Find text javascript

I Have string random length

Ex:

sadsadsadsad(323213)dfsssds

sadsadsadsad(321)dfsssds


How can I find the values in brackets?.

Value random length

Thank for reading

7 Answers
7

Try This:

var str = 'sadsadsadsad(321)dfss888s(120)ds';

str.match(/(d+)/g).map ( value => console.log( value.replace(/[)(]/g, '') ) );

Try regex /(.*)/

/(.*)/

function getValue(s)
var strs = s.match(/(.*?)/g);
if (strs == null)
return '';

return strs.map(str=>str.replace(/[()]/g, ''));
//return strs.join(' ,').replace(/[()]/g, '')




console.log(getValue('sadsadsadsad(323213)dfsssds(abc)'));
console.log(getValue('sadsad(_d_)sadsad(321)dfsssds'));
console.log(getValue('sadsad(33)sadsad(321dfsssds'));

adsdadsdas(123)adadadad(123431)

123123431

,

You can use lastIndexOf and substring

lastIndexOf

substring

var text = "sadsadsadsad(323213)dfsssds";
var newText = text.substring(text.lastIndexOf("(") + 1, text.lastIndexOf(")"));

console.log(newText)

You can use indexOf and substring

indexOf

substring

let str = 'sadsadsadsad(321)dfsssds';

let getFirstIndex = str.indexOf('(');
let getSecondIndex = str.indexOf(')');

let subStr = str.substring(getFirstIndex + 1, getSecondIndex);
console.log(subStr)

var str = "sadsadsadsad(323213)dfsssds";
var val= str.match(/((.*?))/);
if (val)
console.log("found");


You can use Regex

var str = "sadsadsadsad(323213)dfsssds";
var val= str.match(/((.*?))/);
if (val)
console.log("found");



Try by using the following code it will helps you if you have remove nested Parentheses example "a(bcdefghijkl(mno)p)q"

"a(bcdefghijkl(mno)p)q"

function removeParentheses(s)
let openPatterns = ;
for(let i=0; i < s.length; i++)

if(s[i] == '(')
openPatterns.push(i);


if(s[i] == ')')
const lastIndexOpen = openPatterns.pop();
const originalTxt = s.slice(lastIndexOpen ,i+1);
//here you have the raw text
const rawText = s.slice(lastIndexOpen+1,i);
//this code works to remove the parentesis
//s= s.replace(originalTxt, reverseTxt);
//i-=2;


return rawText;



You could catch the group within () using replace(), and passing it to a callback function that push it into an array.

()

replace()

var str = 'sadsadsadsad(323213)dfsssds(1234)dfsssds(4567)dfsssds(abcf)';

var arr = ;

str.replace(/(([a-z0-9]*))+/gi, (a,b)=>arr.push(b));

console.log(arr);

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