how to join










0















I have no previous experience with many to many fields in django. This is the first time I´m using it, so I´m getting a little confused here.
So, this is what I have:



#models.py
class RefereciaCita(models.Model):
titulo = models.CharField(max_length=500, null=True, blank=True, help_text='título da pesquisa')
link = models.URLField(blank=True, null=True, help_text='link da pesquisa')
#pesquisador = models.ForeignKey('AutorPesquisa',null=True, blank=True,
#help_text='pesquisadores que participam da pesquisa', on_delete=models.SET_NULL)
pesq = models.ManyToManyField('AutoresPesq', related_name='autoresDaPesquisa',through='AutorRef', verbose_name='pesquisador')
def __str__(self):
return self.titulo
class Meta:
verbose_name = "Referência bibliográfica"
verbose_name_plural = "Referências bibliográficas"


class AutoresPesq(models.Model):
nome = models.CharField(max_length=500, null=True, blank=True, help_text='nome do pesquisador')
link = models.URLField(blank=True, null=True, help_text='link do currículo do pesquisador')
pesquisa = models.ManyToManyField('RefereciaCita', through='AutorRef', verbose_name='pesquisador',
related_name='pesquisaDoAutor', help_text='pesquisa que o autor participa')

def __str__(self):
return self.nome
class Meta:
verbose_name = "Autores Pesquisa"
verbose_name_plural = "Autores Pesquisa"

class AutorRef(models.Model):
pesquisa = models.ForeignKey(RefereciaCita, null=True, related_name='pesquisarn',
help_text='pesquisa que o autor participa', on_delete=models.CASCADE)
pesquisador = models.ForeignKey(AutoresPesq, null=True, related_name='autorDaPesquisa',
help_text='pesquisadores que participam da pesquisa', on_delete=models.CASCADE)

def __str__(self):
return self.pesquisador.nome + ", " + self.pesquisa.titulo[:190]

class Meta:
verbose_name = "Autor Pesquisa"
verbose_name_plural = "Autor Pesquisa"


I need to retrive, from each ReferenciaCita it´s respective(s) AutoresPesq



So in the template I would have something like the picture



enter image description here



So, I need to get for each 'researchPaper' it´s 'author'



But I´m getting confused with the queryset´s...
I´ve already tried with select_related and prefetch_related,
but I´m missing something here...



The middle table goes like this



enter image description here



Please help, I´m really stuck here, and have no clues...










share|improve this question


























    0















    I have no previous experience with many to many fields in django. This is the first time I´m using it, so I´m getting a little confused here.
    So, this is what I have:



    #models.py
    class RefereciaCita(models.Model):
    titulo = models.CharField(max_length=500, null=True, blank=True, help_text='título da pesquisa')
    link = models.URLField(blank=True, null=True, help_text='link da pesquisa')
    #pesquisador = models.ForeignKey('AutorPesquisa',null=True, blank=True,
    #help_text='pesquisadores que participam da pesquisa', on_delete=models.SET_NULL)
    pesq = models.ManyToManyField('AutoresPesq', related_name='autoresDaPesquisa',through='AutorRef', verbose_name='pesquisador')
    def __str__(self):
    return self.titulo
    class Meta:
    verbose_name = "Referência bibliográfica"
    verbose_name_plural = "Referências bibliográficas"


    class AutoresPesq(models.Model):
    nome = models.CharField(max_length=500, null=True, blank=True, help_text='nome do pesquisador')
    link = models.URLField(blank=True, null=True, help_text='link do currículo do pesquisador')
    pesquisa = models.ManyToManyField('RefereciaCita', through='AutorRef', verbose_name='pesquisador',
    related_name='pesquisaDoAutor', help_text='pesquisa que o autor participa')

    def __str__(self):
    return self.nome
    class Meta:
    verbose_name = "Autores Pesquisa"
    verbose_name_plural = "Autores Pesquisa"

    class AutorRef(models.Model):
    pesquisa = models.ForeignKey(RefereciaCita, null=True, related_name='pesquisarn',
    help_text='pesquisa que o autor participa', on_delete=models.CASCADE)
    pesquisador = models.ForeignKey(AutoresPesq, null=True, related_name='autorDaPesquisa',
    help_text='pesquisadores que participam da pesquisa', on_delete=models.CASCADE)

    def __str__(self):
    return self.pesquisador.nome + ", " + self.pesquisa.titulo[:190]

    class Meta:
    verbose_name = "Autor Pesquisa"
    verbose_name_plural = "Autor Pesquisa"


    I need to retrive, from each ReferenciaCita it´s respective(s) AutoresPesq



    So in the template I would have something like the picture



    enter image description here



    So, I need to get for each 'researchPaper' it´s 'author'



    But I´m getting confused with the queryset´s...
    I´ve already tried with select_related and prefetch_related,
    but I´m missing something here...



