Ajax first time try










1















Could you please help me?
I'm trying Ajax for the first time? what I'm missing?



Ajax code (It gets to the confirm dialog, then nothing happens).



 <script src="https://code.jquery.com/jquery-3.3.1.js"></script>
<script>
//anyjscode

jQuery(document).ready(function()


jQuery('#ajaxSubmit').click(function(e)


e.preventDefault();
$.ajaxSetup(

headers:

'X-CSRF-TOKEN': $('meta[name="_token"]').attr('content')

);

confirm ('¿very sure?');

jQuery.ajax(

url: " url('/gymmgr/public/notas/test/') ",
method:'get',
data:

dcmTest:jQuery('#dcmTest').val()
,
sucess: function(result)

console.log(result);

);


);
);

</script>


This is the route at my web.php file



 Route::get('notas/test/', 'NotasController@test')->name('notas.test');


And it's code



public function test()

dd('Test');



Part of the code I'm using for the test, this at my view.



 <div>
<label for="dcmTest">Test</label>
<input type="number"
class="form-control"
min="0.00"
max="100000.00"
step="0.01"
name="dcmTest"
id="dcmTest"
placeholder="test"
value=0
readonly>
</div>
<button type="button" class="btn btn-default" id="ajaxSubmit">OK</button>
</div>


This is what i got after the call at my console. Could you help me to interpret it? did it really load? why the dd function wasn't call at all?



enter image description here



Does it mean it arrived? why it doesn't showed the text? it's at client side...



enter image description here










share|improve this question



















  • 2





    "It gets to the confirm dialog, then nothing happens", you haven't told it to do anything except log the ajaxed data to the console, hit F12 and click on the console tab you should see a log message there. ajax() doesn't automatically load the result into the page. Also you have a typo: sucess: function(result) it is success

    – Patrick Evans
    Nov 11 '18 at 23:16







  • 1





    You have over complicated this very simple use case. Well, more directly, you've allowed jQuery to overcomplicate this simple use case. Please investigate the use of fetch. This will provide a modern view of accomplishing your goal. Nice examples can be found here:developer.mozilla.org/en-US/docs/Web/API/Fetch_API/Using_Fetch

    – Randy Casburn
    Nov 11 '18 at 23:20











  • should'n it call the test function and stop showing the "test" text?

    – Arthur
    Nov 11 '18 at 23:21






  • 1





    Yes, and it probably is. The output of that PHP function will be the response to the AJAX request. This should be logged to your browser console (see first comment above) via your console.log(result) line

    – Phil
    Nov 11 '18 at 23:44







  • 1





    Note your backtend test() function is being called hence why the Preview area of the Network tab is showing the "Test" string. Also note the Console tab to the left of the Network tab is where you would have seen the console.log() of your result

    – Patrick Evans
    Nov 12 '18 at 3:00















1















Could you please help me?
I'm trying Ajax for the first time? what I'm missing?



Ajax code (It gets to the confirm dialog, then nothing happens).



 <script src="https://code.jquery.com/jquery-3.3.1.js"></script>
<script>
//anyjscode

jQuery(document).ready(function()


jQuery('#ajaxSubmit').click(function(e)


e.preventDefault();
$.ajaxSetup(

headers:

'X-CSRF-TOKEN': $('meta[name="_token"]').attr('content')

);

confirm ('¿very sure?');

jQuery.ajax(

url: " url('/gymmgr/public/notas/test/') ",
method:'get',
data:

dcmTest:jQuery('#dcmTest').val()
,
sucess: function(result)

console.log(result);

);


);
);

</script>


This is the route at my web.php file



 Route::get('notas/test/', 'NotasController@test')->name('notas.test');


And it's code



public function test()

dd('Test');



Part of the code I'm using for the test, this at my view.



