Python Pandas Create New Column with Groupby().Sum()
Trying to create a new column with the groupby calculation. In the code below, I get the correct calculated values for each date (see group below) but when I try to create a new column (df['Data4']) with it I get NaN. So I am trying to create a new column in the dataframe with the sum of 'Data3' for the all dates and apply that to each date row. For example, 2015-05-08 is in 2 rows (total is 50+5 = 55) and in this new column I would like to have 55 in both of the rows.
import pandas as pd
import numpy as np
from pandas import DataFrame
df = pd.DataFrame('Date': ['2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05', '2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05'], 'Sym': ['aapl', 'aapl', 'aapl', 'aapl', 'aaww', 'aaww', 'aaww', 'aaww'], 'Data2': [11, 8, 10, 15, 110, 60, 100, 40],'Data3': [5, 8, 6, 1, 50, 100, 60, 120])
group = df['Data3'].groupby(df['Date']).sum()
df['Data4'] = group
python pandas
add a comment |
Trying to create a new column with the groupby calculation. In the code below, I get the correct calculated values for each date (see group below) but when I try to create a new column (df['Data4']) with it I get NaN. So I am trying to create a new column in the dataframe with the sum of 'Data3' for the all dates and apply that to each date row. For example, 2015-05-08 is in 2 rows (total is 50+5 = 55) and in this new column I would like to have 55 in both of the rows.
import pandas as pd
import numpy as np
from pandas import DataFrame
df = pd.DataFrame('Date': ['2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05', '2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05'], 'Sym': ['aapl', 'aapl', 'aapl', 'aapl', 'aaww', 'aaww', 'aaww', 'aaww'], 'Data2': [11, 8, 10, 15, 110, 60, 100, 40],'Data3': [5, 8, 6, 1, 50, 100, 60, 120])
group = df['Data3'].groupby(df['Date']).sum()
df['Data4'] = group
python pandas
add a comment |
Trying to create a new column with the groupby calculation. In the code below, I get the correct calculated values for each date (see group below) but when I try to create a new column (df['Data4']) with it I get NaN. So I am trying to create a new column in the dataframe with the sum of 'Data3' for the all dates and apply that to each date row. For example, 2015-05-08 is in 2 rows (total is 50+5 = 55) and in this new column I would like to have 55 in both of the rows.
import pandas as pd
import numpy as np
from pandas import DataFrame
df = pd.DataFrame('Date': ['2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05', '2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05'], 'Sym': ['aapl', 'aapl', 'aapl', 'aapl', 'aaww', 'aaww', 'aaww', 'aaww'], 'Data2': [11, 8, 10, 15, 110, 60, 100, 40],'Data3': [5, 8, 6, 1, 50, 100, 60, 120])
group = df['Data3'].groupby(df['Date']).sum()
df['Data4'] = group
python pandas
Trying to create a new column with the groupby calculation. In the code below, I get the correct calculated values for each date (see group below) but when I try to create a new column (df['Data4']) with it I get NaN. So I am trying to create a new column in the dataframe with the sum of 'Data3' for the all dates and apply that to each date row. For example, 2015-05-08 is in 2 rows (total is 50+5 = 55) and in this new column I would like to have 55 in both of the rows.
import pandas as pd
import numpy as np
from pandas import DataFrame
df = pd.DataFrame('Date': ['2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05', '2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05'], 'Sym': ['aapl', 'aapl', 'aapl', 'aapl', 'aaww', 'aaww', 'aaww', 'aaww'], 'Data2': [11, 8, 10, 15, 110, 60, 100, 40],'Data3': [5, 8, 6, 1, 50, 100, 60, 120])
group = df['Data3'].groupby(df['Date']).sum()
df['Data4'] = group
python pandas
python pandas
asked May 14 '15 at 18:44
fe nerfe ner
209136
209136
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2 Answers
2
active
oldest
votes
You want to use transform
this will return a Series with the index aligned to the df so you can then add it as a new column:
In [74]:
df = pd.DataFrame('Date': ['2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05', '2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05'], 'Sym': ['aapl', 'aapl', 'aapl', 'aapl', 'aaww', 'aaww', 'aaww', 'aaww'], 'Data2': [11, 8, 10, 15, 110, 60, 100, 40],'Data3': [5, 8, 6, 1, 50, 100, 60, 120])
df['Data4'] = df['Data3'].groupby(df['Date']).transform('sum')
df
Out[74]:
Data2 Data3 Date Sym Data4
0 11 5 2015-05-08 aapl 55
1 8 8 2015-05-07 aapl 108
2 10 6 2015-05-06 aapl 66
3 15 1 2015-05-05 aapl 121
4 110 50 2015-05-08 aaww 55
5 60 100 2015-05-07 aaww 108
6 100 60 2015-05-06 aaww 66
7 40 120 2015-05-05 aaww 121
What happens if we have a second groupby as in here: stackoverflow.com/a/40067099/281545
– Mr_and_Mrs_D
May 5 '18 at 20:40
@Mr_and_Mrs_D you'd have to reset the index and perform a left merge on the common columns in that case to add the column back
– EdChum
May 5 '18 at 20:56
3
Alternatively, one can usedf.groupby('Date')['Data3'].transform('sum')
(which I find slightly easier to remember).