    The middle table goes like this



    enter image description here



    Please help, I´m really stuck here, and have no clues...










    share|improve this question
























      0












      0








      0








      I have no previous experience with many to many fields in django. This is the first time I´m using it, so I´m getting a little confused here.
      So, this is what I have:



      #models.py
      class RefereciaCita(models.Model):
      titulo = models.CharField(max_length=500, null=True, blank=True, help_text='título da pesquisa')
      link = models.URLField(blank=True, null=True, help_text='link da pesquisa')
      #pesquisador = models.ForeignKey('AutorPesquisa',null=True, blank=True,
      #help_text='pesquisadores que participam da pesquisa', on_delete=models.SET_NULL)
      pesq = models.ManyToManyField('AutoresPesq', related_name='autoresDaPesquisa',through='AutorRef', verbose_name='pesquisador')
      def __str__(self):
      return self.titulo
      class Meta:
      verbose_name = "Referência bibliográfica"
      verbose_name_plural = "Referências bibliográficas"


      class AutoresPesq(models.Model):
      nome = models.CharField(max_length=500, null=True, blank=True, help_text='nome do pesquisador')
      link = models.URLField(blank=True, null=True, help_text='link do currículo do pesquisador')
      pesquisa = models.ManyToManyField('RefereciaCita', through='AutorRef', verbose_name='pesquisador',
      related_name='pesquisaDoAutor', help_text='pesquisa que o autor participa')

      def __str__(self):
      return self.nome
      class Meta:
      verbose_name = "Autores Pesquisa"
      verbose_name_plural = "Autores Pesquisa"

      class AutorRef(models.Model):
      pesquisa = models.ForeignKey(RefereciaCita, null=True, related_name='pesquisarn',
      help_text='pesquisa que o autor participa', on_delete=models.CASCADE)
      pesquisador = models.ForeignKey(AutoresPesq, null=True, related_name='autorDaPesquisa',
      help_text='pesquisadores que participam da pesquisa', on_delete=models.CASCADE)

      def __str__(self):
      return self.pesquisador.nome + ", " + self.pesquisa.titulo[:190]

      class Meta:
      verbose_name = "Autor Pesquisa"
      verbose_name_plural = "Autor Pesquisa"


      I need to retrive, from each ReferenciaCita it´s respective(s) AutoresPesq



      So in the template I would have something like the picture



      enter image description here



      So, I need to get for each 'researchPaper' it´s 'author'



      But I´m getting confused with the queryset´s...
      I´ve already tried with select_related and prefetch_related,
      but I´m missing something here...



      The middle table goes like this



      enter image description here



      Please help, I´m really stuck here, and have no clues...










      share|improve this question














      I have no previous experience with many to many fields in django. This is the first time I´m using it, so I´m getting a little confused here.
      So, this is what I have:



      #models.py
      class RefereciaCita(models.Model):
      titulo = models.CharField(max_length=500, null=True, blank=True, help_text='título da pesquisa')
      link = models.URLField(blank=True, null=True, help_text='link da pesquisa')
      #pesquisador = models.ForeignKey('AutorPesquisa',null=True, blank=True,
      #help_text='pesquisadores que participam da pesquisa', on_delete=models.SET_NULL)
      pesq = models.ManyToManyField('AutoresPesq', related_name='autoresDaPesquisa',through='AutorRef', verbose_name='pesquisador')
      def __str__(self):
      return self.titulo
      class Meta:
      verbose_name = "Referência bibliográfica"
      verbose_name_plural = "Referências bibliográficas"


      class AutoresPesq(models.Model):
      nome = models.CharField(max_length=500, null=True, blank=True, help_text='nome do pesquisador')
      link = models.URLField(blank=True, null=True, help_text='link do currículo do pesquisador')
      pesquisa = models.ManyToManyField('RefereciaCita', through='AutorRef', verbose_name='pesquisador',
      related_name='pesquisaDoAutor', help_text='pesquisa que o autor participa')

      def __str__(self):
      return self.nome
      class Meta:
      verbose_name = "Autores Pesquisa"
      verbose_name_plural = "Autores Pesquisa"

      class AutorRef(models.Model):
      pesquisa = models.ForeignKey(RefereciaCita, null=True, related_name='pesquisarn',
      help_text='pesquisa que o autor participa', on_delete=models.CASCADE)
      pesquisador = models.ForeignKey(AutoresPesq, null=True, related_name='autorDaPesquisa',
      help_text='pesquisadores que participam da pesquisa', on_delete=models.CASCADE)

      def __str__(self):
      return self.pesquisador.nome + ", " + self.pesquisa.titulo[:190]

      class Meta:
      verbose_name = "Autor Pesquisa"
      verbose_name_plural = "Autor Pesquisa"


      I need to retrive, from each ReferenciaCita it´s respective(s) AutoresPesq



      So in the template I would have something like the picture



      enter image description here



      So, I need to get for each 'researchPaper' it´s 'author'



      But I´m getting confused with the queryset´s...
      I´ve already tried with select_related and prefetch_related,
      but I´m missing something here...