 <div>
<label for="dcmTest">Test</label>
<input type="number"
class="form-control"
min="0.00"
max="100000.00"
step="0.01"
name="dcmTest"
id="dcmTest"
placeholder="test"
value=0
readonly>
</div>
<button type="button" class="btn btn-default" id="ajaxSubmit">OK</button>
</div>


This is what i got after the call at my console. Could you help me to interpret it? did it really load? why the dd function wasn't call at all?



enter image description here



Does it mean it arrived? why it doesn't showed the text? it's at client side...



enter image description here










share|improve this question



















  • 2





    "It gets to the confirm dialog, then nothing happens", you haven't told it to do anything except log the ajaxed data to the console, hit F12 and click on the console tab you should see a log message there. ajax() doesn't automatically load the result into the page. Also you have a typo: sucess: function(result) it is success

    – Patrick Evans
    Nov 11 '18 at 23:16







  • 1





    You have over complicated this very simple use case. Well, more directly, you've allowed jQuery to overcomplicate this simple use case. Please investigate the use of fetch. This will provide a modern view of accomplishing your goal. Nice examples can be found here:developer.mozilla.org/en-US/docs/Web/API/Fetch_API/Using_Fetch

    – Randy Casburn
    Nov 11 '18 at 23:20











  • should'n it call the test function and stop showing the "test" text?

    – Arthur
    Nov 11 '18 at 23:21






  • 1





    Yes, and it probably is. The output of that PHP function will be the response to the AJAX request. This should be logged to your browser console (see first comment above) via your console.log(result) line

    – Phil
    Nov 11 '18 at 23:44







  • 1





    Note your backtend test() function is being called hence why the Preview area of the Network tab is showing the "Test" string. Also note the Console tab to the left of the Network tab is where you would have seen the console.log() of your result

    – Patrick Evans
    Nov 12 '18 at 3:00













1












1








1


0






Could you please help me?
I'm trying Ajax for the first time? what I'm missing?



Ajax code (It gets to the confirm dialog, then nothing happens).



 <script src="https://code.jquery.com/jquery-3.3.1.js"></script>
<script>
//anyjscode

jQuery(document).ready(function()


jQuery('#ajaxSubmit').click(function(e)


e.preventDefault();
$.ajaxSetup(

headers:

'X-CSRF-TOKEN': $('meta[name="_token"]').attr('content')

);

confirm ('¿very sure?');

jQuery.ajax(

url: " url('/gymmgr/public/notas/test/') ",
method:'get',
data:

dcmTest:jQuery('#dcmTest').val()
,
sucess: function(result)

console.log(result);

);


);
);

</script>


This is the route at my web.php file



 Route::get('notas/test/', 'NotasController@test')->name('notas.test');


And it's code



public function test()

dd('Test');



Part of the code I'm using for the test, this at my view.



 <div>
<label for="dcmTest">Test</label>
<input type="number"
class="form-control"
min="0.00"
max="100000.00"
step="0.01"
name="dcmTest"
id="dcmTest"
placeholder="test"
value=0
readonly>
</div>
<button type="button" class="btn btn-default" id="ajaxSubmit">OK</button>
</div>


This is what i got after the call at my console. Could you help me to interpret it? did it really load? why the dd function wasn't call at all?



enter image description here



Does it mean it arrived? why it doesn't showed the text? it's at client side...



enter image description here










share|improve this question
















Could you please help me?
I'm trying Ajax for the first time? what I'm missing?



Ajax code (It gets to the confirm dialog, then nothing happens).



 <script src="https://code.jquery.com/jquery-3.3.1.js"></script>
<script>
//anyjscode

jQuery(document).ready(function()


jQuery('#ajaxSubmit').click(function(e)


e.preventDefault();
$.ajaxSetup(

headers:

'X-CSRF-TOKEN': $('meta[name="_token"]').attr('content')

);

confirm ('¿very sure?');

jQuery.ajax(

url: " url('/gymmgr/public/notas/test/') ",
method:'get',
data:

dcmTest:jQuery('#dcmTest').val()
,
sucess: function(result)

console.log(result);

);


);
);

</script>


This is the route at my web.php file



 Route::get('notas/test/', 'NotasController@test')->name('notas.test');


And it's code



public function test()

dd('Test');



Part of the code I'm using for the test, this at my view.



