Why does this C code works on linux but not on Windows without cygwin
I have a C code.
#include <stdio.h>
#include <time.h>
#include <unistd.h>
int main()
int a = 1;
while( a <= 5 )
time_t t = time(NULL);
struct tm tm = *localtime(&t);
printf("Normal prinf funcation call from Cn");
fprintf(stdout, "STDOUT, Got on STDOUT from C. - now: %d-%d-%d %d:%d:%dn", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec);
fprintf(stderr, "STDERR, Got in STDERR from C. - now: %d-%d-%d %d:%d:%dn", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec);
sleep(1);
a ++;
return 0;
On Linux
I compile this C code with gcc. A binary gets generated.
I see the following as output, when I execute the binary;
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:38
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:38
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:39
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:39
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:40
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:40
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:41
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:41
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:42
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:42
On windows machine, using cygwin and gcc, I compile the same C code to a .exe file, Then try to run it in the cmd (not cygwin, works on cygwin). Nothing gets printed on the screen.
Is there any major difference between STDOUT/STDERR on Linux and on Windows?
How Can I make the .exe file print to command prompt(At least printf call should have worked.)?
P.S: I use the following command on both Linux and Windows to generate the binary/exe.
gcc C_code.c -o binary
c linux windows operating-system
asked Nov 10 '18 at 12:25
Nagri
1,36811643
add a comment |
I have a C code.
#include <stdio.h>
#include <time.h>
#include <unistd.h>
int main()
int a = 1;
while( a <= 5 )
time_t t = time(NULL);
struct tm tm = *localtime(&t);
printf("Normal prinf funcation call from Cn");
fprintf(stdout, "STDOUT, Got on STDOUT from C. - now: %d-%d-%d %d:%d:%dn", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec);
fprintf(stderr, "STDERR, Got in STDERR from C. - now: %d-%d-%d %d:%d:%dn", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec);
sleep(1);
a ++;
return 0;
On Linux
I compile this C code with gcc. A binary gets generated.
I see the following as output, when I execute the binary;
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:38
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:38
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:39
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:39
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:40
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:40
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:41
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:41
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:42
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:42
On windows machine, using cygwin and gcc, I compile the same C code to a .exe file, Then try to run it in the cmd (not cygwin, works on cygwin). Nothing gets printed on the screen.
Is there any major difference between STDOUT/STDERR on Linux and on Windows?
How Can I make the .exe file print to command prompt(At least printf call should have worked.)?
P.S: I use the following command on both Linux and Windows to generate the binary/exe.
gcc C_code.c -o binary
c linux windows operating-system
asked Nov 10 '18 at 12:25
Nagri
1,36811643
add a comment |
I have a C code.
#include <stdio.h>
#include <time.h>
#include <unistd.h>
int main()
int a = 1;
while( a <= 5 )
time_t t = time(NULL);
struct tm tm = *localtime(&t);
printf("Normal prinf funcation call from Cn");
fprintf(stdout, "STDOUT, Got on STDOUT from C. - now: %d-%d-%d %d:%d:%dn", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec);
fprintf(stderr, "STDERR, Got in STDERR from C. - now: %d-%d-%d %d:%d:%dn", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec);
sleep(1);
a ++;
return 0;
On Linux
I compile this C code with gcc. A binary gets generated.
I see the following as output, when I execute the binary;
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:38
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:38
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:39
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:39
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:40
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:40
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:41
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:41
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:42
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:42
On windows machine, using cygwin and gcc, I compile the same C code to a .exe file, Then try to run it in the cmd (not cygwin, works on cygwin). Nothing gets printed on the screen.
Is there any major difference between STDOUT/STDERR on Linux and on Windows?
How Can I make the .exe file print to command prompt(At least printf call should have worked.)?
P.S: I use the following command on both Linux and Windows to generate the binary/exe.
gcc C_code.c -o binary
c linux windows operating-system
asked Nov 10 '18 at 12:25
Nagri
1,36811643
I have a C code.
#include <stdio.h>
#include <time.h>
#include <unistd.h>
int main()
int a = 1;
while( a <= 5 )
time_t t = time(NULL);
struct tm tm = *localtime(&t);
printf("Normal prinf funcation call from Cn");
fprintf(stdout, "STDOUT, Got on STDOUT from C. - now: %d-%d-%d %d:%d:%dn", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec);
fprintf(stderr, "STDERR, Got in STDERR from C. - now: %d-%d-%d %d:%d:%dn", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec);
sleep(1);
a ++;
return 0;
On Linux
I compile this C code with gcc. A binary gets generated.
I see the following as output, when I execute the binary;
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:38
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:38
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:39
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:39
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:40
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:40
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:41
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:41
Normal prinf funcation call from C
STDOUT, Got on STDOUT from C. - now: 2018-11-10 17:44:42
STDERR, Got in STDERR from C. - now: 2018-11-10 17:44:42
On windows machine, using cygwin and gcc, I compile the same C code to a .exe file, Then try to run it in the cmd (not cygwin, works on cygwin). Nothing gets printed on the screen.
Is there any major difference between STDOUT/STDERR on Linux and on Windows?
How Can I make the .exe file print to command prompt(At least printf call should have worked.)?
P.S: I use the following command on both Linux and Windows to generate the binary/exe.
gcc C_code.c -o binary
c linux windows operating-system
c linux windows operating-system
asked Nov 10 '18 at 12:25
Nagri
1,36811643
asked Nov 10 '18 at 12:25
Nagri
1,36811643
asked Nov 10 '18 at 12:25
Nagri
1,36811643
asked Nov 10 '18 at 12:25
Nagri
1,36811643
asked Nov 10 '18 at 12:25
Nagri
1,36811643
1,36811643
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Cygwin is a POSIX-compatible environment. When you compile something in Cygwin - it is meant to run in Cygwin.
What you need is a port of GCC to Windows, called MinGW.
answered Nov 10 '18 at 12:31
Zaur Nasibov
13.8k93772
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Cygwin is a POSIX-compatible environment. When you compile something in Cygwin - it is meant to run in Cygwin.
What you need is a port of GCC to Windows, called MinGW.
answered Nov 10 '18 at 12:31
Zaur Nasibov
13.8k93772
add a comment |
Cygwin is a POSIX-compatible environment. When you compile something in Cygwin - it is meant to run in Cygwin.
What you need is a port of GCC to Windows, called MinGW.
answered Nov 10 '18 at 12:31
Zaur Nasibov
13.8k93772
add a comment |
Cygwin is a POSIX-compatible environment. When you compile something in Cygwin - it is meant to run in Cygwin.
What you need is a port of GCC to Windows, called MinGW.
answered Nov 10 '18 at 12:31
Zaur Nasibov
13.8k93772
Cygwin is a POSIX-compatible environment. When you compile something in Cygwin - it is meant to run in Cygwin.
What you need is a port of GCC to Windows, called MinGW.
answered Nov 10 '18 at 12:31
Zaur Nasibov
13.8k93772
answered Nov 10 '18 at 12:31
Zaur Nasibov
13.8k93772
answered Nov 10 '18 at 12:31
Zaur Nasibov
13.8k93772
answered Nov 10 '18 at 12:31
Zaur Nasibov
13.8k93772
13.8k93772
add a comment |
add a comment |
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