      The middle table goes like this



      enter image description here



      Please help, I´m really stuck here, and have no clues...







      django django-queryset jointable






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 11 '18 at 18:57









      Adriel WerlichAdriel Werlich

      55129




      55129






















          1 Answer
          1






          active

          oldest

          votes


















          1














          For your first question, you can do:



          qs_referencia_cita = ReferenciaCita.objects.all() # All ReferenciaCita

          for referencia_cita in qs_referencia_cita:
          for autores_pesq in referencia_cita.pesq.all():
          # Use your autores_pesq


          The rest is unclear what's you're asking.



          PS: You don't need both relations as ManyToManyField: The other relation is created automatically, see this part of the doc.






          share|improve this answer

























          • yes, thanks for the help... I´ve did like your example, but returned the following 'RefereciaCita' object has no attribute 'autorespesq_set'

            – Adriel Werlich
            Nov 11 '18 at 19:28












          • for rf in referencias: for au in rf.autorespesq_set.all(): print(au)

            – Adriel Werlich
            Nov 11 '18 at 19:29











          • Edited my answer, I didn't see you had two m2m relation, that is not needed. You can use ` rf.pesq.all()` in your case, rf.pesq is an object manager.

            – Cyrlop
            Nov 11 '18 at 19:40











          • Yes,@Cyrlop, that worked ... thanks a lot for your help... I was really confused about this, because I´ve never used this feature before.... thanks again!

            – Adriel Werlich
            Nov 11 '18 at 20:15












          • Glad it fixed your problem, feel free to accept the answer if this particular issue is solved.

            – Cyrlop
            Nov 14 '18 at 15:47










          Your Answer






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          1 Answer
          1






          active

          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          For your first question, you can do:



          qs_referencia_cita = ReferenciaCita.objects.all() # All ReferenciaCita

          for referencia_cita in qs_referencia_cita:
          for autores_pesq in referencia_cita.pesq.all():
          # Use your autores_pesq


          The rest is unclear what's you're asking.



          PS: You don't need both relations as ManyToManyField: The other relation is created automatically, see this part of the doc.






          share|improve this answer

























          • yes, thanks for the help... I´ve did like your example, but returned the following 'RefereciaCita' object has no attribute 'autorespesq_set'

            – Adriel Werlich
            Nov 11 '18 at 19:28












          • for rf in referencias: for au in rf.autorespesq_set.all(): print(au)

            – Adriel Werlich
            Nov 11 '18 at 19:29











          • Edited my answer, I didn't see you had two m2m relation, that is not needed. You can use ` rf.pesq.all()` in your case, rf.pesq is an object manager.

            – Cyrlop
            Nov 11 '18 at 19:40











          • Yes,@Cyrlop, that worked ... thanks a lot for your help... I was really confused about this, because I´ve never used this feature before.... thanks again!

            – Adriel Werlich
            Nov 11 '18 at 20:15












          • Glad it fixed your problem, feel free to accept the answer if this particular issue is solved.

            – Cyrlop
            Nov 14 '18 at 15:47















          1














          For your first question, you can do:



          qs_referencia_cita = ReferenciaCita.objects.all() # All ReferenciaCita

          for referencia_cita in qs_referencia_cita:
          for autores_pesq in referencia_cita.pesq.all():
          # Use your autores_pesq


          The rest is unclear what's you're asking.



          PS: You don't need both relations as ManyToManyField: The other relation is created automatically, see this part of the doc.






          share|improve this answer

























          • yes, thanks for the help... I´ve did like your example, but returned the following 'RefereciaCita' object has no attribute 'autorespesq_set'

            – Adriel Werlich
            Nov 11 '18 at 19:28












          • for rf in referencias: for au in rf.autorespesq_set.all(): print(au)

            – Adriel Werlich
            Nov 11 '18 at 19:29











          • Edited my answer, I didn't see you had two m2m relation, that is not needed. You can use ` rf.pesq.all()` in your case, rf.pesq is an object manager.

            – Cyrlop
            Nov 11 '18 at 19:40











          • Yes,@Cyrlop, that worked ... thanks a lot for your help... I was really confused about this, because I´ve never used this feature before.... thanks again!

            – Adriel Werlich
            Nov 11 '18 at 20:15












          • Glad it fixed your problem, feel free to accept the answer if this particular issue is solved.