 <div>
<label for="dcmTest">Test</label>
<input type="number"
class="form-control"
min="0.00"
max="100000.00"
step="0.01"
name="dcmTest"
id="dcmTest"
placeholder="test"
value=0
readonly>
</div>
<button type="button" class="btn btn-default" id="ajaxSubmit">OK</button>
</div>


This is what i got after the call at my console. Could you help me to interpret it? did it really load? why the dd function wasn't call at all?



enter image description here



Does it mean it arrived? why it doesn't showed the text? it's at client side...



enter image description here







javascript ajax laravel laravel-5.5






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 12 '18 at 0:35







Arthur

















asked Nov 11 '18 at 23:04









ArthurArthur

477




477







  • 2





    "It gets to the confirm dialog, then nothing happens", you haven't told it to do anything except log the ajaxed data to the console, hit F12 and click on the console tab you should see a log message there. ajax() doesn't automatically load the result into the page. Also you have a typo: sucess: function(result) it is success

    – Patrick Evans
    Nov 11 '18 at 23:16







  • 1





    You have over complicated this very simple use case. Well, more directly, you've allowed jQuery to overcomplicate this simple use case. Please investigate the use of fetch. This will provide a modern view of accomplishing your goal. Nice examples can be found here:developer.mozilla.org/en-US/docs/Web/API/Fetch_API/Using_Fetch

    – Randy Casburn
    Nov 11 '18 at 23:20











  • should'n it call the test function and stop showing the "test" text?

    – Arthur
    Nov 11 '18 at 23:21






  • 1





    Yes, and it probably is. The output of that PHP function will be the response to the AJAX request. This should be logged to your browser console (see first comment above) via your console.log(result) line

    – Phil
    Nov 11 '18 at 23:44







  • 1





    Note your backtend test() function is being called hence why the Preview area of the Network tab is showing the "Test" string. Also note the Console tab to the left of the Network tab is where you would have seen the console.log() of your result

    – Patrick Evans
    Nov 12 '18 at 3:00












  • 2





    "It gets to the confirm dialog, then nothing happens", you haven't told it to do anything except log the ajaxed data to the console, hit F12 and click on the console tab you should see a log message there. ajax() doesn't automatically load the result into the page. Also you have a typo: sucess: function(result) it is success

    – Patrick Evans
    Nov 11 '18 at 23:16







  • 1





    You have over complicated this very simple use case. Well, more directly, you've allowed jQuery to overcomplicate this simple use case. Please investigate the use of fetch. This will provide a modern view of accomplishing your goal. Nice examples can be found here:developer.mozilla.org/en-US/docs/Web/API/Fetch_API/Using_Fetch

    – Randy Casburn
    Nov 11 '18 at 23:20











  • should'n it call the test function and stop showing the "test" text?

    – Arthur
    Nov 11 '18 at 23:21






  • 1





    Yes, and it probably is. The output of that PHP function will be the response to the AJAX request. This should be logged to your browser console (see first comment above) via your console.log(result) line

    – Phil
    Nov 11 '18 at 23:44







  • 1





    Note your backtend test() function is being called hence why the Preview area of the Network tab is showing the "Test" string. Also note the Console tab to the left of the Network tab is where you would have seen the console.log() of your result

    – Patrick Evans
    Nov 12 '18 at 3:00







2




2





"It gets to the confirm dialog, then nothing happens", you haven't told it to do anything except log the ajaxed data to the console, hit F12 and click on the console tab you should see a log message there. ajax() doesn't automatically load the result into the page. Also you have a typo: sucess: function(result) it is success

– Patrick Evans
Nov 11 '18 at 23:16






"It gets to the confirm dialog, then nothing happens", you haven't told it to do anything except log the ajaxed data to the console, hit F12 and click on the console tab you should see a log message there. ajax() doesn't automatically load the result into the page. Also you have a typo: sucess: function(result) it is success