– Cleb
Aug 24 '18 at 11:32
add a comment |
I stumbled upon an interesting idiosyncrasy in the API. It seems like you consistently can shave off a few milliseconds of the time taken by transform
if you instead use a direct function of GroupBy
and broadcast it using map
:
df
Date Sym Data2 Data3
0 2015-05-08 aapl 11 5
1 2015-05-07 aapl 8 8
2 2015-05-06 aapl 10 6
3 2015-05-05 aapl 15 1
4 2015-05-08 aaww 110 50
5 2015-05-07 aaww 60 100
6 2015-05-06 aaww 100 60
7 2015-05-05 aaww 40 120
df.Date.map(df.groupby('Date')['Data3'].sum())
0 55
1 108
2 66
3 121
4 55
5 108
6 66
7 121
Name: Date, dtype: int64
Compare with
df.groupby('Date')['Data3'].transform('sum')
0 55
1 108
2 66
3 121
4 55
5 108
6 66
7 121
Name: Data3, dtype: int64
My tests show that map
is a bit faster if you can afford to use the direct GroupBy
function (such as mean
, min
, max
, first
, etc). It is more or less faster for most general situations upto around ~200 thousand records. After that, the performance really depends on the data.
I would say this is a nice alternative to know, and is better if you have smaller frames with smaller numbers of groups, but I would recommend transform
as a first choice. Thought this was worth sharing anyway.
Benchmarking code, for reference:
import perfplot
perfplot.show(
setup=lambda n: pd.DataFrame('A': np.random.choice(n//10, n), 'B': np.ones(n)),
kernels=[
lambda df: df.groupby('A')['B'].transform('sum'),
lambda df: df.A.map(df.groupby('A')['B'].sum()),
],
labels=['GroupBy.transform', 'GroupBy.sum + map'],
n_range=[2**k for k in range(5, 20)],
xlabel='N',
logy=True,
logx=True
)
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You want to use transform
this will return a Series with the index aligned to the df so you can then add it as a new column:
In [74]:
df = pd.DataFrame('Date': ['2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05', '2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05'], 'Sym': ['aapl', 'aapl', 'aapl', 'aapl', 'aaww', 'aaww', 'aaww', 'aaww'], 'Data2': [11, 8, 10, 15, 110, 60, 100, 40],'Data3': [5, 8, 6, 1, 50, 100, 60, 120])
df['Data4'] = df['Data3'].groupby(df['Date']).transform('sum')
df
Out[74]:
Data2 Data3 Date Sym Data4
0 11 5 2015-05-08 aapl 55
1 8 8 2015-05-07 aapl 108
2 10 6 2015-05-06 aapl 66
3 15 1 2015-05-05 aapl 121
4 110 50 2015-05-08 aaww 55
5 60 100 2015-05-07 aaww 108
6 100 60 2015-05-06 aaww 66
7 40 120 2015-05-05 aaww 121
What happens if we have a second groupby as in here: stackoverflow.com/a/40067099/281545
– Mr_and_Mrs_D
May 5 '18 at 20:40
@Mr_and_Mrs_D you'd have to reset the index and perform a left merge on the common columns in that case to add the column back
– EdChum
May 5 '18 at 20:56
3
Alternatively, one can usedf.groupby('Date')['Data3'].transform('sum')
(which I find slightly easier to remember).
