Set axis maximum with seaborn distplot

Set axis maximum with seaborn distplot



Is it possible to set the minimum and maximum displayed limits for seaborn distplots?



I am trying to loop over columns of a pandas dataframe but all my outputs get the same axes.


for v in var_list:
df[v].dropna(inplace=True)
var=df[v].max()
vstar = v + "_output.png"
splot = sns.distplot(df[v])
# sns.plt.xlim(0, var)
splot.figure.savefig(vstar)
splot.autoscale()



I have made a few attempts with sns.plt.xlim() and autoscale() but neither seems to do the trick. What am I missing?




1 Answer
1



You should be able to get what you want by just using plt.xlim(0, var) directly:


plt.xlim(0, var)


In [24]: np.random.seed(0)

In [25]: data = np.random.randn(1000)

In [26]: sns.distplot(data)
Out[26]: <matplotlib.axes._subplots.AxesSubplot at 0xfa291967f0>

In [27]: plt.savefig('plot1.png')



enter image description here


In [39]: plt.clf()

In [40]: sns.distplot(data)
Out[40]: <matplotlib.axes._subplots.AxesSubplot at 0xfa291bcd30>

In [41]: plt.xlim(-10, 10)
Out[41]: (-10, 10)

In [42]: plt.savefig('plot2.png')



enter image description here





And by the way, if you'd rather use the object oriented API and operate directly on the Axes that sns.distplot returns (which quickly becomes beneficial for more complicated plots), you could also use splot.set_xlim(0, var) prior to saving the figure. The end result is the same
– fuglede
Sep 2 at 9:13



Axes


sns.distplot


splot.set_xlim(0, var)



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