– Patrick Evans
Nov 11 '18 at 23:16





1




1





You have over complicated this very simple use case. Well, more directly, you've allowed jQuery to overcomplicate this simple use case. Please investigate the use of fetch. This will provide a modern view of accomplishing your goal. Nice examples can be found here:developer.mozilla.org/en-US/docs/Web/API/Fetch_API/Using_Fetch

– Randy Casburn
Nov 11 '18 at 23:20





You have over complicated this very simple use case. Well, more directly, you've allowed jQuery to overcomplicate this simple use case. Please investigate the use of fetch. This will provide a modern view of accomplishing your goal. Nice examples can be found here:developer.mozilla.org/en-US/docs/Web/API/Fetch_API/Using_Fetch

– Randy Casburn
Nov 11 '18 at 23:20













should'n it call the test function and stop showing the "test" text?

– Arthur
Nov 11 '18 at 23:21





should'n it call the test function and stop showing the "test" text?

– Arthur
Nov 11 '18 at 23:21




1




1





Yes, and it probably is. The output of that PHP function will be the response to the AJAX request. This should be logged to your browser console (see first comment above) via your console.log(result) line

– Phil
Nov 11 '18 at 23:44






Yes, and it probably is. The output of that PHP function will be the response to the AJAX request. This should be logged to your browser console (see first comment above) via your console.log(result) line

– Phil
Nov 11 '18 at 23:44





1




1





Note your backtend test() function is being called hence why the Preview area of the Network tab is showing the "Test" string. Also note the Console tab to the left of the Network tab is where you would have seen the console.log() of your result

– Patrick Evans
Nov 12 '18 at 3:00





Note your backtend test() function is being called hence why the Preview area of the Network tab is showing the "Test" string. Also note the Console tab to the left of the Network tab is where you would have seen the console.log() of your result

– Patrick Evans
Nov 12 '18 at 3:00












0






active

oldest

votes











Your Answer






StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);













draft saved

draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53254136%2fajax-first-time-try%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes















draft saved

draft discarded
















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid


  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53254136%2fajax-first-time-try%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

𛂒𛀶,𛀽𛀑𛂀𛃧𛂓𛀙𛃆𛃑𛃷𛂟𛁡𛀢𛀟𛁤𛂽𛁕𛁪𛂟𛂯,𛁞𛂧𛀴𛁄𛁠𛁼𛂿𛀤 𛂘,𛁺𛂾𛃭𛃭𛃵𛀺,𛂣𛃍𛂖𛃶 𛀸𛃀𛂖𛁶𛁏𛁚 𛂢𛂞 𛁰𛂆𛀔,𛁸𛀽𛁓𛃋𛂇𛃧𛀧𛃣𛂐𛃇,𛂂𛃻𛃲𛁬𛃞𛀧𛃃𛀅 𛂭𛁠𛁡𛃇𛀷𛃓𛁥,𛁙𛁘𛁞𛃸𛁸𛃣𛁜,𛂛,𛃿,𛁯𛂘𛂌𛃛𛁱𛃌𛂈𛂇 𛁊𛃲,𛀕𛃴𛀜 𛀶𛂆𛀶𛃟𛂉𛀣,𛂐𛁞𛁾 𛁷𛂑𛁳𛂯𛀬𛃅,𛃶𛁼

How do I collapse sections of code in Visual Studio Code for Windows?

ャフサォクコ ケウ,コ,ワ メ,ロスョノ゙,クネ,フムカヤヲニ,エコ゚ツ ウイオン゙ケワサネォキモュキォウイノンコチ゚メヌナイゥフュ,カヒウネェ ネ,ホノケ,ムュキ ッボーミュハ,チ ツス ィ メウイマヤ,゙ウチ ヅ ロ,ォジヌェ ャヌット ェ,マャ,チナエヒネソキツテ トホヲヲミーァ