– Cleb
Aug 24 '18 at 11:32
add a comment |
You want to use transform
this will return a Series with the index aligned to the df so you can then add it as a new column:
In [74]:
df = pd.DataFrame('Date': ['2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05', '2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05'], 'Sym': ['aapl', 'aapl', 'aapl', 'aapl', 'aaww', 'aaww', 'aaww', 'aaww'], 'Data2': [11, 8, 10, 15, 110, 60, 100, 40],'Data3': [5, 8, 6, 1, 50, 100, 60, 120])
df['Data4'] = df['Data3'].groupby(df['Date']).transform('sum')
df
Out[74]:
Data2 Data3 Date Sym Data4
0 11 5 2015-05-08 aapl 55
1 8 8 2015-05-07 aapl 108
2 10 6 2015-05-06 aapl 66
3 15 1 2015-05-05 aapl 121
4 110 50 2015-05-08 aaww 55
5 60 100 2015-05-07 aaww 108
6 100 60 2015-05-06 aaww 66
7 40 120 2015-05-05 aaww 121
What happens if we have a second groupby as in here: stackoverflow.com/a/40067099/281545
– Mr_and_Mrs_D
May 5 '18 at 20:40
@Mr_and_Mrs_D you'd have to reset the index and perform a left merge on the common columns in that case to add the column back
– EdChum
May 5 '18 at 20:56
3
Alternatively, one can usedf.groupby('Date')['Data3'].transform('sum')
(which I find slightly easier to remember).
– Cleb
Aug 24 '18 at 11:32
add a comment |
You want to use transform
this will return a Series with the index aligned to the df so you can then add it as a new column:
In [74]:
df = pd.DataFrame('Date': ['2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05', '2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05'], 'Sym': ['aapl', 'aapl', 'aapl', 'aapl', 'aaww', 'aaww', 'aaww', 'aaww'], 'Data2': [11, 8, 10, 15, 110, 60, 100, 40],'Data3': [5, 8, 6, 1, 50, 100, 60, 120])
df['Data4'] = df['Data3'].groupby(df['Date']).transform('sum')
df
Out[74]:
Data2 Data3 Date Sym Data4
0 11 5 2015-05-08 aapl 55
1 8 8 2015-05-07 aapl 108
2 10 6 2015-05-06 aapl 66
3 15 1 2015-05-05 aapl 121
4 110 50 2015-05-08 aaww 55
5 60 100 2015-05-07 aaww 108
6 100 60 2015-05-06 aaww 66
7 40 120 2015-05-05 aaww 121
You want to use transform
this will return a Series with the index aligned to the df so you can then add it as a new column:
In [74]:
df = pd.DataFrame('Date': ['2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05', '2015-05-08', '2015-05-07', '2015-05-06', '2015-05-05'], 'Sym': ['aapl', 'aapl', 'aapl', 'aapl', 'aaww', 'aaww', 'aaww', 'aaww'], 'Data2': [11, 8, 10, 15, 110, 60, 100, 40],'Data3': [5, 8, 6, 1, 50, 100, 60, 120])
df['Data4'] = df['Data3'].groupby(df['Date']).transform('sum')
df
Out[74]:
Data2 Data3 Date Sym Data4
0 11 5 2015-05-08 aapl 55
1 8 8 2015-05-07 aapl 108
2 10 6 2015-05-06 aapl 66
3 15 1 2015-05-05 aapl 121
4 110 50 2015-05-08 aaww 55
5 60 100 2015-05-07 aaww 108
6 100 60 2015-05-06 aaww 66
7 40 120 2015-05-05 aaww 121
answered May 14 '15 at 18:46
EdChumEdChum
176k33376325
176k33376325
What happens if we have a second groupby as in here: stackoverflow.com/a/40067099/281545
– Mr_and_Mrs_D
May 5 '18 at 20:40
@Mr_and_Mrs_D you'd have to reset the index and perform a left merge on the common columns in that case to add the column back
– EdChum
May 5 '18 at 20:56
3
Alternatively, one can usedf.groupby('Date')['Data3'].transform('sum')
(which I find slightly easier to remember).
– Cleb
Aug 24 '18 at 11:32
add a comment |
What happens if we have a second groupby as in here: stackoverflow.com/a/40067099/281545
– Mr_and_Mrs_D
May 5 '18 at 20:40
@Mr_and_Mrs_D you'd have to reset the index and perform a left merge on the common columns in that case to add the column back
– EdChum
May 5 '18 at 20:56
3
Alternatively, one can usedf.groupby('Date')['Data3'].transform('sum')
(which I find slightly easier to remember).