            – Cyrlop
            Nov 14 '18 at 15:47













          1












          1








          1







          For your first question, you can do:



          qs_referencia_cita = ReferenciaCita.objects.all() # All ReferenciaCita

          for referencia_cita in qs_referencia_cita:
          for autores_pesq in referencia_cita.pesq.all():
          # Use your autores_pesq


          The rest is unclear what's you're asking.



          PS: You don't need both relations as ManyToManyField: The other relation is created automatically, see this part of the doc.






          share|improve this answer















          For your first question, you can do:



          qs_referencia_cita = ReferenciaCita.objects.all() # All ReferenciaCita

          for referencia_cita in qs_referencia_cita:
          for autores_pesq in referencia_cita.pesq.all():
          # Use your autores_pesq


          The rest is unclear what's you're asking.



          PS: You don't need both relations as ManyToManyField: The other relation is created automatically, see this part of the doc.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 11 '18 at 19:38

























          answered Nov 11 '18 at 19:14









          CyrlopCyrlop

          1,3321818




          1,3321818












          • yes, thanks for the help... I´ve did like your example, but returned the following 'RefereciaCita' object has no attribute 'autorespesq_set'

            – Adriel Werlich
            Nov 11 '18 at 19:28












          • for rf in referencias: for au in rf.autorespesq_set.all(): print(au)

            – Adriel Werlich
            Nov 11 '18 at 19:29











          • Edited my answer, I didn't see you had two m2m relation, that is not needed. You can use ` rf.pesq.all()` in your case, rf.pesq is an object manager.

            – Cyrlop
            Nov 11 '18 at 19:40











          • Yes,@Cyrlop, that worked ... thanks a lot for your help... I was really confused about this, because I´ve never used this feature before.... thanks again!

            – Adriel Werlich
            Nov 11 '18 at 20:15












          • Glad it fixed your problem, feel free to accept the answer if this particular issue is solved.

            – Cyrlop
            Nov 14 '18 at 15:47

















          • yes, thanks for the help... I´ve did like your example, but returned the following 'RefereciaCita' object has no attribute 'autorespesq_set'

            – Adriel Werlich
            Nov 11 '18 at 19:28












          • for rf in referencias: for au in rf.autorespesq_set.all(): print(au)

            – Adriel Werlich
            Nov 11 '18 at 19:29











          • Edited my answer, I didn't see you had two m2m relation, that is not needed. You can use ` rf.pesq.all()` in your case, rf.pesq is an object manager.

            – Cyrlop
            Nov 11 '18 at 19:40











          • Yes,@Cyrlop, that worked ... thanks a lot for your help... I was really confused about this, because I´ve never used this feature before.... thanks again!

            – Adriel Werlich
            Nov 11 '18 at 20:15












          • Glad it fixed your problem, feel free to accept the answer if this particular issue is solved.

            – Cyrlop
            Nov 14 '18 at 15:47
















          yes, thanks for the help... I´ve did like your example, but returned the following 'RefereciaCita' object has no attribute 'autorespesq_set'

          – Adriel Werlich
          Nov 11 '18 at 19:28






          yes, thanks for the help... I´ve did like your example, but returned the following 'RefereciaCita' object has no attribute 'autorespesq_set'

          – Adriel Werlich
          Nov 11 '18 at 19:28














          for rf in referencias: for au in rf.autorespesq_set.all(): print(au)

          – Adriel Werlich
          Nov 11 '18 at 19:29





          for rf in referencias: for au in rf.autorespesq_set.all(): print(au)

          – Adriel Werlich
          Nov 11 '18 at 19:29













          Edited my answer, I didn't see you had two m2m relation, that is not needed. You can use ` rf.pesq.all()` in your case, rf.pesq is an object manager.

          – Cyrlop
          Nov 11 '18 at 19:40





          Edited my answer, I didn't see you had two m2m relation, that is not needed. You can use ` rf.pesq.all()` in your case, rf.pesq is an object manager.

          – Cyrlop
          Nov 11 '18 at 19:40













          Yes,@Cyrlop, that worked ... thanks a lot for your help... I was really confused about this, because I´ve never used this feature before.... thanks again!

          – Adriel Werlich
          Nov 11 '18 at 20:15






          Yes,@Cyrlop, that worked ... thanks a lot for your help... I was really confused about this, because I´ve never used this feature before.... thanks again!

          – Adriel Werlich
          Nov 11 '18 at 20:15














          Glad it fixed your problem, feel free to accept the answer if this particular issue is solved.

          – Cyrlop
          Nov 14 '18 at 15:47





          Glad it fixed your problem, feel free to accept the answer if this particular issue is solved.

          – Cyrlop
          Nov 14 '18 at 15:47

















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