python regex to match file name but get None
I have a few files in the folder and I want to find out the content and match its file name. But when I use re.search to achieve my goal I can only get ‘None’. Anyone could help?
import re
xe = r'D:ABCcc123.xml'
re.search('cc*?.xml', xe)
python regex
edited Nov 12 '18 at 2:27
coldspeed
131k23137222
asked Nov 12 '18 at 2:22
CHENLUCHENLU
244
add a comment |
I have a few files in the folder and I want to find out the content and match its file name. But when I use re.search to achieve my goal I can only get ‘None’. Anyone could help?
import re
xe = r'D:ABCcc123.xml'
re.search('cc*?.xml', xe)
python regex
edited Nov 12 '18 at 2:27
coldspeed
131k23137222
asked Nov 12 '18 at 2:22
CHENLUCHENLU
244
also, for future reference, you can use something like pythex to test your regular expressions, and python regex documentation for syntax
– robotHamster
Nov 12 '18 at 2:33
add a comment |
I have a few files in the folder and I want to find out the content and match its file name. But when I use re.search to achieve my goal I can only get ‘None’. Anyone could help?
import re
xe = r'D:ABCcc123.xml'
re.search('cc*?.xml', xe)
python regex
edited Nov 12 '18 at 2:27
coldspeed
131k23137222
asked Nov 12 '18 at 2:22
CHENLUCHENLU
244
I have a few files in the folder and I want to find out the content and match its file name. But when I use re.search to achieve my goal I can only get ‘None’. Anyone could help?
import re
xe = r'D:ABCcc123.xml'
re.search('cc*?.xml', xe)
python regex
python regex
edited Nov 12 '18 at 2:27
coldspeed
131k23137222
asked Nov 12 '18 at 2:22
CHENLUCHENLU
244
edited Nov 12 '18 at 2:27
coldspeed
131k23137222
asked Nov 12 '18 at 2:22
CHENLUCHENLU
244
edited Nov 12 '18 at 2:27
coldspeed
131k23137222
edited Nov 12 '18 at 2:27
coldspeed
131k23137222
edited Nov 12 '18 at 2:27
coldspeed
131k23137222
131k23137222
asked Nov 12 '18 at 2:22
CHENLUCHENLU
244
asked Nov 12 '18 at 2:22
CHENLUCHENLU
244
asked Nov 12 '18 at 2:22
CHENLUCHENLU
244
244
also, for future reference, you can use something like pythex to test your regular expressions, and python regex documentation for syntax
– robotHamster
Nov 12 '18 at 2:33
add a comment |
also, for future reference, you can use something like pythex to test your regular expressions, and python regex documentation for syntax
– robotHamster
Nov 12 '18 at 2:33
also, for future reference, you can use something like pythex to test your regular expressions, and python regex documentation for syntax
– robotHamster
Nov 12 '18 at 2:33
also, for future reference, you can use something like pythex to test your regular expressions, and python regex documentation for syntax
– robotHamster
Nov 12 '18 at 2:33
add a comment |
2 Answers
2
active
oldest
votes
(Though there is an accepted answer, I don't feel the answer is clear for other people, and there is still room to improve, so I added a new answer here)
The problem is simply OP is using a wrong regex: cc*?.xml
* means any occurrence of the preceding token (which means c in your case)*? is a reluctant match any occurrence.. means any character
Which means what you are trying to do is match a string which is:
- a
c - followed by any occurrence of c
- followed by any character
- followed by
xml
Example of matching strings are c.xml ccccccAxml etc.
What you were trying to do, I believe is
cc.*?.xml
which means matching
cc.*?: followed by any occurrence of any character, matching as few as possible.: followed by a dot (note the difference of.vs.)- followed by
xml
answered Nov 12 '18 at 3:04
Adrian ShumAdrian Shum
28.7k762107
add a comment |
How about something like this with a small tweak?
import re
xe = 'D:ABCcc123.xml'
print (re.search('cc.*?.xml', xe).group())
output:
cc123.xml
answered Nov 12 '18 at 2:31
LeKhan9LeKhan9
946112
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
(Though there is an accepted answer, I don't feel the answer is clear for other people, and there is still room to improve, so I added a new answer here)
The problem is simply OP is using a wrong regex: cc*?.xml
* means any occurrence of the preceding token (which means c in your case)*? is a reluctant match any occurrence.. means any character
Which means what you are trying to do is match a string which is:
- a
c - followed by any occurrence of c
- followed by any character
- followed by
xml
Example of matching strings are c.xml ccccccAxml etc.
What you were trying to do, I believe is
cc.*?.xml
which means matching
cc.*?: followed by any occurrence of any character, matching as few as possible.: followed by a dot (note the difference of.vs.)- followed by
xml
answered Nov 12 '18 at 3:04
Adrian ShumAdrian Shum
28.7k762107
add a comment |
(Though there is an accepted answer, I don't feel the answer is clear for other people, and there is still room to improve, so I added a new answer here)
The problem is simply OP is using a wrong regex: cc*?.xml
* means any occurrence of the preceding token (which means c in your case)*? is a reluctant match any occurrence.. means any character
Which means what you are trying to do is match a string which is:
- a
c - followed by any occurrence of c
- followed by any character
- followed by
xml
Example of matching strings are c.xml ccccccAxml etc.
What you were trying to do, I believe is
cc.*?.xml
which means matching
cc.*?: followed by any occurrence of any character, matching as few as possible.: followed by a dot (note the difference of.vs.)- followed by
xml
answered Nov 12 '18 at 3:04
Adrian ShumAdrian Shum
28.7k762107
add a comment |
(Though there is an accepted answer, I don't feel the answer is clear for other people, and there is still room to improve, so I added a new answer here)
The problem is simply OP is using a wrong regex: cc*?.xml
* means any occurrence of the preceding token (which means c in your case)*? is a reluctant match any occurrence.. means any character
Which means what you are trying to do is match a string which is:
- a
c - followed by any occurrence of c
- followed by any character
- followed by
xml
Example of matching strings are c.xml ccccccAxml etc.
What you were trying to do, I believe is
cc.*?.xml
which means matching
cc.*?: followed by any occurrence of any character, matching as few as possible.: followed by a dot (note the difference of.vs.)- followed by
xml
answered Nov 12 '18 at 3:04
Adrian ShumAdrian Shum
28.7k762107
(Though there is an accepted answer, I don't feel the answer is clear for other people, and there is still room to improve, so I added a new answer here)
The problem is simply OP is using a wrong regex: cc*?.xml
* means any occurrence of the preceding token (which means c in your case)*? is a reluctant match any occurrence.. means any character
Which means what you are trying to do is match a string which is:
- a
c - followed by any occurrence of c
- followed by any character
- followed by
xml
Example of matching strings are c.xml ccccccAxml etc.
What you were trying to do, I believe is
cc.*?.xml
which means matching
cc.*?: followed by any occurrence of any character, matching as few as possible.: followed by a dot (note the difference of.vs.)- followed by
xml
answered Nov 12 '18 at 3:04
Adrian ShumAdrian Shum
28.7k762107
answered Nov 12 '18 at 3:04
Adrian ShumAdrian Shum
28.7k762107
answered Nov 12 '18 at 3:04
Adrian ShumAdrian Shum
28.7k762107
answered Nov 12 '18 at 3:04
Adrian ShumAdrian Shum
28.7k762107
28.7k762107
add a comment |
add a comment |
How about something like this with a small tweak?
import re
xe = 'D:ABCcc123.xml'
print (re.search('cc.*?.xml', xe).group())
output:
cc123.xml
answered Nov 12 '18 at 2:31
LeKhan9LeKhan9
946112
add a comment |
How about something like this with a small tweak?
import re
xe = 'D:ABCcc123.xml'
print (re.search('cc.*?.xml', xe).group())
output:
cc123.xml
answered Nov 12 '18 at 2:31
LeKhan9LeKhan9
946112
add a comment |
How about something like this with a small tweak?
import re
xe = 'D:ABCcc123.xml'
print (re.search('cc.*?.xml', xe).group())
output:
cc123.xml
answered Nov 12 '18 at 2:31
LeKhan9LeKhan9
946112
How about something like this with a small tweak?
import re
xe = 'D:ABCcc123.xml'
print (re.search('cc.*?.xml', xe).group())
output:
cc123.xml
answered Nov 12 '18 at 2:31
LeKhan9LeKhan9
946112
answered Nov 12 '18 at 2:31
LeKhan9LeKhan9
946112
answered Nov 12 '18 at 2:31
LeKhan9LeKhan9
946112
answered Nov 12 '18 at 2:31
LeKhan9LeKhan9
946112
946112
add a comment |
add a comment |
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also, for future reference, you can use something like pythex to test your regular expressions, and python regex documentation for syntax
– robotHamster
Nov 12 '18 at 2:33