– Cleb
Aug 24 '18 at 11:32
What happens if we have a second groupby as in here: stackoverflow.com/a/40067099/281545
– Mr_and_Mrs_D
May 5 '18 at 20:40
What happens if we have a second groupby as in here: stackoverflow.com/a/40067099/281545
– Mr_and_Mrs_D
May 5 '18 at 20:40
@Mr_and_Mrs_D you'd have to reset the index and perform a left merge on the common columns in that case to add the column back
– EdChum
May 5 '18 at 20:56
@Mr_and_Mrs_D you'd have to reset the index and perform a left merge on the common columns in that case to add the column back
– EdChum
May 5 '18 at 20:56
3
3
Alternatively, one can use
df.groupby('Date')['Data3'].transform('sum')
(which I find slightly easier to remember).– Cleb
Aug 24 '18 at 11:32
Alternatively, one can use
df.groupby('Date')['Data3'].transform('sum')
(which I find slightly easier to remember).– Cleb
Aug 24 '18 at 11:32
add a comment |
I stumbled upon an interesting idiosyncrasy in the API. It seems like you consistently can shave off a few milliseconds of the time taken by transform
if you instead use a direct function of GroupBy
and broadcast it using map
:
df
Date Sym Data2 Data3
0 2015-05-08 aapl 11 5
1 2015-05-07 aapl 8 8
2 2015-05-06 aapl 10 6
3 2015-05-05 aapl 15 1
4 2015-05-08 aaww 110 50
5 2015-05-07 aaww 60 100
6 2015-05-06 aaww 100 60
7 2015-05-05 aaww 40 120
df.Date.map(df.groupby('Date')['Data3'].sum())
0 55
1 108
2 66
3 121
4 55
5 108
6 66
7 121
Name: Date, dtype: int64
Compare with
df.groupby('Date')['Data3'].transform('sum')
0 55
1 108
2 66
3 121
4 55
5 108
6 66
7 121
Name: Data3, dtype: int64
My tests show that map
is a bit faster if you can afford to use the direct GroupBy
function (such as mean
, min
, max
, first
, etc). It is more or less faster for most general situations upto around ~200 thousand records. After that, the performance really depends on the data.
I would say this is a nice alternative to know, and is better if you have smaller frames with smaller numbers of groups, but I would recommend transform
as a first choice. Thought this was worth sharing anyway.
Benchmarking code, for reference:
import perfplot
perfplot.show(
setup=lambda n: pd.DataFrame('A': np.random.choice(n//10, n), 'B': np.ones(n)),
kernels=[
lambda df: df.groupby('A')['B'].transform('sum'),
lambda df: df.A.map(df.groupby('A')['B'].sum()),
],
labels=['GroupBy.transform', 'GroupBy.sum + map'],
n_range=[2**k for k in range(5, 20)],
xlabel='N',
logy=True,
logx=True
)
add a comment |
I stumbled upon an interesting idiosyncrasy in the API. It seems like you consistently can shave off a few milliseconds of the time taken by transform
if you instead use a direct function of GroupBy
and broadcast it using map
:
df
Date Sym Data2 Data3
0 2015-05-08 aapl 11 5
1 2015-05-07 aapl 8 8
2 2015-05-06 aapl 10 6
3 2015-05-05 aapl 15 1
4 2015-05-08 aaww 110 50
5 2015-05-07 aaww 60 100
6 2015-05-06 aaww 100 60
7 2015-05-05 aaww 40 120
df.Date.map(df.groupby('Date')['Data3'].sum())
0 55
1 108
2 66
3 121
4 55
5 108
6 66
7 121
Name: Date, dtype: int64
Compare with
df.groupby('Date')['Data3'].transform('sum')
0 55
1 108
2 66
3 121
4 55
5 108
6 66
7 121
Name: Data3, dtype: int64
My tests show that map
is a bit faster if you can afford to use the direct GroupBy
function (such as mean
, min
, max
, first
, etc). It is more or less faster for most general situations upto around ~200 thousand records. After that, the performance really depends on the data.
I would say this is a nice alternative to know, and is better if you have smaller frames with smaller numbers of groups, but I would recommend transform
as a first choice. Thought this was worth sharing anyway.
Benchmarking code, for reference:
import perfplot
perfplot.show(
setup=lambda n: pd.DataFrame('A': np.random.choice(n//10, n), 'B': np.ones(n)),
kernels=[
lambda df: df.groupby('A')['B'].transform('sum'),
lambda df: df.A.map(df.groupby('A')['B'].sum()),
],
labels=['GroupBy.transform', 'GroupBy.sum + map'],
n_range=[2**k for k in range(5, 20)],
xlabel='N',
logy=True,
logx=True
)
add a comment |
I stumbled upon an interesting idiosyncrasy in the API. It seems like you consistently can shave off a few milliseconds of the time taken by transform
if you instead use a direct function of GroupBy
and broadcast it using map
:
df
Date Sym Data2 Data3
0 2015-05-08 aapl 11 5
1 2015-05-07 aapl 8 8
2 2015-05-06 aapl 10 6
3 2015-05-05 aapl 15 1
4 2015-05-08 aaww 110 50
5 2015-05-07 aaww 60 100
6 2015-05-06 aaww 100 60
7 2015-05-05 aaww 40 120
df.Date.map(df.groupby('Date')['Data3'].sum())
0 55
1 108
2 66
3 121
4 55
5 108
6 66
7 121
Name: Date, dtype: int64
Compare with
df.groupby('Date')['Data3'].transform('sum')
0 55
1 108
2 66
3 121
4 55
5 108
6 66
7 121
Name: Data3, dtype: int64
My tests show that map
is a bit faster if you can afford to use the direct GroupBy
function (such as mean
, min
, max
, first
, etc). It is more or less faster for most general situations upto around ~200 thousand records. After that, the performance really depends on the data.
I would say this is a nice alternative to know, and is better if you have smaller frames with smaller numbers of groups, but I would recommend transform
as a first choice. Thought this was worth sharing anyway.
Benchmarking code, for reference:
import perfplot
perfplot.show(
setup=lambda n: pd.DataFrame('A': np.random.choice(n//10, n), 'B': np.ones(n)),
kernels=[
lambda df: df.groupby('A')['B'].transform('sum'),
lambda df: df.A.map(df.groupby('A')['B'].sum()),
],
labels=['GroupBy.transform', 'GroupBy.sum + map'],
n_range=[2**k for k in range(5, 20)],
xlabel='N',
logy=True,
logx=True
)
I stumbled upon an interesting idiosyncrasy in the API. It seems like you consistently can shave off a few milliseconds of the time taken by transform
if you instead use a direct function of GroupBy
and broadcast it using map
:
df
Date Sym Data2 Data3
0 2015-05-08 aapl 11 5
1 2015-05-07 aapl 8 8
2 2015-05-06 aapl 10 6
3 2015-05-05 aapl 15 1
4 2015-05-08 aaww 110 50
5 2015-05-07 aaww 60 100
6 2015-05-06 aaww 100 60
7 2015-05-05 aaww 40 120
df.Date.map(df.groupby('Date')['Data3'].sum())
0 55
1 108
2 66
3 121
4 55
5 108
6 66
7 121
Name: Date, dtype: int64
Compare with
df.groupby('Date')['Data3'].transform('sum')
0 55
1 108
2 66
3 121
4 55
5 108
6 66
7 121
Name: Data3, dtype: int64
My tests show that map
is a bit faster if you can afford to use the direct GroupBy
function (such as mean
, min
, max
, first
, etc). It is more or less faster for most general situations upto around ~200 thousand records. After that, the performance really depends on the data.
I would say this is a nice alternative to know, and is better if you have smaller frames with smaller numbers of groups, but I would recommend transform
as a first choice. Thought this was worth sharing anyway.
Benchmarking code, for reference:
import perfplot
perfplot.show(
setup=lambda n: pd.DataFrame('A': np.random.choice(n//10, n), 'B': np.ones(n)),
kernels=[
lambda df: df.groupby('A')['B'].transform('sum'),
lambda df: df.A.map(df.groupby('A')['B'].sum()),
],
labels=['GroupBy.transform', 'GroupBy.sum + map'],
n_range=[2**k for k in range(5, 20)],
xlabel='N',
logy=True,
logx=True
)
edited Jan 29 at 9:40
answered Jan 29 at 9:09
coldspeedcoldspeed
130k23135221
130k23135221
add a comment |
add a comment |
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StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown